Did anyone else start to get nervous when he didn’t remove his 1&9 for the example half way through

@patricklinford689

9 ай бұрын

I may have started yelling at my screen.

@bloodsausage6635

9 ай бұрын

When he asked if he had the 1 9 domino I got a bit nervous 😅

@RenameJames

9 ай бұрын

I was sure he was going to go with it then discover it broke the puzzle before realizing.

@Anne_Mahoney

9 ай бұрын

OOOH yeah. And it nearly bit him, too -- but fortunately he remembered just in time.

@janerobson2297

9 ай бұрын

I know I was shouting at the screen

a 4x4 in 1 hour. This will be a must watch

@cv507

9 ай бұрын

144 ^??°

@jimi02468

9 ай бұрын

If "digits per unit of time," how fast he figures out digits was the same for 9x9 grid, it would be five hours long video.

Simon: Its not biforcation if I did it in my head Also Simon: fills 90% of grid in head

@Nitrammful

9 ай бұрын

It is a small grid 😂

@Ennar

9 ай бұрын

Meanwhile, every single proof by contradiction is bifurcation. The whole thing is completely subjective.

@sjm6280

9 ай бұрын

So according to Simon, if I write down 3+5=8 on a piece of paper it is a sum, but if I do the maths in my head then it isn't... maybe then it becomes a square root

@Ennar

9 ай бұрын

@@sjm6280 the point is, as I said in my comment above, that acceptable bifurcation is a subjective thing. Most of us will say that if you prove something by contradiction it's ok, but if you randomly fill in number and explore aimlessly, it's not ok, even though if you encounter a contradiction, technically, it's a valid proof by contradiction. So, putting in an objective restriction such as "I'm allowed to bifurcate as much as my memory allows" is reasonable.

@SsSHardt

9 ай бұрын

@@Ennar It is valid, but it gets funny when Simon says that "Bifurcation i would never ever do that it contradicts the fun in the puzzle and we might miss the setters magic" in every video he solves, and then ends up biforcation "in his head" in every puzzle. Simon just loved to make things alot more complicated than they are and its a beauty to watch. Just dont deny the biforcation. Embrace it.

Myxo here! This was an unexpected feature :D I Love Sleeping came up with the idea and we worked on the puzzle together. Simon, there was indeed a path through without (almost) bifurcation! It's possible to determine what digits (from A,B,C,D,5) have to go in all the cells without determining the total first, and then using parity to resolve it. But I am very impressed with your ability to see that all early in your head.

@David_K_Booth

9 ай бұрын

Fascinating puzzle! Well done to you and your collaborator.

@v.sandrone4268

9 ай бұрын

as a lover of Australian wildlife, I thank you for your service.😊

@RyanAtOptimism

9 ай бұрын

I'd really love to see this path! I hope Simon demonstrates it on the channel. Or maybe Myxo, you could post the path somewhere?

@dargonflames7127

9 ай бұрын

I loved the parity bit at the end. That was a beautiful way of clearing the puzzle. great work and I loved it.

@chris5619

9 ай бұрын

​@@RyanAtOptimism I'm not sure if this is the intention: But what I saw at that point in the puzzle was - once we know there is a 5B combo in r34c1, we can ask if it can go in r4c1. That would put the 5 in the bottom row with the purple C. Since r4c2 is in A, that would make row 1 and row 4 the same digits. That puts the 5 in row 3 and the 34/B in row 4. The next thing I noticed was that r4c2 could then simply not be a 2. That makes A 46, which just solves everything at that point.

Simon finding out that R1C4 can't be 6 using the most intricate logic when he could have considered that 16 < 17 is classic.

@techie_nerd_au

9 ай бұрын

The same thing happened multiple times. "B can't be 2".... well, 5 + a V domino means that the purple C will always be the 7/8/9 in 17/18/19. So the moment 17 gets ruled out, C automatically becomes 8 or 9.

@GeekRedux

9 ай бұрын

Shortly followed by backing in to ruling out 7 from r4c3 when he could have considered 5+5+7 < 18 or 19.

@killdyouback

9 ай бұрын

He has two modes, incredibly picking the most incredible and beautiful logic built into the puzzle, and missing the most obvious answers and getting there anyway by sheer power of brute mathing.

@nagranoth_

7 ай бұрын

That's Simon for ya. If there's a more convoluted, difficult way... he's going to find another even more difficult one...

Simon if you think I am going to watch you solve a 4x4 sudoku in one hour instead of starting my homework, you are absolutely right.

