Watch the video about which Ashish sir mentioned in above video - kzread.info/dash/bejne/pqCBtJOMlra-e9I.html For Application based resources & NCERT Case studies for JEE & NEET join PG Telegram - t.me/physicsgalaxyworld Best online courses on JEE & NEET, download Physics Galaxy mobile app. Download link : bit.ly/PhysicsGalaxyApp Best book of chapterwise PYQs of JEE Advanced with detailed comprehensive solutions. Check at : amzn.to/3ZXotZs Best Books for JEE Advanced Preparation - Bestseller book of 700+ advance illustrations. Check at - amzn.to/3qyIK8H

@neerajkabirsharma

Жыл бұрын

I got 96%percentile just by revision checklist+ onion physics+ pyq you are my hero sir❤

@Samarth12334

Жыл бұрын

Your content useful for us sir ❤❤

@user-mu8qr8qz6u

Жыл бұрын

Sir kya advanced illustration and jee advanced book ka new revised edition aayega😢

@BilluSainda

Жыл бұрын

Sir questions nhi hore jo aapne end me diye 3d relative boht weak hai rain man 3d me bhi fas jaata hoo

@umasharma7890

Жыл бұрын

Sir o3 will see projectile

Sir please continue this series , it's extremely helpful

@Yourdemand-hw1sv

Жыл бұрын

Yes....

@pushpachaurasiya3032

Жыл бұрын

@@Yourdemand-hw1sv Yes

@atifbasar8287

Жыл бұрын

absolutely

@anuragmishra5711

11 ай бұрын

Ok

Tan-1(VP/VT2) IS THE ANGLE AT WHICH O3 WILL OBSERVE OBSERVER O2 CATCHING THE PACKET Angle of projection of packet wrt to o3 Tan-1(vb/vT2)

Yes sir we want this type of lecture...it very much help us❤❤❤

Sir please continue this series , its extremely helpful

Sir 🙏 Your class 11 onion physics series is very helpful in my overall understanding, combo of onion physics series along with PG 5 book series buildup my physics from base level to extraordinary level... Sir as i was 24 jee aspirant i request u to continue onion physics series so that my another half portion can also be built up at an extraordinary level 🙏🙏🙏

@afsari1396

Жыл бұрын

Bhai what is combo of onion physics series and PG 5 Book series ,can u plz share the link

Thank you so much sir May you plz continue this series of questions on KZread It really helps us to understand and apply the concepts.

Sir, When you initially posted this TBT 3 (7 Months back), I have solved and Derived some Questions from It like *"What should Be the Range of velocity of ballon So that An Observer at train of length L will be Able to Catch it"* But I never Thought about the Angle of Fall of The packet and Crossroad Situation as you mentioned in the video. Really sir Even Today this question is Helping me evolving My brain and thinking about new cases for This TBT. Thank You sir for these TBT's❤

Sir i have derived one question that if a person in balloon drop two balls at an interval of t sec and if in the train there are two persons sitting at some seperation and train is moving with some velocity then what will be the separation between both persons so that they both will catch the ball .❤

@surendragodara1530

Жыл бұрын

The separation is ( Velocity of train)x(t)

@AmanMaurya-lo8hw

2 ай бұрын

Sepration=velocity of train * time interval

@SayantanPaul35

18 күн бұрын

Iska solution bhi koi boldo

@sayantanpaul4430

7 күн бұрын

@SayantanPaul35 HELLO

@sayantanpaul4430

7 күн бұрын

@SayantanPaul35 HELLO

(6:50 )Road ko parpendicular karne par same approach se banana padega bas ye projectile motion y z axis me hoga.

@Homo_Sapien_earth

Жыл бұрын

Same I also think so

A military bomber is going upward with velocity v1 and horizontal velocity v2 . It threw and bomb aiming at the jet by an angle theta downward from horizontal . If the intercepter was flying below head to head with velocity 3v2 only in horizontal direction , the jet wants to strike down the missile by air to air missile so at what angle from horizontal The pilot should fire such the the the bomb get intercepted at the middle of it's flight?

