My god first time KZread has recommended a very useful video 😄

@serdalhocailematematik1930

2 жыл бұрын

My math question kzread.info/dash/bejne/enWqsraPZd23gJM.html

@pavanprasad7011

2 жыл бұрын

Correct

@bishnudas307

2 жыл бұрын

Same here

@Niki_Tkd

2 жыл бұрын

Yup😂

@R3XxX

2 жыл бұрын

Exactly

CBSE should also include Vedic Mathematics as an extra subject for small children ..

@satyajitroy2331

2 жыл бұрын

Chup chutiye yaasehi chote bache normal math hi handle nahi karpatai

@its_culture_boy2943

2 жыл бұрын

Rbse me pahle ye kuch years tha but ye vedik methamatics nhi hai ye to bus normal si tricks because vedik time me 0 नहीं था

@janhavishende9320

2 жыл бұрын

they will never 😒

@Shadow_AMV

2 жыл бұрын

@@its_culture_boy2943 .....kya? 0 tha vadik mathematics me Vashishth samhita me use hua hai zero ka

@Bludblud69

2 жыл бұрын

"Haha you andhbhakt " some random liberandu

For those wondering how this works, here's an example. 19 = 16 + 3 19 = 4² + (2*3*4)/(2*4) 19 = 4² + 2*4*{3/(2*4)} + {3/(2*4)}² - {3/(2*4)}² Now on RHS, the first three terms form a perfect square identity. 19 = {4 + 3/(2*4)}² - {3/(2*4)}² You can ignore the last term on RHS as we are finding "non perfect roots" √19 = 4 + 3/(2*4) And this is the formula he said in the video. Same logic can be applied on any number you want. Sincerely, an Indian student. :)

@sureshpatil9104

2 жыл бұрын

Nice work!

@tanishdesai7652

2 жыл бұрын

Like this explanation a lot 👍😀

@tanmaykamble827

2 жыл бұрын

Op bro

@sureshpatil9104

2 жыл бұрын

@@anjugupta9488 it's very small...

@supertron6039

2 жыл бұрын

@@anjugupta9488 Because as compared to the first term, it is a small value. You could technically go on expanding to get a closer answer but I didn't bother doing that because of the formula he used in the video.

I am from Telangana State board... And my school started Vedic Mathematics for Classes 4th to 10th mandatory for everybody. Difficulty increasing for every standard. I was in 5th during that and now I am in 12th .Classes being taken twice a week and regular exams included in quarterly and half-yearly too. This was just particular my school having extra curriculum.

@sattaking2177

2 жыл бұрын

Personal👆 number lene ke liye WhatsApp karo👆......

@aarushidubey5202

Жыл бұрын

wow! that's great!

@abhi3112

Жыл бұрын

hey can you tell me which school you studied in and about the study material they provided

OMG !absolutely fantastic.....it will help tremendously in competitive exams....👊

@serdalhocailematematik1930

2 жыл бұрын

My math question kzread.info/dash/bejne/enWqsraPZd23gJM.html

@scienceandmathsbyrahul

2 жыл бұрын

@@serdalhocailematematik1930 kzread.info/dash/bejne/ZY6kmtVtj8mtdbg.html

@animekshokeen3301

2 жыл бұрын

Yes🤣🤣.... I helps alot

@scienceandmathsbyrahul

2 жыл бұрын

@@animekshokeen3301 kzread.infozatCVTRINLE?feature=share

@YuvrajSingh-el8ol

2 жыл бұрын

Bhai caclulation kese krni a

Under root 83 is equal to 9.11 under root 129 is equal to 11.3 under root 105 is equal to 10.25 under root 171 is equal to 13.07 .

@reality1496

2 жыл бұрын

Its within root not under root.... By the way you have done perfectly...

@Ayooosuppp

2 жыл бұрын

@@reality1496 no it's under root

@user-wl9hx4qp7l

2 жыл бұрын

Are मूर्खों कुछ भी बोल lo karna to wahi hai na...

