NMR spectroscopy in easy way - Part 1
Learn Nuclear magnetic resonance (NMR) spectroscopy in easy way. NMR is a special tool that plays a key role in structural elucidation of many organic and pharmaceutical compounds.
In organic chemistry, NMR spectra can be used to identify a structure for which spectral interpretation is essential. By observing the number of NMR signals, one can approximately estimate the types of nuclei present in the structure. In case of 1H-NMR, the number of different types of protons attached in different way to parent chain can be detected by studying NMR signals.
All nuclei can not give NMR signal but nuclei with spin quantum number I = 1/2 can only win this game. Nuclei like proton (1H), 13-carbon (13C), fluorine (19F) and few other nuclei can give NMR signals.
Electrons surrounding a nuclei can oppose the magnetic field applied externally thereby they reduce NMR signal. This effect is knows as shielding effect. But the effect of these electrons highly depends on the connectivity and orientation of the groups in the molecule.
In this spectroscopy, the effect of neighboring groups on the nuclei is also studied. Few of the groups increase the electron density surrounding the nuclei under study thereby they produce an upfield effect. These groups shift the NMR signals to right side leading to decrease in the chemical shift.
This is the part-I of video series in which how easily we can understand NMR spectroscopy was discussed.
Find part -2 of this video here : • NMR spectroscopy in ea...
Part-3 : NMR spectral interpretation and rules: • NMR spectroscopy in ea...
Part-4 : NMR spectral table: • NMR spectroscopy in ea...
Part-5 : Magnetic anisotropy: • NMR spectroscopy in ea...
Part-6: Solvents in NMR : • NMR spectroscopy in ea...
Part-7: 1H vs 13C NMR : • NMR spectroscopy in ea...
Part-8: Number of NMR signals: • NMR spectroscopy in ea...
Part-9: Magnetic equivalence: • NMR spectroscopy in ea...
Part-10: NMR signals in cyclic compounds: • NMR spectroscopy in ea...
#NMRspectroscopy
#NMRprinciple
#protonNMR
Пікірлер: 121
The best video on NMR. Clear with appropriate examples and concise. Thankyou Sir
@egpat
3 жыл бұрын
Glad it was helpful! Thanks for watching.
Hello.... I am not from the physics background so was struggling to understand this; you explained it so well that all my basics about NMR is now clear.... Thankyou so much!!!
@egpat
Жыл бұрын
Glad it was helpful! Thanks for watching.
Well explained . Concepts are clear sir . Thank you so much
It is for the first time I could understand The NMR spectroscopy Thank you sir and expecting more and more videos
@egpat
3 жыл бұрын
Glad it is useful. Thank you. Definitely I will upload more videos, let me know any specific topic you are more interested. Thanks for your interest.
@sangamthakre8799
3 жыл бұрын
Can u give me ppt of NMR spectroscopy
Thank u you sir it is really helpful and easy to understand 👍
You are the best teacher.
Explained in simple way..tq sir
Clear understanding to any chemistry students
he is the best teacher . A true spirit of a mentor . The Real Man .
@egpat
3 жыл бұрын
Thanks for liking.
Thank you sir. This video helped me a lot👌
@egpat
3 жыл бұрын
Glad to hear that. Thanks for watching.
Well explained 👌🏻 ..... Thank u sir 🙂
@egpat
4 жыл бұрын
Glad you liked it. Thanks for watching.
Thank u sir, explained well..first time I understood the topic spectroscopy .
@egpat
4 жыл бұрын
Glad to hear that. Keep watching.
@dwtrowe
3 жыл бұрын
Beast
Super sir.good explanation
You are a good teacher. Thank you
@egpat
4 жыл бұрын
Thank you! Keep watching.
Excellent explained wow👍
Waoooo sir tq so much 👍🙏🙏🙏🙏🙏💐💐 unbelievable sir
Very nice explanation sir.upload more videos sir
Excellent teaching
Crystal clear 👌
Very good sir,ur lecture is very clear& easily understand to studends,thank u verymuch🙏
Thank you so much sir
Sir how is value for I calculated?
Hi, Nice explanation.. It would be better to describe why Resonance term is used in the technique.. and please check once regarding "No spin " in "No external magnetic field". The concept is, in no external magnetic field nuclei with 1/2 spin will be arranged in random, when an external magnetic field is applied, the nuclei with 1/2 spin will allign to the field. And further is as described. Ignore it, if it is irrelevant.
@egpat
3 жыл бұрын
Ya, that's a good point. You are correct, as you said, in absence of magnetic field nuclei will have random spin and they produce a small magnetic filed. These nuclei will have intrinsic angular moment but the net spin of all nuclei is very nearer to zero due to random orientation of individual spins. So practically it can be considered as net zero spin compared with nuclei with spin oriented with or opposite to external magnetic filed when it is applied. Thanks a lot for your interest and suggestion.
Thank u legend 🎉
Really good and easy to understand..Thank you sir
Thank u very much sir
Very good explanation
Thank you very much for such informative session
@egpat
Жыл бұрын
It's my pleasure. Thanks for watching
Excellent
Explained excellently
@egpat
3 жыл бұрын
Glad you liked it. Thanks for watching
Thank you for this helpful video! I really appreciate it :) On a side note - I noticed that at 11:09, the m value for I = 0 should be 1, not 0 (as presented).
