You made it look so easy to understand. I used to struggle really hard drawing this diagram but you made it look simple. Thank you very much

I was so confused about this and found it hard until i watched the video. Fantastic explanation clear and easy to understand.

you taught me what all my teachers failed to teach me! thanks

@Engineer4Free

5 жыл бұрын

Glad I can help

Statics final tomorrow, wish me luck!

@Engineer4Free

5 жыл бұрын

Ahhhh good luck for real Matt!!! Check out engineer4free.com/statics for all my statics videos and then also the first section of engineer4free.com/structural-analysis if you ned more practice with SFD/BMD!

@argenisperez3467

5 жыл бұрын

Same here friend, best of luck to you

@eddiemartin2268

5 жыл бұрын

Hope it went well! Got statics in a few days!

@azamkhan1526

4 жыл бұрын

how was ur result?

@venchanpiseth1321

4 жыл бұрын

@@Engineer4Free what is the program that u used to draw this?

Looking up old notes for a job interview and left my notes at my parents house in California. I now live in Washington. This was a lot better than digging through notes and more straightforward and easy to understand. Thanks for the help!

@Engineer4Free

4 жыл бұрын

Glad I could help! Check out engineer4free.com/structural-analysis for some more examples if you haven’t already, and good luck with the interview!!

You sir, are a hero. Thank you for this labor of love.

@Engineer4Free

5 жыл бұрын

Thanks friend 🙂

4 years later and the video still helps. God bless you!

@Engineer4Free

2 жыл бұрын

Can't believe it's already been 4 years! Thanks for still watching in 2021! =)

thank you so much for these amazing videos!! my structural mechanics exam tomorrow and i’m terrified but a bit less so now that i’ve found these

@Engineer4Free

2 жыл бұрын

Hope it went well!

That's the most humane explanation (simplest) ever. Thank you so much!

@Engineer4Free

2 жыл бұрын

Thanks Yato! 😊

You sir are a whole legend. A method I can finally understand completely. Many blessings!

@Engineer4Free

5 жыл бұрын

Thanks Tahira!!!

UR A LIFE SAVING GENIUS!!! I have watched so many videos to try to figure out how to determine the location the sheer diagram crosses zero and all of them were so messy and complicated! - this was so easy and straight forward! May God bless ur soul!

@Engineer4Free

7 ай бұрын

Thanks Sarah 😊. You might find the rest of the examples helpful too, they are here: www.engineer4free.com/blog/ultimate-guide-to-shear-force-and-bending-moment-diagrams

Your BM calculation and BMD was super helpful. Thank you

Four years of undergrad ME, and this is the cleanest statics beam bending video I've seen. Good stuff

@Engineer4Free

4 жыл бұрын

I got 8 more right where that came form: engineer4free.com/structural-analysis 😂😂. But thanks tho

Explain so much better than my professor. Thank you for all that you do

Sir please know that you are a great teacher, keep it up, I love your videos!!!

I have mechanics of materials finals tomorrow and I want to say my teacher tried to explain this for 2 weeks and couldn’t do what you did in 10 mins! Thank you

@Engineer4Free

5 жыл бұрын

That's unfortunate that you got that professor, but great feedback about my videos.. Thanks for sharing and glad I could help =)

You are helping generations man keep it up

This was great! You explained it in a very good and understanding way. Thank you. I will become a civil engineer in a few years and this has helped me a lot.

@Engineer4Free

4 жыл бұрын

Awesome! Th aks for commenting, and good luck in your studies! I've got a lot of videos that can help you 🙂🙂

Quality stuff. just lovin' these lectures

@Engineer4Free

5 жыл бұрын

Thanks!! =)

This explanation has saved my life. Big thank you sir. God bless you with whatever you want

@gladys5753

2 жыл бұрын

Hey cousemate,we a test today hopefully u still remember

What a helpful video! Thanks for helping me review for the FE :)

@Engineer4Free

5 жыл бұрын

Thanks for the feedback Priscilla, good luck on your exam!!

idk how many times i go back to see this explanation, much helpful than the teachers slides

@Engineer4Free

3 жыл бұрын

Glad to hear its helping!! =)

I have a statics quiz tomorrow. Thank you for the information. You, sir, are a hero.

