Subscribe karke 100k karado 🫠❤️

@asxff730

4 ай бұрын

Secx.tanx - sinx + log|sinx| + c.

@Ajay_Singh

4 ай бұрын

Aadhe logo ko joke hi ni smjh aaya 😂

@Pawanmishraaa

4 ай бұрын

Are ye sab toh toh chhote mote target hai aap to 10M deserve karte ho

@ALearner-du4ls

4 ай бұрын

​@@asxff730galat hai log|tanx + tanx sinx| - sinx hoga

@uwais8816

4 ай бұрын

ln|secx+tanx|-sinx-ln|sinx|+c

* Simplify the expression: * We can use the identities tan(x) = sin(x) / cos(x) and cosec(x) = 1 / sin(x) to rewrite the expression: sin(x) tan(x) + cos(x) cosec(x) = sin(x) * (sin(x) / cos(x)) + cos(x) * (1 / sin(x)) = sin^2(x) / cos(x) + cos(x) / sin(x) * Integrate using the formulas: * Now we can integrate each term separately using the formulas for sin(x) and cos(x): ∫ (sin^2(x) / cos(x) + cos(x) / sin(x)) dx = -∫ cos(x) dx + ∫ sin(x) dx = sin(x) - cos(x) + C Therefore, the integral of sin x tan x + cos x cosec x is sin(x) - cos(x) + C Bohot Jada Mehnat Lagi hai type karne me 😅

@Dazaiosamu_hehe

3 ай бұрын

Respect 👍🏻

@chiragsoni4768

3 ай бұрын

Fir bhi glt javab aaya 😂

@user-sc2ev4on2q

3 ай бұрын

Chat GPT Zindabaad

@advitsingh1084

3 ай бұрын

Ans fir bhi galat hai bro, tune kaise integrate kar diya

@advitsingh1084

3 ай бұрын

Mera to Log(sec(θ) + tan(θ)) - sin(θ) + log(sin(θ)) aaya

Ye 2 saal wale bhaiya me mujhe apna chehra kyun dikh raha hai😅😅😅😅😅

@OnlyStudy-fz3fh

4 ай бұрын

Us bro us 😢😢

@Alok_kumar_-mp7qc

4 ай бұрын

Same bhai 😅😅

@Sh1_Hao0

3 ай бұрын

kyuki ye reel bana raha hai aur to dekh raha hai😂😂😂😂😂😂

@spearsupermanpunch

3 ай бұрын

bhai tumhara naam..............

@inconnue9212

3 ай бұрын

🙂

when you realize, this is a halwa integration qn

@Dirty_pakistan

2 ай бұрын

Yes integration by parts lagega🤓🤓

@Pwkantarpantar

2 ай бұрын

No substitution lagega

@Dirty_pakistan

2 ай бұрын

@@Pwkantarpantar bhai nahi to tum pahle hi simplify kardo integration ko easily solve ho jaayega ,substitution aur ibp mein time lagega

@satvikyadav3242

Ай бұрын

Yes fr

@satvikyadav3242

Ай бұрын

​@Vayu_Aksh no bro

Put that question equal to 'I' now solve 'I' 😂😂😂😂😂😂

@rudranshdixit9184

3 ай бұрын

Sin²x/cosx + cotx So sin²x = 1-cos²x Therefore a new expression is (secx+cosx+cotx)dx Ab to ye baccho ka khel hai koi bhi solve kar lega

@piyush560

3 ай бұрын

Arein pata hain bhai ....kyu Gyan jhaad raha hain​@@rudranshdixit9184

@DiverseDose11

3 ай бұрын

​@@rudranshdixit9184 Kon sa baccha integration khelta hai😢

@Warish..

3 ай бұрын

Bhai jab itna bataya to thoda aur bata deta​@@rudranshdixit9184

@shadow2608

3 ай бұрын

​@@rudranshdixit9184bro mera toh integral(sec∅ + cosec∅cot∅ + cos∅)d∅ aarha hai jiska solution ln|sec∅ + tan∅| -cosec∅ -sin∅ + C aarha h

Preparation ❎ Ratta ☑️

Sahi ans hai ln| secx+tanx| + ln|sinx| -sinx + C Aur last me x ke jagah theata rakh Dena 👍

@abhinavgupta2885

3 ай бұрын

kar mila ye karke job mil gai?

