PYQ chapter 11 Class 12 physics || Dual Nature of matter &Radiation

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Пікірлер: 441

@MuskanSingh-ve7or4 ай бұрын
Who is starting from 0 here for 2024 boards?
@Raginigupta-sv1ol
4 ай бұрын
Mee😢
@adityasingh8632
4 ай бұрын
Abb nahi hora bhai apna kuch Nahi aaraaha ek bhi question smjh
@MuskanSingh-ve7or
4 ай бұрын
@adityasingh8632 2 hr ki jo sir ne krayi h wo complete kro fir ncert solution krlo dekh kr only fir pdho tb smjh aayega Mera to 1.5 din lg gya only ishi chapter me😪😪😪
@adityasingh8632
4 ай бұрын
@@MuskanSingh-ve7or dekh li 🤡
@Bobaa111
4 ай бұрын
Bhai kya hoga kuch nhi kra abhi tk
@ruthyangkitoreplego92355 ай бұрын
1:45:16 the intensity will increase ✅
@monskill_
4 ай бұрын
Sir dhyaan nh diye 1 meter and 50 cm me 😂
@karshitroy15964 ай бұрын
Sir this is genuinely most helpfull video that covered entire dual nature... Not a single detail missed.😊
@kellybaker-pi3fw4 ай бұрын
53:00 final answer is 2v1-v2=Vo nothig big ,sir just misplaced 2Vo instead of 2V1
@Harshitakasana21305 ай бұрын
Thank you sir this gives a lot of confidence to us 😊😊
@supportarmy60724 ай бұрын
Watching 3 March 3:00 PM 😂
@saumayrawat33344 ай бұрын
Legends attendance lagao 😂
@utpreksha494 ай бұрын
Watching on 3 March 2024 ❤
@safgour496
4 ай бұрын
70 mai se 75 lane ka plane lag raha h tumhara to
@user-yu2jk9jm9x
4 ай бұрын
Kyu bhai aisa kyu khe rhe ho@@safgour496
@roshnisharma91955 ай бұрын
Thank you so much sir for providing us such amazing content ❤
@12THBOARDPHODNAHAI5 ай бұрын
1:21:20 THRESOLD WAVELENGTH
@Thevillageranmol5 ай бұрын
The negative value of anode that can stop photo electric current is called stopping potential
@funnywordz34795 ай бұрын
U r great and so helpful sir We r thankful to you!
@aaquibkhan07864 ай бұрын
Thankyou so much sir. your videos have helped me a lot.
@Shivamtripathi01115 ай бұрын
Thanks you sir for all your hard work ❤
@gamingwithffsiri89034 ай бұрын
1:33:25 6.94 x 10 ^-25 J
@khitishsahoo41685 ай бұрын
1:04:03 A) 2.62eV B) 0.5*10^-19J C)0.31v
@yogeshjain7786
4 ай бұрын
Wrong answer ignore it
@Himantakukdar5 ай бұрын
Thank you so much sir for the lecture ❤️
@Angel-mr7wy4 ай бұрын
1:42:20 sir u well explained these types of ques!! Thnku so much ❤ur pyqs series is osm😊bhagwan kre bs ques inhi mein se aje kl k ppr mein 😢
@user-hi3sn7pk1w
4 ай бұрын
Ya😢
@tendertokill54395 ай бұрын
Sir hamre liye ye video helpful hai. Thank you sir ❤🎉🎉
@sreerampraveen55504 ай бұрын
Sir at 57:50 the answer for (a) will be 2ev as the unit specified for the question was eV
@Brock12985
4 ай бұрын
Correct vhai...1240ev/wavelength in nm aaraam se nikal jaayega utna calculation ka jrurat nai
@bundletoonz3332
4 ай бұрын
bro sir converted ev to joul in step 3 as 1 ev =1.6 x 10^-19 joules
@sreerampraveen5550
4 ай бұрын
@@bundletoonz3332 Yeah but the question specified for eV 😊😊
@Baba_nrd5 ай бұрын
Sir you are great 👍
@purvijain1234 ай бұрын
Sir you are God of physics
@iitjee95734 ай бұрын
1:45:16 intensity increace hogi 4 times ho jayegi
@AbhishekKumar-xd9ne5 ай бұрын
this video is really helpful for me ...thank you sir
@prernajha86434 ай бұрын
Amazing lecture sir thank you for so much efforts
@MuskanSingh-ve7or4 ай бұрын
Thank u so much sir for providing best explanation 🤩❤🙏🙏🙏❤
@cyzue5 ай бұрын
sir .....1:21:30 question ask for threshold wavelength not threshold frequency
@12THBOARDPHODNAHAI5 ай бұрын
4HRS LAG GYE BUT SAB KUCH DETAIL ME LIKH LKH KR PRACTICE KARA AND CONCEPTUAL POINTS NOTE BHI KARE CHAPTER KA KAAM TAMAAM ABHISHEK SAHU SIR OP🔥🔥🔥🔥 - words from my mind date - 8 feb