Rules: 06:24 Let's Get Cracking: 07:25 Simon's time: 50m07s Puzzle Solved: 57:32 What about this video's Top Tier Simarkisms?! Three In the Corner: 2x (56:33, 56:36) Maverick: 2x (06:53, 06:55) ​Scooby-Doo: 1x (07:34) And how about this video's Simarkisms?! Sorry: 7x (14:18, 14:57, 15:33, 29:30, 30:53, 37:05, 39:40) Obviously: 6x (02:30, 08:24, 17:59, 32:20, 33:01, 33:07) Ah: 6x (01:39, 31:08, 37:53, 44:22, 48:02, 55:50) Hang On: 5x (17:17, 28:05, 28:07, 38:30, 49:56) Clever: 4x (39:20, 39:23, 55:30, 58:16) Shouting: 4x (03:07, 04:17, 05:31, 06:08) In Fact: 4x (35:31, 51:44, 52:34, 57:51) Unique: 3x (00:23, 06:19, 06:39) Goodness: 2x (48:42, 49:11) Axiomatically: 2x (08:43, 52:54) Beautiful: 2x (22:49, 33:49) Fascinating: 2x (57:05, 57:45) By Sudoku: 2x (09:56, 32:22) Wow: 2x (50:37, 50:40) Cake!: 2x (04:57, 06:11) What on Earth: 1x (48:20) Stuck: 1x (56:51) Lovely: 1x (05:31) Break the Puzzle: 1x (34:55) Incredible: 1x (04:52) Bizarre: 1x (00:19) Surely: 1x (37:25) What Does This Mean?: 1x (11:28) Have a Think: 1x (20:15) Pencil Mark/mark: 1x (11:52) Most popular number(>9), digit and colour this video: Ten (38 mentions) Two (60 mentions) Blue (4 mentions) Antithesis Battles: High (8) - Low (3) Even (8) - Odd (4) Row (49) - Column (38) FAQ: Q1: You missed something! A1: That could very well be the case! Human speech can be hard to understand for computers like me! Point out the ones that I missed and maybe I'll learn! Q2: Can you do this for another channel? A2: I've been thinking about that and wrote some code to make that possible. Let me know which channel you think would be a good fit!

@kiwi5675

9 ай бұрын

Wow, this is so cool! How long did it take you?

@illv3

9 ай бұрын

Missing “ah” at 23:34

@jaimearriagada1907

8 ай бұрын

@@kiwi5675 computer code (probably a long time to write the code though)

@KaeraNeko

8 ай бұрын

@@illv3 isn't that just part of the following "actually?"

@pfaffmaq6584

8 ай бұрын

Wow this is such a cool bot

Simon: "one thing I will not do is bifurcate!" Simon 5 minutes in the future: "in the world where N is 18, we know that this is a 1-7 pair..."

"It's not bifurcation if you fill in the entire grid in your head to realize it doesn't work out!" 🤣

"I think were gonna find n is 20, because.. it's such a beautiful number." pure logic

@jdyerjdyer

2 ай бұрын

I went down that rabbit hole to the extreme, sort of. I did switch to using a unique letter for each of the first two rows cells, which allowed me to get all the way to the end with the three unresolved dominos in columns 1, 2, and 4. Unfortunately I couldn't see a way to disambiguate it at this point and then I saw the logic Simon had used showing that a cell in row one and row two had to be both the same digit and yet it couldn't be the same from the logic, so I knew I'd eliminated a possibility somewhere. I was so close, though.

16 cells? One hour? This must surely be the highest cell-to-minute ratio in a long time

@rgoyal107

9 ай бұрын

Also interesting that for most videos it would be a cells/minute ratio, whereas for this it would be a minutes/cell ratio. 3.6+ at that. A 9x9 would need a 5 hour solve for that kind of ratio.

@Ennar

9 ай бұрын

@@rgoyal107 you know that both cells/minute and minute/cells are valid ratios?

@Anne_Mahoney

9 ай бұрын

Does anybody remember the last time a 4x4 produced an hour-long video? It was April Fool's Day -- 2022 maybe? -- and it was Mark solving. Very, very funny.

@rgoyal107

9 ай бұрын

​@@EnnarYeah, my bad. I meant in most puzzles cells/minute would be a greater than 1 value. And in this puzzle minutes/cells would be greater than 1.

@Ennar

9 ай бұрын

@@rgoyal107 that is true, yes :)

Loved this. A real feat to not only come up with a ruleset that can provide a 4x4 grid that takes an hour to solve, but then to actually execute the idea this well too. Brilliant work

Normally when you're explaining the puzzles, I can follow along and understand but this one I was trying to understand but I was not getting it. This is the puzzle that broke me 😂

I was surprised that once Simon got a 5 he didn't immediately tell that D had to be odd in order to make the top two rows add up to an even number (which is two times N).