@varunlolage7452

3 ай бұрын

​@@abhinavgupta2885satisfaction ki tuzse ye nhi ho rha ye dekhkar

@UPSC_1NDAofficers

3 ай бұрын

❤

@upprrdimensions892

3 ай бұрын

Tumhe ye comment dekh kar jal raha hai?🤣​@@abhinavgupta2885

@neelimasoni1163

2 ай бұрын

@@abhinavgupta2885sukoon

Ans - ln|sinx|+ln|secx+tanx|-sinx+C

@Motivation24x365

4 ай бұрын

Kitne saal hogye taiyari karte hue

@lostbeatz8782

4 ай бұрын

Wrong

@lostbeatz8782

4 ай бұрын

Sin x + Log l sinx l + C

@sukanya-fk1uc

4 ай бұрын

Isko aise bhi kr sakte ln|1-cos@|-sin@ If it had to be integrated wrt to d@

@rajshreepatwa1722

4 ай бұрын

​@@lostbeatz8782sahi hai mera bhi wahi aaya hai..!

I'm in Motion institute, Integration topic tough hai but GB Sir ne ye topic hame bahut hi aasani se sikha diya 👍👌

@arushsharma4745

12 күн бұрын

Im in motion also and Ankit sir ne bhi ache se Kara diya

@ratnajain-bs8dz

9 күн бұрын

@@arushsharma4745 Ha Ankit Sir bhi ache hai Physics ke liye 👌👍

@AddOnGamerz

6 күн бұрын

bhai burmen ke 90 hints dede jo sir ne class me padhaaye the

@clone9762

3 күн бұрын

​@@ratnajain-bs8dzbhai tum online padhte ho ya offline? Mai bhi gb sir se integration padh rha hu telegram ke lectures se and cengage illustration solve kar rha hu

Others : padai ka video Me: ye bhi badminton khelta wo bhi yonex ke mehenge wale racket se😂😂

This integration: 😂😂 But Integration of √tanx : ☠️☠️ Solve this

@SuccessfulInsaanTObe

2 ай бұрын

mera answer root log(cosx) kyu a ra hai? btw i just started integration today, (2026tard) ky ham values ko root me calc kr skte he kya? like my thing came out to be integral of root (sec x d(cosx))

@subhajitnath9654

2 ай бұрын

@@SuccessfulInsaanTObe no wrong ans, again try

@SuccessfulInsaanTObe

2 ай бұрын

@@subhajitnath9654 im very new to integration, can u help me out?

@Fgr25dgs

2 ай бұрын

1/2√tanx differentiation

@Fgr25dgs

2 ай бұрын

Kal iska answer puchkar aaunga

Calculus and vector algebra was my fav chapter ❤

@user-sc2ev4on2q

3 ай бұрын

☠️☠️

@Sou1lessFTP

3 ай бұрын

Nice taste in maths.

@TanishRawat45.

2 ай бұрын

Nice

@sustarokujo1102

2 ай бұрын

💀

@idk-you.69

Ай бұрын

💀💀💀

Ans> Log(secx + tanx) - sinx + log(sinx) +c

@atharvmishra2810

3 ай бұрын

Bhaiya ans khali log(secx+tanx) +c hoga bs

@prt-tanish5547

3 ай бұрын

@@atharvmishra2810 nahi bhai apna answer recheck karo. BTW konsa saal hai prep ka?

@uniqueuser189

3 ай бұрын

​@@prt-tanish5547bro please guide me i am new in class 11th. Which coaching should I take How should I start preparation and which books to follow? How did you prepared. Which mistakes I don't have to do

@UdaySingh-rn4fx

3 ай бұрын

Comments me Dusre wale bhaiya toh kuch aur answer bata rahe hai😂😂😂

@zoravar7405

3 ай бұрын

​@@UdaySingh-rn4fx mathematics me ek X ki equation ke liye infinite number of values aa jati hai to ye to algebric me hai Phir bhi kaise nikala bta deta hu Sin.tan ko sin²/cos banaya aur cosec.cos ko cos/sin banaya Phir sin²/cos me sin² ko 1 - cos² se replace kiya aur cos/sin me let sin=t krke sovle kiya aur answer agya Log|sec + tan| - sin + log|sin| + c