@Engineer4Free

5 жыл бұрын

Good luck!!! =)

Sir you are the best! Thank you very much for sharing this video! You've helped me a lot

@Engineer4Free

4 жыл бұрын

Awesome! Glad to hear it, hope you find my other vids helpful too 🙂🙂

Thank you! Saved me. Fell asleep in my statics lecture and was so lost in this

@Engineer4Free

4 жыл бұрын

😂😴

Thank you for this!

Good job man! helped me a lot :)

@Engineer4Free

5 жыл бұрын

Awesome glad to hear it!!

thank you my friend for this simplify and hope you the best

@Engineer4Free

5 жыл бұрын

You're welcome bud!

I have a question, we were taught (long time ago, already forgot alot) that for all structural analysis on civil engineering problems, we are to put the positive moments at the bottom side of the axis, so that the bmd correlates with tension, and whenever there is a distributed load, bmd has to be parabolic, with the arc bending with the direction of the dis. load, now looking at other people's examples, haven't seen anyone mention the inverted signs on bmd; so now im trying to wrap my head around if that holds true (specifically the arc bend going with the direction of udl) in all examples ?

You earn my subscription. Thanks a lot man!

@Engineer4Free

4 жыл бұрын

Honoured to have it, thanks Joey!! 🤜🤛

You’re amazing thank you so much 😊

@Engineer4Free

5 жыл бұрын

Thankssssss =) =)

You are a lifesaver! had so much trouble with these questions but it all makes so much sense now, thank you :)

@Engineer4Free

3 жыл бұрын

Glad I could help!! =)

Thank you very much Sir for the great content!

Absolutely grateful, thank you.

@Engineer4Free

5 жыл бұрын

Awesome Ahmed!! 🙂

you are the best ,my lecturer never explained where the area came from

@Engineer4Free

3 жыл бұрын

Thanks Elias. I definitely recommend checkout out the other videos I did on SFD and BMD for more practice too: www.engineer4free.com/blog/ultimate-guide-to-shear-force-and-bending-moment-diagrams =)

God bless you my brother, Thank you so much!

@Engineer4Free

4 жыл бұрын

Your welcome Phil!! 😊

cant thank you enough, truly appreciated

God bless you for your nice explaination.

this is so helpful thank you so much!

@Engineer4Free

5 жыл бұрын

Thanks for letting me know, glad to hear it!! I have more examples like it at engineer4free.com/structural-analysis check them out!!

Duuuude you are the OG of statics!

@Engineer4Free

4 жыл бұрын

Hahaha thanks Menyota 🤜🤛

Thank you sir. Your teaching method is easy to understand for a common person like me🤗🤗

@Engineer4Free

5 жыл бұрын

Awesome, that's the goal!

Good PE exam review. Thanks bud.

@Engineer4Free

5 жыл бұрын

Thanks for the feedback, hope the exam goes well!

thank you very much, it helps a lot

@Engineer4Free

5 жыл бұрын

Hey thanks for the comment =)

I have CVE test in like 2 hours 😂😂 this was a huge help

Thank you so much! Studying for the FE exam after years away from school and struggling with this section

@Engineer4Free

4 жыл бұрын

Hey Raúl, happy to help! Make sure you check out the rest of the vids on engineer4free.com this is from the Structural Analysis playlist

@gowthamthotapalli8867

3 жыл бұрын

@@Engineer4Free can u elaborate support reaction A.

You saved me! Thanks a lot. wish me luck for the exam in 6days 😭

@Engineer4Free

4 жыл бұрын

Yeah good luck!! Check out 8 more examples in section one of engineer4free.com/structural-analysis 🙌🙌

It is helpful. Thank you sir.

