Race Start Strategy with Peter Isler

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Thank you Peter Isler and Jose Mieto for this great video. Enjoy!

Пікірлер: 56

  • @NapoleonDynamiteBelg
    @NapoleonDynamiteBelg11 ай бұрын

    Man, this has to be the most inspiring post ever. The effort put into this work is flawless. I can see the details and such that are used to make it what it is. We’re living in a new generation of work, and it’s getting better, but you actually made a whole new generation of art. The depth made into this is just amazing, it’s just flawless what you have done here. The intelligence this price uses to emphasize the meaning is amazing. It’s like the renaissance all over again. You should become a legend, a historical figure. Your work should be seen to millions. No. Billions. You my man have changed my perspective of the world and have inspired me to do what you do. I thank you for that. You are the Albert Einstein/Vincent Van Goh hybrid of our age. Please, use that power wisely for you can also cause a world catastrophe.

  • @SuperMagoo2011
    @SuperMagoo20118 жыл бұрын

    I have been racing thirty years and never had any formal training on this. Thankyou for the info.

  • @shaenebuffster
    @shaenebuffster11 жыл бұрын

    Peter Isler SAILING LEGEND!!

  • @Rob-fx2dw
    @Rob-fx2dw4 жыл бұрын

    Peter Isler is of course right at the 12 minute point about the effect of currents . A simple explanation of this current's effect is that from the time they hit the current it effectively pushes the apparent wind to the left which gives the boat on the left an upwind position on the course. That is all since everything else on the course is the same for each boat. Sail an IOM and you will be able to observe this simple fact if currents are present.

  • @bullthrush
    @bullthrush10 жыл бұрын

    For the situation described at 13:00 Assuming north at the top. Imagine the true wind speed dropped to zero, there would be wind from 270 at 2kts because of the current moving the boat through still air. With the true wind blowing 000 at 20kts, plus the 2kts "current induced" wind, the effect is a shift 6 degrees to the left favoring the boat on the left. I hope this helps.

  • @FuzzyFrenchfy33

    @FuzzyFrenchfy33

    10 жыл бұрын

    Woah.... I have no idea what you said but.. woah, Thats hardcore. Lol

  • @anthonyz.2607

    @anthonyz.2607

    6 жыл бұрын

    bullthrush Thank you that was killing me!

  • @katherinemontgomery6744

    @katherinemontgomery6744

    3 жыл бұрын

    Pppppppppppp

  • @katherinemontgomery6744

    @katherinemontgomery6744

    3 жыл бұрын

    Thanks

  • @katherinemontgomery6744

    @katherinemontgomery6744

    3 жыл бұрын

    Thank

  • @TheSailorman7
    @TheSailorman711 жыл бұрын

    THis is a Great video for starts. Thank you very much.

  • @katherinemontgomery6744

    @katherinemontgomery6744

    3 жыл бұрын

    Thank everyone

  • @katherinemontgomery6744

    @katherinemontgomery6744

    3 жыл бұрын

    Thanks again for letting me know and

  • @petermcfarlane529
    @petermcfarlane5293 жыл бұрын

    From 12:00 to 13:30 is absolute b*ll*cks. Pick the ideal place and tack to cross the boundary where the current starts. As neither end of the line is favoured, the time/distance to get to that chosen point is the same regardless of where you start on the line.

