Really maths challenge from you. Thanks

Really nice problem 😂😂😂

@Mathprowess

Ай бұрын

hahahaha...😂🤣😂🤣 Really nice math problem. Thanks for watching and commenting my good friend. Much love...❤️💖💖

Our Olympiad math problems are not so plain. This one would be OK for 7th grade' regular school lesson, definitely not for Olympiad, unless primary school also takes part. I've opened list of problems for recent 2024 contest and you know what? There are NO equations to solve at all there. I can translate for you the very first problem targeted for 9th grade. Try to solve it. Petya and Vasya know only natural numbers not greater than 10^9-4000. Petya counts as "good" ones only such numbers, which can be expressed as abc+ab+bc+ac, where a, b and c - natural numbers, not less that 100. Vasya calls "good" ones only numbers, which can be recorded as xyz-x-y-z, where x, y and z are natural numbers greater than 100. Who of them has more "good" numbers? That's it. THIS is the level of our Olympiad. Of course, you can simplify the task significantly by renaming Petya and Vasya to Peter and Basil respectively.

@Mathprowess

20 күн бұрын

Ok

I just solved it in 1 min by putting x = a+ib , BTW I m preparing for iit jee advanced

@Lemuel-sp4we

10 күн бұрын

friend I am not from the United States so that is that 😂

You are a very good teacher

@Mathprowess

Ай бұрын

Thanks and welcome sir. We respect you sir

Simple and tough

@Mathprowess

Ай бұрын

Laugh!!! 🤣😂🤣😂🤣

❤

@Mathprowess

Ай бұрын

We love you too sir...❤️💖❤️💖💖

Good ❤

@Mathprowess

20 күн бұрын

Thanks a bunch sir.

Дуже захмарно

@Mathprowess

Ай бұрын

Really!!!

Nice math solution

@Mathprowess

Ай бұрын

Thanks my wonderful friend, hahaha 🤣🤣🤣.

X^2 = plus or minus sqrt(2i) X^2= plus or minus sqrt(-2i)

@Mathprowess

20 күн бұрын

Ok

12 минут это решать🤯? Вон x/7=7

Слишком много лишних вычислений в ролике. x⁴ = -4 x⁴ = 4∙(cos(π + n∙2∙π) + i∙sin(π + n∙2∙π)) - тригонометрическая форма комплексного числа x = (4 ** ¼)∙(cos((π + n∙2∙π)/4) + i∙sin((π + n∙2∙π)/4)) - максимально удобна для извлечения корней x = √2∙(cos(π/4 + n∙π/2) + i∙sin(π/4 + n∙π/2)) - 4 корня для n = 0, 1, 2, 3 x = √2∙(±√2/2 ± i∙√2/2) x = ±1±i

@Mathprowess

20 күн бұрын

Thanks my good friend and mathematician

X^4 - (2i)^2 = 0

@Mathprowess

20 күн бұрын

You are good at math

143

@Mathprowess

20 күн бұрын

143? how do you mean sir?

Square root -3

@Mathprowess

Ай бұрын

How do you sir? Please kindly rephrase your question for proper understanding. Thanks sir.

1

@Mathprowess

20 күн бұрын

Wrong, kindly resolve the challenge or watch this video tutorial from beginning to the end.

x^4 - (sqrt(2i))^4 = 0 ?

@Mathprowess

20 күн бұрын

Kindly simply sir.

X=2i

@Mathprowess

Ай бұрын

correct also

@roninschannel1083

Ай бұрын

Wait is it?

@roninschannel1083

Ай бұрын

I think it’s wrong tho

@roninschannel1083

Ай бұрын

I just took the square root of -4 not the fourth root

can you read it your self

@Mathprowess

Ай бұрын

How do you mean? Your question, comment or statement not clear sir. Rephrase your question or comment sir. Thanks a million sir.

College level

@Mathprowess

Ай бұрын

Yes boss!!!

Bro its hard,the simple solving way in my opinion: x⁴=-4 x²=2i x=±√2i

@whoff59

Ай бұрын

x = +-sqrt(2i) x = +-(sqrt(2)* sqrt(i)) That is not the end of it, as a complex number should be of the form a+bi where a and be are real numbers. sqrt(2) is, but the rest is not. You have to find out then what sqrt(i) is.

@Mathprowess

Ай бұрын

ok sir