Hi Ashish sir, 50yr old phy. Enthusiast here. Still listens to ur channel. Keep the good work on.

Sir can you please explain how step pulley works??? It is mentioned in the physics galaxy book but I'm unable to understand😢😢

Thank you so much sir ....keep making such videos❤

Sir please make video for last 6 months for jee 2024 . Complete ✅

Great series sir, very insightful

Sar before I am not able to think about multiple ways of these questions can be created and also not able to theta will be relative or velocity will be relative with respect to O1 changes. but now i am able to think who we create a a question in a multiple way. Thnak you so much sir

thank you sir for this amazing video 👏👏

Sir uska angle of projection to tin axes k according aaega na Aur angle of catching same hoga kyoki o2 ki aur packet ki o3 wale axis pe koi velocity ni hai

Sir wanna this series to be continued 😍

Concept that should be applied in o3 odserver is same as that of o2 observer

Sir, Maine kuchh similar type ki situations banayi aur derived thinking ko evolve karne ka try Kiya but question banane aur usko solve karne ke bad kaise check Karen ke ans right hai ya wrong? I am unable to find my knowledge Gap. Pls help.

How does the ball appear to the person if the person travels on train toward the path of the falling ball from front side.

Extremely helpful for us sir❤❤❤

Yes sir I do like these type of videos

V3 bhi V2 ki tarah dekhe ga lekin alag direction me Angle v3 dekhega v2 ka same lekin v2 ki jagah v3 kardena

Sir please continue this series

o3 ka observation bhi o1 jaisa hi hoga am i right sir ??

Additional Questions: We have a another train moving perpendicular(T2) to the plane of board with observer O3 and the speed of train is Vt 2(assuming this Vt2 is given wrt ground) Let the Board be x-y axis and z axis perpendicular to it a)What would be the angle of projection of the ball thrown from the balloon(let the ball be B) moving with velocity Vb j cap wrt ground as seen by O3? Solution: The motion of B wrt T2 would be a projectile thrown from a height thrown at an angle, the angle of projection would be tan inverse(Vb/Vt) b)What would be speed of O1 wrt O3? Solution: The object O1 is moving with velocity -Vt i cap and O3 is moving with -Vt2 k cap, so if we see velocity of O1 wrt O3, just it's component gets added, so speed would be under root( (vt2)^2 + (vt)^2 ), c)With what angle O3 will see O2 catch B? Solution: Wrt O3, The final magnitude y component of B's velocity would be under root(vb^2 +2gh), for the magnitude of z component it would be the speed at which the T2 is moving that is Vt2. Hence angle would be tan inverse ( root(vb^2 +2gh)/Vt2). d)Equation of trajectory of B wrt O3? (z, y axis) Solution: Position of B in the y axis is given by (Vb)t-0.5gt^2, in Z axis is given by z=-(vt2)t where t is time, by combining these two equations we have, y=[((Vb)(-z))/(Vt2)]-0.5g[((z))/(Vt2))]^2 which is the equation of trajectory.

@arpshorts4878

Жыл бұрын

Noice❤

@vaishnavisingh6654

Жыл бұрын

I think the the velocity of ball with respect to O3 will be +Vt2 k cap since O3 is moving towards -k cap so it's opposite component in +k cap will be added to the ball so z= Vt2t ? Pls. Correct if I'm wrong !!?

@Raj_vansh_singh

Жыл бұрын

@@vaishnavisingh6654 Hello, Thanks for the input, here i have assumed the axis which is going into the plane as z, the train going into the board moving towards the +ve Z axis, I have taken this assumption because if you change your frame of reference to the right hand side that is, if you look at the whole scene from right hand side, you will see the train going from left to right. It is kind of hard to imagine but, yes this is what i thought. your answer is correct as well if we look at the train from the left hand side where the train moves from right to left. its all about perspective

Thanks sir ❤😊...

Sir i can see only 67 video of onion physics in physics galaxy mobile app where i can get access for newly uploaded weekly videos??

