This video saved me, trig identities is one of the hardest things to wrap my head around so this video was a major help! Thank you so much!

@Swankydopeshow

2 жыл бұрын

Fellow Cowboy Bebop enjoyed I see, anyways thanks for the comment I needed to see how great this video would be, have a good day

@wormdeath

2 жыл бұрын

@@Swankydopeshow Glad I could help you, space cowboy

@maheerhuq6708

2 жыл бұрын

@@wormdeath W INTERACTION W

@johnarickmedinasyc2546

2 жыл бұрын

@@maheerhuq6708 FACTS

@W2CH1

2 жыл бұрын

Ayyy thanks for the comment insight space ranger

I just realized, this man has been helping me ever since middle school algebra, you’re an amazing teacher, thank you so much for your devotion

Such a cathartic feeling when you're halfway through the vid and you can say the answers before he does. Awesome lesson Mr. McLogan!

I was lost by problem 5

This is amazing! I have learnt countless amount of things from this channel. Thanks!

Endless thank you’s go out to you man. Such a great teacher! Keep up the good work man, you always help out tons

Please slow down a little next time. It would also be helpful to include an, "if you are struggling with these concepts review videos a and b." Thanks

At 25:21 isn't 1/sec^2 = cos^2 and not tan^2?

@elijahjohnson3125

3 жыл бұрын

Thought the same thing man

@timothyallshouse3524

3 жыл бұрын

ya same, i was like wth, then i saw that he was wrong but ya it is cos^2

@srihariananthalwan4610

2 жыл бұрын

Yea u right I was like wtf is my whole life a lie and then I realized it was just a silly mistake

@fly4lyf_213

Жыл бұрын

The reciprocal of sec is cos.

This is all...so above my head. Thanks for the help~

how did you distribute number 5?

For problem 14 wouldn't the answer be "sin2x+1"? You should be able to simply the 2sinxcox to sin2x due to sine double angle identity. sin2θ = 2sinθcosθ

This was amazing, thank you! Lots of practice to run through with someone who knows that they're doing. I also got cos^2X for 21, and also didn't understand 22 either. Thanks for the video!

@maomaozzz

3 ай бұрын

I also got cos^2theta for #21 I think he made a mistake

Is the answer to question 5 correct ? I calculated the answer as (sin^2(x)+1)/(cos^2(x)) and verified it with the Symbolab program

I love your vids I was always bad at math and because of your vids I’m able to learn so easily summer pre cal is rough and your vids are a life saver I’ve been watching you ever since I decided to try college and my grades have been straight As, because of you I decided to choose stem major even though I always hated math.

Thanks a lot sir😇😇may God Bless you

I like what you did here. How did you do this to have it show the problems that you are working behind you. Also where can I find more problem sets to work on and practice

This is a Precal topic. Great. Thanks 👍👍👍👍

Thank you so much sir; you the G.O.A.T!!

Error on #20 -- sec^2(x) = tan^2(x) + 1. Denominator should have been -1, which would make the answer -5(tan(x) - sec(x)), or if you prefer, 5(sec(x) - tan(x)).

@fly4lyf_213

Жыл бұрын

I also got -5(tanx - secx) at first. But then, I end up doing what the professor did. So I guess it can be done both ways?

@johnathanpatrick6118

Жыл бұрын

@@fly4lyf_213 The negative sign matters here. When you multiply both the numerator and denominator of the expression by tan(x) - sec(x), you get a difference of squares in expanded form, tan^2(x) - sec^2(x). One of the core trig identities is sec^2(x) - tan^2(x) = 1 (the others are sin^2(x) + cos^2(x) = 1 and csc^2(x) - cot^2(x) = 1); if you had this resulting difference of squares you would be correct to not put the negative sign in front of the 5. In order to get tan^2(x) - sec^2(x) on the left you'd have to multiply by -1 and do likewise on the right, meaning tan^2(x) - sec^2(x) = -1. Back to Professor McLogan's work, because the 5 in front of tan(x) - sec(x) is positive, you have positive divided by negative which is negative; that means if you want to keep tan(x) - sec(x) as part of your answer, you must attach the negative in front of the 5. Otherwise, you can distribute the negative and get sec(x) - tan(x) while keeping the 5 positive.

amazing video, love your energy!

It seems that the sign is wrong on the answer to question 20 since sec^2x=tan^2x+1 not tan^2x-1

Thank you 🙏 this helps a lot

for number 9 cotxcosx can still be simplified can we do cos/sin times cos and we can get rid of cos and get sine as the final answer?

Trig exam the next three hours🇯🇲🇯🇲🇯🇲🇯🇲👍👍i am gonna smash it

24:26 Tan²x - tan²x =1?????

thank u very much.. I have much respect but error in 21:- 1/sec2theta is cos2 theta...... with much respect

@brianmclogan

2 жыл бұрын

Appreciate you letting me know

Thank you Mr. McLogan. You saved my math score 🤧

he switched up number 24 at the last minute. The answer to the original # 24 is secx !

Thank you so much ! :)

Thank you so much!

Fantastic!

Why the question 24 changed in the end @.@

how is #21, 1/sec^2(theta) = tan^2(theta)?

I am truly grateful for this video😭💖Thank you so much! I hope I can answer my exam tomorrow

@brianmclogan

2 жыл бұрын

You got this!!

Thank you.

Thank you

thank you bro

nawa'y makasurvive sa trigo exam bukas

Shouldn't the answer to Question 21 be cos^2x ?

@patrickclinton2802

3 жыл бұрын

Yes

@patrickclinton2802

3 жыл бұрын

Also question 20 is incorrect

in my country csc writes as cosec

Sir in the book identies is (1+tan^2x = sec^2x )

i don't get number 2... how does that make sense? how can that sin of pi/2 -x equal cos x?

@julia-qp1wb

3 жыл бұрын

you may have figured this out by now since you commented this a week ago, but anyway: it’s another set of identities called cofunction identities that include pi/2. find a list of them online, it will make more sense then

1/sec^2θ ≠ tan^2θ 1/sec^2θ = cos^2θ

17:59

Amazingg, but didn't understand no. 22

did you made a mistake on number 20? cause i thought sec2x transform to 1+tan2x, can someone explain this to me?

@brianmclogan

2 жыл бұрын

Could have

you da man

Problem 21 25:13 Minute its 1/sec^2x and the answer was cos^2x

I think there might be an error with 21.

Error at 16:54 , 2sinxcosx = sin2x

I must just be dumb asf cause how the hell did he just do 3

Thank you 😊

You're my bestie

Why did KZread recommend this to me?

21. 1/sec^2x = cos^2x

i don't agree with number 17

@johnathanpatrick6118

2 жыл бұрын

What's wrong with #17?

uhmmm... You never age....

livestream?

@l_Scythe_l

4 жыл бұрын

@Asiful Alam Choudhury I meant if he was going to do one

#20 is wrong. Sec²x = tan + 1 so the answer ends up -5(tanx - secx) You did another mistake #21 1/sec²x = cos²x not tan²x Silly mistakes they get us all!

Let's get it let's go 🚀🥳🤸🏋️⛹️🤾💯💫