1 Year Subscriptions @ FLAT ₹5,499! Lucky Winners can win an Electric Scooter on subscribing now. ➡ unacademy.com/goal/-/TMUVD/subscribe?plan_type=plus&referral_code=NEXUSAK

@AryanPatel-iy9is

Ай бұрын

Sir in Q3, You have find the MAX value of (a^2 + b^2 + c^2) / (ab + bc + ca). But sir why we not use Minimum value of the expression. As If K right side ki minimum value se chota hoga then Max value se bhi chota hoga.

❤Q-4❤ Σ x^n =(1-x)-¹ Differentiate with respect to x Σ nx^(n-1)=(1-x)^-² Multiply ✖️ both sides with x² Σ nx^(n+1)=x²×(1-x)^-2 Differentiate with respect to x Σ n(n+1)x^n=2[x(1-x)^-2+x²(1-x)^-3] Divide both sides with x as in the question it is 2^n-1 Σ n(n+1)x^(n-1)=2/x [x(1-x)^-2+x²(1-x)^-3] Now put x=1/2 We get the summation to be equal to 16 but we don't need the zeroth and first term so subtract them zeroth term is 0 and first term is 2 We get our answer as 📜14📜 Aim°JEE2025 ❤Mera bhai ❤ Thia method might look long but it isn't it will only take around 20 to 30 second to get the Desired answer.

@kaliaiit

Ай бұрын

Its a nice method. So basically u used the approach we use in binomial coeff problems to create desired series. Very good .. its actually much shorter than the approach i discussed.... Keep it up shera❤❤....

@user-nz2iw5ws2k

Ай бұрын

Very good method bro ...

@fantomstranger3965

Ай бұрын

excellent method bro

@AryanPatel-iy9is

Ай бұрын

@@kaliaiit Sir in Q3, You have find the MAX value of (a^2 + b^2 + c^2) / (ab + bc + ca). But sir why we not use Minimum value of the expression. As If K right side ki minimum value se chota hoga then Max value se bhi chota hoga.

@shivx3295

Ай бұрын

​@@kaliaiitjii bhai ❤

Sir in Q3, You have find the MAX value of (a^2 + b^2 + c^2) / (ab + bc + ca). But sir why we not use Minimum value of the expression. As If K right side ki minimum value se chota hoga then Max value se bhi chota hoga.

Sir conic ka video kab aaega ??

Sir in q2, isn't a 3rd case possible where one of the polynomials is zero?

sir 31:39 mai limit as a sum of integral wala concept use nhi kr skte kya ?

Sir, 1:16:00 or MCQ 15, Ans will be option A and D. As we know a + b = c + d So for a2 + b2 Individually c and d must be greater than a and b. Therefore, ab = 2 and cd = 7

Q.4 we can split k^2 + k/ 2^k-1 Sum(k/2^k-1) is solvable by simple infinite AGP WE CAN WRITE k^2 as sum of first k odd numbers Then we can apply method of difference bcoz we get again and AGP which is solvable....At last subtract 2 from ans., since s1=0 but according to k(k+1) we get 2. This might be lengthy but helpful for different questions.

@fantomstranger3965

Ай бұрын

thanks

sir ji q 13 me bola hia ki only one solution isk matlab dono diff functions ke y ke value should be equal at one value of x only par apne toh graph se do do points me cut karvaya correct me if i am wrong

in qsn 1 it is given that f(x) is a polynomial but the f(x) you got is not a polynomial ......

In 01:09:27 we can solve option c and d via coefficient of equation

Ekdm Nazaaredaaar Ssn Bhaii Mazaa aagyaa 🔥❤ Bahut saare nye concepts seekhe aaj promise repeat krlenge🔥 Ek doubt plss btadijiyega - Cosx Quadratic wle Qs me for all x given tha na usme x=0 lekr proceed krskte h kya? Thank you so much LY3M ❤❤#Mera Bhai Mera Bhai ❤

Nazaare Aagaye Sir❤❤❤

(scq)2. sir 2√2 * √2 = 4 = 2² it is still a perfect square

Sir @kaliaiit , I think there is a problem with Q.9, please correct me if I m wrong. We can split 5/2^x as 1+1+3/2^x, then apply AM>=GM. Like this we get min. Possible value of 5(6)^1/5 which is less than 8. Hence I request. to please check.