@buggy879

9 ай бұрын

I was shouting that at my screen

@captainufo4587

9 ай бұрын

Simon is the sort of guy who develops a new branch of algebra with irrational numbers to figure out that 2+2 = 4.

@fulltimeslackerii8229

9 ай бұрын

years of complex sudoku has taken its toll

@haroldoreilly9262

9 ай бұрын

I also found it interesting that he also did not notice that when he placed the 5 r1 had 3 numbers=10 and r2 had 2 numbers=10 so high A + low C = high C the combinations that work are 8+1=9 or 6+2=8

@petergerlagh9858

9 ай бұрын

The 7 in r2c2 was also much easier with oddness/evenness logic. Could have saved him a lot of time.

19:08 Separate colours for each individual digit helped fill out most of the grid into sections, then slowly whittling down the options to find which digit had to missing broke open the finale. Very nice idea to make such a small grod contain so much

Did it in 16 minutes. I have never been that much faster than Simon, now I feel proud of myself.

@Brandon37_

Ай бұрын

That's insane, this would take me many hours to solve (then I would give up)

I'd have to call bifurcation on Simon, and I did essentially the same thing to disprove the 9 in r4c3, except that I can't visualize as much in my head. I just couldn't find the intended trick, so I settled for the solve using that bifurcation, and then watched hoping to see Simon show me the better way. I guess I'll upgrade my solve to successful since Simon's was pretty much the same. :)

This channel has been in my recommended for a while, and I thoroughly enjoyed this video now watching one of these videos! It's a great break from a lot of the fast paced content on youtube, and you really get to think while you are watching the video which is always good and a lot of videos don't give you time to think nowadays. Definitely going to be watching more of these!

@lizzyvv447

8 ай бұрын

Welcome to the club!

This took me ages because I made it too complicated for myself. Once I asked the question "how many ways can you make 10 in 3 digits" I went from stumped to solved in about a minute. This is a real good puzzle. Kind of kicking myself for taking so long to realize the incredible structure behind it. More specifically, I had long since realized that X=18 or 19. R1C3 is a 5 (I forget how I came to that conclusion) so the top row is 10 + R1C4, making it 8 or 9. In addition R4C3 is also that same 8 or 9. I just didn't put together that as a result, this made rows 1 and 4 and columns 3 and 4 take up all the ways you can make 10 in three numbers, the two using a 5 were taken, and that R4C4 had to be the lone shared digit between the remaining ones. ie. a 1, which removed 9 as a possibility.

@SomeRandomGuyOnYouTube

9 ай бұрын

That is nice. I wish Simon had seen it. I was stuck at that point and didn't really find an elegant solution.

@davidarrant

9 ай бұрын

exactly, very elegant. pink +10 forces 1 in the bottom corner, and solves the puzzle. Great puzzle, loved it.

@rhysbyt

9 ай бұрын

OK that's really nice. I was scrolling the comments trying to find a satisfying solution for this step and finally found yours. Thanks a bunch for explaining it so well.

Now Simon has awesome brain power. He causes those digits to flower. But I've ne'er seen before Someone solve four by four And take anywhere close to an hour. Seriously, though, Simon, that was a toughie. Great work!

solved in 18:24 - did a lot of coloring in the top two boxes until I narrowed the sum down to one of two numbers. I'm not sure what the best way is to proceed from there, as I ended up taking educated guesses for the lower half once I found the first digit. interesting puzzle edit: I figured out the way to sort out the bottom half afterwards. the color of r3c2 can't be the same as r2c1 because otherwise row 3 uses the same colors as row 2 due to the X in row 2. this was probably the actual way to clear it up. cool

When Simon pencils the D into box 1 (around 19:00), you can immediately rule out 20 as the total based on the letters in box 1. No matter how much Simon would like it to be 20. :)

@spoilers9723

9 ай бұрын

I figured it couldn’t be 20 on the understanding that the rules implied the numbers 1-9 would appear, including 5. So once you know every box has an X that’s over But that interpretation of the rules turned out to be wrong

@julianvilonen5712

9 ай бұрын

Isn't 20 immediately ruled out with the knowledge that the 2 V's must be distinct? The X in C2 implies that R1C1 and R2C1 must sum to 10 (as all the boxes, rows, and columns sum to the same number), and then R1C2 and R2C2 can't sum to 10 because of the X in R2 and the fact that the V's are distinct.

