It's fun that you're embracing linear algebra

@blackpenredpen

3 жыл бұрын

I am trying! It's been over 14 years that I haven't done any of it, lol. So I am only starting with the computational part first and then I will get into the more conceptual part.

@ranjitsarkar3126

3 жыл бұрын

@Leonhard Euler I am a real big fan of you Mr. Euler. But I cannot subscribe your channel. Because you are faking

@aashsyed1277

2 жыл бұрын

@@ranjitsarkar3126 who?

You have the best timing!!! I literally learned this topic a few days back and always complained about how long it takes! Your third method is awesome! Thank you!

When you drew that big matrix for C that face you made was hilarious knowing we all are suffering from the inverse hahaha

@blackpenredpen

3 жыл бұрын

lol, imagine if it was a 4x4 matrix

@puneetmishra4726

3 жыл бұрын

@@blackpenredpen The third way could work for 4x4 matrix as well?

@virajagr

3 жыл бұрын

@@puneetmishra4726 I guess it will work when n is odd. When n is even, the plus minus sign would mess up.

I have no idea about the pretty 3rd method !!! Thank you 🙏!! I’ll give it to my students next monday !! Very nice !! (Like the D.I. Integrate method 😉)

@blackpenredpen

3 жыл бұрын

Thanks for liking! Cheers!

@SahilSharma-nh8tr

3 жыл бұрын

My teacher already taught me these methods 😎😎😎😎

@megauser8512

3 жыл бұрын

I like the 3rd method the most too!

i love the last one u make it look really easy i will try writting a CPP code to compute the inverse using that algorithm

The second method is best. You won't need to calculate the determinant separately if you don't have it.

There's a guy with a goat beard who holds a pokeball, has the Picasso painting The Scream and is talking about matrices... Pure Excellence! Greets from Greece!

@ytsimontng

3 жыл бұрын

And runs Marathons 🇬🇷

Another method would be from the characteristic polynomial,by writting A^(-1) as a linear combination of A and A^2

@wduandy

3 жыл бұрын

How?

@MA-bm9jz

3 жыл бұрын

@@wduandy so a 3×3 matrix has a characteristic polynomial like this A^3+a_1*A^2+a_2*A+a_3*i=0 ,multiply by A^(-1) and we get A^2+a_1*A+a_2*i+a_3*A^(-1)=0 and from there you get A^(-1)

@SimonClarkstone

3 жыл бұрын

@@MA-bm9jz How do you find a_1, a_2, a_3?

@MA-bm9jz

3 жыл бұрын

@@SimonClarkstone you compute the characteristic polynomial,det(A-x*i),but since A is a 3×3 -a1 is the trace(since the sum of the eigenvalues is the trace),-a3 is the determinant(product of eigenvalues),all those observations come from vieta's formula,a2 is a bit more tricky,is the sum of all 2nd degree diagonal minors,or just compute det(A-x*i) and those a_i will come naturaly

@SimonClarkstone

3 жыл бұрын

@@MA-bm9jz I don't know enough linear algebra to understand that unfortunately.

I just finished this topic in school , finding the inverse of 3x3 is such a pain for me because I always make stupid arithmetic blunders. Just got to be careful

I have an Algebra exam next week, really appreciate these videos you are uploading. Greetings from Chile!

I took Linear Algebra over the summer (and passed!) but I’ve never seen the 3rd way! Very useful and would have saved me a lot of time

I really appreciated the 3rd version! Many thanks for that!

@MrKA1961

3 жыл бұрын

Szerintem is ez a nyerő.

Peyam - Funniest math teacher. Bprp - Coolest math teacher.

The first way is the more "theorically understandable", but the third way is the coolest to perform. Once you have computed the adjugate, you can also ignore the last raw and column and use the centre to compute de determinant (if not previously done). So, an "all in one" method !

@iRam8UnderScore

3 жыл бұрын

Sorry do you mean removing the first column and last row? Because that works out, whereas what you mentioned doesn't work. ??

The last method is Gold. Thanks so much.

thank you so much sir, you made it look easier! I just want to ask a question, regarding the 3rd way 24:30, can I use it still when solving for determinants with 4 x4 or more matrix?