@aditivishwaskamble3525

2 жыл бұрын

@@user-wl9hx4qp7l Wahi yaar.

@Bossrexona

2 жыл бұрын

Bro isko solve kaise karna hai

Thanks very helpful video❤ The ans of the questions are : √83 = 9.11 √129 = 11.3 √105 = 10.25 √ 171 = 13.7

@BHASKARREDDY5300D

5 ай бұрын

root 11 value is 11.36

मैं इस चैनल पर राजीव दीक्षित भाई साहब का वैदिक मैथ का तरीका सुनके आया हूं, गुरूजी सच में बहुत ही शानदार शूत्र बताए है आपने ये हमारी प्राचीन गणित विधि है और बहुत ही उपयोगी है।। आपका बहुत बहुत धन्यवाद।।

@AryanBansal-pr5ke

4 ай бұрын

Ma bhi

@SeemaSingh-dn4gy

3 ай бұрын

Same here 😊 Rajiv Dixit amar rahe ❤

@itz_rx7_

Ай бұрын

Am also

Really Great Video Sir. Power of Vedic Maths Can Never Be Underestimated 💪

@user-of9ug7or1t

2 жыл бұрын

Bro, this chapter is already teaching on. In 12 th class chapter name Approximation.

@PhotonGamerYoutube

2 жыл бұрын

@@user-of9ug7or1t ok !!

@Omega_Plus849

2 жыл бұрын

@@user-of9ug7or1t approximation is based on differentiation. And that's a long method to solve such roots. Plz Don't mislead, I'm seeing your same comment in all chat boxes.

@KSH132

2 жыл бұрын

@@Omega_Plus849 right,I m in twelve now ,

@realtalk9189

2 жыл бұрын

Brilliant

I don't know how to thank you, I had watched many videos but not even a single one is totally applicable but this one is awesome, it's help me a lot. Thank you Brother for this ❤

@sattaking2177

2 жыл бұрын

Personal👆 number lene ke liye WhatsApp karo👆......

Thank you Thank you Thank you So much Sir.... Aap ke jaisa easy me aajtak koi nhi mujhe Root nikalna sikhaya ❤️ Thank you So much Sir ❤️

This was genuinely amazing yaar too good it's gonna be very helpful. Just in order to have trust i took my own no.s and tried their square roots. Fanatstic all were correct

It's a very useful trick to gain the answer of non perfect square

@baboonandanjha4411

2 жыл бұрын

Bahut hi achhi jankari aap ne dee.dhanyabad.

This shows knowledge and feel of early Indian Mathematicians. 🗣️

@disawarbaba4573

2 жыл бұрын

⁸⁹⁵⁰⁵¹⁹⁶⁵⁶,,, ok.....

@mdsharfuddinmd5710

Жыл бұрын

Happy New year sir

You are doing very great work......I am praying to God that .-your channel keep growing and more student see your video and learn so that they can increase their knowledge 🙏🕉

Bahut achhi video hai Bhaiya..... Ab tak KZread ne sabase achha video recommend kiya hai...👌👌🤩🤩🇮🇳🇮🇳

This kind of math is been taught in +2 level in the form of approximation. f(x+delta x) = f(x) + f'(x)* delta x is the approximation formula for any function.

@arsinha8518

2 жыл бұрын

Yes... Everyone steal from India

@ideoamay3594

2 жыл бұрын

What is Delta??