  • @petermcfarlane529

    @petermcfarlane529

    3 жыл бұрын

    @Glenn Watson No, I think you are missing the point. Yes the pin end boat is further to the relative windward, but in this scenario the frame of reference has the water stationary, and as such the mark we're aiming for is not only far upstream, but constantly moving at 2kt eastward. The ideal crossing point into the current may even be to the east of the boat starting at the committee boat end. Let's work out some figures as an example (I'm assuming more of a club fleet boat than an AC75 below) Assumptions: Angle of beat 45° to true wind relative to water (rtw) Speed of boat on beat half of true wind speed (rtw) Consider when boat in current on Port tack True wind speed (rtw) = sqrt(10^2 + 2^2) = 10.2 angle of wind (rtw) = atan(2/10) = 348.7° velocity of boat (rtw) = 5.1 kts @ 033.7° VMG northwards = 5.1 cos(33.7) = 4.24 kts VMG eastwards = VMG over water - current = 5.1 sin(33.7) - 2 = 0.83 kts velocity of boat relative to mark = sqrt(4.24^2 + 0.83^2) @ atan (0.83/4.24) = 4.3 kts @ 011° You should cross into the current 191° south of the mark, (I'd go for due south to allow for lulls when you may drift westwards). If (as you should) you are going for 191°, starting at the middle of the start line, you should tack onto port at just under 30% of the beat (assuming that the current starts at 50% of the way due north to the windward mark). Slightly earlier if starting at the pin end, slightly later if starting at the committee boat. There is certainly no advantage to either end of the start line.

  • @drzeitnot

    @drzeitnot

    3 жыл бұрын

    In summary the pin end boat is further 'upwind', but they have both massively overstood the mark.

  • @haraldholmensorensen

    @haraldholmensorensen

    Жыл бұрын

    @@petermcfarlane529 I would not have used as strong words as you do, as you have made some assumptions that may not be right... In the video, Peter indeed states that the boats have not reached the layline yet when they hit the current. That's contradictory to your assumption, which I guess is that the boat of the left has passed the layline. So even though the layline is perfectly calculated with a sweetspot at 11°, you don't know where this mark is, other than that neither are yet on the 11° line to the mark. To your account, Peter said the boats hit the current half way up the boat, which indicated that the boats are on the layline by this time. But for what we know, then RC may have accounted for the current, and placed the mark far left. Anyway, the points is that a current generates a wind shift, and when sailing into a cross current going left you experience a left shift and should tack to port.

  • @ispasskov
    @ispasskov4 жыл бұрын

    Amazing, thanks!

  • @katherinemontgomery6744

    @katherinemontgomery6744

    3 жыл бұрын

    Thanks

  • @katherinemontgomery6744

    @katherinemontgomery6744

    3 жыл бұрын

    Thank

  • @katherinemontgomery6744

    @katherinemontgomery6744

    3 жыл бұрын

    Thank

  • @katherinemontgomery6744

    @katherinemontgomery6744

    3 жыл бұрын

    I know

  • @geebee3d
    @geebee3d3 жыл бұрын

    Lots of people commenting on the Current vector around 13:00. What Peter didn’t really do a great job of explaining is that while the current velocity would move the boat to the left, in doing so it creates an apparent wind that moves left to right. And remember, it is the wind direction that will determine distance traveled. So his resulting left to right vector and the associated left shift is correct.

  • @evanwellens
    @evanwellens10 жыл бұрын

    I sail in a river where current is huge.. What is calculated here is the effect of wind alone. But the inner boat will sail in adverse current less , hence a shorter course. I don't see how the outter boat would be favored ?

  • @camllamas2

    @camllamas2

    9 жыл бұрын

    It's more about the lay lines than the time in the current. (remember that the boat, in the example that started pin end had a better lay line and could tack and immediately be out of the adverse current). If it doesn't make sense, maybe try reading this: www.teameclipseracing.org/forms/Performance%20Racing%20Tactics%20upwind%20strategy.pdf

  • @finnehmsen5423
    @finnehmsen54237 жыл бұрын

    Super video og forklaringer

  • @Rob-fx2dw
    @Rob-fx2dw3 жыл бұрын

    You can determine how close to the start line you are if you are in the middle of te line but you must measure the angle some time before the start from the committee boats that the line lies on. When you are approaching that angle you know how close it is in front of your bow by referencing the compass angle and allowing for your bow is in front of your measurement point. But you have to do the homework by checking first.

