Graduated from Tech 7 years ago and needed a refresher on double and single shear. Glad to see you are still an awesome instructor!!

As a retired PE that still enjoys learning, this is where I come to get refreshed. Thank you Dr..

@kevcopo

5 ай бұрын

you retired potential energy? I guess you're always on the move huh

@PolyStylized

5 ай бұрын

@@kevcopo bruvv this killed me 🤣🤣

@kevcopo

5 ай бұрын

@@PolyStylized this was the lamest comment I’ve ever made but I appreciate the love 😭😂

This man is the GOAT for mechanics courses... thank you for your service sir.

That was really great. My prof explained it in an hour and I didnt understand a single piece of it. Not until this man came up. Thumbs up for you sir👍

I think after reading other comments now I undrestand why we are using resultant force instead of the Ax. The pin itself is perpendicular to the whole plane (you can imagine it sticking out of board) So because this pin is perpendicular to all other elements and the board (the plane which all elements are on it) the both Ay and Ax are perpendicular to pin and considered shear force.

@mitchell6973

2 жыл бұрын

It looked to me that Ay should have been the one used. I am not sure why he is using the resultant either as the components seemingly act on different areas.

@640everett

2 жыл бұрын

@@mitchell6973 The shear force would be the resultant because the pin is oriented with the end facing you. This means the normal force would be directed either into or out of the board.

@raymondtrann

Жыл бұрын

Adding some further clarification. Background: our previous understanding of shear, is based on a *2D* diagram of a beam, with the shear force perpendicular to the longitudinal axis of the beam. For example we have the beam extending along the x axis, and thus the shear force extends along the y axis. In this problem: - Support A has support forces along x and y - Pin at A is oriented along z, with its faces/cross sections in the xy plane - The diagram in the example is a 2D depiction of an 3D structure (recall the pin has a longitudinal axis in the z-direction) Now, recall the shear force is perpendicular to the longitudinal axis. Since we have a 3D structure here, and the longitudinal axis of the pin is along the z axis, the shear forces on the pin will occur in both the x and y axes (both x and y axes are perpendicular to the z axis). Thus we use the resultant vector, or we can use the individual x and y components, and find the resultant.

@shanthanramsamy7421

Ай бұрын

Thank you so much, I was confused on this same thing

Awesome video, love the fly who’s there for the lesson

Professor Hanson, keep up the amazing work! Your sense of humour is what keeps us engaged! Awesome!

@11:23 The fly also loves your lectures!

Finished Statics and am so excited, and relieved, to see that you have a whole Solids and thermodynamics video set! You are a wonderful teacher. Thank you so much for your work in helping us all!

@danielpaul460

2 жыл бұрын

What major are u taking?

Good sir, I am currently attending NDSU and have an absolutely horrible professor for mechanics of materials (the name of this course at NDSU). He doesn't explain everything, simply writes down equations and says (this is verbatim) 'this is so easy, how can you guys not get it just plug numbers into the equations', all while not explaining any of the theory behind anything of why we use each equation or anything. I've a test tomorrow, and I think you're going to be the man who saves me.

How can you teach me something perfectly in 15 minutes that my professor can't explain thoroughly in 55.... why am I paying tuition

@laughtherapey

3 жыл бұрын

Touche dawg. Some guys are just dumb. they can do things but can;t explain shisse.

@thehoiya5280

3 жыл бұрын

i was about to comment the same thing lol

@camerongrabowski7734

3 жыл бұрын

Funny how the internet as a free educational resource that anyone can use is commonly better than 40k a year in tuition...... Makes me wonder how much more educated the world could be if money was never a factor in education.

@jakob.conrad

2 жыл бұрын

@@camerongrabowski7734 Dr. Hansen’s salary is paid by Texas Tech tuition, soooooo

@camerongrabowski7734

2 жыл бұрын

@@jakob.conrad yeah but Texas tech tuition is not paying him to post this video. Edit: I’m guessing here that it’s not specifically for his students could be wrong though.

This was the video that finally made me understood how simple shear stress is

11:20 that bug SHEAR seems STRESSed out !

Sir I cant thank you enough seriously Wishing you all the happiness and good health out there ♡

This channel carried me through the statics part of the class now I'm trusting he'll get me through mechanics, so far so good

@1234jhanson

Жыл бұрын

Best of luck to you this semester!

@rutaremwa69

Жыл бұрын

@@1234jhanson thank you, I really appreciate everything you do!

i'm seeing this show from Brazil. Amazing! Fantastic. Congrat, professor!

video: super helpful, amount of ads: kinda out of pocket but get those bands jeff

Thank god I found this channel, It is a lot better than my professors.

I'll share your vids prof Hanson, you're our hope👍👍

Jeff you're saving my grades right now i love you

All my profs at UT Austin had terrible accents. This is amazing…so clear. Freaking hilarious!

Hello, Thank you for sharing nice videos. I had a question, for calculating shear stress at A & B why are we taking resultant force? Will not be the force working on perpendicular to the cross-section, that mean Ay and Fbc?

