Normal Electric Field Boundary Conditions
www.patreon.com/edmundsj
If you want to see more of these videos, or would like to say thanks for this one, the best way you can do that is by becoming a patron - see the link above :). And a huge thank you to all my existing patrons - you make these videos possible.
In this video, I use Gauss’ Law to figure out the boundary conditions on the normal component of the electric field (technically the electric flux density, but what’s a permittivity between friends?)
This is part of my graduate series on optoelectronics / photonics, and is based primarily on Coldren's book on Lasers as well as graduate-level coursework I have taken in the EECS department at UC Berkeley.
Hope you found this video helpful, please post in the comments below anything I can do to improve future videos, or suggestions you have for future videos.
Пікірлер: 33
Brilliant video! Thank you Mr. Edmunds!
Well done, amazing video.
this is good...I'm impressed...I tried watching a lot of videos reading a lot of book to get to the bottom of this but to no vail...Thank you jordan!
@JordanEdmundsEECS
2 жыл бұрын
You, Andy, are welcome :)
This is awesome. Thank you sir
Thank you sir.
It helped alot... Thank you
Great explanation!!! My EM professor can't explain boundary conditions as easy as you can. Keep it up Jordan!
@JordanEdmundsEECS
2 жыл бұрын
EM is a hard subject to explain xD Thank you!
Thank you edmunds❤ you saved me
mMy guy, were in the same Quantum Mechanics II class! Nice video, I always sucked at EM, but your vids make a lot of sense. Good luck on this and the midterm tomorrow lol
@jordanedmunds4460
3 жыл бұрын
Ahahahaha that's hilarious xD. Maybe after this semester I'll actually be able to teach QM properly.
@gerardogutierrez4911
3 жыл бұрын
@@jordanedmunds4460 YES I would love to see your explanations in a friendly and straight-foward way lol. Anyways good luck and glad I found your channel.
Thank you very much, way better than my book 📚
@JordanEdmundsEECS
2 жыл бұрын
Thank you, Tarun :) I sincerely appreciate the encouragement!
Is this process the same regardless of the materials in parallel? So, if you have two conductors, dielectric and a conductor, or two dielectrics?
Superb
Amazing ...
@vikaskaushik8171
4 жыл бұрын
Thanks a lot sir ...
There are two formulas for boundary condition I saw in book I guess the tangential one they determined with sin theta I guess. I didn't understand that part would you like to explain please
Can I not say the sides of the cylinder have a surface area perpendicular to E so the flux in the curvy side =0?
HI, 5:50 what do you mean by linear marterial? Linear in what sense? Great video btw
@mgx9383
Жыл бұрын
Linear means that epsilon is not a function of E (same thing for µ and H, and for conductivity).
In 1:58 You didn't mention that Q_encl is the free charge enclosed and not the total charge. Q_total = Q_counfined + Q_free, where Q_confined is the charge that is confinded in diaelectric dipoles.
Isn't the direction of Enorm,2 at 9:25 same as Enorm,1?
8:35 Why did you draw Enorm2 with direction opposite to Enorm1? It doesn't follow from equations.
Hello Mr. Jordan, Thank you very much for your useful videos. I am a little bit confused about one thing that i hope you can make it clear to me. Why we don't follow the same approach as the tangential component, why we didn't use the line integral Maxwell's equation and make the area very small so that ds will equal zero as we did for the tangential components.
@whysoserious0609
2 жыл бұрын
I think we want to keep what we want, if ds goes to zero, then the left-hand side equation containing Enorm1 and 2 are gone, only Qenclosed is left, which seems meaningless since we want the relationship between Enorm1 and 2
@poly3902
2 жыл бұрын
@@whysoserious0609 Thank you :)
why does sigma become zero, isnt there still area of the top and bottom of gaussian surface
@luciferinjustice2632
Жыл бұрын
We assume charge free surface
This got you a subscription
In short: 7:00