The answer to this question is ln(secx + tanx / sinx) - sinx + c

@user-gv1ix3ey9g

4 ай бұрын

Bhai ans galat hai phir se chake kar lo Kyoki sin x भाग मे नही गुडा मे रहेगा क्योकि प्लस मे log sin x hai

@fa-ce_less

4 ай бұрын

Bro x ke jagah theta to tune bdla hi mhi

@rudrashroff8282

4 ай бұрын

Bhai vo bhi glat hai ans mai log|secx+tanx|-sinx-1/sinx +c hoga

@shotonandroid452

4 ай бұрын

Integration by parts??

@rajshreepatwa1722

4 ай бұрын

Sahi ans hai ln| secx+tanx| + ln|sinx| -sinx + C Aur last me x ke jagah theata rakh Dena 👍

Uss sawaal me direct product nikalo aur sin square theta ko 1-cos square theta kardo Aur dusre plus wale part me niche wale cos square theta se cos theta =t lelo phir go upar uska derivative hai phir game jaisa khelke kaam tamam kardo

No matter where u study in the future, integration is always terrifying 😂

ans : ln|secx + tanx|+ln|cosx|+ln|cosec2x-cot2x| - sinc +c

@inspirelite9030

4 ай бұрын

Wrong

Abe ooi meri personal life kyu share kar rahe ho yrr mujhse puche bina case kar dunga 😂😂😂😂😂😂😂😂😂😂😂

ln|secx+tanx|+ln|sinx|-sinx+C

@Renujikiduniya

4 ай бұрын

Absolutely correct

@JapjotSingh-fi2it

4 ай бұрын

​@@harshitvarshney4997yeh 12th mei ata h ya 11 th kyuki meri 11th khtm hogyi aur mujhe nhi ata plzz batado bhai😢

@RahulSharma-gv3ng

4 ай бұрын

​@@JapjotSingh-fi2it12th me 7 chapter integration me h, integration by parts, don't worry, it's easy to learn

@JapjotSingh-fi2it

4 ай бұрын

@@RahulSharma-gv3ng thankss😅🤧

@JapjotSingh-fi2it

4 ай бұрын

@@RahulSharma-gv3ng aur aap kya kr rhe ho 12 th mei ho?

Bro iska integration nahi hoga bcoz (dx) nhi he

@ninjagaming00007

Ай бұрын

Bro dtheta

Bhi tumhari bat suna ki background music ki bat Lamba ha madam lamba😂😂😅😅

My ans is ln|secx+tanx|-sinx+ln|sinx|+c using a simple trigonometric formula and standard integration formulas

@txa4ceas55

3 ай бұрын

Correct ✅ ☺️

Bhai dx kaha hee😂😂

@Mr.360.boy_no.18

27 күн бұрын

dtheta

Question was easy😂😂

Sorry to say if you are preparing for 2 years and still couldn’t solve this sorry but you will face failure😢….

@HITANSH_JEE2

11 күн бұрын

True

Bruhh Pehle stanx ko sinx/cosx likho aur for sin¢2x ko 1-cos^2x likhdo jisse eqn bnjaaegi integration of secx+cosx Second part ke lie cot theta ka integration krdo Basic formulaes Ez maths

Itna bi mushkil sawal nhi h ye 😂😂😂

Change tan x into sinx/cosx and cosec x as 1/sinx then ; It becomes sin^2x / cos x + cosx /sinx then: Write sin^2x as 1-cos^2x then seprate and solve and ans will be ln|secx+tanx| + ln|sinx| - sinx + c ❤

Solution: ❎ Song:✅

Relatable 😅 me bhi ques. puchne gaya tha.

