Honestly, I have asked at least 50 engineers and professors, "How does a modern charger/adapter work? Why is it so much lighter than the old ones? How does it cool down after fully charging the battery? " Surprisingly, not a single one could answer. As if they have never learned how SMPS works. Then I had to tell them how it works. You are the first one who explained it correctly and simply, plus added a few things more than I knew. Thank you. I hope you get a million subscribers. Then next time, please show the inside of a a broken (old) charger/adapter to make it even more exciting. If I could give you 5 star rating, I would have given you 7 stars.

That was the best explanation of a high frequency smps supply I’ve ever seen. Tyvm. Your a great teacher.

Detaiyed and wonderful explanation, thank you from Turkey.

Finally I understand the works behind this circuit. Thank you teacher.

excellent video from FBX Learing and Haseeb Electronics. i am really greatfull to you both.

It's the BEST explanation I've seen. I loved the way you explained it step by step AND built up the circuit diagram step-by-step. Having the entire diagram to start off causes confusion.

Give me a better understanding of an sm c circuit. Many thanks, section by section description is very helpful.

From the input to the output part of the explanation plus the professional illustration of the schematic is really awesome. You are an exelent teacher. Keep It Up. Thanks and more power to you.

This is best explanation I have got on the concept. Thanks a lot looking for more stuffs from you and your crew you guys are great.,💯💕

The world's best teacher thanks

It is indeed an Excellent Vlog about SMPS

Very useful and informative.. thank you

Way of teaching is excellent

Good explanation, but with a few faults, which I point out below: 1. The full wave bridge rectifier does not 'eliminate' the negative half cycle of the supplied 220v power as described but it 'inverts' it so that both half cycles are now positive. A half wave rectifier would have eliminated the negative half cycle resulting in more output voltage ripple and a bigger capacitor to smooth out the ripple. 2. The electrical efficiency of circuit is primarily because the 7805 regulator in the conventional circuit is in fact a power dissipating series resistance conducting the main load current that wastes power. 3. Another primary advantage of the high frequency convertor, is as described, the elimination of the LARGE and HEAVY low frequency voltage step down transformer with silicon steel laminations with a small high frequency transformer made of a ferrite powder core reduces power dissipation. While the small size results from the high frequency as described, the increased efficiency however results primarily from the replacement of the conventional series regulator by the feedback circuit operating at high frequency.

@evansetyawan1990

Жыл бұрын

bro, I want to ask, is the current coming out of the base a negative current?

The best teacher nice explanation sir

Actually, this is the best explanation i have ever come across in terms of the working principle of phone charger. Well done, Bravo dude💪

Best explaination ever.... My students will love you bro....

This was gold! Thank you for being a great teacher.

Very well explained , appreciate your effort , keep making more such informative videos - thanks a lot !

Thanks for your explanation, very clear and easy to understand, I hope you'll make more videos like this, and basic electronics. More 'amps' to your channel.

Great video.

Supper .... explained well.....expect more vediods....👍👍👍

You should do more videos like this. Excellent explanation.

@fbxlearning8725

3 жыл бұрын

More to come! You can suggest us, as well !!!

Very good and understanding. It is helpful for my engineering project.

@fbxlearning8725

3 жыл бұрын

Great to hear!

Excellent video...Be Blessed🎉

Very good explanation & clearly I am understanding .Thanks

Good explanation...expecting more..

@fbxlearning8725

3 жыл бұрын

Sure 👍

in depth explanation. Also, nicely explained.

this was great I never understood the purpose of the auxiliary winding. now I have a much better idea.

@d614gakadoug9

7 ай бұрын

In converters that use an integrated circuit for control the auxiliary winding is normally used to provide power for the IC. The IC can start up through a high-value resistor from the rectified AC input, but it would waste a lot of power to keep the IC going that way. Once switching starts the aux winding keeps the control IC powered. These self-oscillating circuits aren't common in better quality products because they don't perform as well. Their real advantage is that they are cheap and simple.

