How to complete the square (when solving quadratic equations)

Let's discuss completing the square method when we are solving quadratic equations! We learn how to solve quadratic equations in 9th grade algebra but when we cannot solve a quadratic equation by factoring, we will have to use either completing the square or the quadratic formula. In fact, there's a geometric meaning behind the term completing the "square".
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#math #algebra #mathbasics

Пікірлер: 37

  • @bprpmathbasics
    @bprpmathbasics5 ай бұрын

    When should we use completing the square instead of the quadratic formula? 👇 kzread.info/dash/bejne/Z41nxriRmcqvcqw.html

  • @HeavenisnttooFarAway-

    @HeavenisnttooFarAway-

    5 ай бұрын

    What happens to the 25 that you added to the left hand side of the equation?

  • @earlthepearl3922
    @earlthepearl39225 ай бұрын

    I have never seen this “box” approach to solving for X before. Pretty cool.

  • @muneebmuhamed43

    @muneebmuhamed43

    5 ай бұрын

    btw, the quadratic formula is derived using this. There's a video by "Mind Your Decisions". It's pretty old but explains it well.

  • @HeavenisnttooFarAway-

    @HeavenisnttooFarAway-

    5 ай бұрын

    Me neither, excellent video

  • @jaspertyler4557

    @jaspertyler4557

    5 ай бұрын

    i learned about completing the square in ordinary differential equations. the most confusing math class i've ever taken.

  • @samiunalimsaadofficial

    @samiunalimsaadofficial

    3 ай бұрын

    Get ready for PDEs​@@jaspertyler4557

  • @chocolateangel8743

    @chocolateangel8743

    Ай бұрын

    It's called an area model. You can use them to do quite a few things. When you understand (and get practice with them), they really allow you to conceptualize things, so there is less to memorize.

  • @MurseSamson
    @MurseSamson5 ай бұрын

    Awesome. Thanks for the history video as well. I can see based on this how geometry lead to algebra, and eventually conundrums like "+- √x" that lead to the use of the plot graph solutions & proofs, and eventually, calculus. What a great video! Would love to see more of these historically contentious math terms!

  • @bprpmathbasics

    @bprpmathbasics

    5 ай бұрын

    Thank you so much!

  • @Monitorbread
    @Monitorbread2 ай бұрын

    this is the best math channel ever and made understanding the whole completing the square so easily. thank you so much for making these cool videos

  • @EverythingIsLit
    @EverythingIsLit5 ай бұрын

    This would have made it so much easier to conceptualize in school!

  • @toffeetheskunk6319
    @toffeetheskunk63193 ай бұрын

    damn who knew that actually explaining the concept instead of just listing steps aimlessly would make me actually fucking learn this concept 😭😭😭 thank you

  • @kambaakapanga9629
    @kambaakapanga96293 ай бұрын

    On point, not too much talking. Great video. Thank you

  • @dikdndkshxnd7864
    @dikdndkshxnd78643 күн бұрын

    Thank you thank you sooooooooooooooo much you saved me from the exam

  • @ratty_robloxian
    @ratty_robloxian4 ай бұрын

    Hey, I love your videos! You actually helped me pass my maths exam with a random exercise, and I thank you alot!! (keep the good work up, love ur channel🔥🔥💯)

  • @malforon4893
    @malforon48935 ай бұрын

    Very helpful, thanks

  • @rigbyb
    @rigbyb5 ай бұрын

    You are the best math KZreadr 😊

  • @SeegalMasterPlayz
    @SeegalMasterPlayz5 ай бұрын

    This was also visualised in my Mathematics B Edexcel International GCSE study text.

  • @RoachRider666
    @RoachRider6665 ай бұрын

    Interesting analysis

  • @AzureKyle
    @AzureKyle2 ай бұрын

    This is a neat way of doing it. Of course, you could always do it algebraically, by subtracting 24 from both sides, getting x^2+10x-24, which can be factored out to (x-2) and (x+12), giving us the answers of x=2 and x=-12.

