Manifolds - Intrinsic Geometry

Modern geometry is based on the notion of a manifold. This represents a shift from the classical extrinsic study geometry. In this video we introduce the subject and talk about intrinsic geometry. We define the notion of a smooth manifold and see how the notion of tangents spaces from calculus can be extended to this setting.

Пікірлер: 12

  • @jawadhassan6546
    @jawadhassan65465 жыл бұрын

    I have been searched for intrinsic geometry definitions through out the whole web, but they were didnt helped to get a clear idea. Thanks to Danial Chan, the way he is explained is super cool. Loads of stars for your way of explanation .

  • @santafucker1945
    @santafucker19454 жыл бұрын

    I did enjoy this adventure in pure mathematics! Thank you!!

  • @paolor2166
    @paolor21663 жыл бұрын

    Your approach is so clear and so direct, it's inspiring!

  • @henrywoo1668
    @henrywoo16682 жыл бұрын

    Thank you sir ,you are a great professor !

  • @ahmedamr5265
    @ahmedamr52652 жыл бұрын

    Thank you! This video exactly responds to the questions i had!

  • @peter308
    @peter3082 жыл бұрын

    Manifolds shall be taught in high schools already. It is too important nowadays.

  • @jordanweir7187
    @jordanweir71875 жыл бұрын

    Thank you so much, this is the only satisfying explanation that makes sense to me, awesome content

  • @ArthasDKR
    @ArthasDKR4 жыл бұрын

    🎈 example=God level

  • @walkernet4426
    @walkernet44262 жыл бұрын

    thank you !!

  • @sau002
    @sau0023 жыл бұрын

    I like the test for curved surface at 7:42

  • @mathjitsuteacher
    @mathjitsuteacher6 жыл бұрын

    Hi, Daniel. Congratulations on your lectures. You are a very good teacher. I have a question. In your definition of smooth manifold the homeomorphisms where all defined on the d dimensional unit ball and I have always seen this definition using arbitrary open sets. I suppose this definition is fine since any open set on a d-dimensional space is locally homeomorphic to the d dimensional unit ball. Am right?

  • @StatelessLiberty

    @StatelessLiberty

    5 жыл бұрын

    You can show the two definitions are equivalent like this. Let's show that your definition implies his definition (since the other direction is trivial). Given your point p in your manifold, suppose you have a homeomorphism from an open neighbourhood U of p to an open subset V of R^n. Then consider x to be the image of p under this mapping. You can put an open ball around x (contained in V) and the consider the preimage of the open ball, which will also be open by continuity and will contain p. If you restrict your homeomorphism to this preimage of the open ball, you have the definition of a manifold used in the above video.