@Kumar_ansh-ybr4 ай бұрын
1:45:13 sir intensity double hogi 1m and 50 cm diya hai sir
@ranisharma71945 ай бұрын
53:24 ,v°=2×v1-v2
@abhishekyt7501
5 ай бұрын
thats what I was looking for too
@aryansalunkhe5681
4 ай бұрын
correct
@user-sp2wz1mt2c5 ай бұрын
Sir hame physics me kuch nahi samajh aata hai
@Sahilsingh-bc5no
5 ай бұрын
Pyq kr 10 saal ke jldi se jldi
@learningjosh5784
5 ай бұрын
Go and search munil sir
@DeepanshiRajput-mz7bp
5 ай бұрын
Koi reference book bta do? @@Sahilsingh-bc5no
@gaaraofthedesert22
5 ай бұрын
@@DeepanshiRajput-mz7bpreference book ka time nhi bacha ab
@icchaagarwal8973
5 ай бұрын
Nw se padhke dekho aa jayga
@shellysutay48445 ай бұрын
1:03:20 is 4.24 x 10^-19
@SramK16
5 ай бұрын
42.43×10^-19
@manjulatanema63212 ай бұрын
Thankyou so much sir Your videos helped me alot 😊
@iitjee95734 ай бұрын
1:33:26 hw ans 0.69 * 10^-24
@adivaaaaaa5 ай бұрын
10:30 18:44 31:43 39:42 47:00 1:19:40 1:40
@pushpanjalikumari89984 ай бұрын
Sir thank you for this video, I had tried to solve pyqs from my book I wasn't able to solve 😢, and after this video I'm sure this ch is now complete 😊
@ForStudy-vo1ww5 ай бұрын
Attention Plz i think at 53:21 sir should have written 2V1 - V2 instead of 2Vo - V2..??
@madhumahato8956
5 ай бұрын
Yes
@abhishekyt7501
5 ай бұрын
yep I got the same ans
@aryanpatel9596_5 ай бұрын
Sir app aise hi session late Rahiye thanks you sir Sir aapke hi wjh se meri physics strong ho paa rhi hai mene abhi to koii questions bank nhi liya bs aap jo pyqs krwaye ho me bs bhi krta hoo Thanks 🙏🙏🙏 sir for your efforts 🙂
@user-nc2xw3eu4f4 ай бұрын
1:21:23 sir threshold wavelength ka formula nikalna tha ❤
@sanskritiangrish91375 ай бұрын
Thankyou sir it was very helpful
@user-vo9eo8sq8i4 ай бұрын
pyqs are most important as we saw in chemistry mostly questions are pyq
@govindsonipr90325 ай бұрын
Thank you for this series sir love you Sare lecture dekhe h sir mene
@reetaprajapatireeta16834 ай бұрын
yes sir , video is helpfull thank you sir
@Sargunkaur-kw1jp4 ай бұрын
Thnkuu soo much sir!!! 🥺❤
@pschyology3694 ай бұрын
Jai hind dosto corona batch wale sare weak hai koi na hota hai
@dsingh16445 ай бұрын
1:33:24 K=6.94×10^-13 J
@ranisharma71944 ай бұрын
57:50 kE= 2 ev Because value of kE ask in ev .
@prasunraj8297
4 ай бұрын
Yes 💯
@PrinceSharma-fx8xj4 ай бұрын
Done ✅, Thank you so much sir 🙏
@graph_book.4 ай бұрын
Aaj ka din 😂kal paper📄📄 h agar pehle pd lete😂
@Prajapatji1215 ай бұрын
Puri physics ke Imp pyq le kr ayo sir as soon as possible ❤
@Maths_magic-i2s5 ай бұрын
It's very helpful fir us sir thank you sir
@Gopy-sw9zo5 ай бұрын
19. A. 42.432×10-²⁰
@Superpichu074 ай бұрын
Sir you are great
@dibyajyotisahoo55015 ай бұрын
1:21:30 Threshold wavelength is lambda not=lambda1xlambda 2/2lambda2-lambda1
@divyanshxyz-dm9rt
5 ай бұрын
yess
@yakshyadav3519
4 ай бұрын
Thanks yarr😊
@aryan_dubey_015 ай бұрын
Very good sir thanks for the help 😊😊
@thanos6854 ай бұрын
Very helpful vedio sir 🙏👌
@user-ky9od2pd8n4 ай бұрын
Helpful video h sir thankyou
@preetimishra81965 ай бұрын
Thank you so much sir.......ye chapter bilkul clear ho gya ❤
@itzcrazyeditor
5 ай бұрын
Yaar mujhe to nhi aaya AAP kaha se padhte ho??
@user-co1je4rj3k4 ай бұрын
Thank you sir❤
@Superrdicer4 ай бұрын
Sir , 1:14:53 , kinetic energy is directly proportional to frequency, not inversely.
@tusharika3288
4 ай бұрын
He said threshold frequency.
@prashantmittal-dt1lm5 ай бұрын
1:44:08 sir E= 6.02ev aa rhi hai....it means that all electrons show photoelectric emission...
