This 20 minute video teaches you more than school does in a entire quarter AND it is easier to understand

@Greenemath

3 жыл бұрын

I'm glad the video was helpful! :)

@robertreyes2514

2 жыл бұрын

i agree lol

@Bleek_

Жыл бұрын

I agree XD

@Sphyxenix

Жыл бұрын

Kinda agree

@debasishdasgupta.7375

9 ай бұрын

🙏🙏

I'm in 8th grade and due to the pandemic, I'm having a hard time understanding the module given to us. This helps me a lot. Thanks! Edit:I just finished taking our test and I got a perfect score!

@Greenemath

3 жыл бұрын

You are very welcome! :)

@Greenemath

3 жыл бұрын

@Bethany Joy Cool, good luck with class :)

@Greenemath

3 жыл бұрын

@@professionalprocrastinator4397 It will get better, just keep working!

@tobyshea2533

3 жыл бұрын

congrats on your test

@firsttes6753

3 жыл бұрын

What you guys are grade 8 to me too

This legend is still replying to comments after 4 years

@Greenemath

3 жыл бұрын

Yes I am :)

@professionalprocrastinator4397

3 жыл бұрын

Nice

@Greenemath

3 жыл бұрын

@@professionalprocrastinator4397 Thanks for noticing :)

@Inocenciojamil

2 жыл бұрын

6 years now

@kusumchowdhury5758

9 ай бұрын

7 years

When KZread videos help u more then 10 years of school..... thx for the vid it rlly helped me get that 💯

@user-vd3pw6yf7b

4 жыл бұрын

This is very late but we learn when we want to learn. thats why we search videos like these to understand the lessons we miss (since its hard to listen to teachers at school). Unless the teacher is really bad at teaching then

@Beansthecat99

4 жыл бұрын

@@user-vd3pw6yf7b teachers suck i used to go to my algebra 2 teacher for help at lunch twice a week for almost the whole semester and she treated me like i was bothering her on her lunch i still hate her

@leonadawn9998

3 жыл бұрын

@@Beansthecat99 you know that not all teachers are like that right? there are plenty of teacher who can actually a really close friend of yours maybe you just haven't found the right teachers

@Greenemath

3 жыл бұрын

I'm so glad that it was helpful! :)

Insane that 6 mins in, and I already understand more than in my 2 hour long lessons in my college class I had earlier this month.

@Greenemath

3 жыл бұрын

Awesome, let me know if you have questions about the topic.

I am in University of 2022, and I graduated highschool in 2014. When I enterened my math this year (I avoided it last year lol) I had no idea what I was doing. My professor would always say "You guys should know this" but, to be FAIR. Not all of us transition from highschool to University right off the bat (like me). So this was very confusing. I've had 5 classes so far and I literally have a test on the 23rd. These hours Ive been in class I've had no idea until I stumbled onto your videos. YOU TEACH ME BETTER THAN MY SCHOOLS DOES!!! I've learned this under 2 hours of work put into than the 5 days of my class. I did my first practice quiz we have and got 3/12. After I studied and learned from you I retook the test and got 10/12 within those 2 hours of work. I just want to say THANK YOU!!! Im not so dumb at math like I thought I was

@Greenemath

Жыл бұрын

No one is "dumb at math", they just need lots of practice. Good luck with the test and with college.

If you are confused as to where the numbers come from, we can simply choose a value for x and solve for the unknown y or vice versa. For Example: 3x + 5y = 10 I can just pick some value for x, let's say 1. Now since x is 1, I can plug a 1 in for x in the equation. 3(1) + 5y = 10 3 + 5y = 10 Now, I have a linear equation in one variable. I can solve for y: 3 + 5y = 10 5y = 7 y = 7/5 This tells us that if x is 1, y is 7/5. You can pick any number you want and plug in for x and solve for the unknown y or vice versa. If you have a question about the video, please leave a time marker with clear instructions as a new comment. We only respond to NEW COMMENTS WITH CLEAR INSTRUCTIONS.

