IB Physics: Optical Resolution and the Rayleigh Criterion, Topic 9.4
Explains optical resolution and Rayleigh's criterion. Includes practical problems and applications. Also includes using a diffraction grating to resolve line spectra.
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Table of Contents:
00:00 - Introduction
00:08 - Crushing Heads and angular separation
02:48 - The Rayleigh Criterion
05:33 - Circular Aperture Conditions
09:59 - Car headlights resolution problem
15:04 - It's the Beam not the aperture
16:30 - Practical ways to improve resolution
18:21 - Hubble Space Telescope Application
21:35 - Resolvance with a Diffraction Grating
28:21 - Summary
Пікірлер: 22
you are SOOO saving me rn
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@donerphysics
Жыл бұрын
Glad it was helpful!
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Hi, at 21:07, you are using the formula \theta= 1.22lambda/b, but I don't understand why \theta is s/d. And thank you for these amazing videos it genuinely helps a lot.
@yahyahammoudeh1944
2 жыл бұрын
theta is s/d as the triangle is a right angle triangle, take the opposite over the adjacent and that is sin(theta), for small theta it is equal to sin(theta)
@justinho2807
2 жыл бұрын
@@yahyahammoudeh1944 Thanks! so it's the small angle approximation.
Great video! Thanks!
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2 жыл бұрын
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Hello Mr. Doner, It came to my attention that a portion of your older "free" videos (before the membership feature) were listed as Members-only. I wanted to ask why did this change occur, as I usually revise for exams using your physics videos since a little more than a year. I thought only the new videos you made would be for members, not the old free ones from 2013.
@donerphysics
2 жыл бұрын
Some of the new videos were set to public (i.e. Doppler Effect and Resolution) I made individual decisions for other videos (i.e. some videos could not be monetized, so I switched them to member's only videos so that they could help to garner some income.) Most of the old videos remain public but there are likely to be some inconveniences. I am now retired and have a wife and disabled daughter to care for, so this income has become important to me.
@bozkurt-wick
2 жыл бұрын
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@donerphysics
2 жыл бұрын
Thanks!
At around 20:09, why does s/d equal theta? It's obviously not a right triangle.
@donerphysics
Жыл бұрын
It is a small angle approximation that the triangle is essentially a sector of circle, and the definition of an angle in radians is the arc length divided by the radius.
@ashar4121
Жыл бұрын
@@donerphysics thank you!
Hi I would like to ask, theoretically the resolution angle is constant, or does it change if the two source points are not at infinity but at a short distance from the lens?
How come at 29:31 we are using the second order maximum? how do we know that? I get that 28.3 is greater than 2, but why 2?
@donerphysics
Жыл бұрын
We need for mN to be larger than R=998. N=900, so the lowest order maximum that will resolve is m=2.
it is easier to make... angular separation of our maxima bigger than something that's small than it is to make it bigger than something that's a little bit bigger