Norms

Norms
Lecture - 05

Пікірлер: 44

  • @SorryBones
    @SorryBones Жыл бұрын

    Oh man, 3 years later and this is still saving students. Thank you for explaining it so clearly!

  • @heidioid
    @heidioid2 жыл бұрын

    Wow very good straightforward explanation. The simplicity and clarity is A+! Thank you so much for sharing this!

  • @oraz.
    @oraz.2 жыл бұрын

    This is the most in depth definition of the norm

  • @aminuabdulsalami4325
    @aminuabdulsalami43253 жыл бұрын

    Excellent tutor. Norms made simple.

  • @samsilarifeen2367
    @samsilarifeen2367 Жыл бұрын

    simply amazing. you described it as crystal clear. Thank you so much.

  • @zeyadramadan8759
    @zeyadramadan8759 Жыл бұрын

    Excellent explanation of what the norm is. I was searching for days until I found your video. Well done and keep it up please.

  • @rishisingh6111
    @rishisingh61112 жыл бұрын

    Extremely well taught, thanks a ton!

  • @apoorva3635
    @apoorva36353 жыл бұрын

    Beautifully explained Sir!!

  • @tagoreji2143
    @tagoreji2143 Жыл бұрын

    Thank you Sir.It was a Wonderful Session

  • @diegososa5280
    @diegososa52803 жыл бұрын

    Great job, thank you

  • @sumayyakamal8857
    @sumayyakamal88573 жыл бұрын

    great vid, THANK YOU!

  • @arkadipbasu2348
    @arkadipbasu23482 жыл бұрын

    Great explanation, thank you

  • @Rahul_IMD
    @Rahul_IMD Жыл бұрын

    You are advised to enhance your presentation technology i.e. video quality, obviously teaching skill and provided content is excellent 👍.

  • @adiai6083
    @adiai60832 жыл бұрын

    Very nice explaination

  • @Arpita-fo2dl
    @Arpita-fo2dlАй бұрын

    done sir

  • @jamesang7861
    @jamesang78613 жыл бұрын

    THANK YOU!

  • @manasa2927
    @manasa2927 Жыл бұрын

    Crystal clear

  • @khayum009
    @khayum0094 жыл бұрын

    Is there any way I could get the slides of the presentation.. it would be helpful to make notes out of it..

  • @SwavimanKumar
    @SwavimanKumar3 жыл бұрын

    So it's understandable that the L2 norm will give us the distance of the point from origin & L1 norm gives the sum of distances of its 3 base coordinates. But what L3 or higher norms of the same 3d vector signifies? I find it difficult to get the intuition behind higher norms in terms of distance. Kindly explain.

  • @ariffaridi6699
    @ariffaridi66992 жыл бұрын

    Thank you, sir

  • @bharathmadduri
    @bharathmadduri3 жыл бұрын

    Vector addition x+y is based on parallelogram rule of addition

  • @physicsforum4725

    @physicsforum4725

    2 жыл бұрын

    shabas beta

  • @johnk8174
    @johnk81742 жыл бұрын

    can somebody link to the playlist that this comes from?

  • @_justacoder_
    @_justacoder_3 жыл бұрын

    please provide playlist link in description of the video

  • @user-ey8bl1vr3u
    @user-ey8bl1vr3u3 жыл бұрын

    Thanks Sir

  • @user-xl8uo9gp9p
    @user-xl8uo9gp9p3 жыл бұрын

    Isn't it counter intuitive/ productive to associate a number with a vector/matrix.....i mean two entirely different matrices may have equivalent norms,but that closeness will mean nothing.!!!??

  • @anushkaverma914
    @anushkaverma9144 жыл бұрын

    For this is it compulsory that we have prior knowledge of MATLAB...

  • @BVSrinivasan

    @BVSrinivasan

    4 жыл бұрын

    No, it is not. It is just for demonstration.

  • @ytg6663

    @ytg6663

    3 жыл бұрын

    Hi, do you have job?

  • @SMM_5
    @SMM_53 жыл бұрын

    hi sir.. when this course will come in nptel?

  • @shritejchavan6222
    @shritejchavan62225 жыл бұрын

    I am unclear about the difference between Frobenius norm and L2 norm.

  • @AdityaMishra-ve6yu

    @AdityaMishra-ve6yu

    4 жыл бұрын

    L2 norm is for vectors while Frobenius is for matrices. The method is same however.

  • @BVSrinivasan

    @BVSrinivasan

    4 жыл бұрын

    To add to what Aditya Mishra said, Frobenius for matrices looks similar to the L2 norm for vectors. However, for technical reasons, there is a separate L2 norm for matrices with different properties.

  • @physicsforum4725

    @physicsforum4725

    2 жыл бұрын

    @@AdityaMishra-ve6yu if the method is same for both ,it must gives same value but acc ||A||2 should not be equal to ||A||f.

  • @ranjithabc9004
    @ranjithabc90043 жыл бұрын

    What is norm of a vector having complex numbers?

  • @physicsforum4725

    @physicsforum4725

    2 жыл бұрын

    as i know if we have a complex vector say Z=(1-2i,i,3i,1+i) and if we find 1- norm ,||Z||= (|v1|^2+|V2^2|+.......|Vn|^2 )^1/2 =sqrt 17 so it gives a real number.

  • @prithwishguha309
    @prithwishguha3092 жыл бұрын

    You Showed (x+y) Wrongly(in reverse direction)

  • @Ifeeezenwoye-ec6sx
    @Ifeeezenwoye-ec6sx5 ай бұрын

    I still don't understand 😢😢

  • @captainstreamer3261
    @captainstreamer32613 жыл бұрын

    At 7.19 min The Direction Of The 3rd Vector Is Wrong I Think , It Does not Satisfy normal vector addition rule ....

  • @aminuabdulsalami4325

    @aminuabdulsalami4325

    3 жыл бұрын

    I thought as much.

  • @tulaycaglayan8674
    @tulaycaglayan86743 жыл бұрын

    8:10 isn't it x-y instead of x+y?

  • @rinkukumar721

    @rinkukumar721

    2 жыл бұрын

    No, it is x+y, look at the tail and head of the vectors

  • @rinkukumar721

    @rinkukumar721

    2 жыл бұрын

    although, it's either of 3 vectors, one should have the opposite direction...

  • @vikashroy6058
    @vikashroy60583 жыл бұрын

    1. Show that the following relations hold for the input signal u whose 2-norm ≤ 1. Here y is the output signal and G is the transfer function (stable and strictly proper) (a) ||y||2 = ||G(s)||∞ ||u(t)||2 (b) ||y||∞ ≤ ||G(s)||2 ||u(t)||2 (c) pow (y) = 0.