You just helped me out right now. Been really confused about gravimetric technique. Plus I really enjoyed watching you talk and wait😅. Thanks a million

I learned a lot. You explained it in a very detailed manner. Thank you so much. This video is a gold.

Great teacher , and so thankful to you sir , 🙏

how the heck are you so underrated

You better name your channel "Heisenberg".. 🗿

@samuelkandodobandaii5570

Ай бұрын

😂😂 that's right

Thank you so much...i really needed this.

Thank you so much sir. It is completely clear to me now.

I learned more from this video than I did in my high school chemistry class. Partly me and partly poor presentation methods.

The best explanation I have ever seen

@andrewjustin256

7 ай бұрын

I couldn't agree more! His video is the only video I found on KZread; there are no other creators creating this lesson.

Thank you so much for this

wow u make it easy to understand ,thank u

Thank I needed this

This is a really good explanation! What I am wondering about are some tables that I find in the CRC Handbook of Chemistry and Physics, 54th ed., (1973-1974) , that have the title "Gravimetric Factors and Their Logarithms." How do I make a correspondence between this table and what you just did? For example, the CRC table shows Weighed: Al (aluminum, of course) Sought: Al2O3 (aluminum oxide) Factor: 1.88946 Log of Factor +10: 10.27634 Reciprocal of Factor: 0.52925 Log of Reciprocal of Factor +10: 9.72366 Now, some calculation shows that the "Factor" is the ratio of the molecular weight of Al2O3 to the molecular weight of Al2. So that matches nicely with your explanation in the video. What I am wondering about is, why does this table go on to include "log of factor", "reciprocal of factor" and "log of reciprocal of factor"? These seem as if they are not needed for the sort of gravimetric analysis you demonstrated. Are these relics from the days before calculators when one had to do computations by hand?

7:07 Señor, yo tengo una pregunta. By adding water, it does compute to the memory that we are not changing the number of moles of KI, but aren't we changing the volume and thus molarity because molarity is moles divided by volume?

Thank you sir

Tooooooooo much good

Please make a video about titration method

the 0.00369 is the mol of combination for Pbi2 (Lead Iodized). My question is, how come that the 0.00369 is the mol solely for pb?? so supposedly, the mole for Pb is lesser than 0.00369, right?

@layzymarky7351

4 ай бұрын

n(PbI2)= nPb + nI let x be the moles of Pb 0.00369= x + 2x 2x