How to find all the solutions, full video: • comparing cbrt(x) vs l...
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Пікірлер: 14
@neilgerace3554 ай бұрын
Because ln x increases more slowly than any nth root, eventually. If the index of the root is a general positive real number n, we get no real solutions for n e. As n approaches +inf, the lower solution approaches e and the higher one approaches +inf.
@leonardobarrera28164 ай бұрын
lamb w funct???
@SiphamandlaNgcobo-mu8uk3 ай бұрын
Ok but how do you determine that mathematically instead of graphically? Please answer that sir.
@BurningShipFractal4 ай бұрын
What about in complex numbers
@cegexen8191
4 ай бұрын
they don't fit the xy plane
@maheshkushwah84144 ай бұрын
-(-2)= +2 but why
@maheshkushwah84144 ай бұрын
(-1)×(-1) =+1 but why
@mynameisbakr4 ай бұрын
I guessed correctly!
@bochar52154 ай бұрын
Plz (√2)^(√2)^(√2)^... = X
@user-ip9dw4bg5k4 ай бұрын
Wow
@_Utechpro_4 ай бұрын
Pleeeeeeeaaase prove this identity😭😭😭, am not able to solve it: (sin³A + cos³A) /(sin A + cos A) + sin A cos A = 1 This question is suppose to be done without applying a³+b³ formula and vice-versa Solve from L. H. S I am currently in 10th standard 😁✌
@afj810
4 ай бұрын
multiply numerator and denominator of (sin^3A + cos^3A)/(sinA + cosA) by (sin^2A -sinAcosA +cos^2A); it's basically the same steps as using the formula but technically you're not using it
Пікірлер: 14
Because ln x increases more slowly than any nth root, eventually. If the index of the root is a general positive real number n, we get no real solutions for n e. As n approaches +inf, the lower solution approaches e and the higher one approaches +inf.
lamb w funct???
Ok but how do you determine that mathematically instead of graphically? Please answer that sir.
What about in complex numbers
@cegexen8191
4 ай бұрын
they don't fit the xy plane
-(-2)= +2 but why
(-1)×(-1) =+1 but why
I guessed correctly!
Plz (√2)^(√2)^(√2)^... = X
Wow
Pleeeeeeeaaase prove this identity😭😭😭, am not able to solve it: (sin³A + cos³A) /(sin A + cos A) + sin A cos A = 1 This question is suppose to be done without applying a³+b³ formula and vice-versa Solve from L. H. S I am currently in 10th standard 😁✌
@afj810
4 ай бұрын
multiply numerator and denominator of (sin^3A + cos^3A)/(sinA + cosA) by (sin^2A -sinAcosA +cos^2A); it's basically the same steps as using the formula but technically you're not using it
@_Utechpro_
4 ай бұрын
@@afj810 😂 I understood 😉
desmos :)