@AryanPatel-iy9is

Ай бұрын

Bhai ye galat hai. As MINIMUM value aati hai when all terms are equal but in your case 3/2^x can not be equal to 2^x and 1/ 2^x.

@user-nz2iw5ws2k

Ай бұрын

@@AryanPatel-iy9is ok bhai, tq.

sir , in 39:46 the question could be finished in 2 steps using differenciation using maxima minima

@avinashkumarmishra6891

27 күн бұрын

Bhai q no. 2 me k ka value kya aaraha hai

@MAxGaMiNG-oh1jt

21 күн бұрын

yess bro did the same and its easier

ANALYSIS Q1. Got the concept right but idk why answer didn't match....solved 2 3 times ig I'm missing something...have to recheck Q2. Wrong attempt Q3. Concept right but couldn't reach the answer Q4. Made mistake at that k=0 point...rectification reqd Repeat ❗️ Q5. Tried by Vn method...got in the wrong direction...else soln was easy Q6. I didn't proceed due to inertia after seeing big big terms....apologies to myself Q7. Learnt a new method for this....highlighted pt: sigma cannot handle terms like a^x Q8. Millions of apologies to myself for making mistake in taking mod...else qn was easy Q9. Got it right in first attempt Q10. Got it right in first attempt Q11. Majedar question....best feeling after understanding the soln Repeat ❗️ Q12. Simple yet tricky...solved in the wrong direction Repeat ❗️ Q13. Graphical approach was necessary Repeat ❗️ Q14. Got it right in first attempt Q15. Partially correct Q16. Partially correct Q17. Learnt a new way Repeat ❗️ Q18. Wrong attempt Q19. Got it right in first attempt Q20. Got it right in first attempt Q21. Got it right in first attempt Q22. Couldn't solve....but method was damn easy Result: SCQ- 3/9 MCQ- 1/8 INTEGER- 3/4 Nazaaree overloaded❤...Love you bhai❤️❤️❤️

@razia9604

Ай бұрын

shayad 1st ques ka answer galat diya hai answer 1/144 aa raha hai

@sohambhattacharya7451

Ай бұрын

@@razia9604 nhi bro galti meri hai rhs mein cut karke 0 nhi 1 aarha hai

thank you sir

Sir, Q4 me aapne jo bola vo same galti ki and answer came as 16.......ese bohot obvious mistakes batate rehna becoz initially mujhe laga answer wrong hi hai...thanks for spotting the mistakes

Good evening sir I am studying 12th now Sir in my class I can understand what my lecture says but still Iam not able to do sums on my own Can pls tell me sir how to overcome it. I think you will see and reply for my problem. Thank u sir.

@BharatbhaiVDesai

Ай бұрын

Same here broo..

@shivx3295

Ай бұрын

I am also in class 12 You should first do basic questions on the topic so that you can tackle the tough ones I use the same way for every chapter

@user-qr8pq4hk5r

Ай бұрын

​@@shivx3295kha se krta basic?

@letsevolve9441

Ай бұрын

Read Solved Examples and after some time Resolve it on own..This will develop your brain for problem solving

Positive

Sir In ques 1:04:11 Me log indefinite ho Jay ga x+3+a>0 At x=-5 a cannot be 2

@unfunny_homies

Ай бұрын

😢

@kaliaiit

Ай бұрын

Yes, thats why x =-5 is not counted , rather the point of intersection on the right hand side of y axis is accepted as a solution for a=2. Thoda aur dhyan se socho...

@unfunny_homies

Ай бұрын

Thank sir 😊

52:02

P