No one is speaking about sir's unique spectacles collection 😂😎🔥

@pradeepsrivastava2376

11 ай бұрын

Yaa

@shaileshs.3177

11 ай бұрын

😂😂

@Sanatani_10889

11 ай бұрын

Ghar ka store hai glasses ka🤫🤫

@alien3200

4 ай бұрын

Sir ka papa lenskart mai kaam karta tha

@lakshyadhimanld027

3 ай бұрын

Because we are serious jee aspirants

Question about which sir is talking about is of [JEE Advanced 2013 Paper 2 Question 44] ( i.e; Question 4 of Mathematics section) Q) f(x) = 2|x| + |x+2| - |lx+2l - 2lxl| has a local minimum or local maximum at x= (a)-2 (b)+2 (c)-2/3 (d)+2/3

@mainaksarkar4469

11 ай бұрын

Code 0 Q42 Code 3 Q48

@apurvajha1917

11 ай бұрын

+2 aayga answer graph se bnaaye toh pta chala ki 2|x|+|x+2| aaur ||x+2| -|2x|| ka graph coincide krega at all real values of x .

@groovygames4313

11 ай бұрын

@@apurvajha1917 mera graph se minimum -2 aur maximum -2/3 aa rha

@apurvajha1917

11 ай бұрын

My bad

Just for all JEE aspirants reference, I used to wonder how does that trick works in my JEE days for ploting such functions, just by marking values at critical points. It is because no matter how the mod opens for different mods the nature of the whole function will either remain linear or constant ( as with only sign difference we cant produce x power terms ) so simply we mark values at critical point and make the graph linear. PS: even tho the LHS is linear nature and RHS is linear nature but we still get 2 solutions which is like mod eq can store multiple solutions in a linear nature, unlike polynomials(eg.quadratic) they store 2 solutions but their nature of equation is different. In short mod equations are collection of solutions of different/indifferent linear equations. I hope this gave a new perspective to your view of mod equations

GOOD COLLECTION OF BOTH SPECTACLES AND QUESTION

Aman Sir, what are your opinions about solving the Black Book for maths.Many say that, as it is written by Indian author(Vikas Gupta sir), and apt for jee advance. I am currently in class 11th.

@UnstoppableAmit

11 ай бұрын

Bro solve only 44 years jee advanced pyq with coaching material two to three times is much better than opting for any other book 📚....

@shoumiksadhukhan4621

11 ай бұрын

Sir how can we solve this by making case

@QueenDivya43

11 ай бұрын

Bro am also in class 11 and I am also solving black book it is very good book when I completed 1 chapter from it I Sol jee ad pyq I solved many of them

@QueenDivya43

11 ай бұрын

It nice book for jee ad all topers say that

Sir really I solve question without watching video within 15 -35 min.and find the answer But sir when I watch video then I learn graphical method that is too much. Love you and loving your methods.❤❤❤❤

Pranam guru ji❣️

Very nice method sir ❤️

Wao sir " U are great " ❤

Sir you are great mathematician. Your concept and your approach is very beautiful ❤️ sir

My interest in maths to know more depth is increasing day by day and my addiction for maths is also increasing

Awesome sir

On 22 July ,you uploaded a vedio in which you solved bansal sir question but you devide the equation by 'x' but x may be 0 . You can't Devide by x until it is confirmed that x can't be 0 , Sir my question is that how do you know that x can't be zero And I am watching your vedios since last year , your questions are nice love you

@duryodhan903

11 ай бұрын

Videolink?

@Qwerty25414

11 ай бұрын

@@duryodhan903 kzread.info/dash/bejne/nKGKuq5-lteyfrA.html

Sir please make a video for classification of numbers 🙏🙏🙏

Love you sir

Pranaam Sir❤️🙏

Sir plz batado konse year ka hai wo wala iit ka , solve karta phir

Sir please solve. Sinx+Cosx=tanx find the all possible value of 'x'

wese yeh lamba method hai, because left hand side jo points hain wo hain -1,0,1,2 equidistant so right most if it is leaving line at x=2 no need to check it will cross again at x=-2 (if last flip occurs after -2) so need not to plot others

which board are you using??