Took me about 2 hours, but I got there in the end. Basically had no digits other than the 5s placed until the very end. Worked in terms of high/low colour pairs adding to 10 (e.g. dark blue + light blue = 10, dark blue > 5, light blue

When I was studying linear algebra, I once set up and solved a 15x15 matrix to determine the magic square (up to a multiplicative constant!). I'm almost tempted to do the same thing here.

I think Simon overlooked that he had one X in every box, and that that meant that the two other digits would sum to the same total (either 8 or 9) in every box. It would have eliminated 5 from box 4 pretty early (since it would repeat column 3 to get to the right total), and I think you could deduce that the 8/9-total there had to be the same as the one in box 1.

@cathybryant5119

9 ай бұрын

Yes, that's how I did it. There were pairs of digits that added to the "outie" (n-10). I gave each digit its own colour. Knowing the pairs that added to 10 and the pairs that added to the outie, I was able to solve it pretty quickly once the 5 was found in row 1.

Just noticing as I read the rules- each row and column is unique- it does not say box. This is my lawyerly mind, not my logical one, at the helm.

So amazing, Simon. An amazing puzzle, and I could not look away as you were solving. On the topic of bifurcation: I believe that the definition that you (and Mark) seem to have settled on is "if I can see it in my mind then it is not bifurcation." This is a bit hard on some of us who are not as good at visualizing things or running through maths and other matters in our minds. I am so very visual that I sometimes have to actually see something - not just see it in my mind - in order to determine its accuracy. Nonetheless, I think that it is a valid feature of pure logic to use if-then to eliminate options. That does not make things bifurcation, in my view, no matter if you write it down or do it in your mind. Otherwise I would have to admit that every single solve of a sudoku or other "logic" puzzle is bifurcation for me. If-then is legit, I believe, and requires no apology. (I am pleased that most of the comments I have read have not scolded you for bifurcation or even questioned it - well done, sudoku world.) Thanks, Simon, a fascinating hour spent in your company yet again.

After getting the 5, it was all quite easy. There was no need to consider parity. The minimum value of N was 18 (not 17 as you suggested). This is because you'd assumed in C2 that 6 could go with 1, but the 6 would make blue 14, so orange would be 23, so the minimum is 10 + 6 + 2. Similarly, the maximum was 22. However, once you have the 5, in R1, the maximum comes down to 19. Therefore hi C is 89 and lo C is 12. This makes lo B 34, and hi B 67. Working this through, you end up with hi A also 67, so N=18, and the rest is just a matter of ensuring you don't repeat a set of digits. This was quite a fiendish little beasty. I can't recall the specific deduction I used to get N, but it was quite simple, and related to the unique sets. Unfortunately, replaying my solve didn't include any pencil-marking which would reveal what I was thinking at the time. I did have 34 and 12 in the first two cells, rather than 24 and 13, and I got that by eliminating 3 from R1C2. There was some problem with R1C2=3 and R2C3=6. It may have been effectively the same restriction you spotted, although it certainly wasn't as convoluted.

@Chillerkarpfen

7 ай бұрын

After N = 18 it also immediately follows C = 8 from the top row, R1C2 = 1 (from the sum of top two rows, other fields sum to 35), and the whole upper left solution from the relationship R1C2 = 5 + R2C1 (the column and the square containing R2C2 differ by 5, so must the complement set of fields) resolving B and then the rest is trivial.

You're a rockstar, I enjoy watching you solve these increasingly vexing puzzles.. you had eliminated the 1+9 from column 3 in the bottom right box, but didn't try the 2+8 that would have solved the remainder of the puzzle until you'd done some rather impressive brute forcing in boxes 1 and 3... but still. bravo! Keep making these, and we will keep watching them and throwing popcorn at our screens.

i've been binging a few of those video, usually trying myself then watching a few minutes when i'm stuck to get the point i've been missing, but here i completely gave up

Ah i definitely need to get back into this channel and this is the perfect way to start. will watch when im home

I solved it!!! In... 210 minutes lol. I must admit, listening to you solve puzzles while handling tasks around the house is very different from pausing at the start and solving it on my own. Completely fascinating and painstaking. Thanks for goading me into bizarre puzzles I have no background with, my brain is thoroughly exercised now hahaha ❤

This is probably the first puzzle ive watched you solve where i was completely lost and after wwtching someone solve it, theres no way i could now do it

The step that D in r1c2 isn't 2 (or 4) has been on the board for about (edit:) 15 minutes, since r1c3 = 5 is deduced :) Simon even comes close with observing that the sum of the top two rows must be even, but then he phrases it in a very convoluted way. Instead, we can simply observe that the top two rows are AA+BB+CC+D+5, and as each AA, BB, CC is 10 which is even, D+5 must be even.