@EmptyyCups

2 жыл бұрын

Yepp.. right

@anshedit541

2 жыл бұрын

∆

@anshedit541

2 жыл бұрын

@@ideoamay3594 ∆

This video is very helpful to me, thanks sir😊

Thankyou. Very helpful for competitive!! 🙏🏻🙏🏻

आपके द्वारा प्रेषित विडियो मेरे लिए बहुत लाभदायक है ,मै कल ही अपने विद्यालय में अपने छात्र छात्राओं को अवश्य बताऊंगा और सिखाऊंगा भी उम्मीद है आप भविष्य में भी ऐसी ही ज्ञानवर्धक विडियो बनाकर हमारा मार्गदर्शन करते रहेंगे धन्यवाद

Ans- √83=9.11 √105=10.25 √129=11.3 √171=13.07 Really great video sir.... Power of vedic maths can never be Understimated ..... Thnku so much sir😊

@recipes6620

2 жыл бұрын

thank

@factandeducationhubomsharm5260

2 жыл бұрын

√3 ka nikalo

@tamanna1944

2 жыл бұрын

@@factandeducationhubomsharm5260 I already solved... √3=1.75

@recipes6620

2 жыл бұрын

@@factandeducationhubomsharm5260 1.5

@amritasshreyas5317

2 жыл бұрын

@@factandeducationhubomsharm5260 I tried.. Lekin single digit k liye ye work nhi kar rha h 😐 Answer is coming out to be 2(using this method) lekin approx value is 1.732(i remember this lol!)

Very nice sir. Thank you so much ❤ sir

Your videos are very useful...Thank you!!😇😇

It's very useful and time save method. Thanks 👍

OMG 😱 Vedic math should be a subject in schools. Thanks 👍 it help a lot.

@Maopin5748ebuss

Жыл бұрын

Class 12 cbse maths me hai

√83~9.11 √105~10.25 √129~11.36 √171~13.076 I have found a so knowledgeable video... Keep it up sir👍👍👍

@janhavishende9320

2 жыл бұрын

Correct , I have also done it 👏👏👏

@samikshyar1841

2 жыл бұрын

105 ka samajh nahi aaya

Amazing keep explains these Awesome Tricks to solving these kind of questions 👍👍

My deep heartily regards to Vedic mathematics. It made my work simpler by not only this method but also several other methods.

@sattaking2177

2 жыл бұрын

Personal👆 number lene ke liye WhatsApp karo👆.....

Sir Literally Maja Aa Gaya √83~9.11 √129~11.36 √105~10.25 √171~13.076 Thank You So Much Sir ☺️☺️

@Dghbkjfg

2 жыл бұрын

Aapka 105 ka root wrong aaya hai root 105 ka answer 10.24 aayega

@Dghbkjfg

2 жыл бұрын

10.25 aayega

@Filmywisdom

2 жыл бұрын

@@Dghbkjfg Oh 😳, Yes Galti Ho Gaya

@Dghbkjfg

2 жыл бұрын

It's ok ☺

Thank you sir, from the bottom of my heart ❤️❤️❤️

amazing, i was recommended to watch this video.

great bro, I am very very thankful to you for providing this kind of content.

Its not a precise method but still for fast calculations especially in numericals it will be so useful🔥

@_YashPathak_

2 жыл бұрын

@Babulal but you can't use it in exams 🙄

@suraz6435

2 жыл бұрын

Precise method? Nobody writes the complete square root with all decimals in exam

@_YashPathak_

2 жыл бұрын

@Babulal yo i know but you don't need to write the precise values in exams😉

@_YashPathak_

2 жыл бұрын

@Babulal bruh i got 91% in this year only 😁

@_YashPathak_

2 жыл бұрын

@Babulal ok bro thnx it will be a honour for me 😂

thx a lot for this amazing technique

@serdalhocailematematik1930

2 жыл бұрын

My math question kzread.info/dash/bejne/enWqsraPZd23gJM.html

Wow ..I got answers for all ..Amazing way ...Thank you for sharing this valuable trick

This is the best channel I found which nicely describes vedic maths

When I was in school vedic maths was an extra subject in our syllabus. Ya it's a very convenient and easy learning process of maths. It should be a part of presents syllabus of primary class children.