I was little confuse to determine if it is concave upward or concave downward if you sketch in moment diagram but i really appreciate your video 😊

@Engineer4Free

5 жыл бұрын

Where the BMD is positive, the curvature will be concave up, where the BMD is negative, the deflected beam will be concave down. At points where the BMD switches from positive to negative, you have an inflection point in the curvature. This is a good example that highlights it: engineer4free.com/4/shear-force-and-bending-moment-diagram-practice-problem-8 but I also recommend just watching videos 1-9 here: engineer4free.com/structual-analysis for more examples and practice to get the hang of these

thanks from all of my heart

THANK YOU FOR THIS VIDEO

And how to find the bending reinforcement from there ? Would be very pleased, if someone will explain

THANKS FOR SUCH A NICE LESSON.

@Engineer4Free

4 жыл бұрын

UR WELCOME

The video is really helpful

You a hero who save my assignment

@Engineer4Free

4 жыл бұрын

Awesome!!! =) =)

As an architect student, this is really useful (im learning how to do this before its taught in a lecture lol)

@Engineer4Free

4 жыл бұрын

Smart move my friend, it will make your life much easier to be ahead both in the sense of time, and understanding with this stuff!!

@ahmedyehia9560

Жыл бұрын

Where do u use structural analysis as an architect ?

@michaelhunt2222

Жыл бұрын

@@ahmedyehia9560 nah lol

@gadieloros6280

Жыл бұрын

@@ahmedyehia9560 you dont haha its more for the arch. engineers not much architects

@ancy200

Жыл бұрын

It's more useful to Civil engineers not Architecture

thank you so much

thank you. clear and informative.

@Engineer4Free

3 жыл бұрын

Glad it was helpful! =)

thank you, I understand shear force and bending moment much better.

@Engineer4Free

3 жыл бұрын

Glad to hear it!! 🙂

Thanks for the useful video!!!

@Engineer4Free

4 жыл бұрын

You're welcome, glad I can help!!

thank you very much My Teacher , your student from Syria

@Engineer4Free

5 жыл бұрын

You're welcome, I hope you can find more of my videos helpful!

how did you get 10(3)(6) where is the 3m coming from if the point load is at 6m

@Engineer4Free

4 жыл бұрын

(10kN/m)*(6m)=60kN is the magnitude of the entire distributed load. It’s centroid (location of resultant) is in its middle, which is 3m from either side of it. That means the resultant is 3m away from point A. So (60kN)*(3m)=180kNm is the magnitude of the moment that the distributed load causes about A. Note that the units check out too for the units of a moment!

@lemitowfik5881

4 жыл бұрын

Engineer4Free ....so we only multiply centroids for distributed systems cases??

@WetPig

4 жыл бұрын

@@lemitowfik5881 It's physics, the moment is the force times the moment arm(distance). So what happens is you have an integral F(force)x(distance)dx, from in the case of the video from 0 to 6. That integral's solution is (Fx^2)/2 = (10(kN)6^2)/2 = (10x360)/2= 180kN. It could be -180kN, but you have to look if that makes sense in the specific problem. I have this as a one time course in my computer-related physics major (can't translate it) I've had only 2 lessons, don't know anything.

@alupha_216

3 жыл бұрын

Just as lost as you are mate, I’m still looking a video that’ll explain everything from the start ☹️

@drofeng

3 жыл бұрын

Check out this video on force resultants kzread.info/dash/bejne/k4CqrpNuksjgo7A.html

You Sir are a legend

@Engineer4Free

5 жыл бұрын

Thanks Nadeem =)

Great videos. Do you know anywhere one could find shear and moment diagram practice problem videos like this for distributed loads of varying shapes, such as parabolas, triangles, etc?

@Engineer4Free

6 жыл бұрын

I've got some videos for finding reaction forces with triangular/parabolic etc distributed loads under the "centroids and distributed loads" section of engineer4free.com/statics that would be a good starting point, as that is the first step in drawing the SFDs and BMDs. I should include some actual examples through on doing full problems. Thanks for the suggestion, hopefully I can get around to making some soon!

Appreciate your work thanks

@Engineer4Free

3 жыл бұрын

Thanks Lim!! =)

This was helpful asf...thank you 😭❤️

@Engineer4Free

Жыл бұрын

Glad it helped! Full playlist is here engineer4free.com/structural-analysis 👍

Bro you are a real Engineer!!