This technique applies to any sized matrix with an inverse. It is the matrix algebra equivalent of doing simultaneous equations as usually taught to students before they meet matrices.

That last trick is so cool! I wish my lecturer taught me about it!

Another way to find inverse is by using Cayley-Hamilton Theorem, which gives |A -λ I | = 0 , where I is a unit matrix. When we evaluate this determinant we get an equation of degree n , where n is the order of A. The equation is in terms of λ, so replace it with A. Voila! we get an equation with variables being the matrix and constant is the unit matrix. Multiply by A inverse and get simplify the rest o the terms to evaluate A inverse

Gracias por compartir sus conocimientos maestro redpen 💪🙌

Unfortunately, I knew this before u could upload this, but it is always love to see you. PS: You and Quang Tran look alike And I love you both. One for Maths One for Mukbangs

Watching this while doing my linear algebra homework on inverse matrices

@tomatrix7525

3 жыл бұрын

Ditto

This is AMUUUSING! thank you! i love this trick

Fourth way: apply the BPRB technique but the second matrix is not the unit matrix but this: Det 0 0 0 Det 0 0 0 Det This gives you the transpose matrix in the second example. Remember to divide the integer matrix you get by the determinant of the original. You can either divide each element, or just write a scalar multiple of (1/Det A) in front, depending what you are about to use the matrix for. This offers an insight about why there is no inverse when Det = 0 because you'd be dividing by zero... I prefer this fourth way

Gaussian elimination sucks, it’s a bit trial and error and if you take the wrong route you go into a black whole and can’t go out of it

I think I like method #3 the best for manual longhand calculation, but #2 as the easiest to program..

That 3rd method is actually very useful, thank you for showing that

The adjugate is good for rings without inverses because it always works. Though it might not be a real inverse, but good enough in a lot of places.

24:25: "It's not a new way" Title: "Inverse of a 3 by 3 matrix (3 ways)"

All the method i was knowing 😅 but i love...i taught u might have other shortcut .....the 3rd is my favourite i use it every time its easy

please note i do not think the last method applies to matrices greater than 3 x 3

As a HS math tutor, you are very entertaining!

Great! but in the second method, you could use Cofactor Matrix to evaluate Determinant easily! so I think the second method is much more faster than the first one.

the last method is the life saver!!! :))

Love your videos man❤️

This video is so good, now I'm ready for tomorrow's exam, thx a lot

I know all of the method. But, i like your way of teaching ♥️

I always used to use the second matrix. Thx for this

Sir I found 3'rd method the best .Congratulations for it .DrRahul Rohtak Haryana India

3nd way is very clever, thanks Steve!

matrices bless you man, thanks for this dead cool video. Much appreciated

Superb video brother

just happen to be taking linear right now so thanks for uploading! w00t w00t

i remember being good at matrix in college. i remember doing that second method. this was more than 5 years ago. the only chapter that gave me hope of being good at math xD

I’ve a little "improve", making the T operation over the A matrix at the first, and then work with it. You'll avoid the final arrangement for making the T. I'm based on the property Adj(A^T) = (Adj(A))^T. That's only a suggest !! ;-)

One more reason to start watching bprp is that he is now making Linear Algebra videos

I am actually looping 9:40,13:42,15:40 those charming laughter

For the 3rd method, the crossed out -4 is only used for the det. now? And can you actually start anywhere but 1,1 (where the -4 is) is easiest?

Thank you Very much!

Woohoo, I’m inverse ready 😇

@vishwanraja666

3 жыл бұрын

do you play the sims ?

a_{n}=1 a_{m}=-1/(n-m)(sum(a[j+m]tr(A^{j}),j=1..n-m)) This will give you characteristic polynomial and from Cayley Hamilton we will get the inverse This is not as fast as elimination but faster than cofactor method

You should cover pseudo-inverses!