@user-jh2fg7wi4g

2 жыл бұрын

100 % श्रद्धा👌

@Real_Drw_amv

2 жыл бұрын

Yes ✅👍

@omdave1008

2 жыл бұрын

Bhai kuch bhi ye vedic maths nai hai... Ye class 12 ka approximation chapter ka hai jiska isne bas ek formula bana ke rakh diya hai... If you are in class 12 you can realise that you can find cube root or any nth root of any number with this method.... Aur please ye vedic maths mat karo... Jo method easiest hai usko follow kro

@agystyatiwari7907

2 жыл бұрын

@@omdave1008 wo aya kaha se? Roots to ye hi hai na bro...

Really appreciating... ❤❤

@letsderive

2 жыл бұрын

😇

cam on Thay ruy o biet ve tieng nuoc bn nhung toi van xem vy deo bn vi bn chot qua chuan .chuc bn v gd bn khoe manh .hanh phuc VA Dat moi uoc mo nhe bn .

It's very useful.... Thank you for this👍

Sir this is a amazing formula It will help us all Thanks for teaching this trick🙏

@serdalhocailematematik1930

2 жыл бұрын

My math question kzread.info/dash/bejne/enWqsraPZd23gJM.html

@serdalhocailematematik1930

2 жыл бұрын

Thanks Mr Parekh

@love2kill231

2 жыл бұрын

Custom me aa 1 vs 1 freefire

Nice, Just loved it Sir!!! 😊😊, And Again nice job ✌️✌️👍👍 1. 9.11 2. 11.36 3. 10.25 4. 13.076 I Have done these by your given method, the question you gave us at last...... ✌️✌️😄😄

@letsderive

2 жыл бұрын

Well done!

@serdalhocailematematik1930

2 жыл бұрын

My math question kzread.info/dash/bejne/enWqsraPZd23gJM.html

New information for me...Really so helpful...

amazing... thnks this was helpful

Under root 83 is equal to 9.11 under root 129 is equal to 11.3 under root 105 is equal to 10.25 under root 171 is equal to 13.07 also the trick was good and makes calculations easy thank you

@diya__3092

2 жыл бұрын

U r right

@diya__3092

2 жыл бұрын

Your math is too good👍👍

@dabhiparth

2 жыл бұрын

Bro, Under root 105 = 11.35 (calculator) Or 11.5 (Vedic Maths)

@shivgarg9465

Жыл бұрын

Ye kaise kiye ho

@shivgarg9465

Жыл бұрын

Mere ko bhi batao

हमारे भारतीय संस्कृति कुछ कम नहीं है ❤️🇮🇳 Please forgive me if any grammatical mistakes🙏

Wow , Definitely worth trying , Boggled my mind.

Thanku Bhai yeh video to bahut useful hai 👍👍

Or same can also be derived via differential calculus. Take y = x^1/2 dy/dx = 1/(2 x^1/2) = ∆y/∆x Say for (19)^1/2 =( 16+3)^1/2 Say x=16 and ∆x =3 ( Remember ∆x

@SaurabhKumar-pd5qw

2 жыл бұрын

only a jee aspirant can apriciate this , and i appreciate this

@mohitmehla6375

2 жыл бұрын

Yes it does not work for finding root of 3

@anishsingh5321

Жыл бұрын

@@mohitmehla6375 yes this trick gives 1.75 for root 3 approx but not accurate

@GurdeepSingh-xb2ts

Жыл бұрын

Thankyou sir.............

@pat.1718

Жыл бұрын

Approximation!?

I watched this video a year ago and now i felt this was very helpful in exams and for whom who always forget square roots ! This is gonna help me in my exam . I appreciate you sir . Thanks 🙏

Very good sir...thanks for spread knowledge

Thankyou for giving questions..

So useful Sir! Thank you so much🙏❤️. Sir can we find the root of all prime numbers this way especially single digit prime numbers?

@sattaking2177

2 жыл бұрын

Personal👆 number lene ke liye WhatsApp karo👆......