@kinglight1528

3 жыл бұрын

How to solve 9x - 7y= -7? I can't quite understand :(

@israelbernardoabaga5644

3 жыл бұрын

1. Substitution x+y =10 5x + 4y = 4 2.Elimination 2x + 3y = 23 (1) 5x - 3y = 5 (2) Thank you sir for helping me

@Greenemath

3 жыл бұрын

@@kinglight1528 It depends on what you are trying to do? What are the instructions? Are you trying to just give some ordered pairs? If that's the case, you can just pick some values for x and solve for y. One solution, we could pick an x-value of 0 and just plug in. 9(0) - 7y = -7 0 - 7y = -7 y = 1 So if x = 0, then y = 1, so one ordered pair is (0, 1) See how that works, just pick something for x and solve for the unknown y.

@Greenemath

3 жыл бұрын

@@israelbernardoabaga5644 Alright, that's a different video by the way. You need to work with solving linear systems. Anyway to solve a system by substitution, just solve one of the equations for one of the variables. So let's solve the first equation x + y = 10 for y: y = -x + 10 Now plug in for y in the second equation. This works because y is equal to or the same as the expression (-x + 10) 5x + 4(-x + 10) = 4 5x - 4x + 40 = 4 x + 40 = 4 x = -36 Now that we know what x is, we can plug in to either equation and find y. -36 + y = 10 y = 46 So we find that x = -36, and y = 46 or (-36,46) as an ordered pair. For elimination, you will add the two left sides together and set this equal to the sum of the right sides. Notice how your y variable will be eliminated since they are opposites (3y, -3y): 2x + 3y + 5x - 3y = 23 + 5 7x = 28 x = 4 Plug back in to find y 2(4) + 3y = 23 8 + 3y = 23 3y = 15 y = 5 So x = 4 and y = 5 or (4, 5)

@kyeshaaparente3286

3 жыл бұрын

How to solve x + y=11; (1,2) I can't quite understand :)

You Sir are a blessing.

@Greenemath

3 жыл бұрын

Thanks for watching!

Remember: The left value is the X-value and right value is the Y-value. Since you repeated it so many times, it got stuck in my brain. :D Jokes aside, I understood this very well.

@Greenemath

3 жыл бұрын

I'm glad to hear that, you will work with ordered pairs and ordered triples moving forward, so it's important to remember. Good luck with your studies :)

dude seriously, your dedication is unparalleled, thank you for making these videos. really calms my math anxiety haha

@Greenemath

3 жыл бұрын

You are welcome, let me know if you have any questions about the topic. 😎

Thank you so much. This year for school I have 2 hour and 15 minute classes. I have a very short attention span so I don’t learn anything from math. These types of vids really help me. Thanks!

@Greenemath

3 жыл бұрын

I have a short attention span also, especially if I'm bored. The best way to learn math is to practice so that you are actively doing stuff. It helps with spacing out. Good luck with the school year! :)

Hes still replying after 5 years also i have a good ability of catchting things fast i just lost my intrest from learning on online school and when i try comimg back im struggling in math currently and these really help me and i know linear equations quite well now i just dont trust myself

@Greenemath

3 жыл бұрын

Let us know if you get stuck on a problem :)

thank you sir this help me a lot

@Greenemath

3 жыл бұрын

Most welcome!

Sooooo if you make a table you can just pick any number for x or y?

@Greenemath

4 жыл бұрын

Yes, pick any number for x and solve for y or vice versa. There's an infinite number of solutions that can be made for this type of equation.

this guy explained everything i need to answer my assignment in 21 minutes but i don't understand a thing on an 1 hr on this topic thx

@Greenemath

3 жыл бұрын

You are welcome, let me know if you have any questions. I'll try to help out! 😎

Finally, thanks for the clear explanation I understand how to do it now. Thanks a lot

@Greenemath

3 жыл бұрын

I'm glad to hear that, let us know if you run into any tough problems and need help! :)

This is a big help for us students to learn. Thanks!

@Greenemath

3 жыл бұрын

You are very welcome! :)

Thanks sir you made it easier for me, tomorrow's my final exam of maths!

