PreCalculus - Polar Coordinates (14 of 35) Graphing Polar Equations: r=3cos4(theta), Roses
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In this video I will graph polar equation r=3cos2(theta), r=3cos4(theta), r=3cos6(theta), r=3cos8(theta), roses.
Next video in the polar coordinates series can be seen at:
• PreCalculus - Polar Co...
Пікірлер: 68
Thank you soo much for being thorough in your explanation, and pointing out what part does what. You have no idea how much videos 14-18 have helped me understand the topic. no longer is it a grind on a calculator, inserting random values, until I get the desired result. Thanks to you I have a system with which to plot these roses in under a minute! Not all heroes wear capes Professor, and you are certainly one of those!
this channel is so clutch. 2 weeks ago I was watching a video on rotational kinetic energy for physics and now I'm looking at polar coordinates for Specialist maths. Keep up the good work
@MichelvanBiezen
2 жыл бұрын
Glad you found us. Welcome to the channel!
Forgot something important. If the number in front of there is odd, the number of leaves is the same as that number. If even, number of petals is 2x that number.
@MichelvanBiezen
2 жыл бұрын
That is a good observation !
@ronycb7168
8 ай бұрын
Dude that's the next video in the series just sayin ya know
@kevinanderson6367
8 ай бұрын
Thanks for bringing that up. I was stuck on a homework problem.
@OrianaDeng
2 ай бұрын
HELP BRO I LITERALLY ALREADY GRAPHED IT OMG
Thanks so much! I like this method a lot better than the one my professor taught us
OMG, THANK YOU SO MUCH!!! THIS HELPS ME WITH MY ASSIGNMENT!!!
Its so much simpler than I thought. Thank you for breaking down the degree measurement.
@MichelvanBiezen
Жыл бұрын
Glad it was helpful! 🙂
You are a life saver thank you!
muito bom, me ajudou muito, parabéns!
In principle, the even coefficient of Thetta means the number of small angles (or number of halves of a leaf) in the 1st 90 degrees; therefore, the No of complete leaves in the 1st 90 degrees is those given halves of a leaf divided by 2 (i.e. 6 halves of a leaf in 3 cos(6x) divided by 2 giving us 3 complete leaves) BECAUSE 1 leaf is made up of 2 small angles/2 halves of a leaf. For the whole circle/360 degrees, you then multiply the No of complete leaves in the 1st 90 degrees by 4. Generally, take the coefficient of Thetta times 2 to find the total No of leaves.
@himanivatssharma3097
4 жыл бұрын
Sir... Can u please upload this types of tricks for cartesian curves also... Please sir... 🥺🥺
Me salvaste, gracias. Thank you so much. ❤
Loved it! Very clear and easy to understand. Thank you
@MichelvanBiezen
2 жыл бұрын
Glad it was helpful! 🙂
You're a legend
It's very helpful to me
Thank you, vdeo was very helpful.
Thank you so much…a very helpful video 👌🏻👏🏻👏🏻👏🏻
@MichelvanBiezen
Жыл бұрын
Glad it was helpful! 🙂
My favorite part was when you'd begin to form the petals and you could watch it all come together, knowing how it's done
@MichelvanBiezen
Жыл бұрын
It is quite interesting how it works.
Thank you so much your video really helped!!
@MichelvanBiezen
Жыл бұрын
You're welcome! 🙂
Good class❤️❤️❤️
Given the graph of a polar rose that has been restricted , how do you determine its equation and the restrictions being used?
@MichelvanBiezen
8 жыл бұрын
+Javi Lasala Can you give us an example?
@MrBabyJavi
8 жыл бұрын
+Michel van Biezen Could I have your email? This is mine: josejavier66.lasala@gmail.com
@MrBabyJavi
8 жыл бұрын
+Michel van Biezen Example: ONLY the graph/the drawing of r=3cos6θ { 0 ≤ θ ≤ π/2 } is shown. The task is to find the equation of the graph, and the restrictions being used, given only its graph/drawing.
@satmazmazsat641
5 жыл бұрын
I wish he was my instructor.
What if you are given the range of theta....say from 0 to 180°?
@MichelvanBiezen
Жыл бұрын
Then you stop drawing when you rach 180 degrees.
Is it a must to plot a table?because you just told us the easiest way to plot this graph
@MichelvanBiezen
Ай бұрын
It is not "required" but in some cases it is the easiest way.
if the number beside the theta determines how many leaves there are then why in "r=cos5(theta)" does that function only have 5 leaves? and not 10?
@Loots1
Жыл бұрын
wait is it only even numbers that the leaves are doubled?
@MichelvanBiezen
Жыл бұрын
The best way to see that is to draw y = cos ( 2 theta) and y = cos (3 theta) and then using a highlighter, then highlight the part of the curve that corresponds to the angle range from theta = 0 to theta = 90 degrees.
@Loots1
Жыл бұрын
@@MichelvanBiezen thank you!!!
Excelente video, saludos desde venezuela
@MichelvanBiezen
4 жыл бұрын
Welcome to the channel!
why pick four similar examples, instead of switching it to one with sine function and examples when the number in front of theta is odd
@MichelvanBiezen
2 жыл бұрын
This video shows the effect of changing the coefficient in front of the angle. What you are requesting can be found when viewing the other videos in the playlist.
How do you know how wide each leaf is?
@MichelvanBiezen
3 жыл бұрын
We show how to do that in the calculus videos, when we show how to find the area of each leaf.
@VictorRivarola007
3 жыл бұрын
@@MichelvanBiezen Thanks
Sir my english language is very weak. Can you tell me why you devide 2 all time from 360° with theta's coefficient in r = 3cos 2(theta)or some other sums you have done this videos. But in your other video you don't devide 2 when you drawn the graph of r=3cos(theta) or 3cos 5(theta). It would be better if you clear my doubts. Thank you!
@MichelvanBiezen
Жыл бұрын
For even angle cosine functions (cos 2 theta) or cos (4 theta) the number of leafs = 2 x the number of theta. This is found by plugging in number for theta and solving for r
I am from Bangladesh.very nice understanding systems.
@MichelvanBiezen
Жыл бұрын
Thank you. Welcome to the channel! 🙂
Thank you so much
@MichelvanBiezen
2 жыл бұрын
You're most welcome
Big thanks
@MichelvanBiezen
3 жыл бұрын
Big you're welcome!
I think, as a chemistry student, that this is actually linked to orbitals, atomic orbitals theory... Just wondering...
@MichelvanBiezen
4 жыл бұрын
It may look like it, but isn't. The Schrodinger equations dictate the shape of the orbitals. (See the quantum mechanics videos on this channel.)
Thank you
@MichelvanBiezen
3 жыл бұрын
You're welcome
Who is the genius who doesn the thumbnail and how is it done, which program?
@MichelvanBiezen
4 жыл бұрын
That genius is my wife who makes all of the thumb nails in paint.
@Unknown-ln5ly
2 жыл бұрын
@@MichelvanBiezen She deserves some type of award, they're very impressive 🙂
Why are you multiplying the denominator by 2 everytime
@MichelvanBiezen
Жыл бұрын
With the cosine function, we must divide by 2 in order to determine the number of "petals". Try it with the function: r = cos (theta). There will be 2 complete leaves when you graph that function.
Watched this twice
O god