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This is the only place where I learn maths without getting any headaches. Thank you so much for breaking these nerve-wracking questions for us.

Best teacher I've seen on this planet

Very, very helpful. I like your approach very much.

MR. Organic Chemistry Tutor, thank you for explaining the Inverse Trig Functions with Double Formulas and Half Angle Identities in old fashion Trigonometry.

Very helpful.. Thanks 😁👍

THE LAST PART OF THE VIDEO WAS LITERAL MAGIC WHAT!?

"So if you saw a terrible looking expression like this...." LOL! It's almost like you read my mind. Every time I see a terrible looking expression I come and visit one of your videos!

12:05 it could've been in the 3rd quadrant as well . (You didn't mention any sort of angle restrictions)

Thank you so much

thank you!

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Kindly explain; why inverse half angle aren't in square root? Just like... Cos²theta = 1 + Cos(theta) / 2... Why are not in square root?

thenk you proffessor

@3:22 how did you get 13 as the hypothenuse?

@user-xm7zn2gc2k

8 ай бұрын

Same question

cos(sin^-1 8/25)

life saver

How do you determine what quadrant it’s in?

@pratyu.sheesh

3 жыл бұрын

All ratios positive + 1st quad Sin and cosec positive, others negative in 2nd quad Tan and cot positive, others negative in 3rd quad Cos and sec positive, " " in 4th quad. Remember it like A-S-T-C anticlockwise. A- All S- sin ( and cosec ofcourse) T- tan C-cos

@jinnjinn5567

Жыл бұрын

You can also memorize the range of inverse trig functions if you would like and you can multiply radians by 180/π to convert to degrees *Range of inverse trig functions* arcsin [-π/2, π/2] arccos [0, π] arctan (-π/2, π/2) arccsc [-π/2, π/2] arcsec [0, π] arccot (0, π)

@user-si6ey2gq4t

Жыл бұрын

Remember All Students Take Calculus

Why doesn't it exist in Quadrant 3 and 4

when i find the third angle it is giving me a decimal number

I don’t understand, so if I have sin2 theta = 0.87 how do I find theta

@InexorableVideos

2 жыл бұрын

You don't actually need double angle formulae for this. I am going to use X instead of theta but it's the same concept. To isolate the X in sin(2X)=0.87, you just need to perform the inverse function on both sides. So you do arcsin(sin(2X))=arcsin(0.87) (this is sin to the power of minus one on a calculator, or shift sin) then you have 2X≈60.46 degrees because the arcsin cancels out the sin function. So divide both sides by two you have X≈30.23 degrees. Hope this helps.

Only good

How do you determine what is the opposite number of the triangle

@bababooey8820

Жыл бұрын

Pythagoran teorem.

@user-wj2vr7gb4g

9 ай бұрын

a^2+b^2=c^2