@Greenemath

3 жыл бұрын

All the best, good luck with your test! :)

Thank you so much it is easy when you teach i cannot understand when my teacher is teaching me i almost cried when i cannot understand this but when i watch this video i found out that this lesson is very easy thank you so much sir❤️❤️❤️

@Greenemath

3 жыл бұрын

You are welcome! Glad the video was helpful! :)

Oh wow, you really made this easy on my studies!

@Greenemath

3 жыл бұрын

I'm so glad to hear that! :)

Awesome video, as all of your videos, I've watched your videos since 2012.

@Greenemath

3 жыл бұрын

I'm glad to hear that, thanks for watching :)

Thank you so much for your videos!

@Greenemath

4 жыл бұрын

Thanks for watching! :)

Thanks for this video! I could finally explain this lesson to my sister! 👍

@Greenemath

3 жыл бұрын

Glad it was helpful!

so, for these types of equations, is this a liniar 2-var, diphantine equation (doing research for A-level maths) I do understand that you can use tables and graphs for this, just wondering if this would be the type "diphantine equation" liniar 2-var falls under (year 12 UK, 11th grade/junior US)

@Greenemath

3 жыл бұрын

Glad you liked it :)

Very clear teaching, Thank you for helping me review for our exams

@Greenemath

3 жыл бұрын

Awesome, thanks for watching :)

sir pls answer this question Check whether the ordered pairs (-1, -3), (2, 15), and (0, 7) are solutions of the equation: -y = 4x + 7

@Greenemath

3 жыл бұрын

I typed out an answer for this and you deleted the comment. If you delete this one, you are on your own. Basically, you want to just plug in for x and y in your equation and see if the left and the right sides are equal. an ordered pair is (x, y), so the first value is x and the second is y: (-1, -3) Plug in a (-1) for x and a (-3) for y and check to see if the two sides are equal. -y = 4x + 7 -(-3) = 4(-1) + 7 3 = -4 + 7 3 = 3 true, so (-1, -3) is a solution. Now try the other two on your own. Plug in for x and y and see if the left and right sides are equal.

How about something like this"" this? Btw i love this channel thanks for your lesson

@Greenemath

3 жыл бұрын

You want linear inequalities. I have a video on that for graphing: kzread.info/dash/bejne/no6O162BYNa7YZM.html Let me know if you have questions. 😎

I'm just gonna say this but THANK YOU FOR DOING THIS I WAS SO CONFUSED AT FIRST BUT NOW WOW I CANT SAY THANK YOU ENOUGH TYTYTYTY FOR THIS I UNDERSTAND IT NA

@Greenemath

3 жыл бұрын

I'm glad to hear that, let us know if you get stuck on a problem! :)

Wow, I'm really looking for this vid just what I looking for Thanks alot!

@Greenemath

3 жыл бұрын

Glad I could help!

Sorry if this is a bother or if its just common sense but in the dividing/add/subtract process (starting from here 11:53), how do you if you're going to be adding/subtracting or dividing the number to the digit given in the =?

@Greenemath

2 жыл бұрын

You plug in for the variable in the equation and then solve for the other unknown.

I like the way you teach. I can really understand very well :)

@Greenemath

3 жыл бұрын

Awesome, thank you!

Thank God I found you sir, thank you for teaching us! This help me a lot! 😣♥️

@Greenemath

3 жыл бұрын

I'm so glad! Let me know if you have questions 😎

@christinesantiago9895

3 жыл бұрын

@@Greenemath yes sir, thank you very much! 💓

This was so great to explain. I understand now

@Greenemath

3 жыл бұрын

I'm glad to hear that, let me know if you have any questions about the topic.

Thank You Sir.

@Greenemath

3 жыл бұрын

You are very welcome! :)

we will have our exams tomorrow and this helped alot.Tysm :D

@Greenemath

3 жыл бұрын

You are very welcome! :)

Thank you for the video❤❤

@Greenemath

3 жыл бұрын

You are very welcome, good luck with your studies :)

Thanks for this now i can understand and is able to answer my actitivity

@Greenemath

3 жыл бұрын

I'm glad to hear that! :)

We're doing this chapter in 9th standard and this video is actually amazing Far better than others Love from India

@Greenemath

3 жыл бұрын

I'm glad you liked it :)

I like the way you teach and explain. You've got yourself a new subscriber! :)

@Greenemath

3 жыл бұрын

Perfect, glad it was helpful!