Sir,pls make videos on how to know decimal no. are the square on which no. -( the reverse of this vdo)PLZ🙏🏻 This vdo is very helpful for us🖊️📕

@serdalhocailematematik1930

2 жыл бұрын

My math question kzread.info/dash/bejne/enWqsraPZd23gJM.html

@sachkahoonpunjabi3110

2 жыл бұрын

@@serdalhocailematematik1930 kzread.info/dash/bejne/equoz8OAdayZdpM.html

Bohot jayad hi helpful video.... thank you sir 🙏

Sir thank u for teaching this short cut trick. Really i am happy.

This is the power of our Sanatan Hindu Dharma 🚩🙏🏻 🕉 which people in the world are underestimating. Thank u For such a great knowledge 🙏🏻

@arxalier2956

2 жыл бұрын

You're right that this is a very useful Vedic maths trick, but hindu dharam has nothing to do with this. Even Muslim mathematicians like Al' khwarizmi discovered algebra. Thank all our ancestors, not just hindu mathematicians

@_curious_Devansh

2 жыл бұрын

@@arxalier2956 plz study Vedic Mathematics deeply, then u will get me what I am trying to say :)

@byron-ih2ge

2 жыл бұрын

@@arxalier2956 al khwarzmi didnt invent algebra lol.. He copied the work of Bhaskaracharya , translated and modified thats all dont utter bs

@thorstark4114

2 жыл бұрын

@@byron-ih2ge source?

@byron-ih2ge

2 жыл бұрын

@@thorstark4114 those peimitive arabs and their primitive cult was devoid of anything known as maths but then they imvded india.. The caliphate was sucessful in capturing " SINDH" and when that happened thats when they unserstood whats maths is for real..

To understand why it works. This is truncated taylor series approximation. F(x) := F(a) + F'(a)(x - a) So, if F(x) = √x Then, F'(x) = 1 / (2√x) √x := √a + (x - a) / (2√a)

@chiranjitmajhi5702

2 жыл бұрын

Mujhe toh Taylor series ka itne application hai patahi nhi tha

@rishiloona2409

2 жыл бұрын

saala sab kuch indian logon ne khoja tha lekin sab angrej le gaye

@nishantshelar8887

2 жыл бұрын

@@rishiloona2409 Language is also of Indian origin. Sanskrit is the mother of all Indo-european languages. Small examples: Naam = Name Matru = Mother Bhratar = Brother Vividh = Vivid You can find many such examples. The existence of dual, not just singular and plural in Sanskrit, compared to partial existence of dual in Latin, explains a lot. Though I think some people reinvented certain concepts independently and credit should be given to them as well. I would say this what westerners did was they robbed the colonies not only of their wealth but also ideas and culture. They also erased a lot of our culture. Search for Madhava Of Sangamagrama. He was studying and teaching infinite series and calculus way ahead of newton and leibniz.

@rishiloona2409

2 жыл бұрын

@@nishantshelar8887 arre mene bhi wahi likha hai ki sab kuch indian ne dhoonda lekin angrej sab le gaye

@nishantshelar8887

2 жыл бұрын

@@rishiloona2409 Yes, wanted to give you more info. 😊

This video is very helpful to solve sums in math

Bahut shandar aur saral tareeka .thank you sir

Seriously amazing trick derived by ancient Indian mathematicians.great video too 😀

Hey bro!! Excellent video! Just subscribed to ur channel. This will be a gem for my JEE exam now. Just one error was there. In square root of 19, by Vedic method, it comes 4.375 which is ~ 4.4, and by calculator, it comes 4.358 which is ~ 4.4, so instead of 4.3 it would be 4.4 (method was correct, just it should be 4.4 instead,) thank you!

@Trolex6969

2 жыл бұрын

Significant Figures ka khel h bhai ye sab.

