THANKS A LOOOOT you explained it perfectly and easily, i was suffering to understand it

@EnggClasses

3 жыл бұрын

Most welcome. Meanwhile, subscribe to our channel EnggClasses for more quality videos. kzread.info

Love the way you teach sir, nice content in short video☺️

thx so much for this lecture

excillent for this information and more introduction i wish for you

Thank you!

for 3rd signal and 4th signal how you got -1

Awesome bro

when the u(t-1), its indicates that t = 1, while when u(t+1), t = -1, assume that t + 1 = 0, use t as the left side and move 1 into the right side. simple algebra.

Thank you

How do you get amplitude 1+ time signal 3=0 how do you write 4th signal as zero

Thank you very much

Hey appreciate your effort can you do with discrete signal as well

@EnggClasses

3 жыл бұрын

Thank you Safwan. Yes those videos are also in the pipeline. Do subscribe for more videos.

Perfect

In 3rd signal it is about amplitude -2 but u made it -1 how come sir

Thankyou sir

4th signal how's you get 0 amplitude please reply

@mohamaduhadijatu736

3 жыл бұрын

New amplitude at a time=previous amplitude on graph at that time plus amplitude at which switching starts at that time for the new graph.

❤

I think the x(t) graph is wrong🙄🙄🙄u took amplitude 1 and -1 instead of 2 and -2

3rd signal amplitude was -2 you sketched -1

Is U(-t)= -U(t). Plz reply

@EnggClasses

4 жыл бұрын

Nope.! In U(-t) time is getting reflected and in -U(t) amplitude is becoming negative. Both are different. Hope this helps.

@HelloWorld-zt4ol

4 жыл бұрын

Ok. It means in U(-t) line with amplitude 1 is on the left side of x axis . In -U(t)below y axis.

@EnggClasses

4 жыл бұрын

Exactly.! You got it correct.

F(t) = t^2[ u (t-1) - u (t-2)]

Fourth signal is wrong...please do check that...

@EnggClasses

4 жыл бұрын

Thanks for the comment Pratheesh. Yes, I did check again, but there is nothing wrong. Fourth signal is u(t-3), its an unit step signal shifted to the right by 3.

Your addition for this signal is not clear..🤧