You explain so good more good than my teacher

@Greenemath

3 жыл бұрын

Awesome! I'm glad you are learning! :)

I am in 8th class and I want to know how to solve these for future excellence

@Greenemath

3 жыл бұрын

Alright, good luck with high school.

Thank you so much brother

@Greenemath

3 жыл бұрын

You are very welcome! :)

Thank you sir but there's a part that I didn't understand,on 4x + 2y =12 : check:(3,0) Where did (3,0) came from?

@Greenemath

3 жыл бұрын

With a linear equation in two variables you can simply pick a value for x and solve for y. This can be any value that you want. Let's just suppose we pick 5 for our x-value and this is random. Plug in a 5 for x and solve for the corresponding y: 4(5) + 2y = 12 20 + 2y = 12 2y = 12 - 20 2y = -8 y = -4 So another ordered pair is (5, -4). In other words, you can make as many ordered pair solutions as you want by picking something for x and solving for y or picking something for y and solving for x.

THANK YOU SO MUCHH THIS REALLY HELPS ME

@Greenemath

3 жыл бұрын

You are welcome and I'm really glad it's helpful! :)

Thank u so much for the tutorial 😊

@Greenemath

3 жыл бұрын

You are very welcome! :)

Very helpful more easy to understand than the others🥰

@Greenemath

4 ай бұрын

Glad it was helpful!

i want to drop out bec of math but thank you for making this :]

@Greenemath

3 жыл бұрын

You are welcome. If you want to get better at math, just keep practicing. It's really the only way to get better :)

Thank you so much I really understand it.It's ec to understand

@Greenemath

3 жыл бұрын

Glad it helped!

thank you it helped me in my modules

@Greenemath

3 жыл бұрын

You are very welcome! :)

This was very informative, my issue is graphing when there’s 2 separate urns given to see if they intersect, run parallel or don’t exist if you could explain that I’ll be forever grateful

@Greenemath

3 жыл бұрын

What does "urns" mean? Is this a typo for turns? With linear equations, they won't turn, they are straight lines. If you want to see if they are parallel, perpendicular, or neither, I have a lesson for that. If you want to see if were they intersect, I have a lesson for that. Let me know what you are looking for. Also, you can drop your example here and I can work on it with you. Just let me know. 😎 www.greenemath.com/College_Algebra/89/Parallel-and-Perpendicular-Lines.html www.greenemath.com/College_Algebra/115/Solving-Linear-Systems-in-Two-Variables.html

@angelmonae7140

3 жыл бұрын

Sorry two separate equations 3x+y=6 and 2(-1)-y=9

@Greenemath

3 жыл бұрын

So you have the equations: 1) 3x + y = 6 2) 2(-1) - y = 9 You are missing an x from equation 2, is that what you meant to do? Also what do you want to do here? Do you want to solve the system, or find out if they are parallel, or something else? There's many things with this topic. Try reading the instructions at the top.

@angelmonae7140

3 жыл бұрын

GreeneMath.com 2x-y=9, sorry again

@Greenemath

3 жыл бұрын

Sorry about the late replay, your comment went to spam for some reason. Alright so what are you trying to do? 1) 3x + y = 6 2) 2x - y = 9 Do you want to solve the system? One way to do this is to solve one of the equations for one of the variables. Let's say we solve equation #1 for y. This means we will isolate y on one side. 1) 3x + y = 6 Add (-3x) to both sides: 1) 3x + (-3x) + y = 6 + (-3x) 1) y = -3x + 6 Now we can plug in for y in equation 2 since it is equal to -3x + 6. Just plug this in for y: 2) 2x - y = 9 2) 2x - (-3x + 6) = 9 Note the parentheses above since we are subtracting the whole thing away. 2) 2x + 3x - 6 = 9 2) 5x - 6 = 9 2) 5x = 15 2) x = 3 So now we know that x is 3, we can plug in for x in either original equation. 3(3) + y = 6 9 + y = 6 y = -3 So the solution for the system is x = 3, y = -3 or (3, -3) as an ordered pair. You can check this by plugging in for x and y: 3(3) + (-3) = 6 9 - 6 = 6 6 = 6 true 2(3) - (-3) = 9 6 + 3 = 9 9 = 9 true I'll do a separate comment for parallel, and perpendicular.