Limit not difined hai answer alag ho sakta hai Acording to me- Int(sinxtanx)=> Int(sin²x/cosx)=> Int(1-cos²x)/cosx=> Int(1/cosx - cos²x/cosx)=> Int(secx-cosx) Int(secx) - int(cos)=> Ln|tanx +secx| - sinx+c Similarly 2nd part

@yashietasethi

2 ай бұрын

aur by prts ki jagah hm direct sinx tanx ko ILATE se bhi kr sakte h but usse answer differ aayega

§(tanx.sinx+cosecx.cosx)dx By using formula tanx=sinx/cosx Cosex=1/sinx So we can write it §(sinx. sinx /cosx+cosx .1/sinx We know that cosx/sinx=cotx and sin^2x=1-cos^2x So §(1-cos^2x/cosx+cotx)dx §secxdx-§cosxdx+§cotxdx ln|secx+tanx|+sinx+ln|sinx|+c😅

Joh integration padh raha hai usko bhi toh atleast 1.5 yrs ho gaye

Mene socha easy hai karte hai phir dekha to 1 ghanta lag gya phir jab dobara short dekha to pata chala vo second part cosec cos tha mene cotcosec le liya

This question answer is log|secQ +tanQ| -sinQ +log|sinQ|+c

Use integration by parts ; 2nd function:-tan=sin/cos 1st function :-sin

@PrantoHasibul-nt1xv

2 ай бұрын

UV method is also applicable

For sinx tanx = break in sin cos, 1-cos sqaure/ sin , take sin t and alag alg solve khatam Now the next funtion break in sin cos, sin se multiply upr niche, 2sixcos=dt and sin sqaure x=t Khatam

@seeker4231

4 ай бұрын

Bhai second function ke liye sirf sinx=t lelenge fir upar toh cos Hae hi

Bhaiya correction window me category change ka option nhi aa rha h

How can you solve this without a calculator? Can someone explain step by step?

Answer is:- ln | sec theta ( 1 + cosec theta ) | - sin theta + C C IS CONSTANT OF INTEGRATION OR YOU CAN SAY YOU ARE THAT “C”

@ArshSahu

3 ай бұрын

Bro d theta is not given

Easiest question 😂😂. Jee mai aisa aaye toh mja aa jaye dekhte hi ho jaarha pr sadly jee main itna tough aata

@alikarol4900

2 ай бұрын

Yeahh I learnt integration today only and I could solve this. I'm in class 11

Wo sab htao bhai ques me d theeta to hai hi nhi 😂😂 integerate kiske respect me kre

@masoodraza3386

4 ай бұрын

😂😂😂😂

@dakshmehta4498

4 ай бұрын

Common sense h bhai d theta sei krega aur kisse krega

@theraju3469

4 ай бұрын

@@dakshmehta4498 hm wo hai but mathematically to ques glt hi hua na 😂

@apurwaraut6279

4 ай бұрын

D theta valuable hai broo

@startopgaming

4 ай бұрын

@@dakshmehta4498exam me common sence nhi chalta marks katte he

Neet student hoke ye question solve karne ka ghamand hai😎😎

@prasantasutradhar2531

4 ай бұрын

Same here 😅

@Pawanmishraaa

4 ай бұрын

Aur hame Jee student hoke na karne ka ghammand h😂😂😂😂

@user-zp3mc3mi5z

4 ай бұрын

Iska ghamand hai Lekin chaar saal drop lene ka ghamand nhi hai

@ANI0_0

4 ай бұрын

Maha easy question hai

@cutedevjeet9635

4 ай бұрын

10th mai solve karne ka ghamand hai😂😂

Just use integration by parts or you can also subsitute x=pi -theta and solve fromthere

Orally kar liya 😂😂😂 ln(secx+tanx) -sinx +ln(sinx) + c

@bharatbihani6184

Ай бұрын

Rank kitni aayi bhai

@ayushshinde3630

Ай бұрын

@@bharatbihani6184 91k mains m 😓

Oh wow i remember solving this same integration as a step for a countour integration. Pyare jee ke daya the

Ans ln|sec× + tan×| - sin× + ln|sin×| + C

question me dQ nahi lgaya hai btw i am in 10th class but i like calculus

Ans: ln|secx+tanx|-sinx-ln|cosecx|+C This is the simplest question of integration...

