PYQs on CONTINUITY| CSIR NET 2011 to 2023 | Short Cut Tricks
PYQs on CONTINUITY & its Properties CSIR NET 2011 to 2023 Short Cut Tricks #csirnetmaths #csirnetmathematicalscience #csirnet
Жүктеу.....
Пікірлер: 79
@sheemanitinsan72352 ай бұрын
I went to many institutions and invested a lot of money 💵 but no one ☝️ taught like you …..and you taught so very well 👌 without any fees thank you so much dear sir ❤
@yogendravishwakarma5592
Ай бұрын
Forget wrong things only take right and good things.
@sheemanitinsan7235
Ай бұрын
@@yogendravishwakarma5592yes ♥️
@aakashbhuse3170
Ай бұрын
Because he is recognised by the top Indian scientist in the current time and recently included in the top 2% scientists in the world !!
@sheemanitinsan7235
Ай бұрын
@@aakashbhuse3170 absolutely 💯 right brother
@shubhamkumartiwari23792 ай бұрын
@Dr.Harish garg , at 1:16:37 csir net June 2019 . Sir In this problem options (c) and (d) are also correct.
@pusplatasahu57382 ай бұрын
Superb session.....❤
@himanisingh3784Ай бұрын
Thankuuu so much sir.your teaching style is excellent.❤❤❤❤❤❤❤kash ap hmee phle
@steel6792 ай бұрын
very helpful sir `thankyou so much sir .
@goutamjana12922 ай бұрын
Very helpful sir . Please upload more videos.
@Achukutty25Ай бұрын
My prayers and wishes are always for you sir 🙏
@shaswata072 ай бұрын
Very helpful ❤
@rnithyaraj94982 ай бұрын
Tku sir Your videos very use full sir
@rashmimalik97692 ай бұрын
Bahut jyada helpful h sir ji
@supriyarani2645Ай бұрын
Aisa content aaj tak nhi mila you tube pe... difficult topic hai isko banane ke liye bhot thankyou sir... kindly make topicwise aptitude pyq
@imkunalkapoor2 ай бұрын
Sir this is very helpful please upload next 2 lecture very soon please your trick very helpful in exam
@user-ec3dq2bf1c2 ай бұрын
Really, you are teaching Real analysis, sir; thank you so much for sharing such videos.
@yogendravishwakarma5592Ай бұрын
Very nice lecture sir....
@riyagoel8939Ай бұрын
at 35:40 how did we have discarded the unbounded option(d) .Please provide a valid justification for the same
@dipeshvishwakarma3511
Ай бұрын
1/1+e^x is cts, one one and bdd.
@anuragpandey49122 ай бұрын
Thank you so much sir 🙏🏻🙏🏻🙏🏻
@rajkumarmanna38552 ай бұрын
Thank you so much sir ❤
@mathematicslovers28882 ай бұрын
Very nice explanation, thanks sir
@KalpnaDevi-xc3gx11 күн бұрын
Thanku sir
@vandnanamdev4443Ай бұрын
Thank you for your efforts sir 🙏
@ankitadangi16552 ай бұрын
Very helpful 🎉🎉🎉
@user-mk1gu4ug6p2 ай бұрын
Thank you sir😊
@positivethoughts64192 ай бұрын
Really you are great sir ❤
@SanchitMehra-mf3rh2 ай бұрын
Thanks again ❤
@riyagoel8939Ай бұрын
37:10 how can we consider A=R in the (4) option sinceR is not compact
@newsteplaiddown9481
Ай бұрын
A={1} it is compact , f^-1({1})=R it is not compact
@itsyourdev51432 ай бұрын
Thank you sir 🙏
@siddhusiddharthan1612 ай бұрын
Thank you❤ sir
@anitakaushik-be8mo27 күн бұрын
@ dr harishgarg 41:00...a option kaise shi ho gya ...f(a ) bdd to a ko bdd kaise bol skte h ..inverse image thode hi bdd hoti h
@ranachanda28392 ай бұрын
Thanks sir...❤
@intelligencecorner6092 ай бұрын
You are genius sir
@nerdhayafs6252511 күн бұрын
Please complete this topic with uniform continuity and all
@DrHarishGarg
11 күн бұрын
Already uploaded.... See at my youtube channel.