This is a great video for smps beginners. Hope you intend to go further on smps

🙏🌾💓very nice teach sirji valubal lesson continue sir poor stundent new electronic fild nice help🙏🙏

Much appreciated sir. Thanks a lot for very good explaining sir

YOU SIR MADE ELECTRONIC SIMPLE AND INTRESTING THANKS 😊

you are the best big thanks from Iraq

Thank you sir for the good explanation.

very clearly explanation,good teacher.

Very informative sir. Thank you 🙏

I search this type of knowledgeable video about how circuit perform any action. I can't find and lastly I found this one but some video post on this channel related to this I expect more to understand all types of circuit easily about how the circuit work.

Thank you for this vidéo, good explain to this circuit. Good job

tq sir.. you are a great teacher,

Wow this is a very nice technical educational video...thank u very much

Nice video tutorial on how smps works. More power

Very cool, much more efficient I think with my limited understanding.

Very good explanation ! Thank you.

Very nice explanation, thanks sir

WONDER SIR ONLY FEW CAN MOULD OVER MANY COULD MAKE EVICT THE THIRSTY LEARNERS....OUR BLESSINGS, IF WE THE INDIANS LISTEN SUCH LECTURES MAKE IN INDIA WOULD NOT BE A DREAM.......

This is veyr good !!! Thankyou for the explanation ❤

@fbxlearning8725

3 жыл бұрын

Glad it was helpful!

Very useful video sir....and. Good explanation

Please help us with signal amplification in a clap switch sir we really appreciate your work

Very good information

Nice explanation .Thanks sir.

Very useful & knowledgeable information

you've earned yourself a subscriber!

Good way of explanation Please continue sir

@fbxlearning8725

3 жыл бұрын

Glad you got interested.

Love your explanation thanks

Best video , thank you.

Bravo🎉👏👏 Happy new year 2021

@fbxlearning8725

3 жыл бұрын

Thank you! You too!

@PianisticArdour1105

3 жыл бұрын

@@fbxlearning8725 🙏

Very clear. Thanks

Great job, thanks

Excellent explanation

Thank you so much for this video. Very informative and more than that very very in depth , accurate and very well analyzed . One question : what is the usage of the resistor connected in parallel , just under the zener diode . and why parallel not in series . Thank you again .

@fbxlearning8725

3 жыл бұрын

If you analyze closely, then the 100 Ω, resistor is in SERIES with the zener diode. It limits the current flow through it. The zener is marked 4.2VZ. The other diode in the bottom you see is the opto-coupler LED. However, this LED is fabricated inside a 5 or 6 pin package. The LED's forward bias drop of 0.8V (typically), is visible across the 100 Ω resistance as well. This in turn lifts the -ve potential point of zener by 0.8V, thereby adding up to the zener breakdown voltage (in this case 4.2V). Hence output Vo now becomes 4.2V + 0.8V = 5.0V. Hope you understand it now.

@farhaadfarhaad497

3 жыл бұрын

@@fbxlearning8725 Thank you so much for your reply . I think I need to study and concentrate more on the issue .

@edinfific2576

2 жыл бұрын

@@fbxlearning8725 That resistor doesn't do so much limiting of the zener current as much as it shunts zener current away from the opto-coupler. If the zener current got too high, the optocoupler LED would burn above 50-60mA. Since the OC LED is in parallel with the resistor, this resistor actually INCREASES the zener current (due to decreased total series resistance.

Very Nice explanation sir. First secondary you mention is auxiliary winding i think. Please make video on working of 50w LED Driver/power supply circuit, constant current, primary side regulation without optocoupler and with IC. Thank you in advance.

@fbxlearning8725

3 жыл бұрын

Yep, you are correct. First secondary is the auxiliary, ancillary, subservient, subsidiary. Choose a way you want, to describe the behavior :-) We will follow up this request. Ok, we will create in a separate video to explain operation of SMPS regulation without feeback opto-coupler. Just to brief you quickly, the switching mechanism remains the same, but APPROXIMATE regulation happens at the primary. The N1:N2 coil ratio does the rest at secondary. Thanks for your feedback & suggestion.

