SA17: Shear Influence Line

This lecture is a part of our online course on introductory structural analysis. Sign up using the following URL: courses.structure.education/

Пікірлер: 301

  • @k.w.9242
    @k.w.92426 жыл бұрын

    Best tutorial ever. Well presented. If I were rich I would fund people like you. Thanks for making student's lives easier. God bless!

  • @tauseefraza3094

    @tauseefraza3094

    3 жыл бұрын

    Very high thinking May Allah make you capable of this

  • @a-02sagarjadhav53

    @a-02sagarjadhav53

    3 жыл бұрын

    I too 👍10000000000.....K👍

  • @abhishekmina3996
    @abhishekmina39965 жыл бұрын

    You deserve a gold medal ...... Just cleared my concept in just 15 minutes , which I was facing from last two year

  • @thobanigoba2024
    @thobanigoba20245 жыл бұрын

    I’m watching this from my structural mechanics class and in 15 minutes I assure you I’ve learned more than 75% of the people listening to the lecturer for the passed 45 minutes. Quality video👌🏽👌🏽👌🏽

  • @musica3955

    @musica3955

    4 жыл бұрын

    ahahahahha Savage

  • @87455451jose
    @87455451jose4 жыл бұрын

    Amazing, I've been struggling with this for weeks, and I got it all cleared in 15 min. Cant wait to see SA18 moment influence lines. Cheers!

  • @FaizYah
    @FaizYah3 жыл бұрын

    God bless you Dr. ! Thank you for such an easy-to-understand explanation!

  • @RohitRaj-pq3ie
    @RohitRaj-pq3ie2 жыл бұрын

    This channel is a gem.

  • @Kamikorosu0416
    @Kamikorosu04168 жыл бұрын

    Unbelievably amazing! Very clear and understandable. Cheers from the Philippines

  • @wongsathornphatcharaphisut3020
    @wongsathornphatcharaphisut30208 жыл бұрын

    This video is better than my in class lecturer. I can understand all of a chapter just in quarter an hour. Thank you so much Dr.

  • @ahmadshahi4421
    @ahmadshahi44215 жыл бұрын

    This was the greatest training videos i ever seen in youtube

  • @omohosagie4772
    @omohosagie47724 жыл бұрын

    Demystifying....You are truly a Doctor of Structures!

  • @azhysurkew
    @azhysurkew Жыл бұрын

    idk how to thank u,, this influence line has been a nightmare for me but u make it very simple and easy ,, much respect

  • @tabzz03
    @tabzz03 Жыл бұрын

    I can't thank you enough. I was breaking my head from past three days on drawing ild. I saw numerous videos on yt but thy didn't help. Thank you so much for making us understand in such simple way. God bless 🙏

  • @tuze5474
    @tuze54747 жыл бұрын

    OMG you helped me a lot, now I understand how it works! Marvelous video!

  • @rahulmalpekar4631
    @rahulmalpekar46314 жыл бұрын

    Thankyou so much @Dr. Structure for providing this wonderful video. It was really concept clearing.

  • @asaddavar43
    @asaddavar437 жыл бұрын

    This is the best youtube video for influence line of beam so far.... thanks from bd..

  • @moisestorrespe
    @moisestorrespe5 жыл бұрын

    Excelente video!!! It helps me a lot in my master's advanced bridge design class

  • @reginavillalobos1301
    @reginavillalobos13012 жыл бұрын

    OMG years of trying to understand this concept and I just finally did! Thank you so much!

  • @DrStructure

    @DrStructure

    2 жыл бұрын

    You’re welcome.

  • @UnknownUser12
    @UnknownUser127 жыл бұрын

    Thank you for your videos and putting so much effort in them. Regards from Aus

  • @abeal-qudah1619
    @abeal-qudah16194 жыл бұрын

    Thank you. I was to understand influence lines from you video that 5 years of education could not do for me. Thank you again!

  • @AhmetOzdemir-lk1bl

    @AhmetOzdemir-lk1bl

    3 жыл бұрын

    )))

  • @kaylal3875
    @kaylal38755 жыл бұрын

    The best video out there! Thank you so much!

