Problem on Principle of superposition |Simple Stresses & Strains | Strength of Materials | MOM | MOS
This video explains simple solution to "Problem on Principle of superposition".
Жүктеу.....
Пікірлер: 48
@kerenkanzemwarabu9 ай бұрын
This is really amazing so easy to understand thumbs up Sir 👍
@deepakdagar591 Жыл бұрын
Thanks for the nice explanation 😊
@user-so2uc7vf5n2 ай бұрын
How can i thank you sir! Until now, even after watching thousands of videos, I didn't understand, but your video made me understand just in 17minutes, so thank you very much sir from Nepal🇳🇵
@SampurnaEngg
2 ай бұрын
Glad to hear that
@THANUSHR-mk6yb6 ай бұрын
Excellent explanation 😮🎉🎉
@enjoyyourtripwithnature81512 жыл бұрын
Good explanation....
@babarrind6757 Жыл бұрын
Really good sir ❤️
@dheerajdexterous8929 Жыл бұрын
Thank you Sir..🥰
@siddumoosewala2160 Жыл бұрын
Thank you so much sir for clearing the concept
@user-tl1gi5mn7j
Жыл бұрын
kzread.info/dash/bejne/ZX9tta6ilteqgKg.html
@Biranchiofficial-bp8sc5 ай бұрын
Thank you so much sir ❤❤
@kiran31182 жыл бұрын
Thank you so much for your help sir ❤
@sumanthnenavath Жыл бұрын
Thank you sir 😚
@dramoyoedward9229 Жыл бұрын
Thanks alot for the wonderful explanation
@user-tl1gi5mn7j
Жыл бұрын
kzread.info/dash/bejne/ZX9tta6ilteqgKg.html
@c-116ujjurilavanya69 ай бұрын
Chala bada explain chesaruu sirrr thank you so much ❤
@SampurnaEngg
7 ай бұрын
Follow the Sampurna Engineering KZread channel on WhatsApp: whatsapp.com/channel/0029VaALnef7dmehZn80DV11
@sleazyR55735 ай бұрын
Will this process work in the case case of fixed ends??
@SampurnaEngg
3 ай бұрын
No,it won't work.
@allinformation.3a8542 жыл бұрын
🙏
@ranjan70892 жыл бұрын
Tnx sir
@Yourfather781 Жыл бұрын
Sir my calculations is going always wrong plz guide
@SampurnaEngg
Жыл бұрын
Where you are going wrong, kindly let us know.
@collinsokello-26133 ай бұрын
How does that force 60 comes from
@chuchuscast
2 ай бұрын
Equal and opposite force at the beginning
@ikennaagu5689 ай бұрын
Please I'm not still clear on this. This particular question is from exercise 2.2 of Rajput strength of materials but in the text book the lengths are not evenly distributed like how it is in this video. Is it that we can make it evenly distributed ourselves when solving or what?
@ikennaagu568
9 ай бұрын
*2.12
@SampurnaEngg
9 ай бұрын
You can take the respective length for the respective section. Like (PL/AE) where L is the length of the respective section.
@anushav5502 жыл бұрын
Thank u sir
@SampurnaEngg
2 жыл бұрын
Welcome
@bangalkids9596 Жыл бұрын
Portion BC has comprehensive force of 50 kn .. please clear it
@bhagwaa__01
Жыл бұрын
No u r wrong it is not comprehensive kindly note the original question
@BarelyEditing57
9 ай бұрын
Yes you r correct
@souravjena4982 Жыл бұрын
Sir compression stress me -ve hoga
@SampurnaEngg
Жыл бұрын
Didn't got your point.
@fieryscout2110
Жыл бұрын
Yes in compression your P becomes -ve but as in the given sum each part having tensile force acting on it thus the values are +ve
@ferdousalam13662 жыл бұрын
Sir, pls give Ans A Steel bar long 1m ang 20mmx20mm is cross section is subjected to a tensile force 40Kn. Determine the elongation of the rod. If the modules of elasticity of the rod 200GPA
@ranjan7089
2 жыл бұрын
0.5 mm
@nanasochaugule817
Жыл бұрын
0.5
@hardiksolanki831 Жыл бұрын
Giga means 10^9 ? Why sir take as 10^3 ?
@SampurnaEngg
Жыл бұрын
Yes. But if it's GPA then we have to convert it into N/mm2. So, We multiply it by 10^3.
