Thanks a lot!!! Literally saved me.

Very well understood sir .. thanks 🙏🏻

Thanks for the excellent job. My question is on the formula to apply in conducting Median test for single small sample size

Dear Sir. thank you very much for your excellent video. I have a remark on your probability computation in the exercise min.13:30. You have computed the probability of the single outcome table. Unless I'm mistaken you should sum the probabilities of the more extreme cases, that is to say the cases in which sample B has 1 and 0 items above or equal the median. Furthermore for a two sided test one should add also the probability of the other tail, that in my opinion corresponds to the cases in which sample B has 5 and 6 items items above or equal the median (that correspond to sample A having 2 and 1 items below the median). So notwithstanding the conclusion of the test is the same, the probability of the test is 0.001 + 0.033 + 0.196 + 0.078 + 0.005 = 0.315. This probability is bigger than 0.1958 reported in the conclusion. Given that I'm not totally sure of my statements I look forward for your kind reply

Hi, can you explain more about the degree of freedom used in calculating the critical value? I still don't understand why it is 1 instead of 2.

Hlo sir I don't understand how you get calculate the probability calculation that bracket one 13:13 13:13

Sir agr aap pdf b provide krte ...

Hello sir aapne yh jo non parematric test or probability distrbution karwya hai bahut acha padya h bt sir please inke liye hindi ki book batao na please

Thank you

@DrHarishGarg

2 жыл бұрын

Most welcome always.

Tqq so much sir.... An extraordinary teaching.....tqq sir

@DrHarishGarg

10 ай бұрын

Many thanks for the comment.... I respect