@ChandanKumar-dn9lz2 ай бұрын
Thanks a lot sir jee .
@steel6792 ай бұрын
solid content sir
@SunitaPooran-bi8gjАй бұрын
37:24 can anyone tell me..why sir had not taken compact subset A...why he has taken A=R
@Dearbhanusir
Ай бұрын
Yes A can't take R because A is compact
@ASHISHKumar-zu7xo2 ай бұрын
Please explain in bilingual. Your lecture is very useful for me. Thanks sir
@user-uv3ef6ps2t2 ай бұрын
Thank you sir
@PIMMATHS2 ай бұрын
Thanks sir ji
@ThoihenbaKeishamMeetei2 ай бұрын
love you sir❤❤❤
@sumitsharma29262 ай бұрын
Thank u sir ❤️❤️❤️❤️
@Siyagupta52Ай бұрын
@50:14 option (d) is incorrect as compact set will map to compact set. Is this correct or not? Can someone confirm?
@BEGINNERMATHS2 ай бұрын
Thankyou sir
@saikatmalla73902 ай бұрын
sir last request..... please upload a video on pyqs of ring theory.... 🙏🙏
@shreya22622 ай бұрын
Thankyou
@vikasmehta80272 ай бұрын
Thanku sir❤
@kalyandasgurujiАй бұрын
Sir please upload the vedios of linear algebra ... inner product spaces...and orthogonal...invariant subspcaes...
@DrHarishGarg
Ай бұрын
Linear algebra, inner product space etc already uploaded.. Explore at my youtube channel.
@kalyandasguruji
Ай бұрын
@@DrHarishGarg ok sir thanku
@anamfatima35242 ай бұрын
Please upload the next lecture,
@prabavathig4622 ай бұрын
Sir... Please... Which software you are using for screen recording this video ?
@anusuiya.Ай бұрын
Thank you sir🙏 Sir at 43:04 image of close interval under countinous function is always closed. and range of tan ^-1x is -pi/2 to pi/2 . So how option 1 is incorrect
@Siyagupta52
Ай бұрын
Take f(x)=e^x , A=R then f(A)=(0,oo) which is not closed
@shefalithakur4580
Ай бұрын
@@Siyagupta52 ha to in this case you take A=R which is not closed But continuous function always map closed to closed Compact to compact Cauchy to cauchy So option 1 is true here
@Siyagupta52
Ай бұрын
@@shefalithakur4580continuous function maps compact to compact Closed to closed is not true . As take the same example of e^x
@shefalithakur4580
Ай бұрын
@@Siyagupta52 I got it dear thanks Continuous not necessarily map closed to closed
@sahanar5228
Ай бұрын
Continuity maps Closed inteval to closed interval...but not closed set to closed ..ie ex R
@professorragavan97832 ай бұрын
8:17 I have a doubt in selection of option c. We neglect [-1,1] because 0 belongs to it. Similarly option C also have 0. Then why we take as a correct answer?.... Please someone explain me 😢
@DrHarishGarg
2 ай бұрын
The given option is set not interval because 1/n, n€N given .. So we need to find the function corresponding to this set and then check it continuity.... For example, for a and b option, function is given , but for c and d , function is not defined.... That's why, first defined the function and then check... Hope it help you.
Пікірлер: 79
I went to many institutions and invested a lot of money 💵 but no one ☝️ taught like you …..and you taught so very well 👌 without any fees thank you so much dear sir ❤
@yogendravishwakarma5592
Ай бұрын
Forget wrong things only take right and good things.
@sheemanitinsan7235
Ай бұрын
@@yogendravishwakarma5592yes ♥️
@aakashbhuse3170
Ай бұрын
Because he is recognised by the top Indian scientist in the current time and recently included in the top 2% scientists in the world !!
@sheemanitinsan7235
Ай бұрын
@@aakashbhuse3170 absolutely 💯 right brother
@Dr.Harish garg , at 1:16:37 csir net June 2019 . Sir In this problem options (c) and (d) are also correct.
Superb session.....❤
Thankuuu so much sir.your teaching style is excellent.❤❤❤❤❤❤❤kash ap hmee phle
very helpful sir `thankyou so much sir .
Very helpful sir . Please upload more videos.