@Engineer4Free

2 жыл бұрын

Hahaha, thanks!! 💪

thanks a lot sir.........keep up the good work.....may you propsper more and more

@Engineer4Free

4 жыл бұрын

Thanks friend!!!

You are a mazing thank you so much Good luck From Egypt 🇪🇬

@Engineer4Free

3 жыл бұрын

Thanks and welcome =) =)

thank u bro!

@Engineer4Free

5 жыл бұрын

ur welcome marco👌👌

just so you know you're still saving lives

@somtoobienu5081

3 жыл бұрын

Yep

@Engineer4Free

3 жыл бұрын

Glad to hear it =) =)

If the vertical load and moment are removed, what is the final length of the beam after deformation? I've got this question in one my exams what do it mean?

@olevel_maths1470

2 жыл бұрын

BMD and SFD (100%) kzread.info/dash/bejne/dIhkrq6eZMKzY6Q.html

Wow, thank you, sir, It's hard for me to understand the mechanics of deformable bodies in this online class. I'm glad that I found your playlist sir thank you very much 💚💚

@Engineer4Free

3 жыл бұрын

Glad I can help!! I have 3 playlists related to structures. Depending on the topic, the videos may be in one or another: engineer4free.com/statics engineer4free.com/mechanics-of-materials engineer4free.com/structural-analysis =)

@brenkolenicolas4186

3 жыл бұрын

@@Engineer4Free oh thank you very much I appreciated all your effort to help us learn about these lessons thank you very much sir :)

Sir you have just saved my life

@Engineer4Free

3 жыл бұрын

Glad to hear it! You can check out more examples here: www.engineer4free.com/blog/ultimate-guide-to-shear-force-and-bending-moment-diagrams =)

i'm having trouble getting Ra and Rb i wish you do it step by step

@Engineer4Free

5 жыл бұрын

The line where I write sum of moments about A has a single unknown, which is B (Rb). Just rearrange to solve for B. For A (Ra), just take the sum of forces in the vertical direction. Knowing that Rb is 30kN up from the previous step, the sum of forces in y is (-10kN/m)(6m) - 20kN + 30kN + A = 0 ... just simplify and rearrange for A ... A = 50kN up. Hope that helps.

Hello sir thank you very much. I would like to ask 8:13 is the point of zero shear (crossing zero part in shear) always where you get the maximum moment? Im doing an exercise right now and the maximum moment im getting is not on the point of zero shear.

@Engineer4Free

3 жыл бұрын

Hey Nigel, yes, where the SFD crosses the x axis you will always have a local max (or min) on the BMD. Also good to know, where the BMD crosses the x axis, you will have an inflection point on the deflected shape. So it sounds like you just have an error somewhere in your work. Double check that you have solved for the reactions correctly.

Thanks so much for the tutorial! Please may you elaborate on the "similar triangles" solution to find x on the SF diagram? Also, are there other ways of finding x? Thank you.

@sacayan_johnn

2 жыл бұрын

So the 50/x is the smaller triangle on the SFD. x is the distance (run) you are looking for. So you divide the 50/x (rise/run). Now equal it to the bigger triangle which has a rise of 10(6) = 60 load and divide it with 3+3 = 6 m. You solve for x by cross multiply it so 50/x = 60/6 would become 60(x)=50(6) and just solve for x. Hope this helps.

@olevel_maths1470

2 жыл бұрын

BMD and SFD (100%) kzread.info/dash/bejne/dIhkrq6eZMKzY6Q.html

just want to say thank you.

@Engineer4Free

5 жыл бұрын

Thanks for taking time to leave the comment, you're welcome!

Sir how do u find point of inflection and point of bending moment of this kind of question

Does anyone knows an app that can draw shear and moment diagrams so i can see if my diagrams are correct or false

@Engineer4Free

5 жыл бұрын

bendingmomentdiagram.com/ is pretty legit

there is another way to solve this question by using Equilibrium equation can you do videos about it plz

nice video, thanks!

@Engineer4Free

5 жыл бұрын

Thanks!

This video alone worths more than my three hours class.

