Introduction to projections | Matrix transformations | Linear Algebra | Khan Academy

Determining the projection of a vector on s line
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Пікірлер: 104

  • @chongdak152
    @chongdak15210 жыл бұрын

    nice teaching with very basic concept unlike many just simply dump out formula without explaining :D thumbs up for that

  • @royminsukkim9182
    @royminsukkim918210 жыл бұрын

    This lecture is really better than my university professor. I really appreciate it.

  • @eqwerewrqwerqre
    @eqwerewrqwerqre Жыл бұрын

    Amazing video. Every 13 years later this has explained projections better than my linear algebra book (admittedly skipped all calculation instruction in favor of waiting until inner products were defined, but then it just went straight to subspaces!). Thank you for your amazing information, my ancestors praise you

  • @squared8290
    @squared82902 жыл бұрын

    Love, love, love these videos!!! Can't express how grateful I am for them. Can't wait to finish these and pursue more and more. So generous of Sal and the team! One thing that I hope people find interesting is that there's another way of arriving at the formula for the scalar multiplier of v for the projection of x on L. I think of it as first determine the length of the projection, then ensure it's directed appropriately. The length to me is simply x cos(theta) where theta is the angle between x and v. But we know that x cos(theta) is then just v dot x divided by the length of v, which in the numerical example yields 7/sqrt(5) as the required length of the projection using his example vectors for v and x. Then to find the right direction of the projection vector, it must be some scalar c times the starting vector of L, v, to yield the projection. And c times v must have that length v dot x divided by the length of v which we calculated as being 7/sqrt(5) using his example vectors as stated above. Solving for c gives you v dot x divided by (the length of v times the length of v) which is just (v dot x) divided by (v dot v) which is exactly what Sal arrived at as well with the resulting vector being [14/5, 7/5]. He just got there using the difference of vectors and leveraging the resulting normal vector to the line and this version outlined above doesn't, felt a bit more intuitive to me, just focusing on the projection itself using cosines.

  • @udayshankars5734
    @udayshankars57348 жыл бұрын

    Thank you for the series of these amazing lectures. This helped me a lot to brush up and understand more about linear algebra, so a big thank you to you Sal!!

  • @leafslizer2376
    @leafslizer2376 Жыл бұрын

    I don't think I have ever been so surprised how easy a concept could be explained. I've struggled with understanding formulas and the books explanation of projections and with info from this video noted down. I'll never forget it :) Thanks for guiding us all toward a more rich understanding of math Sal & khan team

  • @Murf_Workshop
    @Murf_Workshop10 жыл бұрын

    Thank for the upload. My instructor's explanation was a little tough to follow, and I am usually able to understand him pretty well, but your video helped out a lot.

  • @jar0bi
    @jar0bi9 жыл бұрын

    thanks sal it was killing me not knowing where the equation for a projection came form

  • @hannabethhansen9362
    @hannabethhansen9362 Жыл бұрын

    I succeeded in my uni only thanks to Khan Academy!!! Ty so much! Love, Hannabeth

  • @christoferkalda1396

    @christoferkalda1396

    Жыл бұрын

    tuupur Christofer

  • @pussiestroker
    @pussiestroker11 жыл бұрын

    I needed a refresher (like this one) on projections for me to write a hit detection/test on an arbitrarily-oriented rectangle.

  • @BoZhaoengineering
    @BoZhaoengineering4 жыл бұрын

    Linear algebra is my favorite topic. As I am engineer , this topic is the fundamental of infinite element method or called an application of it. Thinking of the car we drive daily, we actually benefit from this topic .

  • @behrampatel4872
    @behrampatel48728 ай бұрын

    Love it ! Its worth mentioning that V-hat is a normalized vector and that the scalar c when multiplied by a normalized vector (v hat) gives us the vector projection of x onto v. cheers, b

  • @gurra1351
    @gurra135110 жыл бұрын

    You're like one million times better at explaining this than my teachers!! Thank you alot, I'd be so lost if it wasn't for Khan Academy :D

  • @FskLeO
    @FskLeO14 жыл бұрын

    Great video!!! Helps a lot!!

  • @JagadeshRaoThalur
    @JagadeshRaoThalur7 жыл бұрын

    thank you for your awesome explanations.