  • @leovandorp
    @leovandorp10 жыл бұрын

    I don't fully agree with the first situation. Cause if there is a substantial shift, or if the wind is very shifty, starting at the pin statistically gives you more options Peter ... contact me if you will

  • @thomaswalker9182

    @thomaswalker9182

    8 жыл бұрын

    agreed

  • @paulhanly1942
    @paulhanly194210 жыл бұрын

    At 13:00 isn't it better to have less distance to do against current so boat end is better start? In fact why not boat end and tack to right lay line so you get into what is then current going partially with you, rather than going pin end to far left and having partially against you at 2 knots? If higher rung towards wind is best, why not higher rung towards current?

  • @ILLEMORO1

    @ILLEMORO1

    5 жыл бұрын

    He started drawing the vector correctly, so he designed it on the wrong side of the wind. According to him, one will experience a left shift, wrong! With the vector on the right side it will be the right shift. Boat launch best!

  • @MozzySails

    @MozzySails

    5 жыл бұрын

    @@ILLEMORO1 No, he draws the vectors correct. The tide is taking you from right to left and this creates an apparent wind from the left. A tide coming from the right, will make the wind feel like it's coming more from the left. So, the video is correct. If you're heading in to an increasing side current from the right, you want to position yourself to the left of the fleet.

  • @igbc176

    @igbc176

    5 жыл бұрын

    It is counter-intuitive but he said it right

  • @drzeitnot

    @drzeitnot

    3 жыл бұрын

    @Paul Hanly is correct: Assumptions: Angle of beat 45° to true wind relative to water (rtw) Speed of boat on beat half of true wind speed (rtw) Consider when boat in current on Port tack True wind speed (rtw) = sqrt(10^2 + 2^2) = 10.2 angle of wind (rtw) = atan(2/10) = 348.7° velocity of boat (rtw) = 5.1 kts @ 033.7° VMG northwards = 5.1 acos(33.7) = 4.24 kts VMG eastwards = VMG over water - current = 5.1 asin(33.7) - 2 = 0.83 kts velocity of boat relative to mark = sqrt(4.24^2 + 0.83^2) @ atan (0.83/4.24) = 4.3 kts @ 011° You should cross into the current 191° south of the mark, (I'd go for due south to allow for lulls when you may drift westwards). If (as you should) you are going for 191°, starting at the middle of the start line, you should tack onto port at just under 30% of the beat (assuming that the current starts at 50% of the way due north to the windward mark). Slightly earlier if starting at the pin end, slightly later if starting at the committee boat. There is certainly no advantage to either end of the start line.

  • @haraldholmensorensen

    @haraldholmensorensen

    Жыл бұрын

    @@drzeitnot Looks like you made some assumptions that are not correct... You base your conclusion that the boats have to tack to port before they reach the current in order to fetch the mark. Neither boat has reached the port layline when they hit the current. All boats hist the current at the same time, and as you pointed out, all experience a 11 degree left shift. The boat furthermost to the left would of course benefit most from this.

  • @user-cq4mv1zp2x
    @user-cq4mv1zp2x3 ай бұрын

    Tge current one is wrong, from an angle perspective is correct however he's not taking into account the effect of tidebon boat speed. Both boats will slow when they tack as in SOG . But boat that started at pin has to sail slowee for longer

  • @morganahouse2109
    @morganahouse210910 жыл бұрын

    The vector calc at ~13:00 is backward. Imagine a 10 kt current (we have them here in WA) --no way to sail against that.

  • @MozzySails

    @MozzySails

    6 жыл бұрын

    The vector calc is correct. You have a 2 knot current pushing the boats right to left, they therefore feel an apparent wind from the direction they are pushed toward. The addition of this tidal induced wind from the left skews the true wind left. A left hand shift favours the left hand boat. The degree of shift will depend on how windy it is (more tide and less wind = bigger shift, less tide more wind, smaller shift).

  • @ChristianNally
    @ChristianNally10 жыл бұрын

    I'm a little confused about the argument being made at 8:30. It seems to me that the 15 deg. wind shift being discussed on the upper half of the course is equivalent to a new direction for the ladder rungs. How can it matter how smart the right hand boat is? Doesn't the 'fewest number of ladder rungs to cross' path include the pin end?