@MisterIncog

9 ай бұрын

yessss this!

Simon saying he not gonna bifurcate, got me trying from 40:00. What I did is looking at the column 2&3 realising R1C2 must be odd. Then realising R2C2 can’t be 6, else it will create a sum more than 18

Oh, this is such a clever puzzle! I'm impressed that it solves uniquely.

@I_Love_Sleeping-Leeor

9 ай бұрын

Thank you! :)

At 48:49 when you have the 345 in c1r4, you can rule out 5 because 24 is then canceled due to then 3 numbers in the 4th and first row being the same. Causing a repeat in rows since the rows have to be the same value the 4th number in both rows would also have to be the same. Which if the 5 was used in c1r4, then you get 5 plus 6 plus 8 or 9. This breaks the row from not being able to be 18 or 19. This gives you the 5 in c1r3. Always love watching you solve these.

Simon...says "I refuse to bifurcate" and then bifurcates his way through the rest of the puzzle.

@tovekauppi1616

9 ай бұрын

He very clearly states that he only considers it bifurcation if he has to write it out to work it out. He doesn’t do that. Instead, he works it out in his head, then writes it out to show *us* why something doesn’t work.

41:13 Another way to see this is if you add the x dominoes with the 5 and the V you get 30. And you know the sum has to be even.

It took me a while (about 70 mins), but my strategy was to colour the top of the grid (after making Simon’s similar deduction that they all had to be unique) and then seeing how that fell into the lower half. Really tricky puzzle for sure!!

very entertaining video as a whole. insane puzzle too

My first try of a solve, worked out heaps of different logic, got stuck, watched a bit of the video up till you proved the 5 then finished it off!! Love this channel!!

@lukehudd5619

9 ай бұрын

And my first 3 in the corner was so exiting!🎉

I think I'm gonna give this a try first, but I fully plan on needing to watch the video to solve it!

@I_Love_Sleeping-Leeor

9 ай бұрын

Good luck! As you can tell by the video length, it is not an easy puzzle.

Simon really has a knack for marking cells in the most convoluted way. Sp far (20:55) I think we have blue and pink b/c. and the orange and white A, B and D.

@srwapo

9 ай бұрын

I didn't watch this solve, but I did color the cells to indicate they were specific digits AND I used different colored lines to indicate that the two cells the line joined summed to the same value as any other two cells joined by that line. And pencil marked, of course.

@terracottapie

9 ай бұрын

Usually in this scenario I make the V digits A, B, C and D, and their counterparts on the Xs are E, F, G and H.

Solved it! Hooray! Usually I feel too intimidated to try these prior to watching the video. Attempted solving with x at a fairly high value, and felt it was just too hard very quickly. Dropped to the right x value by luck and pushed through quite fast with trial and error. Thanks for that :)

I spent an hour proving various thing about what various cells could or couldn’t be but I never found the trick that you did to not row 1 column 3 was either a 5 or a complement. But I had already narrowed down the top right cell to not be 9 and had proven N was either 18, 19, 21, or 22 so it couldn’t be 20. Most of my deductions were from the relationship between r1 c2 and r2 c2. After ages of no more deductions I had to give up and watch your video, but when you made your deduction I immediately knew it was a 5 because I had already disproven N being 20 and thanks to all my other deductions the puzzle had no more resistance and everything fell into place. The pivotal thing for me would be knowing N was at least 18 and the top right cell couldn’t be 9 so once the 5 got placed the top row gave me N=18 and the top right cell was 8 which permeated across the grid. Great solve and I had a wonderful time solving with help from your 1 deduction.

31:36 I spent a lot of time searching for sums that can be the same X + low, V + high, and X + high + something

what saved me from the guessing and checking was i noticed the top right digit in the top left box had to be odd due to the fact that there were 3 other 10s and an odd in the top 2 boxes but the sum of all the digits in the top 2 boxes had to be even as it was 2x the amount each row/column is set to

4x4? I'll give it a try! Saw the video length... well, or maybe not 😅

When trying the puzzle I came up with a crazy reasoning why the total cannot be 16. Of course there would have been an easier way, but I still like it. There are only 8 different ways that 4 different digits sum to 16, Howevrr, only one of them includes a 9. But Since 9 would appear in a row and a column, there need to be two different ways that four digits, including 9 sum up to 16.

@kupopo1

9 ай бұрын

That's similar to my approach. I enumerated all the ways to make sums from 17 to 23 (excluding 20, for obvious reasons, and others because there weren't enough to be unique) and found the only sum that permitted enough combinations with elements satisfying all the (explicit and hidden) X/V sum rules. Once I got the sum, the rest fell out pretty quickly.