Itna aasan question hai mind mein hi solve hi gaya waise

Integration solve karte hain: \[ \int (\sin x \cdot \tan x + \cos x \cdot \csc x) \, dx \] Sabse pehle, \(\tan x\) aur \(\csc x\) ko unke trigonometric equivalents me convert karte hain: \[ \int (\sin x \cdot \frac{\sin x}{\cos x} + \cos x \cdot \frac{1}{\sin x}) \, dx \] Simplify karte hain: \[ \int \left( \frac{\sin^2 x}{\cos x} + \frac{\cos x}{\sin x} ight) \, dx \] Ab isse do alag-alag integrals me split karte hain: \[ \int \frac{\sin^2 x}{\cos x} \, dx + \int \frac{\cos x}{\sin x} \, dx \] \[ \int \frac{\sin^2 x}{\cos x} \, dx + \int \cot x \, dx \] Pehle integral ko simplify karte hain: \[ \int \frac{\sin^2 x}{\cos x} \, dx = \int \left( \frac{1 - \cos^2 x}{\cos x} ight) \, dx = \int \left( \frac{1}{\cos x} - \cos x ight) \, dx \] \[ = \int \sec x \, dx - \int \cos x \, dx \] Ab integrals solve karte hain: \[ \int \sec x \, dx - \int \cos x \, dx + \int \cot x \, dx \] \[ = \ln|\sec x + \tan x| - \sin x + \ln|\sin x| + C \] Yeh final answer hai: \[ \int (\sin x \cdot \tan x + \cos x \cdot \csc x) \, dx = \ln|\sec x + \tan x| - \sin x + \ln|\sin x| + C \] Jahan \(C\) integration constant hai.

@Digital_Rockey72

17 сағат бұрын

Jise samjh me aa gya ho like kr de 😅

From chat gpt To solve the expression \(\sin\theta \tan\theta + \csc\theta \cos\theta\), let's break it down into simpler parts using trigonometric identities. 1. \(\tan\theta = \frac{\sin\theta}{\cos\theta}\) 2. \(\csc\theta = \frac{1}{\sin\theta}\) Using these identities, the expression becomes: \[ \sin\theta \left(\frac{\sin\theta}{\cos\theta} ight) + \left(\frac{1}{\sin\theta} ight) \cos\theta \] Simplify each term separately: \[ \frac{\sin^2\theta}{\cos\theta} + \frac{\cos\theta}{\sin\theta} \] Combine the fractions over a common denominator: \[ \frac{\sin^2\theta \sin\theta + \cos^2\theta \cos\theta}{\cos\theta \sin\theta} \] Simplify the numerator: \[ \frac{\sin^3\theta + \cos^3\theta}{\cos\theta \sin\theta} \] Since the numerator cannot be simplified further with common trigonometric identities, the expression \(\sin\theta \tan\theta + \csc\theta \cos\theta\) simplifies to: \[ \frac{\sin^3\theta + \cos^3\theta}{\cos\theta \sin\theta} \] Therefore, the simplified form of the given expression is: \[ \frac{\sin^3\theta + \cos^3\theta}{\cos\theta \sin\theta} \]

Bhai kyu IIT Naam kharab kar rahe ho 😅😅😂😂

best thing to do is multiply both side by 0 , proved

@chetanvarshney7132

2 ай бұрын

its not proving kiddo its about finding the value !!

Bro I have succeeded to 11th in 2024 but still this question is easy for me😅😅😅

Solution: 1.Write the expression in terms of sinx and cosx. 2.Convert all sinx into cosx using [(sinx)^2 +(cosx)^2 =1] 3.Divide and break the fraction (a-b/c =a/c-b/c) Remaining: secx-cosx+cosecx.cotx Now integrate... Answer: ln(|secx+tanx|) - sinx - cosecx + c

log(cosecx-cotx) + log(secx + tanx) + cosx- sinx + C Yahi aayega kya ??