Good presentation !

dude thanks so much perfect timing

Great video...actually Today i was trying to find some more ways to calculate the inverse of a matrix and you helped me a lot. thank you...but now I'm wondering how to compute inverse of a (n by n) matrix where, n is any unknown positive integer Please share how to do this

@blackpenredpen

3 жыл бұрын

Thank you for you comment. I think, unfortunately, once we get a bigger matrix, we have to use either method 1 or method 2..

"6 - 2 is... Why is that so hard?"...FELT!!!!

WHATTT the third way is actually witchcraft. I have been wasting my time doing the second-way smh.

I loved the third method.

It's the same matrix as the o e for the determinant trick. Is it special?

What if you have a 4 x 4 or 5 x 5 or anything like and n x n where n is greater than 3. Do we still add the two columns and rows to expand the matrix for the shortcut method ?

The third way is excellent. May I teach my students this method?

The last method is very beautiful for optimazing the inverse. I really want to use it in an exam, but i think that i need to demostrate it. Could you please help me, please? Thx

Congratulations from Brazil.

Very good...👏👏👏👏👏👏from Brazil...

Can you do proof for second method? Thank you

The 1st method that you've done is Gauss-Jordan method

The method used in the thumbnail was already taught by my teacher last year

The last one really made me happy

You should do topology or abstract algebra!

Needed this

I have a doubt on characteristic equation of a matrix..For a 3x3 matrix A , we know that sum of eigenvalues = trace of A(sum of diagonal elements of A), and product of eigenvalues= determinant of A..For a 3x3 matrix,is there any significance of sum of product of eigenvalues taken 2 at a time? (i.e. (coeff of A) )

I've always loved method two.

If you have a prime determinant, you usually end up with that as the denominator of a fraction in at least one row. If you have a compound determinant, you could have that as the denominator in one row, or you could choose to have fractions in different rows whose denominators multiply to that number. There are occasional exceptions to both the above.

I feel like a form of cryptographic key could be constructed with matrixes somehow.....maybe this will inspire me for the next week.

does the third method work for matrices with range > 3?

can somebody clarify the rigorous name of the 3rd method in order to pre-quote the method before solving the exercise.

Does this work for all matrices for n x n matrices with n > 3 ?

I don't even know linear algebra but I am watching this because it seems smart.

很久沒看你影片了，怎麼突然留鬍子了XD

The 2nd way is familiar, and the third one is rather peculiarly interesting.

I wish I watched this video yesterday. before my linear algebra final😂

Can the 3rd method be extended for higher order matrices as well? That is, copy first 3 columns and rows for 4×4 instead of 2 which is for 3×3. And then take determinant for each 3×3 matrices formed inside

@ShinichiKudou2008

3 жыл бұрын

I think that will work for sizes of an odd number (but not even number) because when a column in a square matrix of size of an odd number is shifted to the opposite end the determinant doesn't change sign.

@virajagr

3 жыл бұрын

@@ShinichiKudou2008 ah that makes sense, thanks

He : inverse of a matri- Me : *adj(A) / |A|* Adjugate ? I learned it as adjoint . Well both are same anyways so doesn't really matter

11:00 "either you like it or you hate it" Clearly hates it

like ur matrix video. thx

Just when I need it ❤😭

Question: Do all of these methods work for matrices that are larger than 3x3?

@smrtfasizmu6161

3 жыл бұрын

The first method has to work for square matrices of any size (as long as their determinant is not zero of course)

The sad part is i see this when i already completed my linear algebra course :'

"dididididida" (delete this, delete that) Love ur vids, keep going on !!

Now that you have used a blue pen, are you going to rename your channel to blackpenredpenbluepen?

Is it a coincidence that one of the rows of the inverse don't have the nasty 13 denominator, or is something deeper going on? It's suspicious to me that, in the cofactor matrix, the multiples of 13 happen to line up.

Buenas! Obrigado!

Way 3 is better if you have the determinant if not then gotta go with way 1.

i like the 3rd way the most

3rd is nice

Here's the ‘how to determinant‘ video: kzread.info/dash/bejne/hp-Cx6axn7XPm7w.html (Maybe put that link in the description, 曹?)

Cayley-Hamilton Theorem go brrrrr!

Last time was this early It was your previous video

What is the name of 3rd method?

❤