  • @musichub6752
    @musichub67523 жыл бұрын

    best explanation i have ever experience in my student life . Thanks alot

  • @_jojo11
    @_jojo117 жыл бұрын

    this is a godsend a few days before structure exams thank you

  • @patrickwoolery6000
    @patrickwoolery60006 жыл бұрын

    Thank you so much for these videos. My SA professor spent like 5 minutes on influence lines and thought we'd all understand. I don't know why he didn't just play your videos for the class because these teach the material so much better. Again, thank you.

  • @DrStructure

    @DrStructure

    6 жыл бұрын

    Thank you for the feedback.

  • @user-ni9op5xm7i

    @user-ni9op5xm7i

    5 жыл бұрын

    @@DrStructure am from Iraq and very difficult to understand English language

  • @lebogangtsietsi3608
    @lebogangtsietsi36085 жыл бұрын

    I just love you Dr Structure....

  • @ahamadromen
    @ahamadromen5 жыл бұрын

    A wonderful work. Thank you for your v.well simple explanation.

  • @pronoybhat
    @pronoybhat7 жыл бұрын

    What a way to learn Structure.. Great work. Thanks !

  • @smboston12
    @smboston127 жыл бұрын

    this is so great, makes it so easy to understand. Thank you

  • @vuralmert9497
    @vuralmert94979 жыл бұрын

    Awesome.! Greatings from Turkey , Dear Dr.Structure :)

  • @prakashpandey4907
    @prakashpandey49076 жыл бұрын

    You have mind blowing teaching style....

  • @dayana6532
    @dayana65324 жыл бұрын

    This is amazing! Thank you so much for this!

  • @imbimb1403
    @imbimb14038 жыл бұрын

    Thank you for such a great explanation. It really helped me .

  • @johnkim4026
    @johnkim40263 жыл бұрын

    Dude i have a final tomorrow and this saved my life. U are amazing

  • @yadrzgar9980
    @yadrzgar99804 жыл бұрын

    A structural analysis professor at my uni who has a PhD & 12 years experience could bot explain this half as good as this video! Thank you 😭😍

  • @omarpasha2968

    @omarpasha2968

    4 жыл бұрын

    I believe it! I once took my junior College electrical problems to a university electrical engineering tutor. And, the problem was too complicated for him!

  • @franciscovasquezramirez5705
    @franciscovasquezramirez57058 жыл бұрын

    Thank Dr Structure; Congrats from Bolivia

  • @rmrafsanzanilabib6881
    @rmrafsanzanilabib6881 Жыл бұрын

    You explained IL so well. thank you for making our study easier

  • @rubencasinillojr9852
    @rubencasinillojr98523 жыл бұрын

    Thank you! Great explanation ever.

  • @ibrahimacar8262
    @ibrahimacar82624 жыл бұрын

    Whoever found this is out of this world bro, It's epic. You don't need functions to solve anymore.

  • @nisreensalameh1887
    @nisreensalameh18878 жыл бұрын

    Keep up the good work. Can you do some video series on concrete and steel design? Thank u so much, people like you makes world a much better place

  • @Ilsan1111
    @Ilsan11115 жыл бұрын

    thanks for this lecture! awesomeeee

  • @Mm-hw9yb
    @Mm-hw9yb7 жыл бұрын

    Thanks a lot Dr. Structure!

  • @1f7sivakumarponakalla74
    @1f7sivakumarponakalla743 жыл бұрын

    U really nailed it! Thanks a ton!!

  • @bishalnayak6162
    @bishalnayak61623 жыл бұрын

    God bless you to whoever made this video.

  • @manikantagodi3239
    @manikantagodi32395 жыл бұрын

    is that that much hard? my reaction when I heard this topic in the class...but after this video is that that much easy?...overturned my reaction...thank you so much..you just nailed the topic...

  • @ahmetkasmoglu1576
    @ahmetkasmoglu15765 жыл бұрын

    Great work. İ know a little english but i understand this lesson. Thank you very much.

  • @noorhanalkhatib4341
    @noorhanalkhatib43414 жыл бұрын

    I love this channel .. amazing

  • @KonjoTube
    @KonjoTube6 жыл бұрын

    u save my life i love u Dr.

  • @1carlos83
    @1carlos834 жыл бұрын

    Thank you for this, the graphics are the best I have seen for anyone lecturing structures. You should do a P.E. course.