  • @zainthemaynnn
    @zainthemaynnn3 жыл бұрын

    awesome, I went through three other videos and they threw me a magic scalar formula without explaining why :) sal never disappoints

  • @theghost3133
    @theghost31337 жыл бұрын

    Thank you Khan Academy for your free online courses!

  • @habesha9779
    @habesha977912 жыл бұрын

    thanks man that was really easy to understand

  • @user-qh1nh3ty7k
    @user-qh1nh3ty7k9 жыл бұрын

    Thnx a lot SIR....I really foumd it utile...wish the best from you

  • @jatirijhatjhat
    @jatirijhatjhat2 жыл бұрын

    thank you!!!! Really helpful!

  • @What-ef8wj
    @What-ef8wj4 жыл бұрын

    Love the graphs

  • @chrischatergoon3207
    @chrischatergoon32075 ай бұрын

    PERFECTLY EXPLAINED.

  • @TZAHISTRULOVICH
    @TZAHISTRULOVICH12 жыл бұрын

    as usual- life saver!

  • @johnphilipangeles1825
    @johnphilipangeles18255 жыл бұрын

    Thanks for helping me in my EE class :D

  • @WaCKafAce
    @WaCKafAce12 жыл бұрын

    Thank you so much.

  • @ianordonez5267
    @ianordonez526711 жыл бұрын

    Thanks a lot!

  • @jsquaredm
    @jsquaredm5 жыл бұрын

    Could you also find the angle between the two vectors and then just multiply the vectors magnitude by Cos(theta)?

  • @creativefla
    @creativefla14 жыл бұрын

    its very helpful thx

  • @SuperSciFy
    @SuperSciFy4 жыл бұрын

    I wish my professor explained it this way.. 4 wasted lectures lmao, instead of a simple 14 mins explanation

  • @biswabhanupuhan7036
    @biswabhanupuhan70364 жыл бұрын

    Thank you Soo much.....

  • @canetguy
    @canetguy13 жыл бұрын

    Thank you for the video, it is great. My only suggestion would be to add the tag: orthogonal.

  • @basmaal-ghali9174
    @basmaal-ghali91748 жыл бұрын

    Thank you

  • @proboyrulide
    @proboyrulide13 жыл бұрын

    mate ur a legend

  • @fairy_19
    @fairy_1911 ай бұрын

    Old but gold ✨✨

  • @19-gouthamkumarreddy58
    @19-gouthamkumarreddy584 жыл бұрын

    I watch explanations of you only.....as you explain what I want exactly,but even one video is there like this....which explains what I want

  • @MONYSIRRourkela
    @MONYSIRRourkela7 жыл бұрын

    Impressed

  • @tedtdu
    @tedtdu13 жыл бұрын

    Never buy books of projection matrix, just listen what the man are talking about!!Thanks again.

  • @l3aIIin23
    @l3aIIin238 жыл бұрын

    thanks

  • @shivasharma8306
    @shivasharma83062 жыл бұрын

    Linear Algebra Comeback season

  • @ad2181
    @ad218114 жыл бұрын

    Sal, QR decomposition uses this process. What is QR used for? Thanks,

  • @AndyErdene
    @AndyErdene10 жыл бұрын

    Even me did understand :D Thanks

  • @kelcamer
    @kelcamer10 жыл бұрын

    You make calc so much easier :)

  • @jahitrst2863

    @jahitrst2863

    4 жыл бұрын

    This isn't calc

  • @oni8337

    @oni8337

    2 жыл бұрын

    @@jahitrst2863 he still does in his other vids tho

  • @s0m0c
    @s0m0c12 жыл бұрын

    Gracisas.

  • @creesrees6235
    @creesrees6235 Жыл бұрын

    Dont forget to mention about youtube n khan academy for your graduation speech!

  • @LAnonHubbard
    @LAnonHubbard13 жыл бұрын

    I'm going through Eric Lengyel's book " Mathematics for 3D game programming & computer graphics". I've been staring at his explanation of vector projection and it's not very well explained. This video has been a great additional resource. Thanks Sal!

