Two spherical stars A and B have densities pA and pB, respectively. A and B have the same radius, and their masses Ma and Mb are related by Mb 2Ma. Due to an interaction process, star A loses some of its mass, so that its radius is halved, while its spherical shape is retained, and its density remains pA. The entire mass lost by A is deposited as a thick spherical shell on B with the density of the shell being pA. If vA and vB are the escape velocities of A and B after the interaction process, then the ratio of Vb/Va = √(10n/15⅓)
The value of n is .......
Hello IIT JEE aspirants.......
In this video the above mentioned question is solved in orderly manner with clear concepts of Mechanics from Physics.
Here is the link for my another Channel in தமிழ்:
/ @krishnaiit-mpctutor
This channel is exclusively for the aspirants who are preparing for IIT JEE examinations that could serve as the gateway for the aspirants to enter into Top Institutions like NITS, IITS, IIITS, GFITS etc...... Welcome to the journey of love towards the Three dominating subjects: Maths, Physics, Chemistry. Here you will find the content about Rigourous Problem solving of these three subjects in English.
Each and Every books including Famous materials and Publications will be solved in my channel. Each and every question related to these three subjects will be solved in a orderly manner with the Concepts and Tricks and Shortcuts in English. To ace JEE MAINS and JEE ADVANCE examinations follow for more.....