Thank you so much I understood this better because our professor teaches too fast so thank you so much I understand it better.

@Greenemath

3 жыл бұрын

You're very welcome!

That's pretty fking easy, good tutorial.

@Greenemath

3 жыл бұрын

Awesome, glad you liked the video, good luck with your studies :)

this really helped me out thanks

@Greenemath

3 жыл бұрын

You are very welcome! :)

Thanks this is a great video

@Greenemath

3 жыл бұрын

You are very welcome. Thanks for watching :)

from all of the videos I've watched, only this video made me realize that linear equations is definitely not hard hahah

@Greenemath

2 жыл бұрын

It's very easy.

OMGGG THANK YOUUU I FINALLY GOT ITT!! Thank you so so much

@Greenemath

3 жыл бұрын

Glad it was helpful! :)

grrr im just on 7th grade and it's so confusing to understand since we have this pandemic. thank you so much sir, keep safe!

@Greenemath

3 жыл бұрын

I'm glad you are learning, good luck with your studies :)

@maeve9615

3 жыл бұрын

daming filipino d2 omg hahaha

@Greenemath

3 жыл бұрын

@@maeve9615 Thanks for the comment, hope you are doing well :)

how can we get the check trial and error sir???? ty

@Greenemath

3 жыл бұрын

When you are working with this topic, you are generally doing a plug and chug. So you pick a value for x and solve for the unknown y or you pick a value for y and solve for the unknown x. The value you pick can be whatever. Once you have your solution you can plug back in and see if it is a true statement. 2x + 3y = 6 I pick x = 1, so this gives me: 2(1) + 3y = 6 2 + 3y = 6 3y = 4 y = 4/3 So now I have one ordered pair, x = 1 and y = 4/3 (1, 4/3) If you want to check just plug back in and see if you get a true statement, meaning the left and the right sides will be equal. 2(1) + 3 * 4/3 = 6 2 + 4 = 6 6 = 6 true

But then what uf they never give me a number for the variable? Like no check, no table. Then what?

@Greenemath

4 жыл бұрын

It depends on what you are trying to do. There should be some instructions, such as make a table of ordered pairs, or graph the equation. If you want to make a table of ordered pairs, just pick values for x and solve for y or vice versa.

You Speak English Fluently. And I understand it Perfectly. I am considering Subscribing and smashing that like and bell.

@Greenemath

3 жыл бұрын

Sounds good, but GreeneMath.com is a better resource for all our free math content. Good luck with your studies :)

Thankyou so much sir!

@Greenemath

3 жыл бұрын

Most welcome!

Thanks a lot , phew now I will have no tension in the future

@Greenemath

3 жыл бұрын

You are welcome.

It's relly useful for me, thank you

@Greenemath

14 күн бұрын

You are welcome.

Thanks for this video it help me so much

@Greenemath

3 жыл бұрын

I'm glad to hear that, let me know if you have any specific questions or get stuck on a problem 😎.

Sir how do we get (3,0) as x and y value? I mean where does these two numbers come from?

@Greenemath

3 жыл бұрын

Hi, in the video I said you can pick anything you want for one variable and solve for the other. In other words, there are an infinite number of solutions for a linear equation in two variables. So if you choose a number, any number you want for x, then you can plug in that number and solve for y. Let's say we had: x + y = 4 Just pick some number for x, any number. Let's suppose we just choose 3: x = 3, so what does y equal? Plug in a 3 for x: 3 + y = 4 Solve for y: y = 4 - 3 y = 1 So (3, 1) is an ordered pair that satisfies this equation, but I could choose something else, anything else and do the same thing. Let's say I let x = 15. 15 + y = 4 y = -11 So (15, -11) is another ordered pair that satisfies this equation. You can continue in this fashion for as long as you like. Just pick something for x and plug it in and then solve for the unknown y.