@Engineer4Free

3 жыл бұрын

Thanks Faras!!!! =)

helped alot thx a ton

@Engineer4Free

3 жыл бұрын

Glad to hear it! There are some more examples here too: www.engineer4free.com/blog/ultimate-guide-to-shear-force-and-bending-moment-diagrams =)

Thank you very much! 👍

@Engineer4Free

4 жыл бұрын

You’re welcome!! 🙂

Trying to explain to my son. Indeterminate Beam with even distributed load and 3 support, and different length between supports. Can´t find any explanation how to divide into separate cases and superposition for that?

@Engineer4Free

5 жыл бұрын

Superposition + indeterminate problem is referred to as the force method. You can find some tutorials that I did on force method here: engineer4free.com/structural-analysis On that page you'll also find a section dedicated to superposition for statically determinate problems that would be a good review/intro. Also, you could solve your problem with a different method, such as the slope deflection method which there is also a section on that page describing it. Cheers =)

Hey! Good afternoon. Why is the line from +50kN to -10KN a slant line? Is it because it has a varying load?

@Engineer4Free

5 жыл бұрын

It's because there is a uniformly distributed load in that region. I recommend checking out videos 66-72 here: engineer4free.com/statics for a much more detailed look into the math of SFDs and BMDs

Great video

@Engineer4Free

4 жыл бұрын

Thanks Devin!! 🙃

Nice presentation. May i ask what software are you using?

How do you know if the parabola in the moment diagram opens up or down? Is there an easier way to know other than the mathematical method?

@Engineer4Free

4 жыл бұрын

I use a rather un-mathematical (but fast) way to do it: Do a fake numerical integration of the triangular shape of the the section on the SFD. Slice it into many vertical bits. The bits that are taller have more area than the bits that are shorter. More area in any given section of SFD means more change in magnitude across same section on BMD. The area of this triangle is all positive, so the change in magnitude from left to right on BMD will always be increasing. This triangle is taller on the left, and shorter on the right. This means the slices on the left will have greater slope than the slices on the right. By knowing the values of BMD on the left side (0kNm) and the right side (125kNm), and that its a parabolic shape, and that its slope is greater on the left than it is on the right, there is only one way to draw a parabola that works (it must be concave down in this case). Writing this explanation out never seems to come across that simple, but think about it, and try it a few times, and you’ll realize that its 100% the fastest and most foolproof way to do it if you only need to draw the general shape and the endpoints. Keep in mind where a SFD crosses the axis (has a sign change, that is a local max or min on the BMD, but it shouldn’t affect anything in your determination of the concavity. I really hope that helps!! This is an easy trick that often gets left out of instruction!!

Can point loads in the y direction have an effect on the Axial Force Diagram in beams?

@Engineer4Free

4 жыл бұрын

For a simply supported beam like this, no. Point loads will only impact shear and bending moment diagrams

How to figure out when to bent upward or downward on bending moment diagram of parabolic line?

@Engineer4Free

3 жыл бұрын

You know the area of the SFD is positive, so the change in magnitude on the BMD will be positive from left to right. Next, do a quick and dirty numerical integration in your head of the triangular area on the SFD. slice it up into many tall skinny rectangles. The rectangles will be taller on the left, and shorter on the right. Area on SFD = change in magnitude on BMD across that same section, so the taller rectangles have more area than shorter ones. This means that the change in magnitude across each dx will be more on the left side than the right side. Greater change in magnitude per dx means greater slope. So the parabola is steeper on the left and less steep on the right. It also has positive change in magnitude from left to right. This leaves only one option for the parabola to be drawn (which is concave down in this case).

Sir i realy thank for you

@Engineer4Free

5 жыл бұрын

You're welcome =) =)

Could you please do a video on bending & shear force diagrams including equations please

@Engineer4Free

5 жыл бұрын

Hey Christian I have several that include the equations, they’re just in a different playlist. Please see videos 66-72 here: engineer4free.com/statics 👌👌

@Holyacrobat1

5 жыл бұрын

@@Engineer4Free thank you ! Love your videos!

Sir how do you know what type of parabolic curve in the moment diagram by just looking at the slope in the shear diagram?