Wow that was an impressive solve of a an impressive puzzle.

This puzzle took me about 3 hours to solve, its crazy to watch the video and see how they solve it contrast to the way you solved it.

An hour long 4X4 Sudoku video? Oh this is going to be INTERESTING! Let's go 😁

you're doing so good omg!!!

"How hard can a 4x4 be?" *one hour and a flood of sweat and tears later*

"That's three in the corner..." I literally said that as you did...So happy to see someone have the exact same thought as me sometime!

Wish the rules had said "Fill the grid with digits _selected_ _from_ 1-9." As it was stated, it implies that you have to use all the digits.

I could never solve this but sometimes I see something a minute or so before simon and it makes me feel clever

This was one of the first puzzles featured on this channel that I actually tried solving myself (or, more precisely, the first after the disaster of trying some when I first found Cracking the Cryptic and discovered that they were, in fact, much harder than Simon made them seem). Watching this video upon giving the puzzle up is really funny to me, because I placed three digits in the first couple minutes (using logic that I can’t actually recall), and then proceeded to make very little progress for another couple minutes, subsequently staring at it without learning anything for about half an hour. I go to watch Simon’s solve, and he reveals about three dynamics I had not noticed in the first five minutes, but without placing a digit quickly at all. I haven’t finished watching this, so I’m not even convinced the logic I used to place the digits was at all sound, but if it was then the comparison between my attempted solve and Simon’s successful one would be quite funny. Edit: yep. Idk what kind of oversight happened at the beginnings of my solve, but my placed digits were in fact wrong. I think it was so early into the puzzle that I hadn’t completely understood the rules and their implications yet.

Long time viewer, this puzzle inspired me to try to solve it on stream! While I didn't manage to solve it, I'm proud that most of the first steps where the same Simon did! (I'd link my video here but it's in Italian so there's not much point I guess)

Simon: “I haven’t got a Scooby Doo” Me: “Ruh roh” Every. Time.

When we do “WHAT-IF” analysis, isn’t it the bifurcation anyway? It seems that it’s an essential part of sudoku

I havent seen someone else solve it my way. Once the beginning is done. So you determined all x,v and same numbers. You can determine that r1 amd r2 consists of 8 different digits. And the missing one is 5,6,7,8,9 which means the sume of r1+r2=[36,40] so the only options are 18,19,20. 20 is easily sort out because of b and c. And 19 follows quickly once the numbers are reduced to their posibility. How to say that alle digets are different: r1c2 cant be r1c3 because then r2c2 must be the same as r1c4. Which makes the the same sum but box 1 is now the same as r1 :)

38:49 I actually really love that you refuse to bifurcate and solve these awesome puzzles solely through common sense and maths.

first puzzle we have tried and managed to complete in under 24 minutes!

It is a Semimagic Square. The positive diagonal adds up to 18 too. But the negative diagonal only sums to 14. Amazing solve of an amazing puzzle.

At 25:32 it would've been possible to deduce that D is not 2 or 4, since its complement must be the odd number not used in the first two rows.

Amazing!!!

some insights on the general structure I gained after solving: (1) if two vertically adjacent 2x2 boxes have a digit in common, they have a vertical domino in common, and both boxes are identical to the columns (2) in our case, boxes 2 and 3 have a digit in common, so boxes 1 and 2 have no digits in common, otherwise row 1 or 2 is identical to column 3 or 4. Boxes 3 and 4 are disjoint for the same reason (3) rows 1+2 and rows 3+4 are 8 disjoint digits out of 9 with the same sum, hence the same digits (4) the vertical dominos in rows 1+2 also show up in rows 3+4

"How hard could a 4x4 sudoko be?" Me: Checks time stamp and sees its an hour for Simon. "Good lord. Well, definitely gotta watch this."

new rule; if you bifurcate in your head it isn't bifurcation.

Great puzzle. I think an easier way to get into the lower half is to think about the low digits in the dominos r34c1 and r34c4. In this way you can see (like simon did), that r34c1 has to be a 5B domino. Because 5 cannot go with the high C it has to be in r3c1. Then it is not too complicated to remove the possibilities for low AB and C in the right domino, so it has to be lowD and highA.

18:38 but I'm not entirely sure how I did that. Running through the numbers needed to min and max the totals for each row, column and box helped a lot to see which totals could be achieved through a unique set of digits in the most ways. I've saved my replay, but now I need to figure out how to view it so I can see if I actually got through it without bifurcation (I'm highly suspect).

@jacobcombs1106

9 ай бұрын

What is the taboo around bifurcation?

