Monty Hall Problem | Goat or Car behind a door
Ғылым және технология
#monty #Car #goat #montyhall
The Monty Hall problem
In this video, we're going to solve the Mind-Bending Monty Hall Problem: Car or Goat Behind 3 Doors?. This classic game has been debated by mathematicians for years, and is still a mystery to many.
In this video, we'll use probability theory to figure out which option is the most likely. By the end of the video, you'll understand the principles behind the Monty Hall Problem and be able to solve it yourself!
The Monty Hall Problem has captivated minds and sparked debate, but is it true? Is it correct? In this in-depth video, we thoroughly explain the Monty Hall Problem, providing clarity and insights. Discover the answer and gain a solid understanding of this fascinating problem. We explore the statistics, mechanics, and solutions, ensuring you grasp the concepts. Learn how to simulate and understand the Monty Hall Problem, and even how to play the Monty Hall game yourself. Our explanations provide both simple and comprehensive insights, demystifying this puzzling dilemma. We also delve into the history of the Monty Hall Problem and its creator, Monty Hall. Uncover the reasons why the Monty Hall Problem is not a 50/50 scenario and why switching doors is the optimal strategy. Join us as we unravel the confusing elements and shed light on the conditional probability involved. Watch now to gain a complete understanding of the Monty Hall Problem, its solutions, and why the odds favor switching doors.
Пікірлер: 4
Tell us more about the goats, please ...
This is yet another video trying to support a specious argument on Monty Hall problem. The following scenario exposes the flaws easily. Suppose we have two contestants appearing at the same time and they choose a separate door. For clarity we keep the car in door A and contestant number one chose door A, as presented in the video, and contestant number two chose door B. As the host opened door C and offered them to switch doors, contestant number one always kept the same door but contestant number two always switched from door B to door A. At this point they both chose door A and consequently should have the same probability of winning, contradicting the popular belief. Another example is that suppose both contestants switched doors consistently, in effect trading place. The question is who has more advantage? The answer is any door cannot have a one third probability for the keep door player and have a two third probability for the switch door player at THE SAME TIME.
@thethinkingman-
Ай бұрын
its not a special arguement! there is only ONE contestant! NOT 2! get a Brian!
The situation is that "decision without results" and "choice with actual benefits" are confused and regarded as the same meaning. It is obvious that the decision has been made, but the rule is changed from one of three to two, and it misleads you into thinking that you have already made a choice. , but the fact is that you don’t get any of the so-called choices. In order to prove how smart and knowledgeable you are when you finally make the choice, of course there are only two choices, but you have to treat them as 2/3. What a Goebbels effect. Verification. If scholars and the education community have not corrected the problems derived from the Monty Hall problem and still believe that 2/3 is correct, what is the meaning of educational scholarship? It will be destroyed.