LeChatelier Principle: Change Pressure

Predict the shift in equilibrium with a change of pressure or volume.
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Website: LeanThink.org

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  • @snook1150
    @snook115013 күн бұрын

    all i needed was the thought process to truly understand it instead of just memorizing, no one else provided it with such clarity, very grateful

  • @OldSchoolChemistry

    @OldSchoolChemistry

    12 күн бұрын

    Hi Snook, that makes me so pleased it was helpful. I am proud of you for wanting to UNDERSTAND and not just memorize. Well done! :)

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    @user-mb5tt8ki8k5 ай бұрын

    This was the best among all the KZread lessons..❤

  • @OldSchoolChemistry

    @OldSchoolChemistry

    4 ай бұрын

    Hi Ms. Nisar, thank you so much! I appreciate you watching. :)

  • @aerdis3814
    @aerdis38142 жыл бұрын

    This channel should have millions of subscribers. Great video.

  • @OldSchoolChemistry

    @OldSchoolChemistry

    2 жыл бұрын

    Hi Erdis - thank you! I hope so😃 Thanks again!

  • @pranavborse91
    @pranavborse9110 ай бұрын

    thank you, you explained it so much better than the textbook!

  • @OldSchoolChemistry

    @OldSchoolChemistry

    10 ай бұрын

    Hi Pranav, I am so glad! Thank you for your comment:)

  • @baraskparas
    @baraskparas3 жыл бұрын

    Essential chemistry, explained clearly. Thanks.

  • @user-jp6iu3wv2j
    @user-jp6iu3wv2j Жыл бұрын

    omg thank you so much. I was struggling before just reviewing my notes and reading the book. Its not just this video, but your other equllibrium videos, and other videos in general has helped me so much! Thank you!!

  • @OldSchoolChemistry

    @OldSchoolChemistry

    Жыл бұрын

    Hi Evan, I am SO glad. Thank you for letting me know. I hope your class goes well.

  • @user-jp6iu3wv2j

    @user-jp6iu3wv2j

    10 ай бұрын

    @@OldSchoolChemistry I ended up getting a 90 on the final and ended with an A. Thank you so much!!!!

  • @OldSchoolChemistry

    @OldSchoolChemistry

    10 ай бұрын

    @@user-jp6iu3wv2j Evan! Way to go!!! I am so proud of you. Your extra effort and hard work paid off. Well done:)

  • @nalabrown4839
    @nalabrown48395 ай бұрын

    You truly are heaven sent thank you so much !

  • @OldSchoolChemistry

    @OldSchoolChemistry

    5 ай бұрын

    Hi Nala, You are so kind. I am glad it was helpful. Thanks:)

  • @dhilanamin6018
    @dhilanamin6018 Жыл бұрын

    yo this made it clear to understand, thank you!

  • @OldSchoolChemistry

    @OldSchoolChemistry

    Жыл бұрын

    Hi Dhilan, I am so glad! Thank you for your comment:)

  • @sneha66a49
    @sneha66a493 жыл бұрын

    This is is a really helpful video. Thanks so much, also I just subscribed :)

  • @OldSchoolChemistry

    @OldSchoolChemistry

    3 жыл бұрын

    Oh, great!! Thanks so much🎉🎉

  • @johnnubari8469
    @johnnubari84693 ай бұрын

    Learning effect of conc n pressure today has taken me almost the whole day untill i met your video, thank you very much love you

  • @OldSchoolChemistry

    @OldSchoolChemistry

    3 ай бұрын

    Hi John, wonderful! That makes me so happy. Thank you for your comment:)

  • @rayowork
    @rayowork3 ай бұрын

    Thanks from kurdistan🇹🇯 for your great vedio with best explained❤🎉

  • @OldSchoolChemistry

    @OldSchoolChemistry

    3 ай бұрын

    Hi Rayowork, Greetings to you in Kurdistan! I am proud of your hard work. Thank you for your kind comment:)

  • @EmmaTharman-ws4vv
    @EmmaTharman-ws4vv Жыл бұрын

    I love you mom. You’ve helped me much ❤

  • @OldSchoolChemistry

    @OldSchoolChemistry

    Жыл бұрын

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  • @gio3798
    @gio3798 Жыл бұрын

    My queen, i love you 🥲

  • @lassejrgensen9956
    @lassejrgensen9956 Жыл бұрын

    have an exam in chem tomorrow, this channel clutched it, tysm

  • @OldSchoolChemistry

    @OldSchoolChemistry

    Жыл бұрын

    Hi Lasse, Wonderful! I am so proud of your extra effort and work. Good luck on the test:)

  • @mohdsajid5629
    @mohdsajid5629 Жыл бұрын

    Amazing explanation

  • @OldSchoolChemistry

    @OldSchoolChemistry

    Жыл бұрын

    Hi Mohd, I am glad you think so. Thank you!