Agree! Best professor ever!

Thank you very much, very helpful and funny to watch !

Legend! Best explanation I've heard

Wonderful Lectures ! Thanks.

that " shingle" part kill me hahhahaha, best professor ever

@giftonjalloh9644

3 жыл бұрын

😂

THANK YOU SO MUCH PROFESSOR .LOVE ALL THE WAY FROM PAKISTAN

I jumped back from that interrupting fly

SUCH AFUNNY MAN THANKS MR. JEFF

Thanks so much, professor!!!!!!!!!!!!!

You are truly wonderful!

Greta clases 🎉 Enjoyed yogur videos

Loved it!

God bless you Jeff

love the sound effect at the end lol

Finally, I can understand shear stress

you blow my boring ass teacher outta the water sir. thanks professor hanson.

great help sir

I like your humor mixed lecture

Why are you taking the resultant on A for the shear stress? The x component acts on a different cross sectional area on the internals of the pin vs the y-component.

@howardbaxter2514

2 жыл бұрын

Both are acting across the same cross sectional area. Both are acting across the xz-face.

Thanks prof.

When drawing the FBD of bar AB, why do we neglect drawing the reaction forces on Pin B? Does that mean that we can eliminate drawing reaction forces at a joint if there is another two force member which emerges from that same joint?

thanks from Turkey❤️❤️❤️

Thanks Professor The only thing i'm trying to understand is how you did a sum between normal & shear stress while they are not on the same surface

I'm in Kurdistan in Iraq. You're really good. I didn't understand this subject. You taught me very easily. Thank you very much I used to have a lot of fear of taking the Mechanics of Material exam but you made me do it but now I am looking forward to it thanks

Doctor, thank you for your lectures. I have learned a lot from them. I have one question. Why do we neglect point C I'm not sure if it is pin?

@ShAlAmAnAyA3

3 жыл бұрын

C isn't neglected. It's one end of the two force member F_BC and its value is already calculated.

examples for inclined beam sir pls. im confused in that thanks

Thank you Prof for this video. Although I hae got a question. Shouldn't the Force used in calculating the Shear stress be the shear force and not the resultant force as used in the calculation. Thank you as you dispel my misconception and calrifying imthe resultant force should be used. Thank you sir

thanks

How can you tell that it is a double shear stress or a single stress? Is it given in the question?

11:29 bug

"shingle" what a king

can you explain more on why you used the resultant force at point A and not Ay to get the shear stress

@mitchell6973

2 жыл бұрын

Same problem here.

@fadelity4444

2 жыл бұрын

because the support at A has two components or reactions, Ay and Ax. So, using the resultant force of the two components gives you the more accurate reaction that is applied at support A, therefore, using resultant force to get the shear stress.

@AlbertVathapally

Жыл бұрын

@@fadelity4444 I am still not following. If I was to obtain normal stress, id only use the x component of the force, but for shear why arent we using just y component of the force?

Why did we take the resultant force since for shear stress the force needed that is tangential to the area correct? Im pretty sure the resultant of the forces isn't tangential correct?

@panirys1226

3 жыл бұрын

Because we are calculating shear stress acting on a pin

bu videolar olmasa asla anlayamazdım bu konuyu. gerçekten iyi bir öğretmensiniz emekleriniz için teşekkür ederim. çok sağolun

@yigitcan824

5 ай бұрын

Knk bu adamı dinlemek yeterli oluyor mu geçmede

@harirusamiru2836

5 ай бұрын

@@yigitcan824 dersi geçemedim.

@yigitcan824

5 ай бұрын

@@harirusamiru2836 Umarım bir dahakine geçersin,geçmek için ne yspılmasını önerirsin bu arada

@harirusamiru2836

5 ай бұрын

@@yigitcan824 soruları önce kendim çözmeye çalışarak sonra da izleyerek konuyu net bir şekilde anladım. ama sorun anlamak değil. Hocaların sizi geçirmeyi isteyip istemediğine bağlı.

@biridun9999

Ай бұрын

ben önce bu hocadan izleyip sonra hibblerin kitabındaki soruları çözüyorum ve içinden geçiyorum sınavların. çok havalıyım.

Thanks Prof. I thought at pin A we only include V as it is the perpendicular force.

@x2iseynedir

3 жыл бұрын

Did you understand why is it like that? If you do, can you explain?

@marcosdyonel

3 жыл бұрын

@@x2iseynedir I think, you always need to use the resultant force

@hancar8142

3 жыл бұрын

@@x2iseynedir pin bağlantısında pin, her iki yönde de kesmeye maruz kalıyor. Bu nedenle bileşke kuvveti aldı.

@lucastadesse2678

2 жыл бұрын

V is the force parallel to the cross-sectional area of the object. The pin is oriented so that it faces the whiteboard.

Pull up to UT fr, we need you here

why is the resultant force being considered for calculating shear stress.. shouldn't it be the tangential one...

@surferrosa7285

3 жыл бұрын

That's what I was thinking. For the single shear case wouldn't it be the 4/5 Fbc used as that is acting parallel to the plain in question?

