Thanks a lot sir you clear my very deep doubt 🙏🙏🙏🙏🙏🙏

great work , it is simple and clear

@garytiner508

Жыл бұрын

Thank you for your nice comment!

Thanks a lot for this clear explanation😇😇😁

Very nice explanation

That was great . Thanks a lot .

this is awesome

❤🔥🔥

thanks a lot

One question, how do you know what epsilon to pick? Is it just for convenience?

@jacobguerreso675

2 жыл бұрын

Same question. Everything else makes perfect sense. Trying understand why epsilon equals greater than |f(x1)-L| wouldn’t work

@jacobbarats1493

2 жыл бұрын

Pretend that you didn't know it was 1/2 at the beginning. We just need to make the formula work for some epsilon, so at the end when we see that |...| + |...| > 1 when know that one of those terms is greater than 1/2 which we then let be the epsilon

@jesusdanielmiguelcova2360

2 жыл бұрын

Same question everything else is perfect

Thanks sir

what a goat

If I have a more complex function, that F(x1) and F(x2)aren't numbers, like "lim x - > 2 of g(x) = { x^(2) if 0