@tanishdesai7652

2 жыл бұрын

This method relies on binomial approximation. The method here approximates the root by only 1+nx (where highest power of x is 1), so if you want greater approximation, you will also have to work with higher powers of x (like square, cube, etc). So it is not really an error. It's just approximated. Working of root19- root19=root(16+3) =root(16(1+3/16)) =4 x root(1+3/16) =4 x (1+3/16)^½ =4 x (1+(1/2 x 3/16)) =4 x (1+3/32) =4 + 3/8 ~4.3

@omdave1008

2 жыл бұрын

@@tanishdesai7652 nice one keep it up 🔥👍

@MalavDoshiDGDKT

2 жыл бұрын

Bhai this formula works beautifully when u r nearer to the perfect square since it is based on approximation using graphs more the difference more error is introduced but u can get it correct to first place

@devdyumnaupadhyay9762

Жыл бұрын

@@Trolex6969 if u take 25 insted of 16 then the answer will be 4.4

Amazing sir . Thank you 🙏

Thank you so much, it was really very helpful:))

OMG. 😀😀 End mei 4 questions toh chutkiyoon mei hoo gye.. Amazing broo👌👌👌👌👌👌 Pehli baar yt nei koi achi cheez recommend ki hai 😀❤️😊

Good content, you provided us friend The result obtained by this method is very approximate and differ from the actual value by less than 1 . Keep it up.....

@sattaking2177

2 жыл бұрын

Personal👆 number lene ke liye WhatsApp karo👆.....

@mdsharfuddinmd5710

Жыл бұрын

Happy New year sir

Thank you, it's really helpful

Thank you youtube for recommend to me this video 😊

Amazing❤️❤️

@serdalhocailematematik1930

2 жыл бұрын

My math question kzread.info/dash/bejne/enWqsraPZd23gJM.html

My god You are the life saver that will help me in my 10th Board exam ...

Thanks🌹 YT to recommend me this video!!

THANK YOU. IT HELPS A LOT

Under root of 83= 9.11 Under root of 129= 11.36 Under root of 105= 10.25 Under root of 171= 13.076

@gdp1947

Жыл бұрын

Bhai solution batao na 😭😭😭

@SAZZ3DM

Жыл бұрын

How sqrt of 129is 11.36 , i am getting wrong answer . By the rule its 11+(8/88 ie 0.0909090...) so my soln is 11.09090... how you are getting .36

@subhransupanda4896

Жыл бұрын

How to find √404.41?

@kelp3474

Жыл бұрын

@@SAZZ3DM how are you getting it would be 8/22 you have to multiply by 2 everytime

@SAZZ3DM

Жыл бұрын

@@kelp3474 nah in denominator , you have to multiply the remaing ie.8 in this case with the number you've done square of in this case 11

this is going to help me to solve JEE questions

@yashubanna776

2 жыл бұрын

Mera bhi same purpose h🥰

@physicslover9701

2 жыл бұрын

Ary ye tu nursery ka concept hai

@yashubanna776

2 жыл бұрын

@@physicslover9701 hamare board me nhi padhayi jati vedik maths

@physicslover9701

2 жыл бұрын

@@yashubanna776 agr app jee advance ki preparation karte hona tu ye concept clear honai chahiye

@yashubanna776

2 жыл бұрын

@@physicslover9701 mains par h jyada focus.

Thankyu so much for helpful video 🙏🙏

Great video Thank you for making this video

Ok if try to find anything square root , cube root Then use... f(x+∆x)=f(x)+∆x.f'(x) Where f'(x)=Differentiation of f(x) If u find out sq.root of 19 then f(x)=√x. f'(x)=1/2√x x=16. ∆x=19-16=3 Then put all in f(x+∆x)=f(x)+∆x.f'(x) If u find out the cube root of 9 Then f(x)=x^⅓. f'(x)=1/3x^⅔ X=8 and ∆x=1 And u also find out log and many other functions too...

