Molar Mass From Osmotic Pressure - Molarity & Van't Hoff Factor - Chemistry Problems

This chemistry video tutorial explains how to calculate the molar mass from osmotic pressure. Given the osmotic pressure and the van't hoff factor, you need to calculate the molarity of the solution which can help you to determine the number of moles of solute in the solution if you know the volume of the solution. The molar mass is the ration between the mass in grams and number of moles of solute.
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Molarity, Molality, Density, & Mass %:
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Normality & Equivalent Weight:
• How To Calculate Norma...
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PPM and PPB Concentrations:
• Parts Per Million (ppm...
How To Convert PPM to Molarity:
• How To Convert PPM to ...
Enthalpy of Solution & Hydration:
• Enthalpy of Solution, ...
Solubility Vs Concentration:
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Solubility Curves:
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Henry's Law & Gas Solubility:
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Vapor Pressure & Clausius Equation:
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Raoult's Law - Vapor Pressure:
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Chemical Kinetics Initial Rate Method:
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Пікірлер: 38

  • @TheOrganicChemistryTutor
    @TheOrganicChemistryTutor Жыл бұрын

    Chemistry PDF Worksheets: www.video-tutor.net/chemistry-basic-introduction.html Full-Length Videos & Exams: www.patreon.com/MathScienceTutor/collections Next Video: kzread.info/dash/bejne/oZxorpSgk6yblNY.html

  • @bob34258
    @bob342584 жыл бұрын

    How much does this guy know honestly? He has playlists for various subjects! I wonder if I honestly will ever be as smart as he is now.

  • @swizinSims
    @swizinSims4 жыл бұрын

    I like how he always does his videos always assuming the learner is a beginner

  • @kellybarzykowska6500

    @kellybarzykowska6500

    Жыл бұрын

    FCC he C C C C

  • @retiredmeme2751
    @retiredmeme27514 жыл бұрын

    always happy to see the infamous black background with the digital writing whenever i look up a topic i need help with, i know im in good hands

  • @user-ox1kc7ih5c
    @user-ox1kc7ih5c10 ай бұрын

    This was an amazing video and allowed me to help my daughter with some of her chem2 homework. Love math, especially when it is explained so well. Thanks again. Life saver.

  • @indiraesquivel-chang970
    @indiraesquivel-chang9704 жыл бұрын

    you made it look so easy! I'm glad I found this video. It helped me with my homework, Thank you very much.

  • @hazimrassam9389
    @hazimrassam93894 жыл бұрын

    just another life saving video

  • @abdullnur7804
    @abdullnur78042 жыл бұрын

    before this video I was 0 and know I am 100% thank u bro god bless you

  • @hoh1113
    @hoh11132 жыл бұрын

    I literally can't thank you enough 😫

  • @berylimani
    @berylimani6 ай бұрын

    Such amazing lesson within 10minutes awesome

  • @KazianGaming
    @KazianGaming4 жыл бұрын

    Thank you so much

  • @jace1601
    @jace16013 жыл бұрын

    Thank you so much.

  • @SeletaPhiri
    @SeletaPhiri3 ай бұрын

    Excellent teacher

  • @AhmedNabil-qo6tz
    @AhmedNabil-qo6tz5 жыл бұрын

    you are great. i want to ask you to make a video about the reverse osmosis

  • @razasyed575
    @razasyed5752 жыл бұрын

    you the man homedog

  • @israeljesuslopez3833
    @israeljesuslopez38332 жыл бұрын

    I think units are in L/mol (Time 4:35) You should divide by one to get proper units (mol/L)

  • @marshapple
    @marshapple4 жыл бұрын

    In another video you made, you did the same exact question but there is a part you did differently here. When you obtained 0.6248M, in the other video, you divided it by the Liters. In here, you multiplied them. How do you know when to do that? Note: I calculate my conversions (g to M, mL to L) separately.

  • @user-mu2kz8bj4i

    @user-mu2kz8bj4i

    2 жыл бұрын

    Hi just in case you are still interested in this, I think the solution from this video is correct, I did a similar mistake as you said in another video, its just because of the wrong interpretation of M=c/v. hope this explanation could help

  • @JbasiBoi
    @JbasiBoi2 жыл бұрын

    Whats the Vant hoff factor of an unknown Polymer? I was given the grams of the polymer, liters of solution, osmotic pressure, and temperature.

  • @jroachannel9268
    @jroachannel9268 Жыл бұрын

    How can you calculate the temperature if the only given is the mass of the solute?

  • @Golden_Crown46
    @Golden_Crown462 жыл бұрын

    One question pls But I saw it in one textbook where the ideal gas constant R was expressed in as 8.314J/mol.k Is that also right?

  • @mistletoeariesthine

    @mistletoeariesthine

    2 жыл бұрын

    It depends on what you're calculating. They are both correct but just be careful with units because if you are calculating atm (atmospheres) then you cannot use that one with Joules.

  • @ssana2000
    @ssana20004 жыл бұрын

    In this video you had taken (I = 1) for NaCl while (I = 3) for MX2.. Will you please explain it clearly.. Secondly is there any instrument to measure Osmotic Pressure. Will you please elabora

  • @soumyajha8744

    @soumyajha8744

    4 жыл бұрын

    i of NaCl is 2

  • @rolakhaled7147
    @rolakhaled71472 жыл бұрын

    why didnt you use the osmotic coefficient in the equation?

  • @bongatojoannemariei.4394
    @bongatojoannemariei.43945 жыл бұрын

    Where did you get 0.08206

  • @rvg_2483

    @rvg_2483

    4 жыл бұрын

    it's the gas constant it is already given

  • @oldGnRrocks1

    @oldGnRrocks1

    4 жыл бұрын

    its r, a constant. r= 0.08206

  • @kamilleromero6061
    @kamilleromero60612 жыл бұрын

    But who was HIS organic chemistry tutor...

  • @tanner74
    @tanner745 ай бұрын

    can you come teach my chemistry lecture

  • @thatguy5358
    @thatguy53584 жыл бұрын

    why don't you distinguish between the M for molarity and the M for molar mass? looks the same. hell the m for mass is hardly distinguishable

  • @savannahgiord

    @savannahgiord

    3 жыл бұрын

    That’s chem for ya

  • @samsrocky

    @samsrocky

    3 жыл бұрын

    You are not alone. Im pretty sure everybody struggles with this at some point

  • @thatguy5358

    @thatguy5358

    3 жыл бұрын

    @@samsrocky i always denoted my Ms differently so that I didn't have to struggle with it, at least on my own piece of paper. you'd *think* this would be standard practice... but it seems chemists are only interested in making things more difficult when possible.