  • @ssshj

    @ssshj

    3 жыл бұрын

    hey 10 yrs ago i was 10 , lol,

  • @newbarker523

    @newbarker523

    3 жыл бұрын

    @@ssshj Blimey - and I was 40. How time flies! (I am LAnonHubbard by the way but use that account rarely now).

  • @nnnn65490
    @nnnn654906 жыл бұрын

    I've done this out on graph paper and x - proj(x) does not = that orthogonal line. Just by looking at your drawing you can see that. I've watched all the videos and I have no idea how you came up with that. And what is v? Is that just arbitrary? Can someone please help??

  • @meeharbin4205

    @meeharbin4205

    5 жыл бұрын

    The projection of x going in the same direction as v with length ||x||*cos(theta), where theta is the angle between the vectors. That would cause x, proj(x) and proj(x) to make a right angled triangle. v is a given vector.

  • @Peter_1986
    @Peter_198610 жыл бұрын

    I always thought Sal sounded quite different in most of his videos older than 3 years, but in this video he sounds almost as if it were made in 2012 or 2013.

  • @Waranle
    @Waranle14 жыл бұрын

    Thank you Sal :)

  • @ssshj

    @ssshj

    3 жыл бұрын

    really 11 yrs ago , 11 yrs ago i was 9 , lol , now i have my exam in 3 days

  • @56jmoney
    @56jmoney11 жыл бұрын

    Thank you! my book gives me the formula for finding projections but doesn't show how the formula is derived. This helped a lot!

  • @ssshj

    @ssshj

    3 жыл бұрын

    8 yrs ago woahhhhhhhh i have exam in 3 days lol

  • @56jmoney

    @56jmoney

    3 жыл бұрын

    @@ssshj Good luck. I don't remember any of this.

  • @elizabethduffy1958
    @elizabethduffy19586 жыл бұрын

    Just wondering, does anyone know why he multiplied the projection equation by the original vector v at the end?

  • @MyNguyen-xu4oj

    @MyNguyen-xu4oj

    5 жыл бұрын

    Well, you should carefully watch the video again. That original vector v comes from the original formula: L=c*V

  • @tedtdu
    @tedtdu13 жыл бұрын

    Please upload Linear Block Codes tutorial

  • @AK-cy3ql
    @AK-cy3ql2 жыл бұрын

    doing gods work sal doing gods work.....

  • @karimkhan1312
    @karimkhan131210 жыл бұрын

    thank you thank you thank u thank u

  • @TheRojo387
    @TheRojo387 Жыл бұрын

    Orthogonal, I'd been calling that function "rightangle" the way I had implemented it.

  • @instaminox
    @instaminox7 жыл бұрын

    Salman may God rewards you Jenna

  • @davidmurphy563
    @davidmurphy5633 жыл бұрын

    I got very confused for a while thinking that a vector dot itself is 1. But that's only true with unit vectors, in other cases the dot is the square of the magnitude. So, the area of the magnitude, like a square box coming off the vector. Which now has me thinking: what does the determinant look like geometrically? Is it the area between the vectors?

  • @mohammedabulsoud517
    @mohammedabulsoud51710 жыл бұрын

    dam man i REALY REALY LOVE YOU best ever , finally i understand it . thanks thanks very gratefully

  • @seungholee8552
    @seungholee855210 жыл бұрын

    Thank you so much!

  • @user-hi7iy4pl8w
    @user-hi7iy4pl8w11 ай бұрын

    Thanks a lot. Even studying in 2023.

  • @jonathannielsen1247
    @jonathannielsen12478 ай бұрын

    Just for clearity it's not (x-cv)*v. Because you start in cv and go up to x, so it is (cv-x)*v however you will get the same result because they are both orthogonal to v :)

  • @jakehunt204
    @jakehunt2047 жыл бұрын

    Cheers, understand it now.... But why would I ever use this? (Other than being required to for a test). What is the application of this? Thanks very much!!

  • @ardensetiawan353

    @ardensetiawan353

    7 жыл бұрын

    If you're doing IT in graphic study, you'll find this calculation used a lot. Displaying 3-dimensional objects are actually projection to 2-dimensional surface (the screen), so each time we "render" 3D objects, we project them into 2D. While people just use library or plugin these days, it's useful to know the basic behind how it works so you can tweak it to your own desire

  • @dvda1987
    @dvda198711 жыл бұрын

    What do I get? It. I get it!