  • @williamsentemtz9652
    @williamsentemtz96526 жыл бұрын

    Mind blowing!👍👌 5 stars for u

  • @catobsessed379
    @catobsessed3797 жыл бұрын

    u r awesome dr.!!!!!!!!!!!!!!!! thank you

  • @user-gd4kw5ei7n
    @user-gd4kw5ei7n2 ай бұрын

    الله يباركلك يا هندسه❤

  • @love-and-faith
    @love-and-faith5 ай бұрын

    You deserve gold you have to teach other teachers how to teach 😮😮😮😮

  • @charrysalce4580
    @charrysalce45806 жыл бұрын

    Very well presented and explained. Thank you so much!

  • @DrStructure

    @DrStructure

    6 жыл бұрын

    Thank you for the feedback.

  • @rabbiahmed6760
    @rabbiahmed67606 жыл бұрын

    u explained in the easiest way.tnx a lot

  • @coolbro1502
    @coolbro15024 жыл бұрын

    You deserve to be respect sir

  • @gopalkumar-mh7zx
    @gopalkumar-mh7zx7 жыл бұрын

    thanks from India ..for make understanding concept very clealy

  • @kitetama13
    @kitetama136 жыл бұрын

    thanks for sharing! God bless you

  • @sheilabelcabrera4043
    @sheilabelcabrera40438 жыл бұрын

    thanks Dr. Structure! you're good at explaining.. i understand the video:) i just hope i could answer our exam..

  • @ieuhfuffffff
    @ieuhfuffffff4 жыл бұрын

    I'm Vietnamese, I'm not good at in English, but I can understand all of things you explain. At my University, I cant understand it. Thank you very much, you are a master in explain.

  • @DrStructure

    @DrStructure

    4 жыл бұрын

    Thanks for your comment and feedback.

  • @callofpotatoe
    @callofpotatoe8 жыл бұрын

    Holy Crap, amazing explanations, thankyou!!

  • @veersundarr7821
    @veersundarr7821 Жыл бұрын

    Very nice explanation!

  • @Julian-xe3gw
    @Julian-xe3gw8 жыл бұрын

    Just one word: thanks!!

  • @lifeisbeautiful350
    @lifeisbeautiful3502 жыл бұрын

    Thanks so much for this presentation

  • @user-gq5sd7qz7r
    @user-gq5sd7qz7r7 ай бұрын

    OMG Thank you i love this video

  • @junielvillas8820
    @junielvillas88206 жыл бұрын

    for 4:10, is it possible to be drawn the other way around, like upward force at the left roller and downward at right?

  • @DrStructure

    @DrStructure

    6 жыл бұрын

    By definition, shear in a beam segment is considered positive when the force is acting downward at the right end of the segment, and upward at the left end of the segment. That is what you see @4:10, positive shear in both segments. If we define positive shear the other way around, then yes, we would have to switch the direction of the arrows.

  • @siguerhakim4723
    @siguerhakim47237 жыл бұрын

    thanks, great teacher

  • @Gespenstish
    @Gespenstish9 жыл бұрын

    Thanks a lot, this is very helpful.

  • @osuwatchdog7154
    @osuwatchdog71542 жыл бұрын

    thanks for saving my life

  • @ikbenvoetbal
    @ikbenvoetbal Жыл бұрын

    Thank you so much. I would bake you a cake. This really helped me a lot. May God bless you and your family

  • @oscarrinn
    @oscarrinn4 жыл бұрын

    I love Dr. Structure!! My structural sicknezz is kured

  • @obaidurrahman4300
    @obaidurrahman43008 ай бұрын

    Good lecture. Thank you ❤❤

  • @saurabhdhadiwal129
    @saurabhdhadiwal1293 жыл бұрын

    4 yr passed away in college didn't understood the concept but ur video clr my doubt...🙏🙏🙏

  • @rabin5903
    @rabin59035 жыл бұрын

    very convenient explanation thanks...

  • @meargbrihanu8139
    @meargbrihanu81395 жыл бұрын

    thank you so much its very help full , please add some videos on design

  • @aswinjomike9466
    @aswinjomike94669 жыл бұрын

    super thnx once again.. awaitin influence lines for bending moment.. i 'd realli be thankful if u cld show huv to construct influence lines in load cases with 'series of loads' or 'a distributed load'...

  • @madisonstafford6619
    @madisonstafford66192 жыл бұрын

    You actually just saved my grade.