Yes sir please continue this series🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻

You're great sir ❤️

excellent series sir 🙏

Sir please also start sme series for chemistry as it is also common subject for engineering batch and medical batch students

Continue this series sir ❤

extremely nice video by ashish sir

If the train is coming with the velocity Vc then he will se the packet in projectile towards himself with an angle of tan inverse Vc/Vb

Sir, isme v(T) ki condition nikal ne padegi na ki osko kitne velocity se move kr na chaiye to catch the packet.

Sir where can I find Dpyqs sir

Sir kya advanced illustration and jee advanced book ka new revised edition aayega😢

Sir i am dropper student aisi hi video laiye bhut faydemnd h ❤❤🙏🙏

@bhaveshanand6138

Жыл бұрын

Good bro

Sir I have derived a question on this situation....... Suppose the person in the ballon drop two balls at an interval of time t from ballon...........a person in a moving train observe the projectile motion of the two balls ........according to the person in train, will the two balls meet at common point or not? Give answer with explanation

@Raj_vansh_singh

Жыл бұрын

I dont think they will meet, here is the explanation according to me, the deciding factor for the two balls to meet would be the y component as the x component would be same for all wrt to that person in the train considering the train is moving with same velocity. Let the velocity of baloon here be u, and time after which the 2nd ball has been launched be t. lets look at motion in the y axis, first thing to note is that after t seconds the ballon would have moved u*t upwards from the launch of the first ball, on top of that the first ball would have moved ut-0.5gt^2, and the velocity of the ball at this instant would be u-gt. and also at this instant the 2nd ball is launched which with velocity u upwards, so the distance between the two balls would be, distance travelled by baloon in t seconds - distance travelled by the ball= ut-(ut-0.5gt^2)=0.5gt^2. Now lets look at their velocities for the first ball it was u-gt and for the second it will be u, now it is clear that as velocity of first ball is less than the second, so both will not meet.

@RaghavAnand-ik8qe

Жыл бұрын

@@Raj_vansh_singh i think it has two answer....both can meet or cant because when the first ball going up...when second ball is launched when first ball is going upward...then there a chance they xan meet

@Raj_vansh_singh

Жыл бұрын

@@RaghavAnand-ik8qe i was thinking the same before, but as i explained in my other reply, the velocity of the second ball is greater than the first ball, and their relative accelerations will be zero and if you see the velocity with respect to the second ball, the velocity of the first ball will be -gt that is gt in downwards direction. so what the second ball will see would be just the first ball going down with gt speed. and they will just never meet

Great value

Sir what are ur views on the marks of thr neet students. Like many people on the internet are criticizing the nta for such easy paper and 100% marks in neet as if it is a cbse baord exam. Many are demanding for better level paper in neet as compared to the previous ones. Do u think that the standard of the exam is getting worse or its the hardwork of the students and their study level that they are getting such high marks. Plz share ur views on the result of neet 2023 and questions level and cutoff.

Sir I want kinematics 1Dand2D from basic’s videos

Sir neet ki pyq book ka latest edition kab aayega please reply ❤

Honestly maine socha nahi Air Friction .. Ek doubt bhi hain Air friction viscosity ki value same rahegi aur ke liye

Sir it will more helpful if you just make a concept video of every theory brain onwards I know you are busy with your schedule but a 10 min video will be much helpful

@user-brown5911

Жыл бұрын

Agreed

@NTzeB3ST

Жыл бұрын

Yes 😊

Same angle and trajectory will be observed in such a case

sir please make video on carrier option for neet failure🙂

sir I think videos of this kind would be a solution to "the no / bad solution video".

Sir please Speed solution realse kr dijiye.. 🙏🙏 Us se pta chl jata hai ki ek ghante me paper krna kaise h... Precise thinking ki habit Ho jaati hai... Please 🥺🥺🥺

Wow

Ist comment and 2nd like ❤ We love you Aashish sir

Onion series kya hai

Nothing just Ashir Sir flexing his drawing skills ...

