Very clear process but you need a bigger board so that you keep most of the work available.

@JJONLINEMATHSCLASSchannel

28 күн бұрын

Yes, you are right. But the board is big enough, what I need is a better camera that will get the whole board. Thanks.

Accelerated Girard-Newton method: x^2-(a+b)x+ab=0 (Vieta). x^2-x-1/2=0 x^2=x+1/2 (1) S(k)=a^k+b^k (1)*x x^3=x^2+x/2 ⇒ S(3)=S(2)+S(1)/2=2+1/2=5/2. (1)*x^2 x^4=x^3+(x^2)/2 ⇒ S(4)=S(3)+S(2)/2=5/2+2/2= 7/2 (1)*x^3 x^5=x^4+(x^3)/2 ⇒ S(5)=S(4)+S(3)/2=7/2+5/4=19/4 (1)*x^4 x^6=x^5+(x^4)/2 ⇒ S(6)=S(5)+S(4)/2=19/4+7/4=13/2 Acceleration is your solution, direct multiplication, instead of boring calculation S(7), S(8), S(9) S(10). By the way x^2-x+abx^0 =0 ⇒ S(2)-S(1)+ abS(0)=0 S(0)=a^0+b^0=2 ab=-1/2😎

Could also use synthetic division: let g1=a + b - 1 (=0), g2=a^2 + b^2 - 2 (=0), g3= a^11 + b^11 =(?) 1st obtain p2(b) =remainder= (g2/g1) = 2b^2 - 2^b - 1 = 0 . (here use 'a' as independent to return function of 'b') 2nd step get remainder p10(b)= g3/g1. Only need coefficients: [11 -55 165 -330 462 -462 330 -165 55 -11 1] final step, compute remainder p10(b)/p2(b)= 989/32. Advantage? never need to obtain values of 'a' or 'b'.

@JJONLINEMATHSCLASSchannel

27 күн бұрын

Thanks

Very good...

@JJONLINEMATHSCLASSchannel

27 күн бұрын

Thanks

Yes, you got me riveted. Well done 👍🏿

@JJONLINEMATHSCLASSchannel

27 күн бұрын

I'm glad!

Best maths teacher!

@JJONLINEMATHSCLASSchannel

28 күн бұрын

Thanks for the compliment

To easy method for understanding the concepts

@JJONLINEMATHSCLASSchannel

24 күн бұрын

Welcome

@dbrovnievic

21 күн бұрын

You are so beautiful and so smart and on top of that, you have such a good-mood.

👌

@JJONLINEMATHSCLASSchannel

26 күн бұрын

Thanks

Problem solving outline given: a+b=1 and a²+b²=2 Outline: Find ab through (a+b)²=a²+b²+2ab Find a³+b³ through (a+b)³=a³+b³+3ab(a+b) Find a⁹+b⁹ through (x³+y³)³ Find a¹¹+b¹¹ though (x⁹+y⁹)(x²+y²)

@JJONLINEMATHSCLASSchannel

26 күн бұрын

Nice approach 🤝🤝

One can use other exponentials to get the result. It just takes more time. Its important to show students other possible ways to get the same result. For example, the sum of a exponent 2 +b exponent 2 to the fourth power!!

@JJONLINEMATHSCLASSchannel

27 күн бұрын

Thanks but that will make the video to be too long

please teach us from basics on derivatives

@JJONLINEMATHSCLASSchannel

26 күн бұрын

Ok. Noted.

Genius lady indeed!

@JJONLINEMATHSCLASSchannel

28 күн бұрын

Thanks

Where are you from

@JJONLINEMATHSCLASSchannel

26 күн бұрын

Nigeria

@JomilHussainBarbhuiya

26 күн бұрын

Wow nice love from India

🇯🇲🇯🇲🇯🇲🇯🇲🇯🇲🇯🇲🇯🇲🇯🇲

@JJONLINEMATHSCLASSchannel

27 күн бұрын

U are welcome

If it is allowed to use the calculator, it can be solved within 5 minutes.