@thomasdalton1508

9 ай бұрын

​@@jacobcombs1106It's just not a very satisfying way to solve a puzzle. And, technically, if you bifurcate and guess correctly then you haven't proven uniqueness without going back and trying the other option and showing it fails, so if you think it is important to prove uniqueness then you have a bunch of extra work to do. I'm not sure how many people care about proving uniqueness, though.

@jacobcombs1106

9 ай бұрын

@@thomasdalton1508 ah I see, what I've been doing and calling bifurcation isn't bifurcation then. Bifurcation in this context is exploring one possibility to the exclusion of others? I had been using the term to describe how if I realize there are only two possible combinations through logic using corner marks to show one and center marks to show the other until I find one breaks and then I can either control delete or shift delete erasing the disproven path. That would not meet the criteria for the taboo bifurcation since it is validly disproving the other path before committing to the correct one? For example this puzzle once I'd proven in my mind logically the sum of the rows columns and boxes must be 18 I logically worked my way to the realization I needed a five somewhere in the top half and there are only 2 valid cells for 5. So I corner marked 1 as 5 and center marked the other as 5 and began filling in corner marks with valid possibilities to make everything 18 following the Xs and Vs with the 5 in that spot and center marking the valid combinations for the 5 in the other spot. Quickly I worked out there was no valid combination for putting the 5 in box 2 because I would be forced into a repeated combination by the Xs and Vs and I deleted the invalid path. Eventually I had the top buttoned up and found myself in a similar bifurcating path on the bottom where it was either a 1/5 or 1/3 pair in r4c1 and r4c4 which meant an opposing pair of pairs in r3c1 and r3c4 to reach my sums and I used center marks to show one and corner marks to show the other and began stripping away the options that required repeated combinations which eventually disproved one of the pair of pairs and left the other pair of pairs resolved. I then filled in my cells certain it was the only possible combination.

@thomasdalton1508

9 ай бұрын

@@jacobcombs1106 No, that's bifurcation. If you guess incorrectly and get a contradiction, it's completely solid logically. It is only if you guess correctly that you have arguably missed something out, since you don't actually know that the other option wouldn't have also worked.

@jacobcombs1106

9 ай бұрын

@@thomasdalton1508 ok so it is indeed the guessing and arbitrarily excluding one of the paths without actually disproving it that makes it taboo bifurcation, so I feel like my method where I work both options in parallel which will always result in properly logically excluding one of the paths doesn't fit the taboo as I will still always show uniqueness and not just got lucky.

This stumped me so hard, I had to watch the video.

I'm actually proud of the fact that I had a solid element of logic Simon never used. Each of the top boxes has a 10 domino and a 5 domino. If you label the other two dominos, it becomes a LOT easier to eliminate options. The problem is I still got stuck on the bottom two boxes outside dominos.

@super_7710

9 ай бұрын

I think you gotta do some magic square stuff where lows are paired with highs. I couldn't solve it myself.

@ToroHarfang

9 ай бұрын

@@super_7710 I finally got it last night! There was some minor bifurcation followed by reverse engineering the logic XD But in the end I had an actual logic path through the whole puzzle. But yeah, those summed pairs I mentioned are almost always a low/high pair where 5 and one other digit are the weird ones.

I don't know where that "3 in the corner" joke came from but I it got me laughing so hard

57:25, but the time doesn't really count because I had to watch the video until Simon put the first digit in in order to be able to solve it. I had mostly done a lot of parity work before that point, so that single digit almost unraveled the entire thing. Really nice puzzle!

Crying at him not takign out the 1 9 at the base of column 3 and thinking it was actual digits afterwards.

Took me about 55 minutes. I used the fact that the remaining 3 cells of the bottom row added up to 10 a little earlier. This basically left 3 different permutations that solved themselves when you wrote all the numbers in

Great solve. It's a bit of a Parker square analog in that all rows columns boxes and ,alas, only one of the diagonals add to 18

@I_Love_Sleeping-Leeor

9 ай бұрын

Wow! I didn't think about that! That's funny XD

I think I could only solve this by trying out all possible combinations until I miraculously stumble upon the solution

Spencer here and me and aisha listened to the birthday message today and both had a good laugh its awesome to get a little ahout out her and my daughter made brownies for me instead of chocolate cake and my favorite dinner an awesome birthday for sure

Solved in 30:04, but I was only able to deduce the row/column/box sum to 2 options, started guessing and a few digits later I was done. At least I found one correct digit without guessing 🙂

Loved the puzzle :D 10:49 for me; just a little confusion when I took colouring too far.