@A.Random-Guy

2 ай бұрын

Bhai question dhyan se padh cotx nahi cosecx hai

answer ln|secx+tan x| - Sin x + ln |Sin x | + C

@Opmemer8820

4 ай бұрын

Yess this is correct I got the same answer 🥰

@bittombarman8207

4 ай бұрын

Yes i did it orally 😂😂😂

@bittombarman8207

4 ай бұрын

I did it oralyy 🥰🥰🥰🥰

@CricSourya18

3 ай бұрын

@minakumari7552 nhi sahi hai ... aap dekho aap kahi galti kar rhe ho

To integrate the given expression, we can start by rewriting it in a more tractable form: sin(theta)tan(theta) + cosec(theta)cos(theta) = sin(theta)(sin(theta)/cos(theta)) + (1/sin(theta))(cos(theta)) = (sin^2(theta) + cos(theta))/cos(theta) = (1 + cos(theta))/cos(theta) (using the Pythagorean identity sin^2(theta) + cos^2(theta) = 1) = sec(theta) + 1 Now, we can integrate: ∫(sec(theta) + 1) dtheta = ∫(1/cos(theta)) dtheta + ∫(1) dtheta = ln|sec(theta) + tan(theta)| + theta + C where C is the constant of integration. Therefore, the integral of sin(theta)tan(theta) + cosec(theta)cos(theta) is ln|sec(theta) + tan(theta)| + theta + C.

bro be sniffin em maths problems 💀

@neerubalamakeover9097

4 ай бұрын

Bro you chose the wrong comment section people here won't understand the humour 😭

@akshaylipare0

4 ай бұрын

@@neerubalamakeover9097 i didn't commented for the sake of attention, i genuinely felt too do so, and your point is true as well

log(tan ◇ + sin ◇ tan ◇) - sin ◇ +c is the required answer.

Correct answer is sec thetta.class 10 th walo like karo.

@raghavclass8eroll261

27 күн бұрын

Hahaha

Upon simplification, It is integral of secx . We can write is as log|secx + tanx| - ln|sinx| - sinx + c

@mayureshchaudhary8238

4 ай бұрын

Wrong

@druhindatta1976

4 ай бұрын

saaheb ji ham janat hai ki ham galat hai, bas batana bhul gye

@mayureshchaudhary8238

4 ай бұрын

@@druhindatta1976 it's not integral of secx though, that's what I was trying to say 👍🏻🔥

@druhindatta1976

4 ай бұрын

@@mayureshchaudhary8238 got it brother

answer is infinity (integrand wasnt multiplied by dx)

ANSWER:- ln (| tan(x) + sec(x) |) + ln(| sin(x) |)−sin(x)+C

Even as an 10 grader i can solve this question

Un dono ko alag alag seperate kardo change into sin and cos form, pehle wale mein by parts laga do simply and second will change into ln form :)

Separate the integral sin theta*tan theta and cosec theta*cos theta And solve separately by integration by parts🤗method its so easy😅,you won't get trapped in this part ANSWER IS ln(secx+tanx)+ln(sinx)-sinx +c and i counted 1 as a constant so i ignored it,replace x with theta🤓

Meanwhile me a 10th grader :sin aur tan saatha mai hai toh than koh sin/cos mai change karke solve kardu

@Tanishq-oj7sg

4 ай бұрын

Tan x = sinx÷cosx BTW

@vivanshaggarwal6860

4 ай бұрын

10 grade may tune galat pad liya lgta hai

@vivanshaggarwal6860

4 ай бұрын

Sin /cos hota hai

@shubham85200

3 ай бұрын

mai v yhi soch rha tha baad m smjh aaya integration hai😅

Sir woh 2nd part easily ho jata hai.... Sirf first part ko sin and cos ke terms me likho aur fir take cos as t fir integration by parts... fir (1-t²) ko v manlo

Bhai pehle dono terms ko alag kr lo second term simple hai ... Second term ko simplify kroge to cot x aa jayega jiska intigration log |sinx|+ C or Rahi baat first term ki to tan ki din cos me change kr lo aur sin ² upper cos niche phir sin ko 1-cos²x likho phr term aa jayega 1-cos²x / cos x . Ab dono ko alag kr lo 1/cos x = secx aur cos ²x / cos x = cos x aayega. Ab dono ko alag alag intigrate krenge cos ka sin aur sec ka log |secx + tanx|. Final answer : log|sinx|- sinx+log|secx +tanx| + C

@altboi7154

3 ай бұрын

galat its -sinx not +sinx

Someone please help me in maths i am in 12th please 🙏🏻🥺

d theta is not given in question how did the whole comment section integerate it anyways?