Nice

Sir aapne point functions ko continuous bola hai lekin ncert unko continuous nahi manti toh jee ke liye use continuous maane ya nahi???????

Just came from the movie and sir uploaded this video 😂😂

Great sir

Lots of love ❣️ sir , now I am in IIT ISM Dhanbad ❤

@aashishkumar9658

11 ай бұрын

Bhaiya jalao mtt😢

Sir peheli baar me hogaya dono triko se 😀

JEE ADVANCED 2013 multiple. Modulus question also same approach se ho jayega

Sir please 🥺 aik video chahiye about strategy to solve math questions by self .sir bohot dikkat aati hai .who wants this video from Aman sir please like 👍

maan gaye sir app ho actually BHANNAT 🙏🙏🙏🙏🙏

I will rise soon

@growth7143

11 ай бұрын

No need to rise just beat yourself

@advaymayank1410

11 ай бұрын

😬😬😬😬

@Naman_JEE25

11 ай бұрын

Me too And best of luck

@aniasprelltinerosdez333

11 ай бұрын

"I will rise soon"🤓🤡

@alien3200

11 ай бұрын

​@@advaymayank1410👍🏼👍🏼

At the Beginning, what's the background music name ??

legend ho sir

how to solve it algebrically?

Sir maine aise hi kiya tha

Bahut badhiya solution hain aapka. Aapke solution koh optimize kiya jaa sakta hain, x+2 koh bhi LHS mein lagaa loh, RHS koh bana doh zero. Phir graph draw karna, aur roots (X-axis crossings) honge solutions.

Sir agr hmne is question ko cases se solve kiya to bhi to solve hota hai vo glt method hai?

Just because of you sir I am able to develop the critical thinking in maths.....thank you sir so much..... Coming to this video....I solved this in 1st attempt

Sir mujhe bhi Bansal sir ke problems and solutions dekhne hai Mai kaha se dekh sakta hu

My jee journey is over (is in iiitA ) but still watching your content ❤️

Really great method...You are great sir jee ❤

Koi advanced wala question batayega??

mathsmerizing also give the sam solution of this type of questions

Graph se jyada jaldi solution aa aata hai sir ji i understand

Samajne ki koshis kar rahi hu❤

It hits me really hard that why RUSSIA was written at the top of question

I feel like this problem is from prelipko aka problems in mathematics by v govorov

I love the way you teach sir🙇🙇💕

I did same thing . Jee aspirants but took 2 min

But here we need exact sketching know sir but which don't do in general?

Mai yaha thumbnail dekh kar aaya 😂😂😂😂😂😂GADAR

sir aap trigonometric functions ke questions aur concepts ka video bana sakte ho

@gauravaggarwal

11 ай бұрын

kzread.info/dash/bejne/qJVtmtuwp8K-qMY.htmlsi=pM8uosm82OEMi9n_

Tell me sir how to join your paid course

What if there is an enequality in this problem?

Aap kaise h sir

Sir madhyamik mai maths hai aache marks kaise laayn pls Batao

😮😮😮

7:40 sir Waha (-3 ) = | (0) - 1 | × 3 , Hoga answer aapne 3 leke 1 k sath jod diya

My favorite mathematics teacher ---- *Aman sir*

Ye bahut majedaar tha sir👍👍

Sir S L loney k coordiinate geometry book review pls

bhaisahab next level thinking sir jii

Just a normal method for modulus question, so much hyped he has done

@utkarshgoyal7420

3 ай бұрын

yeah either by cases or graph

Sir give some of this type

Jabh yeh plot banaya, toh x + 2 koh bhi LHS le jaasaktay hain aur directly roots hee read kar saktay hain, no?

