This is Prof. Jay Mistry Prof. Of statistics. Wonderful and amazing explanation. Keep it up.😇

Thank you Mam for Wonderful Explanations .

Thank you so much... it's really needed for sem 6 tybcom exam

Ans : Mean = 4.5 S.D. = 1.5 Z = 2 So , H0 is Rejected .

Whichever is less positive or negative is considered r right ?

Mam Z

Thank you mam your explanation is very well 🤗

Best video ever in youtube

The question u solved is two tailed. significance level for two tailed test is 0.025 (0.05/2) not 0.05

Thanks a bunch ma'm...

Hello Mam.... Second Example Normal distribution H0 is accepted Binomial distribution H0 is rejected

great explanation I say

Hello mam can u give me the solution of that question u have given in home work

Mam why we have decided negative signs i.e. 2 as r.......why not positive?

Mam , You are really so Nice .

How to get r ??

Memm binomial method is answer is 0.003 and normal method is answer is -2 right yaa wrong answer

In finding z value ...there should be minus sign but you write positive sign kindly explain this mam

The table you derived was wrong there is no value as 12 in question you must have mistakenly taken 12 in place of 15 please re check it

Wonderful Expansion ma'am 🤭

Thanks 👍🏻❤

I really counfuse in this sum book . And I found this thanku

How to find value of ⁷Co

Z ki value to negative m.arahi h ?? Then uska kea bnega mam plzz

Accepted both

Some teachers use directly t pstv t netv and t minm.

Wowwww.

7c2 how to solve it???please help

You comapre with 1.96 in normal distribution but in case of bionomial distribution you compare with 0.05 i have confusion with this

@apoorvasaxena6351

2 жыл бұрын

Actually for large n we use standard normal usually binomial distribution

Mem 1.wald wolfowitz run test 2.kruskal Wallis test इन दो टॉपिक पर वीडियो बना दो एग्जाम है हमारे इसलिए plz

આભાર બહેન

Normal distribution R=1.5 Mean=4.5 S d=1.5 Z=2 Z≤1.96 then our Z=2 ..so HO is rejected.. Binomial distribution... n=9 R=1 P(r≤ro)>0.05 Ans= p(r≤ro) =0.01953=0.02 Then HO is rejected... Is it correct mam ??!

@statisticsforall3433

2 жыл бұрын

Yes correct

we can use Z statistics if Positive (+) sign + Negative (-) sign >25. Otherwise we cant use Z Statistics

Z= 0.2 Ho is accepted

If positive and negative sign are equal how can we compute

@Knowledgeislight16

Жыл бұрын

We will consider lesser value sign

Ma'am I didn't get, how did u solve 7C0, 7C1, 7C2.... how did u get 1,7,21 ?

@statisticsforall3433

2 жыл бұрын

I used combination formula nCr = n! / r! (n-r)!

there is soo much error in this video. Firstly we will not get -= sign becase the value of x is 15 n not 12. And second i am getting Z as -0.75 because it is 2.5-3.5

Madam you took mean as n/2 but mean is something different, like add values and then divide by Numbers. Kindly explain this. Secondly how did you take s S. D? What's it's General formula? By the way your method of teaching is best, I like it

@kmrathex40

Жыл бұрын

Same confusion

By normal distribution : Z=2 S.d=1.5 Revised n = 9 Mean = 4.5 r=1.5 Ho is rejected By binomial distribution : P(r≤ro) = 0.02 P(r≤ro) Ho is rejected Thank u ☺️

@yesheshshreereddy2111

2 жыл бұрын

Exactly!!, I got confused for a minute

@akanksharajpoot4662

6 ай бұрын

Why n is 9 not 8 ...total numbers are 8

What is Z

@mishaj2603

3 жыл бұрын

They give u z value.

12 nai h 15 hai + hoga

If median is greater than 2 , so when we find d = x - M , we have to take M = 2. Is it correct?

@tanishjain4375

3 жыл бұрын

And for binomial distribution we will take n as 10 or 9?

@statisticsforall3433

3 жыл бұрын

Yes take m = 2 and n = 9 because there is one = sign

Mam aap ne 15 ki jaga 12 liya hai question or answer pura galat hai

Z = 2, mean = 4.5, sd = 1.5, r = 1.5 2 > 0.05 Ho is rejected.

@dhruvdesai6473

2 жыл бұрын

2 value comes in minus so it is Accepted na......

Mean 4.5 R = 1.5 S.d 1.5 1.5-4.5/1.5...so Its -2 so It is Accepted na bcoz value comes in minus...... Leeser than 1.96

@Horrorwithritesh

2 жыл бұрын

No man you're wrong we have to ignore that minus and have to write it in positive form !!

@dhruvdesai6473

2 жыл бұрын

@@Horrorwithritesh Thanks Man 👍🏻

The production manager in a large undertaking randomly paid 10 visits to the work site in a month. The number of workers who reported late for duty were found to be 2, 4, 5, 1, 6, 3, 2, 1, 7 and 8 respectively. Using the sign test, verify the claim of the production superintendent at 0·05 level of significance that on an average not more than 3 workers report late for duty. Ma’am please tell how can solve it.

@statisticsforall3433

Жыл бұрын

Put negative sign for numbers which are less than three and positive sign for numbers which are more than three then solve by the explained method

Me'am 15 ki jagah apne 12 le liya hai!! = nahi ayenga!!

r = 2 hi Kyu liya?? 5 Kyu nahi??

@statisticsforall3433

3 жыл бұрын

Smaller value is taken as r

@nehaprajapati699

3 жыл бұрын

@@statisticsforall3433 thank u ma'm

@RiteshKumar-td8kv

Жыл бұрын

Ma’am if positive sign and negative sign are equal then what is the result

Aapne 15 ki jagah 12 likh diya questions dekho apna

@statisticsforall3433

2 жыл бұрын

Yes you are right. There is mistake in the question it is 12 not 15