@I_Love_Sleeping-Leeor

9 ай бұрын

I'm glad you liked it! Well done for solving!

I am thankful 9 made a solid appearance in the video even though it did absolutely nothing for the solve.

"How Hard Can A 4x4 Sudoku Be?" Clearly not as hard as you made it. GEOMETRY!!! Completed in 21m17s.

72:14, I spun my wheels for like 20 minutes, looked at the video for the logic that r1c3 had to be a 5 (just wasn't seeing it), then looked again for a little help with box 3 (guess I just had to try and see what my options were). I still felt a bit stuck at that point, got up to do something else, and realized that I was only thinking about the columns, not how they interacted with Rows 3 and 4. Sat back down and finished it in like 1 minute at that point.

At 17:30 he had just gotten the top left domino sums to 10. There is a very useful algebra that can be done then: Call R1C3 as A and call R2C1 as B. The top two rows total 10 + 10 + 5 + A + B. Thus, 2N = 25 + A + B. Another way of looking at the top two rows is as 10 + 10 +10 + 5 + A - B (we counted the B twice but not the A at all). Thus, 2N = 35 + A - B. Those equations give B = 5 and 2T - 30 = A which gives T < 20 and gives T = 19 with A = 8 OR T = 18 with A =6. (I think I had already eliminated 17 as T at that point).

I am so happy I did this! Really amazing puzzle.. My approach was to use letters for all digits and then solve it algebraically. I got stuck coz I assumed all 9 digits must be used and I couldnt see a way to do that while 8 digits gave an elegant solution. So I came back to watch the solve and realized that was an artificial constraint in my head..

@I_Love_Sleeping-Leeor

9 ай бұрын

Good job for solving! I'm glad you enjoyed :)

Oh wow, this 4x4 took me an hour and a half. I did waste a lot of time wrongly thinking even boxes were not allowed to share a set of digits with any column or row, but still, this was very hard. And beautifully constructed!

@I_Love_Sleeping-Leeor

9 ай бұрын

Well done for solving! And thank you for the kind words :)

I wander if you could've spotted the permutations resulting in repeating digits sooner if it was considered that there are 12 unique combinations of 4 numbers, and the limitations and bounds set on the boundary of possible permutations by various discoveries when used in combination with the 12 combination knowledge.

I misread it and thought that every row, column AND BOX had to be unique. I soon broke the puzzle and had to skip forward in the video to see what I was doing wrong.

@HunterJE

9 ай бұрын

Interestingly I am pretty sure that ruleset would be impossible to fulfill. You would need 12 unique 4-digit sums (four row,s four columns four boxes), which at first glance would seem possible for 20 since there are exactly 12 ways to reach that sum in four sudoku digits. But since every cell will appear in a row, column, and box, every digit need to appear in a number of sum divisible by 3. But the exactly 12 ways to sum 20 in four digits include some digits which appear a non-3-divisible number of times, e.g. five of the sums use a 1...

@RichSmith77

9 ай бұрын

I may have misunderstood, but it seemed to me like Simon was saying a set of digits couldn't repeat in a box at 1:30, when he said his hypothetical 6,7 in row 1 couldn't repeat in row 2 in box 1, "because it would break". I couldn't see why it would break, unless he thought the set of digits in row 1 couldn't repeat in box 1? But he didn't use this thinking during his actual solve.

Splendid little logic problem. I definitely just bifurcated at the end to choose between the 67 in r2c2, but that's alright. 47:24

Good Morning from New Zealand!! Big party today David! Pot luck backyard styles bahaha, how're you doing?

"Normal sudoku rules do NOT apply" hit me like a truck.

Simon's thought process is so amazing. I wish I could conclude logic as fast as he does.

It took me 29 mins to solve. Great puzzle with a lot of mathematics involved.

In the end, instead of eliminating 4 from R3C1 and R4C1, it is easier to put 5 in R3C1 by eliminating it from R4C1. A 5 in R4C1 would force Row 1 and 4 to have the same set of digits and is therefore impossible. From there it gets easier again once you see R3C2 can't be 68 as it would force the placed 5 in R3C1 to be part of a 10 sum (because of the X and the digits in R2). The rest just falls in place from there.

Here is a slightly simpler way to proceed at 50:30 Let m be the 1s digit of the mystery total. We see from row 2 that the high A digit plus the low C digit equals m. Suppose for a contradiction r3c2 is the high A digit. This is next to the low C digit so the other two cells in the row add to 10. This places 5 in r4c1. But now row 4 contains 5, the low A digit, and the high C digit, making it the same as row 1.

I originally misread this as all rows, columns, and boxes having to have unique sets of digits.