Hello sir I HAVE A DOUBT 🙌🙌 sir agar hum log 0 with base 2 rakhe to output kya aana chayiye?🙋‍♂️🙋‍♂️🙋‍♂️🙋‍♂️🙋‍♂️🙋‍♂️

@keshavchoudhary3976

11 ай бұрын

-(♾️)

@sankalpsharma594

11 ай бұрын

@@keshavchoudhary3976 🤝🤝

My favourite teacher is ashish agrawal ❤❤❤ and you too

@ShubhamSingh-we8hv

11 ай бұрын

Ashish Aggarwal sir ❤❤❤ Ne bhi aise method sikhaya hai

Sir #karan_Sangwan sir ke bare mein kuchh boliye

Sir aapko kitne mile hai jee advanced mei phir jab aap try karte ho

Indirectly cases toh bna rhe?

@itishreepanda1641

11 ай бұрын

Sahi kaha bhai wo chiz karke gadar bolte hai

-2 without seen solution

sir graph me aapne origin alag alag liya hai,jaise f(x) = x + 2 ke liye aapne graph ko (2,4) se start kiya hai,aise hi f(x) = -(x+2) ke liye aapne graph (-1,-1) se start kiya hai,sir ye to galat hai kyuki sabhi graph ka starting point or refernce point aapne ek rule ke hisab se nhi liya.Sahi to tab hoga jab f(x) = x+2 ko aap (0,2)se shuru kroge.Kindly clear my doubt

Sir plz solve this problem X^5+x+1=0 Then x^3-x^2=?

@gauravaggarwal

11 ай бұрын

if x^a + x^b + x^c given such that out of a,b,c one is of the form 3k, one is 3k+1, one is 3k-1 then that polynomial is divisible by (x^2+x+1) so 5 = 3*2-1, and other exponents are alraedy 0,1 so perfct triplet so just divide it by x^2+x+1 you will get x^3-x^2+1 so answer is -1

Hi sir

sameer sir taught this in class

Good evening, sir, I am currently a student of grade 10. I just thought of this way to solve the question. Kindly check this and let me know if this solution has any problem. Take 2 cases 1) x greater than or equal to 2. For this |x+a| = x+a where a belongs to real numbers and |x| > |a| -----{Since x is positive} {Here |x| can also be equal to |a|} => x + 1 - x + 3x - 3 -2x + 4 = x+2 => 2=2 Hence for all values of x greater than or equal to 2, the equation is satisfied --------- {We have not taken below 2 because we need |x| > |a| or are equal} 2) x less than -2 We have taken x less than -2 because, |x+a| can be written as |x| - |a| for all |x| > |a| and 'a' being positive. ------{Hence |x| must have been greater than 2} {Since we have taken all positive values, x must be less than 2} Similarly, |x-a| can be written as |x| + |a| for all |x| > |a| and 'a' being positive. Using these, |x+1| - |x| + 3|x-1| - 2|x-2| = x+2 => |x| -1 -|x| + 3|x| + 3 -2|x| -4 = x+2 => |x| - x = 4 => Either x-x = 4 OR -x-x = 4 Discarding 0 = 4, -2x = 4 => x= (-2) HENCE ONLY ONE POSSIBILITY FOR x Therefore, x belongs to {-2} U [2, infinity) Kindly confirm this approach to the solution. Thank you!

@ayushrana124

11 ай бұрын

Correct ❤❤

Sir parnam

Acha laga khud krke

Not first but fast

My exponential graph has crossed x=1 now it's about time

@rudranilmukherjee3798

11 ай бұрын

What

@abeersharma9487

11 ай бұрын

@@rudranilmukherjee3798 value of exponential graph increases rapidly after x=1 and also value is >1

@rudranilmukherjee3798

11 ай бұрын

@@abeersharma9487 but what do you mean by " my exponential graph has crossed x=1 now it's about time. "

@abeersharma9487

11 ай бұрын

@@rudranilmukherjee3798 that means I have improved enough to score enough to clear cutoff for jee advance now I am improving so that i can clear iit as well

Sir in the case 0

@ashgreninja5699

11 ай бұрын

X 0 se 1 liye ho toh ans x =-1 aa rh Tumne toh x ko (0,1) liya n toh usme -1 ni aata toh nhi hoga woh