Deserve a Like & Subs

Спасибо за объяснение!

Nice Explained

Nice video, thanks for sharing, like it :)

Good. Thanks 🙏🙏🙏🙏🙏

Very helpful video for me as a student . But sir,,, Is this type of Small and modern transformer is available in "open electronics market" to buy separately ?

Best explanation sir

Thank you very much,but is it ok to use a transistor instead optcoupler, and what determines the frequency of the oscillator circuit please

Thank you very much

thank you sir you are awesome. one's again sir. please sir I want to learn more about the transformer coiling. the position of the coiling. positive and negative of the transformer. starting of the primary. starting of the auxiliary. nd the secondary. please sir am having this problem help me out sir thank you nd God bless you.

Very nice

Thank you so much.

Very nice explanation. One thing you forget to tell. The capacitor value near T13001 Transistor. You have written it there but it is not clear and can't be read. Please specify. Thank you very much.

Please make one video explaining how should we pick values for our components when designing our own circuit.

Thankyou so much sir🙏🙏

Very good, comrade!

@fbxlearning8725

3 жыл бұрын

Glad to hear from you.

Already clarified. Thx

Thanks for your 6v or 5v smps circuit I got more knowledge please give me the details of components in13003flyback aera

bravo bravo ..........

Very good video.

Very very nice explain

one of the explanation ive seen

Good explanation. So if you *double* the secondary voltage and *change the zener* to 18.2 volts you can convert this circuit for use as a miniature _laptop_ charger.

@fbxlearning8725

2 жыл бұрын

😃 Absolutely. You got the point. Play around with secondary voltage and zener values and get any desired output. But there is a catch. The amount of current that you can draw out of this circuit. Laptop charger needs more current (rather a steady current). I did not touch on that part yet. Probably left it for some other discussion.

@edinfific2576

2 жыл бұрын

You would need a much more powerful input transistor and output diode(s), plus a larger transformer and output capacitor.

U are a gd teacher. Pls can I get 50v/2A from this type of SMPS.If so,how. Tnx.

very nice

Sit, why the current from the winding can be pass the capasitor and triggered the basis of the transiator? Thx

This circuit needs a good transformer that does not saturate over high frequency and current. A special attention is needed over Foucault currents on high frequencies too.

@fbxlearning8725

9 күн бұрын

Yes true. I will publish a page or video to explain the calculations involved in designing the flyback transformer.

Supper 😁😁👍class

Hello sir, excellent explanation. There's just one thing bugging me what is the reason for placing a 100 ohm resistor in parallel to the optocoupler diode?

@fbxlearning8725

9 күн бұрын

It limits the current flow through the zener.

good video

Thanks.

Nice video

Thank u sir

A nice concept sir, a small doubt wt is the fuse rating

@fbxlearning8725

2 жыл бұрын

I did not touch base on the fuse requirement and design. Because it need a detailed explanation and I kept it for another session. For now. the fuse rating depends on the Operating Current. The current rating of a fuse is typically de-rated 25% for operation at 25ºC to avoid nuisance blowing. For example, a fuse with a current rating of 10A is not usually recommended for operation at more than 7.5A in a 25ºC ambient. Moreover, the fuse rating is decided by load current as well.

bro, I want to ask, is the current coming out of the base a negative current?

How can we decide the values of the component used in this like resistors and capacitors ?

A small correction is required. The output voltage is shown as 10V but the Zener voltage 4.2V plus photocoupler diode voltage add up to 5V so the output voltage should be 5V. Perhaps you meant 10V is the maximum voltage with feedback removed but should be explained.

@evansetyawan1990

Жыл бұрын

bro, I want to ask, is the current coming out of the base a negative current?

sir can you share the circuit diagrom which contain the ratings of all the components including the transformer