  • @imanfarahbakhsh4052
    @imanfarahbakhsh40528 жыл бұрын

    Brilliant ... thanks a lot

  • @bendeng2768
    @bendeng27685 жыл бұрын

    Very good explanation.

  • @FRSHBL
    @FRSHBL8 жыл бұрын

    Very creative .. Thanks alot

  • @eironce9032
    @eironce90325 жыл бұрын

    Life SAVER! 😍😍

  • @user-yb3cc4yh2g
    @user-yb3cc4yh2gАй бұрын

    認真的老師.

  • @dylandewilzen1864
    @dylandewilzen18645 жыл бұрын

    How would you go about calculating the influence line if you had one continuous member, with varying cross-section, spanning from A to F as per the above illustration?

  • @DrStructure

    @DrStructure

    5 жыл бұрын

    If the beam is statically determinate, its cross-section does not impact the shape of the influence line. That is, shear in the beam would not be a function of the cross-sectional properties of the member. but if by continuous you mean indeterminate beam, the qualitative approach would be of little use.

  • @meetvaghasiya3681
    @meetvaghasiya36817 жыл бұрын

    tnk u so much..... upload more n more video.... 😎

  • @saurabhdhadiwal129
    @saurabhdhadiwal1293 жыл бұрын

    Excellent video

  • @engineersoutlook7
    @engineersoutlook73 жыл бұрын

    Excellent tutorial

  • @sabbirnadim5269
    @sabbirnadim52692 жыл бұрын

    best tutorial ever

  • @DK-db4ot
    @DK-db4ot5 жыл бұрын

    *Hello Dr. Structure!! I'm a huge fan of your videos!! I would really like to know if I can get complete videos on others subjects of civil engineering as well!! If not, then please upload here on KZread itself!! It will be of great help, thanks a ton!!!!* ❤

  • @DrStructure

    @DrStructure

    5 жыл бұрын

    Thanks for the feedback. There are no other video lectures available at this time. You will see them here when they are ready for use :)

  • @DK-db4ot

    @DK-db4ot

    5 жыл бұрын

    @@DrStructure Thanks for the reply and please do continue uploading others subjects as well..!! ❤ #Bestteacher

  • @SHUBHAMKumar-qd1pi
    @SHUBHAMKumar-qd1pi5 жыл бұрын

    Awesome video 👍👌👏

  • @fatimamancuso
    @fatimamancuso6 жыл бұрын

    On the example with shear @ E, rollers B & C on either side, (@7:54 )with a hinge at D. What if B & D were switched to: hinge at B and roller at D instead? The shear with a hinge next to it on the left, roller to the right, and roller to the left of the hinge? I did not see an example with a hinge and then a roller next to the IL of question, only saw rollers side by side or roller / hinge combo. Does it act like the example with two rollers where the bar cannot move and the IL goes to the hinge and stays there? Thank you! Hope that makes sense.

  • @DrStructure

    @DrStructure

    6 жыл бұрын

    Thanks for the question. Yes, in such a case the left segment of the beam from A to B (the new location of the real hinge) remains flat. E moves downward to the left of the fictitious roller at E, causing BE to rotate clockwise. And, E moves upward to the right of the fictitious roller making EC to turn clockwise as well.

  • @fatimamancuso

    @fatimamancuso

    6 жыл бұрын

    Makes sense!!! I appreciate it!

  • @manuelatakchangen
    @manuelatakchangen Жыл бұрын

    Thank youuuu so muchh 🫶

  • @ahmadabdelgalil5894
    @ahmadabdelgalil58945 жыл бұрын

    Thanks 💖💖💖

  • @gnidnoeled786
    @gnidnoeled7867 ай бұрын

    To get the shear influence line at the midspan (at point C) of the simply suppoted beam, a pair of rollers is placed at point C. The left roller is pushing downward and the right is pushing upward. Let's say, I wish to get the shear IL at points A and B by placing a pair of rollers at those points. Is the shear at point A positive, and at B negative based on the pair of rollers placed at points mentioned?

  • @DrStructure

    @DrStructure

    7 ай бұрын

    If A and B are points very close to the left and right ends of the beam, then yes, the shear influence line for point A is basically a right triangle with a positive height of almost one (1) at A. The influence line for B is also a right triangle having a height of negative one at B.