Sir, I have been creating new questions based on jee advanced syllabus. 61 st question in my notes is same model as tossing coin in JEE ADVANCED. These questions are definitely super different models which you might not seen anywhere. How can I send it to you and how can I use my skill?

@user-kv6cu7hw3k

Жыл бұрын

Through email

@bhargavsai8014

Жыл бұрын

Well even if that question was a new type of model,it was indeed an extremely easy question Also in many coachings,teachers usually pick questions not by analysing past year papers,but from many different sources,including books,papers and also from olympiads

@lavanyaappala4474

Жыл бұрын

@@bhargavsai8014 no definitely hard question

Ye question shi tha mera 😊

(At 90 degree) the observer traveling perpendicular road If i am not wrong 😊

Onion physics for thermodynamics and for class 12

observer v3 will se it as projectile going away from him in north west direct with speed {(vb^2 +vt^2 +vt2^2)}^1/2 , unable to be concrete enough on angle . correct me if i am wrong

@the_guy_crimson

Жыл бұрын

North West ??? Bro this is 3d projectile not 2D u can't express it in N S E W !

@buck8922

Жыл бұрын

​@@the_guy_crimson ya

@bobbyanand5608

Жыл бұрын

@@the_guy_crimson it is a 2d projectile wrt to observer 3.....and angle is not 3d it's 2d.......Vnet^2=Vb^2+V3^2 Angle = tan -1(Vb/V3) I think

O3 will be discussed as same as 02

Sir, i would meet you one day.

Im a neet student .. but these are really mind groggling ❤❤

@creativebonding

Жыл бұрын

Don't come to advanced level to waste ur time 😊😊

@8BitGamerYT1

Жыл бұрын

@@creativebonding Yes exactly, it's of no use. (Even if you are scoring above 700)

@juliuscaesar564

Жыл бұрын

​@@creativebondingit could be he has interest in phyiscs that's why

@adityarajsharma6029

Жыл бұрын

@@creativebonding but what if he has curiosity sir already told that this is jee main and neet level in the starting og the question so don't be so immature to tell what others should do

@xeesoxee2

Жыл бұрын

​@@8BitGamerYT1 the one scoring above 700 can solve jee adv questions within 2 minutes they have extra ordinary speed

Sir op ❤

you said that 64% marked the wrong, but they marked the right since the person in the train was correct.

Thanks sir

Hello sir...please make a video for aspirants who have wasted their class 11th

@pokeshorts9333

Жыл бұрын

Bhai class 11 th mostly sabki waste kyu hoti hai🤔?(ps:-i have just entered 11th)

In this question of situation are same except train is in circular motion what is the motion of the stone w.r.t the observer in the train.

@bondingwithknowledgebwk1848

Жыл бұрын

Sir please reply my question

By practicing these brain teasers theoretical problems will become easy

Sir is this theories is beneficial for class 11 students

@physicsgalaxyworld

Жыл бұрын

yes very much !

@marianne-wt8it

Жыл бұрын

Yup

@Shreyas_Jaiswal

Жыл бұрын

Projectile is in class 11 only.

o3 will see this being caught at angle 90-alpha

I think o3 observer see backward projectile

Kon kon sirf Ashish sir ko dekhne aate hai Advanced ho Jane ke baad??

@user-sp2do3wl7u

2 күн бұрын

koi nahi

Sir aap itni speed se kaise bol lete ho

@pareshborase4414

Жыл бұрын

He teaching same from decades...

@sampritdatta1752

Жыл бұрын

He recorded a 14 mins video and edited it to 2x

@realavdhut

Жыл бұрын

I am watching at 2x still feeling slow how in the world at 1x you feel sir's speed is fast

@legendarymathematician

Жыл бұрын

He is one the most legendary teacher of physics in India , he was considered god when I used to teach in institute students dreamed in getting the batch in which he used to taught

@rupeshsaini2344

Жыл бұрын

@@sampritdatta1752 no you can see his hand movements they are actually in normal speed

Thanks sir ♥️