  • @kmjohnny
    @kmjohnny5 ай бұрын

    Quadratic solution now kinda makes sense geometrically - it's just a question if I want to add or remove from x square

  • @alejandromargulis2053
    @alejandromargulis205310 күн бұрын

    Thank you, proffesor

  • @johanndohmann1281
    @johanndohmann12815 ай бұрын

    you are a genius!

  • @adamdevmedia
    @adamdevmedia5 ай бұрын

    I like to define perfect squares first and then you just use c=(b/2)^2 and see what's extra

  • @AyushTomar-wp3is
    @AyushTomar-wp3is5 ай бұрын

    The equation i.e ((1/√(x!-1)+1/x^2)! It surprisingly approaches to 0.999. For x>2 lim x→∞ I would really appreciate you if you check it and I would like to ask can this be constant which is mine?

  • @Areco777
    @Areco7775 ай бұрын

    can you please post the solution to sqrt(1/x^2 - 1/x^3) + sqrt(1/x - 1/x^3) = 1 without just squaring both side and making it very long.

  • @youngmathematician9154

    @youngmathematician9154

    5 ай бұрын

    Here is how I did it (it does use squaring both sides but it's not that long, don't worry :)) : First, let t=1/x. Our equation becomes sqrt(t^2-t^3)+sqrt(t-t^3)=1. We will now make a series of algebraic manipulations: Isolate sqrt(t^2-t^3): sqrt(t^2-t^3)=1-sqrt(t-t^3) Square both sides: t^2-t^3=1+t-t^3-2sqrt(t-t^3) Cancel the t^3 terms and isolate 2sqrt(t-t^3): t^2-t-1=-2sqrt(t-t^3) Square both sides again: t^4-2t^3-t^2+2t+1=4t-4t^3 Move everything to the LHS: t^4+2t^3-t^2-2t+1=0 Notice our LHS looks a lot like t^4-2t^3-t^2+2t+1, which we know is equal to (t^2-t-1)^2 since we worked it out earlier. This motivates us to introduce the substitution t=-y. Our equation then becomes y^4-2y^3-y^2+2y+1=0, which factors as (y^2-y-1)^2=0, which is equivalent to y^2-y-1=0. Solving this quadratic equation gives us y=(1+-sqrt(5))/2. Since t=-y=1/x (our substitutions from earlier), we have x=-1/y. Therefore, x=-1/((1+-sqrt(5))/2)=-2/(1+-sqrt(5)). Rationalizing the denominator gives x=-2/(1+-sqrt(5))*(1-+sqrt(5))/(1-+sqrt(5))=-2(1-+sqrt(5))/(-4)=(1+sqrt(5))/2. Hence, x=(1+sqrt(5))/2 or x=(1-sqrt(5))/2. However, we have to reject the second solution since it makes the second square root in the original equation a complex number. Therefore, the only solution x=(1+sqrt(5))/2, which just so happens to be the golden ratio!

  • @Momolaranya
    @Momolaranya4 ай бұрын

    im not confused any longer

  • @kavinesh_the_legend
    @kavinesh_the_legend5 ай бұрын

    And now I'm confused

  • @APUS_NUNN
    @APUS_NUNN5 ай бұрын

    ... Und jetzt noch den Zusammenhang zwischen x=2 und der Abbildung... bzw x=-12 und der Abbildung 😮.....

  • @channelbuattv
    @channelbuattv5 ай бұрын

    why do we always assume that x is greater than the number?

  • @zemyaso

    @zemyaso

    5 ай бұрын

    Graphs are not gonna be 100% accurate. If x was or = the number, then just draw the x accordingly. This is just to get the idea of where completing the square comes from.

  • @channelbuattv

    @channelbuattv

    5 ай бұрын

    @@zemyaso When people draw (a±b)² sometimes they assume either a>b or a

  • @bprpmathbasics

    @bprpmathbasics

    5 ай бұрын

    It doesn’t matter. I could have done a smaller square first then a bigger one. 😃

  • @channelbuattv

    @channelbuattv

    5 ай бұрын

    @@bprpmathbasics Divide by 2 or multiply by ½?

  • @blissard96
    @blissard965 ай бұрын

    ! warning do not trust this guy !