@anjaliutsav3144
5 ай бұрын
No bro your answer is incomplete. You didn't convert the energy into electron volt, for that you've to divide the given value by charge of electron because the answer you've written is E=hc/lamba= 6.02 and if you'll divide it by charge of electron then the answer will be 3.76 eV. So, Na and K will show photoelectric emission.
@khitishsahoo4168
5 ай бұрын
abey usko firse 1.6x10^-19 se divide kr
@DeepakSharma-qu1ev4 ай бұрын
53:51 ans is vo= 2v1 - v2.
@user-qr8nt3dq6e4 ай бұрын
Very helpful❤
@shauryarathore5 ай бұрын
Thanks sir
@MukeshSingh-iv3wc5 ай бұрын
Sir, please give us a formula sheet video including all chapters as soon as possible
@divyanshxyz-dm9rt5 ай бұрын
1:33 ans will be K;E=6.86*10^-28
@Sany_aa4 ай бұрын
Thanku sir❤
@prabhdeepsingh37505 ай бұрын
Yes sir helpful video ❤
@srushtidarji66905 ай бұрын
*NEET* keliye bhi jaldi se Revision series laiye❤
@aayushreemohanty31385 ай бұрын
It's really sad to see tht how selfish students have come watching a whole vd for their betterment and not appreciating the teachers efforts like see ... views is 21k n more bt likes only 800 likes
@user-gc1nh2lb8r
4 ай бұрын
🐁
@bilalsekh446
3 ай бұрын
Chup kr bkl
@devendersingh-vh9wk4 ай бұрын
33:20 sir esme h/p ka relation bi lag skta h na 😊
@adweita9904 ай бұрын
SIR THANK YOU SO MUCH
@Sanskritiii164 ай бұрын
1:42:42 Sir Thank you so so much for this pyq series ... My numerical portion is so good now and I'm not scared anymore ... Tomorrow is my phy paper and i watched all ur pyq videos ... It helped me a lottt .. thank you sir ✨
@nishakumari21755 ай бұрын
Thank you so much sir 😊
@shivamkumar50415 ай бұрын
Im jee aspirant and this video very helpful jo hmlog ko pdhate h wo vibe match karte h inek saath
@rohansharma13594 ай бұрын
10:12 sir yeh h ki value mei 10 ki power -34 kaise hogya 19 hona chahiye tha na?
@shivangsharma20465 ай бұрын
Sir please upload part 2 ray optics and optical instrument
@tabbasumqureshi98255 ай бұрын
Sir If u have important formulas list of all chapter so please share it ,it may be helful for us to do numericals easily..
@yashburande4827
5 ай бұрын
Yes I can
@prarthanasaikia40755 ай бұрын
you nailed it ❤
@339145 ай бұрын
Sir bhot helpful h ❤
@vaibhav96964 ай бұрын
nice lecture sir
@muskandasi2295 ай бұрын
Sir kitna yrs ka ques solve kra rahe h??
@x-sachin4 ай бұрын
Sirf aaj ke Raat hai guyssss
@noneofthesehima.7997
4 ай бұрын
Vhi to
@anuraj56725 ай бұрын
sir cased based q. ka ek video laiye, hmari bhut help ho jaegii
@akshatsrivastava25805 ай бұрын
sir exam gap mai live marathon kriyega questions ki huge request ....
@Nayakvanita5 ай бұрын
Thank you sir 🥰
@ShishirTiwari-in7qs5 ай бұрын
Very very thanks sir 😊😊
@maxxjee5 ай бұрын
❤ this is best pyq session thnkuuuuu
@harshita_20245 ай бұрын
Sir plz important questions for class 11 also ...we have our exams in upcoming days plzzz🙏🏻🙏🏻
@studenttt7305 ай бұрын
Sir please update the playlist , all physics oneshots class 12
@AdityaSahu-vp6nz5 ай бұрын
Sir appna chapter 5 ka pdf nhi Diya hai please provide the pdf
@user-lq2kj7sz1r5 ай бұрын
Sir electromagnetic induction and alternative current k bhi pyq kara dijiye
@ronakkeshwani17095 ай бұрын
Sir jaldi jaldi upload karte jao time bhut kam h ab and haa thank you very much sir….❤
@user-yb3lm5rs6q5 ай бұрын
Thank u so much sir
@vanshchaudhary29175 ай бұрын
Thanks so much
@running23485 ай бұрын
25:36 option b is correct
@MuskanSingh-ve7or4 ай бұрын
1:33:20= 6.93×10^-25
@h.yallroundervideos514 ай бұрын
Sir very helpfull❤❤
@user-jg8vh3sr6r5 ай бұрын
At 57:44 in questions we have find value of kinetic energy in (eV)not in joule
@divyanshxyz-dm9rt
5 ай бұрын
just relax its not a mistake just ignore this😇
@sumitsoni-uf9hq
5 ай бұрын
9.96 * 10*19 ev
@Brock12985
4 ай бұрын
It would have been easy to calculate using 1242ev/wavelength in nm
@bhumikarathour18595 ай бұрын
Sir aapne angstrom ki value 10^-7 kyu rakhi hai