  • @TarushiSah
    @TarushiSah9 ай бұрын

    This great teacher❤ Love from India 🇮🇳

  • @OldSchoolChemistry

    @OldSchoolChemistry

    9 ай бұрын

    Hi Tarushi, thank you for your kind comment! Sending love to you from the USA💗

  • @gameblitz202
    @gameblitz2023 ай бұрын

    You explained very well as compared to others ❤

  • @OldSchoolChemistry

    @OldSchoolChemistry

    3 ай бұрын

    Hi Pocky, I am so glad you think so. Thank you for commenting!

  • @gameblitz202

    @gameblitz202

    3 ай бұрын

    @@OldSchoolChemistry Most welcome and best of luck

  • @user-wo7do8um8d
    @user-wo7do8um8d10 ай бұрын

    Thank you so much!!

  • @OldSchoolChemistry

    @OldSchoolChemistry

    10 ай бұрын

    You are very welcome:) Thank you for your comment!

  • @mahmoudwahidi8873
    @mahmoudwahidi8873 Жыл бұрын

    a blessing

  • @OldSchoolChemistry

    @OldSchoolChemistry

    Жыл бұрын

    Hi Mahmoud, what a great comment. Thank you. God bless you!

  • @luciddoggo5094
    @luciddoggo50942 жыл бұрын

    Super helpful

  • @OldSchoolChemistry

    @OldSchoolChemistry

    2 жыл бұрын

    Hi Lucid, I'm so glad. I hope chemistry goes well for you. Please subscribe if you have not already.😊

  • @yeorimpark
    @yeorimpark Жыл бұрын

    Hello, thank you for this informative video! For the reaction written below, H2 + Cl2 --> 2HCl, which way would the equilibrium shift if pressure was increased? Or would it change at all, since they both have 2 moles on each side.

  • @OldSchoolChemistry

    @OldSchoolChemistry

    Жыл бұрын

    Hi Yeorimpark, you are correct! If you have the same number of gas moles on the reactant and product sides of the reaction, there is no shift in equilibrium with a change of pressure or volume. Thanks! :)

  • @Alexis.j3nni
    @Alexis.j3nni2 жыл бұрын

    Thank you!!

  • @OldSchoolChemistry

    @OldSchoolChemistry

    2 жыл бұрын

    Hi Jenni, you are so welcome. I hope chemistry goes well for you. Please subscribe if you have not already. Thanks!

  • @Alexis.j3nni

    @Alexis.j3nni

    2 жыл бұрын

    @@OldSchoolChemistry already did :))

  • @OldSchoolChemistry

    @OldSchoolChemistry

    2 жыл бұрын

    You’re awesome. Thanks😊

  • @wycliffenyandika9017
    @wycliffenyandika9017 Жыл бұрын

    Love your videos ! Do you still make more ?

  • @OldSchoolChemistry

    @OldSchoolChemistry

    Жыл бұрын

    Hi Wycliffenyandika, Thank you for the comment. I only made a couple of videos the past year. In the fall I will begin making videos with homework problems. Thanks!

  • @OldSchoolChemistry

    @OldSchoolChemistry

    Жыл бұрын

    @@EmaanIqbal-bb1yy Thank you for your comments Emaan! I hope you have a good chemistry class experience:)

  • @samarth1698
    @samarth16986 ай бұрын

    I am from india preparing for my medical exam …. I was struggling in this thanks for helping

  • @OldSchoolChemistry

    @OldSchoolChemistry

    6 ай бұрын

    Hi Samarth, I am glad it was helpful. I am so proud of your hard work. God bless you on your exam!

  • @Aisha-gd6dq
    @Aisha-gd6dq Жыл бұрын

    Thank you❤❤❤❤

  • @OldSchoolChemistry

    @OldSchoolChemistry

    Жыл бұрын

    Hi Aisha, You are welcome!! :)

  • @lubegamathias3862
    @lubegamathias3862Ай бұрын

    ilike ur explanation

  • @OldSchoolChemistry

    @OldSchoolChemistry

    Ай бұрын

    Hi Lubega, I am so glad! Thank you for your response:)

  • @ED-gq1ds
    @ED-gq1ds10 ай бұрын

    Thanks for the video is so helpful. but I have a question what if is in endothermic or exothermic reaction

  • @OldSchoolChemistry

    @OldSchoolChemistry

    10 ай бұрын

    Then you have two impacts at once. Consider both. It takes advanced knowledge and math to predict the shift if you change both temperature and pressure.