@duryodhan903

11 ай бұрын

Bro u are contradicting yourself. First you are saying case 0

@trulysatyam8231

11 ай бұрын

Thanks bro😄👍

@YuezhiTribe

11 ай бұрын

Bhai vo sol (x= -1)tumhari uper mentioned condition (0

@dangerzone3200

11 ай бұрын

Imaginary

i solved it graphically without even seeing the solution

Bari hea

Sir ap JEE Advanced 2023 ke maths ke Solutions ki Video bna dijiye . Apke Solutions bohot acche hote ha ❤❤🙏🙏

I solved it I don't believe

Hii 🥰🥰🥰🥰

First like and first comment ❤

Mod ke andar linear and quadratic donon a gai to

@user-tp2qh5zn7m

11 ай бұрын

FIR kya karenge sir

@SaifKhan-mf4ho

11 ай бұрын

Quadratic ke factors karke use linear me convert aur phir wavy curve apply karna

I will bounce back

First view sir ji

Sir I want to join your paid course

@Ajeetkumar-zp6uy

11 ай бұрын

How to join your paid course sir ?

We indians always love Russians 🌚

@MixbOOsted

11 ай бұрын

stop it.... atleast here🤡

@YuezhiTribe

11 ай бұрын

Irodov🗿

@Enchantedquillx2

11 ай бұрын

6k

@BelieveConfident

11 ай бұрын

​@@YuezhiTribe haha

@AvikGupta-ch7oh

10 ай бұрын

🤡🙂

Sir this method cannot be applicable for all questions See this question |x-3| +|2x-3| = 3|x-2| try this question u cannot solve this by graph method

Sir mera solution to x = -1 and x ≥ 2 aa rha hai.... Maine galat kiya hai kya?

@advarbindkumar5791

11 ай бұрын

Obviously

@roar-and-rattle

11 ай бұрын

@@advarbindkumar5791 galat hai?

@advarbindkumar5791

11 ай бұрын

@@roar-and-rattle ha galat hai

@roar-and-rattle

11 ай бұрын

​@@advarbindkumar5791aapne Kiya?

I bet you can't factor this : x^2-2(p+q)x-pq(p-2)(q-2)

@gauravaggarwal

11 ай бұрын

bet accepted (x-2p -2q -pq)(x+pq)=4pq

@gauravaggarwal

11 ай бұрын

How i factorized suppose p,q are roots of t^2 -at+b =0 then (p-2),(q-2) will be roots of z^2 - (a-4)z + (2a+b+4) = 0 so (p-2)(q-2) = 2a+b+4 your equation can be rewritten as x^2 -2ax -b(2a+b+4) = (x-a)^2 - (a+b)^2 -4b =(x-2a-b)(x+b) -4b = (x-2p-2q-pq)(x+pq)-4pq

@bijayanandamahata464

11 ай бұрын

Yeah thanks

@bijayanandamahata464

11 ай бұрын

But the answer is : (x-pq-2p)(x+pq-2q)

@gauravaggarwal

11 ай бұрын

@@bijayanandamahata464 hey buddy answer nahi batana tha , could have denied only

Sir i have more better approach

@Mohitsaini-fb5dw

11 ай бұрын

In less than 50s i have done

@Mohitsaini-fb5dw

11 ай бұрын

Plz reply

@Giles_corey_

11 ай бұрын

Can you tell?

Sir aapne point functions ko continuous bola hai lekin ncert unko continuous nahi manti toh jee ke liye use continuous maane ya nahi????????

@An_ony_mous

11 ай бұрын

Discontinuous. Always prefer NCERT because even IIT strongly recommends it. I know it's not good for the prep but follow it strictly.

@An_ony_mous

11 ай бұрын

It is actually continuous because the graph dosent break.

Sir aapne point functions ko continuous bola hai lekin ncert unko continuous nahi manti toh jee ke liye use continuous maane ya nahi??????

@BHANNATMATHS

11 ай бұрын

Khaan Bola ??

@neilvincent

11 ай бұрын

@@BHANNATMATHS sir aapki continuity wali playlist me ek video hai continuity of point functions usme bola hai aapne.

@neilvincent

11 ай бұрын

​@@BHANNATMATHSsir aapne continuity of point function me bola tha please reply