  • @gnidnoeled786

    @gnidnoeled786

    7 ай бұрын

    @@DrStructure Thanks a lot. I really do understand now how shear IL behaves. I appreciate your continuous replies. 👍👏

  • @DrStructure

    @DrStructure

    7 ай бұрын

    You’re welcome!

  • @laughinggood
    @laughinggood8 жыл бұрын

    doc,though the +ve SF convention is right side down and left side up why does the roller moves right side down and left side up which is -ve sign convention for SF????

  • @DrStructure

    @DrStructure

    8 жыл бұрын

    +Ajay Balan This qualitative approach require that we place a (fictitious) positive shear at the cut point and draw the deformed shape of the beam. This fictitious shear force is not to be confused with the real shear force in the beam. The real shear in the beam is shown by the diagram.

  • @alfredjrtovar1499
    @alfredjrtovar14997 ай бұрын

    What what happen if we applied the "hinge" at a roller position to determine the shear influence line atba roller position... does it move even tho there is a roller there?

  • @DrStructure

    @DrStructure

    7 ай бұрын

    There is no shear force at a roller support. At such a support we can draw the reaction influence line, not a shear influence line.

  • @mohamednoor2567
    @mohamednoor25677 жыл бұрын

    Thank you..

  • @FranCoVids
    @FranCoVids5 жыл бұрын

    What if you want to draw the shear influence line on the left and right of a pin/roller support?

  • @DrStructure

    @DrStructure

    5 жыл бұрын

    The same principle applies. Say, we want to draw the shear influence line for the point just to the right of B for the beam @9:00. Note the influence line for E where the amount of upward movement (of the roller to the right) equals to the amount of the downward movement (of the roller to the left). They each equal 1/2 adding up to 1. Keeping in mind that that total height is always 1 regardless of the position of E, start moving E to the left toward B. As the point gets closer to B, the height above the x axis increases (becomes larger than 1/2, approaching 1 but never reaching it) while the height below the axis gets closer to zero, but it never reaches zero since shear at B is undefined. No matter how small that negative height gets, it results in a downward movement that causes the segment between the hinge at E (now positioned just to the right of B) to rotate clockwise.

  • @FranCoVids

    @FranCoVids

    5 жыл бұрын

    @@DrStructure So, you are basically saying that the shear influence line just to the right of support B will essentially be the same as the shear line for point E? (Just with different heights)

  • @DrStructure

    @DrStructure

    5 жыл бұрын

    @@FranCoVids Yes!

  • @FranCoVids

    @FranCoVids

    5 жыл бұрын

    @@DrStructure thank you!! You're the best!! 😄

  • @greatminds8977
    @greatminds8977 Жыл бұрын

    God bless you 🙏

  • @nasseryariphdpe648
    @nasseryariphdpe6484 жыл бұрын

    Great work, what program are you using to make the animation ?

  • @DrStructure

    @DrStructure

    4 жыл бұрын

    We used Adobe Illustrator and Camtasia Studio for this particular video. And, the talking head was done using CrazyTalk.

  • @nasseryariphdpe648

    @nasseryariphdpe648

    4 жыл бұрын

    @@DrStructure Thanks

  • @sumitchowdhury6103
    @sumitchowdhury61037 жыл бұрын

    Thank you very much :) :)

  • @GracefoolReacts
    @GracefoolReacts4 жыл бұрын

    Thanks a lot maam!!!

  • @feryalighani-missaghi1649
    @feryalighani-missaghi16494 жыл бұрын

    Great tutorial. On Exercise#1 why you don't rotate the left side beam around B and only shear on the left?

  • @DrStructure

    @DrStructure

    4 жыл бұрын

    Note the support at the left end of the beam. It looks like a vertical roller, but it behaves a bit differently. The support at A can resist both a horizontal force and a bending moment (similar to a fixed support, but minus a vertical reaction force). This behavior causes a bit of problem for our qualitative approach for drawing the shear influence line. Since the support at A cannot carry any shear (vertical force), no matter where the unit load is placed on the beam, all of the load is going to be counteracted by the vertical reaction at B. That is, the vertical reaction at B is always 1, no matter where the unit load is located. This means, when the unit load is to the right of point C, the left segment of the beam does not carry any vertical (shear) force. That is, as long as the unit load is to the right of C, shear at C (and any other point to the left of C) is zero. Whereas when the unit load is to the left of C, the shear force at C (and any point from C to B) must be equal to 1. This insight yields the rectangular influence line shown in the video.