@user-tl1gi5mn7j
Жыл бұрын
kzread.info/dash/bejne/ZX9tta6ilteqgKg.html
@oscarabdallah18832 ай бұрын
Bro unajua
@user-sx2rk4bn7m Жыл бұрын
Please I can't see the handwriting well oo 😞😢
@chandachouhan9560 Жыл бұрын
Thank you so much 🥰 sir
@SampurnaEngg
Жыл бұрын
Most welcome
@omegaarcex25277 ай бұрын
thank u sir
@SampurnaEngg
7 ай бұрын
Follow the Sampurna Engineering KZread channel on WhatsApp: whatsapp.com/channel/0029VaALnef7dmehZn80DV11
Пікірлер: 48
This is really amazing so easy to understand thumbs up Sir 👍
Thanks for the nice explanation 😊
How can i thank you sir! Until now, even after watching thousands of videos, I didn't understand, but your video made me understand just in 17minutes, so thank you very much sir from Nepal🇳🇵
@SampurnaEngg
2 ай бұрын
Glad to hear that
Excellent explanation 😮🎉🎉
Good explanation....
Really good sir ❤️
Thank you Sir..🥰
Thank you so much sir for clearing the concept
@user-tl1gi5mn7j
Жыл бұрын
kzread.info/dash/bejne/ZX9tta6ilteqgKg.html
Thank you so much sir ❤❤
Thank you so much for your help sir ❤
Thank you sir 😚
Thanks alot for the wonderful explanation
@user-tl1gi5mn7j
Жыл бұрын
kzread.info/dash/bejne/ZX9tta6ilteqgKg.html
Chala bada explain chesaruu sirrr thank you so much ❤
@SampurnaEngg
7 ай бұрын
Follow the Sampurna Engineering KZread channel on WhatsApp: whatsapp.com/channel/0029VaALnef7dmehZn80DV11
Will this process work in the case case of fixed ends??
@SampurnaEngg
3 ай бұрын
No,it won't work.
🙏
Tnx sir
Sir my calculations is going always wrong plz guide
@SampurnaEngg
Жыл бұрын
Where you are going wrong, kindly let us know.
How does that force 60 comes from
@chuchuscast
2 ай бұрын
Equal and opposite force at the beginning
Please I'm not still clear on this. This particular question is from exercise 2.2 of Rajput strength of materials but in the text book the lengths are not evenly distributed like how it is in this video. Is it that we can make it evenly distributed ourselves when solving or what?
@ikennaagu568
9 ай бұрын
*2.12
@SampurnaEngg
9 ай бұрын
You can take the respective length for the respective section. Like (PL/AE) where L is the length of the respective section.
Thank u sir
@SampurnaEngg
2 жыл бұрын
Welcome
Portion BC has comprehensive force of 50 kn .. please clear it
@bhagwaa__01
Жыл бұрын
No u r wrong it is not comprehensive kindly note the original question
@BarelyEditing57
9 ай бұрын
Yes you r correct
Sir compression stress me -ve hoga
@SampurnaEngg
Жыл бұрын
Didn't got your point.
@fieryscout2110
Жыл бұрын
Yes in compression your P becomes -ve but as in the given sum each part having tensile force acting on it thus the values are +ve
Sir, pls give Ans A Steel bar long 1m ang 20mmx20mm is cross section is subjected to a tensile force 40Kn. Determine the elongation of the rod. If the modules of elasticity of the rod 200GPA
@ranjan7089
2 жыл бұрын
0.5 mm
@nanasochaugule817
Жыл бұрын
0.5
Giga means 10^9 ? Why sir take as 10^3 ?
@SampurnaEngg
Жыл бұрын
Yes. But if it's GPA then we have to convert it into N/mm2. So, We multiply it by 10^3.
@user-tl1gi5mn7j
Жыл бұрын
kzread.info/dash/bejne/ZX9tta6ilteqgKg.html
Bro unajua
Please I can't see the handwriting well oo 😞😢
Thank you so much 🥰 sir
@SampurnaEngg
Жыл бұрын
Most welcome
thank u sir
@SampurnaEngg
7 ай бұрын
Follow the Sampurna Engineering KZread channel on WhatsApp: whatsapp.com/channel/0029VaALnef7dmehZn80DV11