@hancar8142

3 жыл бұрын

if it was a beam yes you are right. But it is a pin connection so pin is under shear stress either x and y direction. because of this we take the resultant force at the pin.

@bardia8225

3 жыл бұрын

@@hancar8142 Man I hate statics and solids. It makes no sense. It is never clear. Are we trying to calculate stresses on the pin or on the member. Last lesson he mentioned that axial forces acting on a member are considered normal stress. Then Ax has to be normal stress of the AB member. But if we talking about the pin, then Ax is obviously perpendicular to pin and is a shear stress. So which one is it.

@hancar8142

3 жыл бұрын

​@@bardia8225 if you look at the question its asking to find shear stress at pins. So if you analyse pin connection and if there are force acting tangential direction of the pin, there occurs shear stress on the pin. But it depends on what you are analyse on which part of the system. in order to be a normal stress on the pin, there must be a force acting z direction I mean the direction must be normal/perpendicular to the pin/body. English is not my native language I hope I helped you understand man.

@bardia8225

3 жыл бұрын

@@hancar8142 yeah kind of. thank you. One more question, why is the Ay considered in shear stress too? The Ay force only applies tension force on the pin. is that not true?

Damn I found these videos after rating 1/5 to my Mechanics of Materials professor

can you do a theory of structure class

Sir hanson, about the area of a circle. Isn't it pi*d^2 over 4?

@edwardli9856

3 жыл бұрын

pi*r^2 is the same

why do you set V to be the resultant of Ay and Ax when you said at the beginning V is the vertical component of the reaction force

Ok but we just need vertical force for shear or both normal and vertical????

Professor shouldn’t be used the force of 12.5 kN to calculate the shear stress in the pin A, being the force that will shear the pin because is actuating on the horizontal direction!?

@howardbaxter2514

2 жыл бұрын

Both Ay and Ax are acting parallel across the face of the pins. Therefore, both forces are shear forces. If there was a Az force, that would be the normal force.

@howardbaxter2514

2 жыл бұрын

Think about how the pin is along the z-plane

I’m not sure about the area of the circle because we were given the diameter, can’t it be rewritten pi*d^2/2 or something else

@bag-aogianresterdaquis2296

3 жыл бұрын

its okay men cause d/2 = r so the given diameter is 20 and you divide it by two so that you can get the radius and use the πr² as a formula. anyways you can use also the πd²/4

thank you

@insmnac6526

2 жыл бұрын

so much

@insmnac6526

2 жыл бұрын

because i have no idea what im doing here

Area is given right 20mm? is a radius or diameter? because the formula of diameter is π/4 (d)^2?

@AB-gu9ui

3 жыл бұрын

The diametre of the pin was given as 20mm so we can half it to find the radius and use π*r^2 or use π/4 (d)^2 with the diametre

why you don't use only y axis forces

¿Dónde estabas cuando te necesité en el 2016? :(

Professor, YOU ARE MY FUCKING GOD.

10:45 We want to calculate the shear stress on pin so shouldn't we just use Ax because it's the shear force apllied on pin.

@samvalmassoi4237

3 жыл бұрын

Think of shear force as a “tearing” force. Both Ax and Ay are trying to tear the pin apart.

@mitchell6973

2 жыл бұрын

@@samvalmassoi4237 Yes, but they act on different cross sectional areas so how can you just get a resultant like that?

@bahramaghakhan1024

2 жыл бұрын

That’s my question too. How can we add shear to normal the way he did?

@dannydang1507

2 жыл бұрын

@@mitchell6973 they both acting on the same cross sectional area of the pin which is circular

@abbastufan7508

Жыл бұрын

@@samvalmassoi4237 i got your point, thanks. samely, why dont we take into consider Ax and use resultant force when we consider normal stress?

10:51 please HELP !!! How do he got 35.6 ? Can someone explain how to find the 'V'.

@monaji222

3 жыл бұрын

Never mine, just got it. V^2 = 12.52^2 + 33.342^2 V = 35.6

I don't get it. Why do you consider Ax as part of the shear stress. On lesson 2 you said that the forces acting axially on a member are considered normal stress. So Ax must be a normal stress

@AB-gu9ui

3 жыл бұрын

Its because we are calculating the shear stress on the pin, not the beam. Think about the pin and you will realise that both Ax and Ay is perpendicular to the pin (as the pin is going into the page)

@brandonf3865

Жыл бұрын

@@AB-gu9ui thank you this was the best explanation. The top down view I think confused me some

@abbastufan7508

Жыл бұрын

@@AB-gu9ui so do we have to use Ay with Ax when calculating the normal stress on the pin?

2x3 6 alright calculator :D

Bu nabarlaaaa

0:30 I hold my breath if you didn't do miki mouse voice.

This online lectures is gonna carry me, my prof. is terrible lecturer

Can you have your Facebook account?

Allah izin verirse sensin abimmm

ucalgary enme317 gang?

these ads have to stop

11:30 bug

@jorgetrevino325

3 жыл бұрын

Haha