  • @ED-gq1ds

    @ED-gq1ds

    10 ай бұрын

    @@OldSchoolChemistry do you have a video on that so I can watch please

  • @OldSchoolChemistry

    @OldSchoolChemistry

    10 ай бұрын

    @@ED-gq1ds I am sorry I do not :/

  • @yousrayousri4190
    @yousrayousri4190 Жыл бұрын

    Will there be a change in equilibrium if you add a catalyst?

  • @OldSchoolChemistry

    @OldSchoolChemistry

    Жыл бұрын

    No:) The reaction will achieve equilibrium faster but equilibrium does not shift. Great question!

  • @prachisharma457
    @prachisharma4578 ай бұрын

    Thank you very much for this Ma'am, It was very helpful. I had a question that if we introduce an inert gas during the reaction, do we take the change in pressure in that case as well??

  • @OldSchoolChemistry

    @OldSchoolChemistry

    8 ай бұрын

    Hi Prachisharma, here is a great explanation from Chemistry Libre Texts: Add an inert gas (one that is not involved in the reaction) to the constant-volume reaction mixture: This will increase the total pressure of the system, but will have no effect on the equilibrium condition. That is, there will be no effect on the concentrations or the partial pressures of reactants or products. Thanks!

  • @prachisharma457

    @prachisharma457

    8 ай бұрын

    @@OldSchoolChemistryThanks for your explanation Ma'am, I'm sorry but I think I'm still not really sure about why will the reaction not move towards the side with lesser no. of moles. Does that have to do with the volume being constant?

  • @OldSchoolChemistry

    @OldSchoolChemistry

    8 ай бұрын

    @@prachisharma457 I am sorry, I do not understand the question. Are you referring to one of the examples in the video?

  • @prachisharma457

    @prachisharma457

    8 ай бұрын

    @@OldSchoolChemistry No, I was considering the addition of inert gas in a given reaction.

  • @OldSchoolChemistry

    @OldSchoolChemistry

    8 ай бұрын

    @@prachisharma457 The inert gas will not change the partial pressures of the gases in the container. The overall pressure of the container will increase. I hope that helps! Thanks:)

  • @SonuKumar-kh4wl
    @SonuKumar-kh4wl2 жыл бұрын

    Great

  • @OldSchoolChemistry

    @OldSchoolChemistry

    2 жыл бұрын

    Hi Sonu, thank you! I appreciate your comment:)

  • @OscarJuvera
    @OscarJuvera4 ай бұрын

    Thank you so much for the lovely explanation! Super side note, have you ever been told you look like Dakota Johnson, or maybe I should say, Dakota Johnson looks like you lol. Either way, thank you again!

  • @OldSchoolChemistry

    @OldSchoolChemistry

    4 ай бұрын

    Hi Oscar, I am glad it was helpful. Thank you for the kind compliment:)

  • @herreraherrera4462
    @herreraherrera44622 жыл бұрын

    Sorry am dumb ,but how do you know how many moles each side have ?

  • @OldSchoolChemistry

    @OldSchoolChemistry

    2 жыл бұрын

    Hi Herrera Herrera, that is not a dumb question. It is a great question! You add the molar coefficients (those are the large numbers in front of the compounds) on the reactants side and product side. For example every species in this chemical equation is a gas: 1 N2 + 3 O2 -> 2 NH3. There are 2 moles on the product side and 4 moles on the reactants side. I hope that helps!

  • @herreraherrera4462

    @herreraherrera4462

    2 жыл бұрын

    @@OldSchoolChemistry thank you!! It helped

  • @Wvwwvwvve
    @Wvwwvwvve Жыл бұрын

    I wish you were my teacher

  • @OldSchoolChemistry

    @OldSchoolChemistry

    Жыл бұрын

    Hi H7, I wish you were my student! I hope your class goes well:)

  • @Alkimachos
    @Alkimachos Жыл бұрын

    Watching this 8 min before lab quiz

  • @OldSchoolChemistry

    @OldSchoolChemistry

    Жыл бұрын

    I hope it went well!!

  • @ande5090
    @ande50908 ай бұрын

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    @lamia997 Жыл бұрын

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  • @lukuwazzow9553
    @lukuwazzow9553 Жыл бұрын

    H20 is a liquid not a gas but you counted it

  • @OldSchoolChemistry

    @OldSchoolChemistry

    Жыл бұрын

    Hi Lukuwazzow, water is counted because it has the (g) phase written next to it. I hope that helps. Thanks!

  • @itsyeboiandrew
    @itsyeboiandrew4 ай бұрын

    came for help in equilibria, now i’m in love with this teacher🫠

  • @OldSchoolChemistry

    @OldSchoolChemistry

    4 ай бұрын

    Hi @isyeboiandrew, I am so glad it was helpful. Thank you for watching!