Math Olympiad | A Nice Exponential Problem | Solved by 2 Methods
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Пікірлер: 13
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@vijaymaths5483
17 күн бұрын
👍
awesome
super explanation
SENSATIONAL!!
Excellent and nice twice solutions, but the 2nd is more beautiful thanks sir.
@vijaymaths5483
17 күн бұрын
Thank you
2.585
very nice Sirii
@vijaymaths5483
17 күн бұрын
Thank you ✒️
3/2a= 1a.1 (a ➖ 1a+1) 4/3b =1b .1 (b ➖ 1b+2) 5/4c =1c.1 (c ➖ 1c+1) 6/5d=1d.1 (1d ➖ 1d+1)
aln2 = ln3 bln3 = ln4 cln4 = ln5 dln5 = ln6 abcdln2 = ln6 *abcd = (ln6)/ln2 = 1 + (ln3)/ln2*