@kapangaigonmei8535

3 жыл бұрын

@@Greenemath Thank you so much sir. Now I totally get it.😍

@Greenemath

3 жыл бұрын

I'm glad to hear that! 😁

How about taking 2for x value for the equation of 2x+3y=-24

@Greenemath

3 жыл бұрын

Just plug in for x and solve for y. 2(2) + 3y = -24 4 + 3y = -24 3y = -28 y = -28/3 So your ordered pair is (2, -28/3)

This help me a lot thank you

@Greenemath

3 жыл бұрын

Glad it helped! Good luck with your studies 😎

It helps a lot 😊

@Greenemath

3 жыл бұрын

I'm glad to hear that! :)

thank you so much this really helped

@Greenemath

3 жыл бұрын

Glad it helped!

11:33 why would it not be +3 times -5? because on the previous example, you didnt do -3 times +7. edit - oh, is it because you cant do a negative minus a negative? so you turn that only that one sign into a plus?

@Greenemath

17 күн бұрын

This can be done multiple ways, the easiest way is to bring the sign along for the ride. Method 1) -7(2) - 3(-5) = -7(2) + (-3)(-5) = -14 + 15 = 1 Another way would be to subtract away a negative, which changes into adding a positive. Method 2) -7(2) - 3(-5) = -14 - (-15) = -14 + 15 = 1

this helps me a lot😍

@Greenemath

3 жыл бұрын

I'm glad to hear that :)

I dont get the formula what happens if its like 2x+3y=-24 how do we solve that?

@Greenemath

3 жыл бұрын

With a linear equation in two variables there is an infinite number of solutions. You have two variables. One thing you can do is choose a number for x and solve for y. This number you choose can be any number. Let's just pick 3 for x. x = 3, y = ? So plug in a 3 for x: 2(3) + 3y = -24 6 + 3y = -24 3y = -30 y = -10 So one solution is (3, -10) but there are an infinite number. Let's suppose we choose 0 for x. x = 0, y = ? 2(0) + 3y = -24 3y = -24 y = -8 So another solution is (0, -8). Your assignment should give you some instructions on what you need to do. Usually they will give you an ordered pair and ask if it's a solution or ask for you to make a few on your own. Let me know if you have another question :)

@samanthawoodchuck9142

3 жыл бұрын

@@Greenemath afterwards how do we solve for y?

@Greenemath

3 жыл бұрын

@@samanthawoodchuck9142 When you pick something for x, you plug it in. This gives you a linear equation in one variable. So you would solve it using the normal steps. 2x + 3y = -24 Let's pick x = 8 Plug in an 8 for x. 2(8) + 3y = -24 16 + 3y = -24 So now you have an equation with one variable, just y. So solve for y, get this on its own on the left hand side. 16 + 3y = -24 Let's subtract 16 away from each side: 16 - 16 + 3y = -24 - 16 3y = -40 Let's divide both sides by 3 to isolate y: 3y/3 = -40/3 y = -40/3 So if x is 8, y = -40/3 (8, -40/3) So again, just pick something for x and plug it in. This gives you a linear equation in one variable. Just solve for that variable. If you are still confused drop your homework problem here with the instructions and I'll show you how to solve it.

Tnx tomorrow is my exam without this video i cannot pass

@Greenemath

3 жыл бұрын

Perfect, glad it was helpful! :)

This guy is a legend teacher

@Greenemath

Жыл бұрын

Thanks for the nice comment.

Thank you

@Greenemath

3 жыл бұрын

You're welcome

THANKYOUUUU🥺🥰 BE SAFEEEE

@Greenemath

3 жыл бұрын

You are welcome.

i understood almost everything, but i still can’t understand which numbers you have to choose for x or y in order to get a whole number, and not decimal. could somebody explain that, please?

