not your AVERAGE Putnam limit (2021 Putnam A2)

not your AVERAGE Putnam limit. We evaluate a limit with exponential functions and averages, taken from the William Lowell Putnam Math Competition. This is problem A2 from the 2021 Putnam exam. We do this by taking logarithms, hospital’s rule, derivatives of exponential functions, and the definition of e as a limit. This is a must see for calculus 1 students and anyone interested in math Olympiad problems, enjoy!
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Пікірлер: 28

  • @vasuhardeo1418
    @vasuhardeo14182 жыл бұрын

    your vids are such fun, great vibes sir.

  • @olli3686
    @olli36862 жыл бұрын

    Love the little Mohawk

  • @manwork6545
    @manwork65452 жыл бұрын

    Basic stuff but interesting. Especially the use of the l'Hospital rule (not very intuitive...). Thank you Dr Peyam.

  • @Szynkaa
    @Szynkaa2 жыл бұрын

    i did it slightly different- first i took ln(g(x)) as you did, but then i didn't use de"hospital rule- instead i used inequality y/(y+1)

  • @SuperYoonHo
    @SuperYoonHo2 жыл бұрын

    also... GREAT VIDEO!

  • @SuperYoonHo
    @SuperYoonHo2 жыл бұрын

    saw this ahter 14 secs it was loaded

  • @diniaadil6154

    @diniaadil6154

    2 жыл бұрын

    awesome !

  • @SuperYoonHo

    @SuperYoonHo

    2 жыл бұрын

    @@diniaadil6154 thanks!

  • @harikishan5690
    @harikishan5690 Жыл бұрын

    nice!!

  • @mtaur4113
    @mtaur41132 жыл бұрын

    There is a mean value theorem trick for this one, when I saw this problem in a forum thread a while ago. Sadly I was stumped by most of the other problems, maybe I got one of the others right? But Real Analysis 1 is one of my strongest areas. A difference of two things with a "+c" inside the parentheses once suggests MVT! A slight change, but I had to save the limits for the end and define (g(x,h))^h = (x+1)^(h+1) - x^(h+1). This is equal to f(x+1) - f(x) = f'(x*), for some x* in (x,x+1), where f(x) = x^(h+1). So g(x,h)^h = (h+1)x*^h, and g(x,h) = (1+h)^(1/h)*(x*). x*/x is in the interval (1, 1+1/x), so you can take the limits as h to 0 and x to infinity in that order with a bit of squeeze theorem thrown in.

  • @adityaekbote8498
    @adityaekbote84982 жыл бұрын

    This was a fun one!

  • @isimyok5848
    @isimyok58482 жыл бұрын

    i like this

  • @win764
    @win7642 жыл бұрын

    Does the logistic map recurrence relation have a closed form?

  • @perappelgren948
    @perappelgren9482 жыл бұрын

    That smile @ 5:00 😆😆😆

  • @draaagoo7799
    @draaagoo77992 жыл бұрын

    yessir

  • @iRReligious
    @iRReligious2 жыл бұрын

    LMAO , that mic🎤 drop at end 🔚 😂😂😂

  • @zeropotential6830
    @zeropotential68302 жыл бұрын

    Sir do you teach at any University?

  • @hccuugxt7cj8jbk9utgx
    @hccuugxt7cj8jbk9utgx2 жыл бұрын

    شكرا على معلومات 🙋‍♀️🙋‍♀️🙏🙏🙏🙏👈👈👈👈🔔🔔🔔👍👍😥😥😥😥🙏🙏🙏🙏

  • @DavesMathVideos
    @DavesMathVideos Жыл бұрын

    Hello Dr. Peyam, just to let you know, your title is wrong. It should be Question A2. Question A1 is about the grasshopper, which I actually solved over on my channel. It's also a not-to-hard question involving vectors and 3-4-5 right triangles, somewhat easy for a Putnam. Looks like 2021 was an easy year, relatively speaking. Your solution by the way is elegant and your explanation is great. As you say, a Calc 1 student can do it if he knows what to look for.

  • @drpeyam

    @drpeyam

    Жыл бұрын

    Thanks!!

  • @ready1fire1aim1
    @ready1fire1aim12 жыл бұрын

    We're 4D. Like quaternion math. I keep hearing theories like "simulation", "holographic" or back to Leibniz' "contingent" universe. Those theories all match the i, j, k in quaternions. Quaternion MATHEMATICS a complex number of the form w + xi + yj + zk, where w, x, y, z are real numbers and i, j, k are imaginary units that satisfy certain conditions. RARE/biblical a set of four parts, things or persons. (dimensions?)

  • @alexdemoura9972
    @alexdemoura99722 жыл бұрын

    L'Hôpitalizable... 😁😁😁😁😁😁

  • @ready1fire1aim1
    @ready1fire1aim12 жыл бұрын

    3 sets of 3 dimensions. 1D, 2D, 3D are spatial 4D, 5D, 6D are temporal 7D, 8D, 9D are spectral 1D, 4D, 7D line/length/continuous 2D, 5D, 8D width/breadth/emission 3D, 6D, 9D height/depth/absorption

  • @giorgibliadze1151
    @giorgibliadze11512 жыл бұрын

    Doctor! Please show some respect and do proper hornes)))), not some spider man ))))

  • @drpeyam

    @drpeyam

    2 жыл бұрын

    Hahaha

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