  • @BarringtonOASmith
    @BarringtonOASmith5 жыл бұрын

    Re: The situation at 13:00 minutes where the wind is from the North and the current from the East (moving right to left). Based on my vector addition, the resultant is a shift to the RIGHT not the left. Based on my rationale, both boats get a lift. However, the boat from the pin end is sailing into the current for a longer distance than the boat that starts at the Committee boat end. To me, this means that the boat on the committee boat end has a huge advantage. If the boat that starts on the committee boat end immediately goes on port tack after the start, and take advantage of the lack of current, then tacks on the lay line. When it gets to the gulf stream, the boat starting on the Committee boat end will use the current to it's advantage. The current will then bring the boat down to the pin. The boat on the pin end would be fighting the current in the gulf stream for the entire second half of the first leg. What am I missing? Please explain why I'm wrong.

  • @trainspot74

    @trainspot74

    4 жыл бұрын

    Because a current that is right to left, generate an apparent wind coming from the left (west). Imagine the same current of 100kts...like being over a train. You will feel the wind coming from the opposite of the direction of the train itself...that is...from left to right. So, because of the vector sum, because the current has added a westerly component, the resultant shift will be to the left. For the sake of clarification, the wind from 360 will appear from 350 (no precise calculation has been made).

  • @haraldholmensorensen

    @haraldholmensorensen

    Жыл бұрын

    @trainspot74 responded to your first question. Your second assumption is that the boat on the pin would stay longer in the current than a boat starting at the committee boat end. No matter what end of the line you start, or what tack you are at, you will reach the current exactly at the same time. This means the boats spend the same amount of time in "universe 1" with wind from top. And they spend the same amount of time in "universe 2" with a wind shifted to the left, until the pin starter has crossed ahead.

  • @gemeinerhund
    @gemeinerhund8 жыл бұрын

    what software is he using at 49:30 ?

  • @BR-hi6yt
    @BR-hi6yt2 жыл бұрын

    There is a much simpler rule - but I am not going to tell it to you because you might beat me in a race.

  • @sailgears
    @sailgears9 ай бұрын

    you wrong about the current

  • @finnehmsen5423
    @finnehmsen54237 жыл бұрын

    Addition of Vectors is wrong

  • @MozzySails

    @MozzySails

    6 жыл бұрын

    Vectors are correct. Right to left current creates apparent wind from left. You then add this apparent wind vector to the true wind to get the shift.

  • @AlohaRaceTeam
    @AlohaRaceTeam3 жыл бұрын

    This guy is drunk as hell

  • @markm417

    @markm417

    3 жыл бұрын

    Any real sailor is still drunk at the 10am start of a saturday seminar and Peter Isler is a very real sailor

  • @hikikimorimasqueerade8743
    @hikikimorimasqueerade87437 жыл бұрын

    The explanation and advice given between 9:42 and 13:37 is TOTALLY WRONG. Neither end of the line is favoured. The only decision to make is how to cross the band of current. You should choose which tack you need to be on and where on the interface between static water and flowing water you want to be. In the scenario described you would want to be on a port tack at wherever the lay line happens to cross the interface (it doesn't matter that the lay lines will have a shallow corner at that point). Now, in order to get to that point of crossing the interface on port tack, it really does not matter which end of the line you start; neither end is favoured.

  • @MozzySails

    @MozzySails

    6 жыл бұрын

    It's very hard to say it's totally wrong, however, I'd agree I wouldn't really call this 'starting tactics'. What he's really explaining is that when the boats hit the current, they will experience a left hand shift and boats further left will gain. That is absolutely correct. However, what I feel he's trying to emphasize here is, if you see a gain by getting yourself left of the fleet, starting left on the line sets you up to take advantage of that later in the beat.

  • @haraldholmensorensen

    @haraldholmensorensen

    Жыл бұрын

    The explanation is actually totally right. It seems like you have made some wrong assumptions... It is not a band of current. It is constant current from the middle of the beat and all the way up to the mark.

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