Sir, I have been following your content for some time now and I have to say there are so many concepts taught here that can't be found anywhere else which makes solving questions so much easier and faster. Thank you so much sir. Also a humble request, please do upload videos on pipes and cisterns back again.

@Rodha

2 жыл бұрын

Never deleted

Thank you so much, sir. This video has cleared all my doubts and your methods are much easier than the conventional methods of AM and GM.

RAVI SIR YOU ARE A GEM OF PERSON NEVER HAD A TEACHER LIKE YOU BEFORE ........ SIMPLY THE BEST!!!!!!! THANK YOU VERY MUCH😍

Super level of Questions to raise the thinking bar ! thank you for such videos!

Great level of thinking + great level of explaining that thinking = Rodha.

@Atulvermaa76

3 жыл бұрын

is that you comment on all videoss

@monishmoolya8919

Жыл бұрын

We got a stocker here

@AkshayN-rh5ek

11 ай бұрын

@@monishmoolya8919 stalker*

Awesome Content .......Thankyou Sir.

The great Ravi sir!

i donno why but directly applying AM-GM concept is far more satisfying and less time consuming than the traditional method discussed above

@devashish4690

4 жыл бұрын

true..wanted to just crosscheck if at 7:00 the answer should be 3^9? please acknowledge

@bhaskarmaniraj

3 жыл бұрын

@@devashish4690 Yes, even i got the same answer through am and gm method.

@Rodha

3 жыл бұрын

@@devashish4690 no. Right answer is 3^10

@jaiganeshbaskar9888

Жыл бұрын

@@devashish4690 The value that you got is the maximum value of (x^2.y^3.z^4) by AM-GM method but in the question they asked the maximum value of (x^4.y^2.z^3) so for this case using AM-GM method will not fetch you the result.

@sujalsonkar1657

2 ай бұрын

will you please explain how ?

Super content sir👍🙏🙏

Sir can we take ratio of x y z and then solve eqn

Great 👍 sir

Sir, a humble request, please do upload videos on coordinate geo back again.

Thanks a ton sir🌼

How can u identify the no. Is maximum or minimum? In 7th question, 2 is minimum and -2 is maximum . How please explain

The first question was easily solvable by linear equations.

interesting topic, well explained👏

Legend🤩

Thank You Sir

Since it was never mentioned but both x and y to be positive in the first question. Can't we just assume a big value of negative x and corresposing y and yield Infinity as an answer

Thanku sir

Sir in first question... Cant X be -15 and Y be 15 as 2(-15)+3(15) = 45 and (-15)² + (15)³ = Maximum Value of x²y³.

@ 7:03 ques, shouldn't the values of x:y:z (max) be 24:8:9 got it by the traditional method we did in prev ques to this one and eventually we'll be getting largest value (24)^4(8)^2(9)^3. @Rodha sir plz correct me if I'm making an error.

@avijanpaul9367

11 ай бұрын

Well it’s just the ratio not the real answer to the question

in frst ques.if we keep close value as x=7, and y=8 then we'll get maximum value....y don't this to be done

@DhanushAdns

3 жыл бұрын

Then the value of 2x+3y would be 2(7) + 3(8) = 38

this is the second lecture in inequalities🤗

Sir how is it possible that number and its reciprocal sum is =2 ifi take 100+1/100 then it is more than 100 how can it be 2 ?

@swapneelrao8276

3 жыл бұрын

Bro, read the questions carefully. Here he never said the value is 2. The "minimum value" is 2.

@Rodha

3 жыл бұрын

Min value is 2

at 17:41, min can be 0, if we put a=-1

sir se ek sec phele answer likh kar khush hota hua main

The 1st question is for maximum and 3rd question is for minimum, but we use the same rule for both. How is that possible?

@kronikevaporation6007

10 ай бұрын

Look intently. 1st question is asking for product and 3rd is asking for sum. It's maximum for product and minimum for sum.

@9:15 I got the answer as 9. through am and gm method.

@priyabratanayak4359

3 жыл бұрын

Bro can you explain the am and gm method or share some link where i can find those!!

@bhaskarmaniraj

3 жыл бұрын

@@priyabratanayak4359 You can learn it from Takshzila KZread channel.

@bond-hn4wd

3 жыл бұрын

@@bhaskarmaniraj but its not full, we can still get problem with the fact the if we got maximum of addition and minimum of multiplication, then we have to rely on his teaching.

@ankitsharma-pf3zx

3 жыл бұрын

u did calculation mistake... in gm part u have to write product as [(2x/4)^4][(3y/2)^2][(4y/3)^3] ..now u will get right

Is there any formula for (AB)min. When A+B=constant ?

@AbyjithK

2 ай бұрын

Take A=1 and B= n-1 if A+B=n This will give the min value

2:29 Max value of (x^2).(y^3) is not 243 but infinity. For instance, x=-3, y=7, satisfy the equation 2x+3y=15, thus making (x^2).(y^3)=3087, which is greater than 243... Keeping reducing the value of x by 3 and y by 2 indefinitely, thus x approaches negative infinity and y positive infinity, thereby making the answer as infinity...

@garlapatisaibhargavreddy4834

3 жыл бұрын

Actually question was incomplete. Their should be x and y are natural numbers. Hope you got it

17:37 Error... Minimum value of expression is not 64, but 0. Put a=b=c=-1.

@Rodha

3 жыл бұрын

1st read the main statement Question at 12:22. a,b,c,d are positive real numbers. Already given.

@6:15 it should be (3 raised to 9)

@parvathymarangattu7097

Ай бұрын

Yes it is 3 raised to 9

@parvathymarangattu7097

Ай бұрын

And answer will be 19683

2x+3y+4z=27 . solution is wrong. if we calculate x,y,z by normal method we get the values as x=8, y=8/3,z=3. this gives the maximum value as : 786432. but if we put your values to get maximum we get a smaller number than this.

@avinashbajpai7091

4 жыл бұрын

Bro it's (2)x + (3)y +(4)z =27 . So if we put your values the sum will exceed the constant value of 27.

@akshat9282

3 жыл бұрын

according to your values for x, y, z; the initial equation of 2x+3y+4z=27 is not satisfied