@Engineer4Free

3 жыл бұрын

Hey Jessie. The quickest way to do it is as follows. Pretend that you're going to do a numerical integration, and slice up the triangle shape on the SFD into many skinny rectangles. The area under the curve on the SFD represents change in magnitude across that same section of BMD. So where the rectangles are tall, the change in magnitude will be greater across their skinny width than where they are shorter. If all slices are the same width of dx, then that means a greater change in magnitude corresponds to a greater slope in that region of the BMD. So the tall side of the triangle on the SFD will correspond to the side of the parabola on BMD with steeper slope, and the short side of the triangle will correspond to the more gentle slope on parabola. Also knowing that a positive area on SFD will cause a positive change in magnitude on BMD and a negative area on SFD will cause a negative change in magnitude on BMD, then it always only ever leaves one possible option for the concavity of the parabola. That's a pretty quick and dirty way to do it, but once you get used to it, it's extremely fast. I recommend checking out videos 1-9 here: engineer4free.com/structural-analysis for more examples. I think with more practice it gets easier to notice the pattern.

Thanks sir. But I have a question, is the slope for the first parabolic suppose to curve in the 'n' direction or 'u' direction

@Engineer4Free

3 жыл бұрын

The quickest way to do it is as follows. Pretend that you're going to do a numerical integration, and slice up the triangle shape on the SFD into many skinny rectangles. The area under the curve on the SFD represents change in magnitude across that same section of BMD. So where the rectangles are tall, the change in magnitude will be greater across their skinny width than where they are shorter. If all slices are the same width of dx, then that means a greater change in magnitude corresponds to a greater slope in that region of the BMD. So the tall side of the triangle on the SFD will correspond to the side of the parabola on BMD with steeper slope, and the short side of the triangle will correspond to the more gentle slope on parabola. Also knowing that a positive area on SFD will cause a positive change in magnitude on BMD and a negative area on SFD will cause a negative change in magnitude on BMD, then it always only ever leaves one possible option for the concavity of the parabola. That's a pretty quick and dirty way to do it, but once you get used to it, it's extremely fast. I recommend checking out videos 1-9 here: engineer4free.com/structural-analysis for more examples. I think with more practice it gets easier to notice the pattern.

Sorry,, clarify me how did you get that value of x?

Thanks to you. Question is can we apply this method to the frame problems for finding diagrams?

@drofeng

3 жыл бұрын

Yes, see my channel for example frame problems.

you missed out in the last part of the SFD part where you are supposed to connect the line back to 0 in the x axis as the last support gives a force of 30 kN upwards so from -30 + 30 = 0 so just draw a perp line from the end point and stop at the y-axis = 0. i hope you get what i meant.

@Engineer4Free

3 жыл бұрын

Yeah it's true. You will sometimes see them with or without that vertical line. As we take the virtual cut a distance dx away from the right hand side support, and as dx approaches zero, the shear remains unchanged. This value of shear that is infinitesimally close to but not touching the reaction is actually we're concerned with. Like if someone asked you what the shear at B is in this case, we would tell them it's -30kN, not 0kN. But yeah should have drawn in the vertical line anyways I suppose!

So much helpful

@Engineer4Free

5 жыл бұрын

=) =)

thanks for the great explanation, can you please explain to me how you get A=50KN and why you multiply the 60 by 3m

@Engineer4Free

4 жыл бұрын

Hey, the A comes from the sum of force equation in y direction. I skipped the work. Sum of forces in y = A + B - 10kN*6m - 20kN = 0 .... A + 50kN - 10kN*6m - 20kN = 0 ... A = 60kN + 20kN - 50kN ... A = 30kN. And for why 60 is multiplied by 3: that is happening in the sum of moments equation about A. The resultant of the distributed load (overall magnitude) is (10kN/m)*6m =60kN. You need to also know how far away from A this is acting, and the location of a resultant for a uniformly distributed load is in the centre of it, so 3m from either side if it's 6m long. So the moment caused by the udl is 60kN*3m =180kN. Hope that clears it up!

@adoomyforever3673

4 жыл бұрын

@@Engineer4Free thank you so much