  • @sso1328
    @sso13289 жыл бұрын

    Watching the video before my maths exam

  • @pebble2259
    @pebble22596 жыл бұрын

    Say, who is this guy? He does all of the math videos.

  • @laputahayom
    @laputahayom14 жыл бұрын

    the quality of your previous video is much better then this one and i am wondering why that is (in this one your voice is echoed and sound like you are in a 'tin can' and the video is pixelly )

  • @ScilexGuitar
    @ScilexGuitar7 жыл бұрын

    How do I find the projection of a point onto a line on the form x=[x1, x2] + t[x3, x4] using the equation?

  • @noellundstrom7447

    @noellundstrom7447

    7 жыл бұрын

    you cant project a point onto a line, you can project vectors onto vectors, but by the time you read this you will probably have learnt that, oh well.

  • @theghost3133

    @theghost3133

    7 жыл бұрын

    hahahah love it when i see this answers after a while haha

  • @ScilexGuitar

    @ScilexGuitar

    7 жыл бұрын

    Haha ja det har jag. Thanks Noel :)

  • @ScilexGuitar

    @ScilexGuitar

    7 жыл бұрын

    Haha happens all the time xD

  • @understandtheuniverse2199
    @understandtheuniverse21992 жыл бұрын

    Can anyone say why on the earth we should project a vector onto another orthogonally, but not like an arch

  • @SuperNerd707
    @SuperNerd70713 жыл бұрын

    I'm learning about projections in calculus right now, but it's not taught like the linear algebra way.

  • @ssshj

    @ssshj

    3 жыл бұрын

    wow 9 yrs ago, you okay now?

  • @rohanarora3266
    @rohanarora32662 жыл бұрын

    How is the pink vector x - projection of x?

  • @tobias2688
    @tobias26887 жыл бұрын

    Is it by accident that his formula in 9:08 c = c*v/v*v reminds me of the ols formula b = x*y/x*x???

  • @mlaumusic

    @mlaumusic

    7 жыл бұрын

    The two are clearly related, I think that in OLS, the estimated Y is the projection of Y in the subspace generated by X

  • @demetriusdemarcusbartholom8063
    @demetriusdemarcusbartholom8063 Жыл бұрын

    ECE 485 UofA

  • @sukhWins
    @sukhWins6 жыл бұрын

    how do you get x - proj(x) ??

  • @That_One_Guy...

    @That_One_Guy...

    5 жыл бұрын

    remember pythagorean theorem ? it's similar to that , x is the hypotenuse while proj(x) is the adjacent, than you would need the opposite to create a triangle

  • @thepoet82
    @thepoet8214 жыл бұрын

    First comment! First view! Must be my lucky day! :-)

  • @jahitrst2863

    @jahitrst2863

    4 жыл бұрын

    Are u still alive?

  • @G_Koch

    @G_Koch

    4 жыл бұрын

    @@jahitrst2863 hahaha good question, is he still alive???

  • @amiraalias4208
    @amiraalias420813 жыл бұрын

    awesomeeeeeeeeeeeeeeeeeeee

  • @ssshj

    @ssshj

    3 жыл бұрын

    god really 10 yrs ago , guys what were u ecen thinking

  • @Kornackifs
    @Kornackifs Жыл бұрын

    gREET

  • @pushkarkumar3089
    @pushkarkumar3089 Жыл бұрын

    Instead of black background, white background would be more effective. Problem in viewing.

  • @TuesDay2k12
    @TuesDay2k1212 жыл бұрын

    whata fuck is this? xD

  • @ecompablo
    @ecompablo11 жыл бұрын

    dis sounds so wrong

  • @ssshj

    @ssshj

    3 жыл бұрын

    whyyyyyyyyyyyyyyyyyyyyyy tell me i have exam in 3 days

  • @grandorottcod1
    @grandorottcod110 жыл бұрын

    I hate the sound of this voice.

  • @Arthedes
    @Arthedes7 жыл бұрын

    isn't the scalar x dot v /(magnitude of v squared)?

  • @gulgaffel

    @gulgaffel

    7 жыл бұрын

    magnitude of v squared and v dot v is the same thing.