My prayers and wishes are always for you sir 🙏
Very helpful ❤
Tku sir Your videos very use full sir
Bahut jyada helpful h sir ji
Aisa content aaj tak nhi mila you tube pe... difficult topic hai isko banane ke liye bhot thankyou sir... kindly make topicwise aptitude pyq
Sir this is very helpful please upload next 2 lecture very soon please your trick very helpful in exam
Really, you are teaching Real analysis, sir; thank you so much for sharing such videos.
Very nice lecture sir....
at 35:40 how did we have discarded the unbounded option(d) .Please provide a valid justification for the same
@dipeshvishwakarma3511
Ай бұрын
1/1+e^x is cts, one one and bdd.
Thank you so much sir 🙏🏻🙏🏻🙏🏻
Thank you so much sir ❤
Very nice explanation, thanks sir
Thanku sir
Thank you for your efforts sir 🙏
Very helpful 🎉🎉🎉
Thank you sir😊
Really you are great sir ❤
Thanks again ❤
37:10 how can we consider A=R in the (4) option sinceR is not compact
@newsteplaiddown9481
Ай бұрын
A={1} it is compact , f^-1({1})=R it is not compact
Thank you sir 🙏
Thank you❤ sir
@ dr harishgarg 41:00...a option kaise shi ho gya ...f(a ) bdd to a ko bdd kaise bol skte h ..inverse image thode hi bdd hoti h
Thanks sir...❤
You are genius sir
Please complete this topic with uniform continuity and all
@DrHarishGarg
11 күн бұрын
Already uploaded.... See at my youtube channel.
Thanks a lot sir jee .
solid content sir
37:24 can anyone tell me..why sir had not taken compact subset A...why he has taken A=R
@Dearbhanusir
Ай бұрын
Yes A can't take R because A is compact
Please explain in bilingual. Your lecture is very useful for me. Thanks sir
Thank you sir
Thanks sir ji
love you sir❤❤❤
Thank u sir ❤️❤️❤️❤️
@50:14 option (d) is incorrect as compact set will map to compact set. Is this correct or not? Can someone confirm?
Thankyou sir
sir last request..... please upload a video on pyqs of ring theory.... 🙏🙏
Thankyou
Thanku sir❤
Sir please upload the vedios of linear algebra ... inner product spaces...and orthogonal...invariant subspcaes...
@DrHarishGarg
Ай бұрын
Linear algebra, inner product space etc already uploaded.. Explore at my youtube channel.
@kalyandasguruji
Ай бұрын
@@DrHarishGarg ok sir thanku
Please upload the next lecture,
Sir... Please... Which software you are using for screen recording this video ?
Thank you sir🙏 Sir at 43:04 image of close interval under countinous function is always closed. and range of tan ^-1x is -pi/2 to pi/2 . So how option 1 is incorrect
@Siyagupta52
Ай бұрын
Take f(x)=e^x , A=R then f(A)=(0,oo) which is not closed
@shefalithakur4580
Ай бұрын
@@Siyagupta52 ha to in this case you take A=R which is not closed But continuous function always map closed to closed Compact to compact Cauchy to cauchy So option 1 is true here
@Siyagupta52
Ай бұрын
@@shefalithakur4580continuous function maps compact to compact Closed to closed is not true . As take the same example of e^x
@shefalithakur4580
Ай бұрын
@@Siyagupta52 I got it dear thanks Continuous not necessarily map closed to closed
@sahanar5228
Ай бұрын
Continuity maps Closed inteval to closed interval...but not closed set to closed ..ie ex R
8:17 I have a doubt in selection of option c. We neglect [-1,1] because 0 belongs to it. Similarly option C also have 0. Then why we take as a correct answer?.... Please someone explain me 😢
@DrHarishGarg
2 ай бұрын
The given option is set not interval because 1/n, n€N given .. So we need to find the function corresponding to this set and then check it continuity.... For example, for a and b option, function is given , but for c and d , function is not defined.... That's why, first defined the function and then check... Hope it help you.
@professorragavan9783
2 ай бұрын
Yes sir thank you ❤
🎉❤
😃😃
At 7:50, c is not correct
🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏
❤
Thank you sir😊
Thank you sir
Thanku sir
Thank you sir❤
Thank u sir😊
Thank you sir
Thanku sir
Thanku sir