@Greenemath

2 жыл бұрын

Let's take one example. 2x + 3y = -24 If we are choosing x-values, then we know that we end up with: 3y = -24 - 2(x) If we want to only have integers, then what we choose for x, needs to result in a right-hand side that is divisible by 3.

Thank you very much💜

@Greenemath

3 жыл бұрын

You are very welcome! 😎

How did you get the valie of Y?

@Greenemath

3 жыл бұрын

For this type of equation, you can pick any value you want for y and solve for x or pick any number you want and solve for y. For example. 3x - 5y = 10 Pick anything you want for x, I'm going to pick 1, but you can pick whatever: 3(1) - 5y = 10 After I plug in a 1 for x I can solve for y: 3 - 5y = 10 -5y = 10 - 3 -5y = 7 y = -7/5 So one ordered pair is (1, -7/5) Again you can choose whatever you want for x and solve for y or choose whatever you want for y and solve for x.

Thank you now I got it

@Greenemath

3 жыл бұрын

I'm really glad to hear that! :)

your teachings is pog

@Greenemath

3 жыл бұрын

Play of the Game from twitch? I had to look it up. Thanks for the nice comment :)

@ioriii78

3 жыл бұрын

@@Greenemath eyy, no prob, it helped me alot

Thank you sir😊

@Greenemath

3 жыл бұрын

Most welcome! :)

how did you get 12 in 4 plus 2 pls help

@Greenemath

3 жыл бұрын

Are you talking about 4x + 2y = 12, with (3,0) as the ordered pair? You plug in a 3 for x and a 0 for y as given by the ordered pair: 4(3) + 2(0) = 12 12 + 0 = 12 12 = 12 If you were talking about something else please give us a time marker and we'll be happy to explain. :)

Thanks man you helped me.

@Greenemath

3 жыл бұрын

Perfect, glad it helped :)

Thank you!

@Greenemath

2 ай бұрын

You're welcome!

Thank you so much

@Greenemath

2 жыл бұрын

You're most welcome

Thank you i appreciate sir

@Greenemath

5 ай бұрын

Most welcome

THANK YOU VERY MUCHHHHH

@Greenemath

3 жыл бұрын

You are very welcome! 😎

Thank you ^^

@Greenemath

3 жыл бұрын

You're welcome 😊

Thank you sir

@Greenemath

3 жыл бұрын

All the best

@gmn_kyl11

3 жыл бұрын

You're a great teacher

@Greenemath

3 жыл бұрын

@@gmn_kyl11 Thank you for your kind words :)

Not gonna lie this helps me alot now i can finish my math activity,thank you

@Greenemath

4 жыл бұрын

Great to hear!

Why so hard to understand math

@Greenemath

3 жыл бұрын

It just requires practice like anything else.

How can I solve 2x=5, 3y=4, 4y=5, y=6 ?

@Greenemath

3 жыл бұрын

Are those individual problems? If they are just isolate the variable. This means you want to undo the operation. 2x = 5 Solve for x? Divide both sides by 2 (undo the multiplication by 2): x = 5/2 3y = 4 Solve for y? Divide both sides by 3 (undo the multiplication by 3): y = 4/3 4y = 5 Solve for y? Divide both sides by 4 (undo the multiplication by 4): y = 5/4 y = 6 is already solved for y.

KZread is better than a classroom

@Greenemath

3 ай бұрын

Great, glad to hear that!

Thanks

@Greenemath

3 жыл бұрын

You are welcome, good luck with your studies :)

This is for my exam tomorrow, well wish me luck😅❤

@Greenemath

3 жыл бұрын

Good luck!!

THANK YOU SIR BE MY MATH TEACHER PLZ

@Greenemath

3 жыл бұрын

You are very welcome, all of our courses are free at GreeneMath.com if you want to do a deep study :)

lmao i have a test tomorrow this helped alot thx

@Greenemath

3 жыл бұрын

I'm really glad it was helpful, good luck with your test! :)

Clear pronseation

@Greenemath

2 жыл бұрын

Thanks for watching and commenting!

Thanks sir

@Greenemath

3 жыл бұрын

You are very welcome! :)