@satyamev_jayatey_

2 жыл бұрын

I.e. only for small ∆x N to bhari error ki sambhavna hai😂

@ravikotadiya3403

2 жыл бұрын

@@satyamev_jayatey_ 👍

@mathsrelated

2 жыл бұрын

Is this numerical formula ok?

@ravikotadiya3403

2 жыл бұрын

@@mathsrelated this formula is in ncert 12th science course

@mathsrelated

2 жыл бұрын

Ok... I'm from bsc mathematics course😀

This is an application of Derivatives where we use derivatives to determine square root of non perfect number

@Anonymous-fs1od

2 жыл бұрын

😁

@Shubham-xr8ih

2 жыл бұрын

Can you explain bro! Plz

Excellent technique for all......keep it up .... waiting for next.......

Your video is really praisable Thanks

You saved my time in exams

This technique is thought to us in Application of derivatives..😀

Superb trick sir❤ Thank you sir 🙏

Dil khush ho gaya 👌🏼👌🏼👌🏼👌🏼

√83=9.1 √105=10.2 √171=13.07 √129=11.3

@letsderive

2 жыл бұрын

Well done!

@Goluyadav90000

2 жыл бұрын

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@unequalgamer8152

2 жыл бұрын

Abe nehi hua √83 ka kese kiya

@vibhakulshrestha6589

2 жыл бұрын

Google guru ha 🧠🧠😀😀😂

@chagankumawat4651

2 жыл бұрын

83 ka 9.1 kaise aaya

This method relies on binomial approximation. The method here approximates the root by only 1+nx (where highest power of x is 1), so if you want greater approximation, you will also have to work with higher powers of x (like square, cube, etc). So it is not really an error. It's just approximated. Working of root19- root19=root(16+3) =root(16(1+3/16)) =4 x root(1+3/16) =4 x (1+3/16)^½ =4 x (1+(1/2 x 3/16)) =4 x (1+3/32) =4 + 3/8 ~4.3

@Shadow_Assasin_

2 жыл бұрын

Yess bro

@yugyt2185

2 жыл бұрын

Your mathematics playar ok

@tanishdesai7652

2 жыл бұрын

@@yugyt2185 r u Baria?

@allifazhar

2 жыл бұрын

Arey Shi pakdyy hoo. Binomial approximation is very useful and Good approximation.

@supertron6039

2 жыл бұрын

Yep

Thanks a lot. It is of great help 😇

Bhi meme apni jindagi me pahal asa youtuber dekha h jo vadik mathes ki trick sikhakar apni sanakriti aur apne vedo ke prati logo ko sikha raha h 😙😙😙 Thank you

Long division method still works perfect for me and it also gives accurate answer and not an approximation

Very helpful......vedic maths should be included in the syllabus.

Thank you sir. It was a very helpful video.

superb brother... what a wonderful trick to solve square roots...

Satya sanatan vedic dharm ki Jai 🚩

This technique is not ACCURATE but Very Useful For JEE and Various Competitive Exams🤟

Thanks for providing such valuable information

It really helped Thanks Bro ...

BUT HOW CAN WE CALCULATE THE SQUARE ROOT OF DECIMAL NUMBLERS LIKE 22.5,30.9 ETC...

@ksr3535

2 жыл бұрын

separate them like sqrt.2250/100 for 22.5 and sqrt.3090/100 for 30.9…

@lakshveerverma7857

2 жыл бұрын

Ok

Sir, I got for root105 = 10.1, But in the calculator, root 105 = 10.2 came. Plz , help me I'm confused for these differences.

@letsderive

2 жыл бұрын

Bro calculate it to 2 decimal places and then round it off

@tadurivenkataramakrishna1671

2 жыл бұрын

Ok, ThanQ, sir

@MBStudy

2 жыл бұрын

Calculate again. Your calculation mistake

it helps me alot thanku very much

Thnk you so so much , square root was always my weakness. Very useful video