Bhaiya ek question tha.. Maine 11th and 12th me jee ka kuch bhi nhi padha but mujhe ab jee krna hi hai please aap batao ki kya kru . Mai bohot chote Village se hu mujhe koi bhi guide krne wala nhi hai

Answer- log|sec+tan|+log|sin|-sin+C

Bhai thode Capital “C” ho kya ?? Pls reply

Use by part Best method to solve integration is remember 15. Ways or type of inte. Method which ur good teacher gave u in notes Aur xam m 1 min phir last m inte ka ques ko time deena

Bhai integration se hard toh A.P G.P aur Binomial ke questn aate hai😂💀

@ram.......111

3 ай бұрын

Bhai kahi tum PNC aur probability ko bhul to nhi gaya h😅

@Socrates240

2 ай бұрын

​@@ram.......111 sab hi hard

The correct answer to this question is ln(tanx+secx)+ln(sinx)-sinx+C we are taking theta is equal to x here since I don't know how to write theta in keyboard

Ans - ln(secx + tanx) - sinx + ln(sinx)

Bhai second wala to cot x ban raha wo to ho hi gaya fir First wale ko sin cos me change karke fir divide by sec^2 x karenge to tan or sec me ban jayega and then tan^2x=sec^2x-1 use karke cos + sec aa jayega

@freenumberop

4 ай бұрын

Hmm Pura ko sin x cos x meh change karlo Sin ² theta / cos theta + cos theta / sin ² theta = 1 - cos² theta / cos theta + cos theta/ sin theta Isme substitute apply kar rahe hey Sin theta = t Cos theta = dt = Sec theta - cos theta + dt/t =Log(sec+tan theta) - sin theta + log sin x

Bhai mera to 12 ka integration me hi Brian hang ho Raha hai 😢

If u do integration by parts that is the easiest question

But still they have time for uploading videos😂😂

Answer is log(tanx+secx)-sinx+log(sinx)

Who is majorly focusing on song 😅

Separate krke solve kro phir tan ko sin ke form cosec ko bhi usi form mein likhe substitute krdo

Aayein mera cosec x aaya 😅 newbie hu kya kre 😀

Ans) ln|Secθ + Tanθ| + ln|Sinθ| - Sinθ + C (Solved by assuming to integrate with dθ given)

Ans: I= -sinø + ln|tanø+secø-cosø| +c

dono ko alag alag integrate krlo right side wala to straight up {cotx} aur left side wala {secx} aur {-cosx} ban jayega ab bas jo bracket me hai unhe integrate krlo ans ln|secx+tanx| -sinx+log|sinx| aajaega.

Jo question tune dikhaya hai us question ka ans ek line nikalata hu main😂😂😂

answer is ln(secx+tanx)-sinx+ln(sinx)+C

Bhaiya aap iss question ko aise solve kijiye tantheta ko sin/cos break karlo aur likh do sinsquare theta /costheta then sintheta ko t man lo phir aapka expression t^2dt aa jayega phir udhar aap cosec theta ko 1/sintheta kardo wo banjayega cot theta aur ha pehle integration ko break karlena aapka answer phir ayega sin^3theta/3+ln sintheta +c 😊

Bhai sabse easy hai yeah toh 😂😂

@lletsgobuddy

4 ай бұрын

Bro me maths ka board dekar aa chuka hu tab bhi yeh mere se nhi ho rha ☠️🥲 btw me to commerce student hu mujhe kya matlab

I can relate with you i am younger than you and no one of my age is interested in yoga.

@pt.prabhunarayanjha1617

17 күн бұрын

You are talking about kundalini energy am i correct

when you start to solve physics just think that you are Einstein when you start to read or doing any mathematical problem just think that you are Lavoisier when you start to solve Mathematics just think that you are Ramanujan when you start to read biology just think that you are Aristotle......Then see the magic...

@rijupaul7076

2 ай бұрын

@mehaksharma8810 do this method then see....the feeling will happen inside you makes you joyous to study

Lekin ek minute... Chota bhai 12th mein hai isiliye integration ke questions solve kar raha aur bada bhai do saal se IIT ki taiyari kar raha hai matlab woh drop year mein hai, yeh kaise sambhav hai.

Imagine people whose 11th maths is barbaad and thinking that they will do 12th in maths well

Same here jab bhi me ghar aata hu mera bhai mere liye questions ki poori book banake rakhta hai😢😢❤❤