@pratikshetye7004
2 жыл бұрын
No I guess I = 0 and m should be = 1 and not 0 as presented
@pradeepbhakar6029
22 сағат бұрын
Yes m should be 1
Well explained
vvv nice explaination
Awesome sir tqsm 🙏
@egpat
3 жыл бұрын
Welcome, thanks for watching.
12:19 i think the multiplicity in case one is m=1 as 2i+1 and i =0 then m is equal to 1
Tq soo much sir🥰🥰🥰👍👍
The ever best video on NMR ,.... really helpful...thank you soo much 😊
There can be signal for others than half
Thank you so much sir...tht helped me to understand the concept
@egpat
4 жыл бұрын
Glad to hear that. Thanks for watching.
Sir is 17O^2 is shown by NMR ACTIVE OR RAMAN ACTIVE..... please clarify my query sir
Never before ever after...
Nice explanation sir tq
@egpat
3 жыл бұрын
You're most welcome
The part 4 is not available. nmr spectroscopy in easy way part 4 egpat. How can I get it please
This way of teaching is very excellent
@egpat
4 жыл бұрын
Thanks for liking.
Sir ... I have a question When we provide RF the electrons can also absorb the radiation,so why nuclei absorb???
Tnx to made tis🔥
@egpat
3 жыл бұрын
You are welcome. thanks for watching
Nice
Nice teaching 👌👍
@egpat
3 жыл бұрын
Thanks for liking
an outsanding explanation tnks sir
@egpat
3 жыл бұрын
Most welcome
Very good ...in11:28 I=0,m=1 is right
@egpat
4 жыл бұрын
Thank you. Yes, as stated earlier in the video when I =0 , m value is 1. Thanks for watching.
@naseehan8856
4 жыл бұрын
@@egpat Yes right 👍 I watched 3 parts of nmr.very useful
Wao Thanku so much
@egpat
3 жыл бұрын
Welcome, thanks for watching
Nmr spectroscopy range please tell
Hlo sir very nice
Is nmr applicable to compounds that donot contain hydrogen?
@egpat
3 жыл бұрын
Yes, it can be used for silica and other inorganic compounds also.
@midcrizzz812
3 жыл бұрын
More than 1H NMR scientist will use 13C NMR...
Sir ur explaining very well but try urdu or hindi .as for english so many british are there
In case 1 m=1 while comparing the cases there is m=0
🙏🙏🙏🙏🙏🙏🙏
i feel am prepared for m MSC Exam now
You are from South India?
Which app you are used for making this video 😢
Nmr active nuclei I should not be equal to 0....other than 0 can be anything not only 1/2
@egpat
3 жыл бұрын
When I value is 1 or greater it results in non-spherical charge distribution resulting in signals with variable line width which are not easy to study. But when I=1/2 it leads to spherical charge distribution which is easy to study. That's why nuclei with I =1/2 are selected for NMR spectroscopy.
@chemicalworld7800
3 жыл бұрын
@@egpat but we talking about nmr signal
@egpat
3 жыл бұрын
Yes, NMR signal better observed with nuclei I as 1/2. Can you give any example of nuclei studied in NMR with different I value?
@chemicalworld7800
3 жыл бұрын
Boran 11 Chorine 35 Both I=3/2
@egpat
3 жыл бұрын
That's great. You are right. So these are the quadrupolar nuclei. But here in this video we are discussing NMR spectroscopy for pharmaceutical analysis where we study nuclei mainly like proton, and carbon in organic compounds which have I value as 1/2. As you said, quadrupolar nuclei are useful to study inorganic nuclei like Cl and B. Thanks for your interest and watching the video.
14 odd ????
12:36 tell it to deuterium NMR
I wish my our online classes were like this..😁
Nitrogen 14 is even, it is given under both odd.
@pradeepbhakar6029
22 сағат бұрын
Individually the number of protons are 7 and neutron is also 7 therefore these both are odd
8:56 doubt
We are supplying RF not EMR
What is I sir
How can 14 will odd sir,,
@pradeepbhakar6029
22 сағат бұрын
Individually the number of protons are 7 and neutron is also 7 therefore these both are odd
N is 14 and 7 how can this be included in both odd? 14 is an even number!
@pradeepbhakar6029
22 сағат бұрын
Individually the number of protons are 7 and neutron is also 7 therefore these both are odd
how desperate did i have to be to reach here:)
can I = 3/2 GIVES NMR
@erikzuiderweg6824
2 жыл бұрын
yes, and also I=1, but rhe signal is difficult to observe
spin quantum number is l not 'i' ...you have been constantly calling it "i"
@soumyadeepsarkar7819
7 ай бұрын
Nuclear spin quantum no. is denoted by "I"
@pradeepbhakar6029
22 сағат бұрын
Bhai orbital angular momentum is "L"
Nearly all of the information presented in this video is wrong. The claim that you can only observe NMR signals from spin-1/2 nuclei is especially agregious.
7.26🤣🤣14 is odd number???😬
@shindekrushna8170
Жыл бұрын
It is about number of neutrons bro, i.e. 7 and this is odd.
@SouvikNagYT
Жыл бұрын
You dumb, sir is talking about neutron number which is odd
@dranjups8911
Жыл бұрын
It's based on number of protons and neutrons, it's odd in number...
@ranaalimudassar5859
Жыл бұрын
😂😂
@pradeepbhakar6029
22 сағат бұрын
Individually the number of protons are 7 and neutron is also 7 therefore these both are odd
Thank you very much sir
@egpat
3 жыл бұрын
You are welcome.