Best explanation of this on KZread, by far. Thank you.

Brilliant explanation. Thanks so much for your awesome video.

Thank you for the very helpful video!!

This is the best explanation so far. Thank you.

@DaChemOG

2 жыл бұрын

Glad you found it helpful!

Helped alot thank u so much ❤❤

helpful video thank you!

So clear !

More than wonderful work

@DaChemOG

3 жыл бұрын

Thank you so much 😀

what a chad, if only I had you as a prof

@DaChemOG

3 жыл бұрын

Haha

thank you my friend

Thank you so much

فديو جميل جدا روعه معلومات طيبه

@DaChemOG

3 жыл бұрын

Thank you!

I am happy that I subscribe to this channel 😍😍

@DaChemOG

3 жыл бұрын

I'm glad too!

Here's what's always confusing to me: for delta g naught, since concentrations are held to 1 M , then Keq naught is ALWAYS 1, and so delta g naught is ALWAYS 0. For any reaction. So, by definition, delta g naught is a constant: ALWAYS at equilibrium and ALWAYS zero. So what the hell use is it? How do we have tables where delta g naught varies? The only way that would be true is if concentrations of all products and reactants were NOT all the same at 1 M. And here you're talking about how changing Keq changes delta g naught. Bu based on the DEFINITION of standard conditions, Keq should never vary from 1, so its ln should ALWAYS be zero, all the time. What the hell am I missing here?

@aliza5923

Жыл бұрын

At standard conditions you start with 1M .. -ve value of ∆G° implies rxn is spontaneous... So the 1M of reactants will react to form products and finally equilibrium will be attained ... .. For spontaneous rxn at equilibrium we will end up with more products than reactant .. We won't have 1 mole of reactants left Or products as reactants are reacting to form products... At equilibrium :Moles of reactants 1 .. So keq>1

شكرا يا مستر 🥰

@DaChemOG

3 жыл бұрын

You're welcome.

I liked all the information thanks

@DaChemOG

3 жыл бұрын

Most welcome

Are endergonic and exergonuc reactions at equilibrium but one favors reactants while the other favors products? Thank you for your explanation

@DaChemOG

2 жыл бұрын

Hello Dana. A reaction that's at equilibrium actually favors neither side, which is why ΔG = 0 for a reaction at equilibrium. If a reaction favors products, it is exergonic and has a negative ΔG. If a reaction favors reactants, it is endergonic and has a positive ΔG. The vast majority of reactions will lean toward one side of a reaction or another until equilibrium is established. Once a reaction reaches equilibrium, it will stay there and won't favor either side.

@hha756

2 жыл бұрын

@@DaChemOG I thought you could have at equilibrium K>1, product favored or K

useful information

@DaChemOG

3 жыл бұрын

So nice of you

Where did the RTLn(Q) came from? Is there any explanation to this relationship in this equation?

@DaChemOG

2 жыл бұрын

The spontaneity of a reaction relates to its distance from equilibrium in the following manner: ΔG = RT ln (Q/K). Higher values of Q give a more positive ΔG. That's because larger values of Q indicate an overabundance of products relative to reactants. The corrective course of reaction is to make more reactants. Similarly, smaller values of Q lead to negative values of ΔG. When Q = K, the ratio is 1 and ΔG = 0.

تبارك الله عليك ⚘

@DaChemOG

3 жыл бұрын

J'vous remercie

شكراً👍👍

@DaChemOG

3 жыл бұрын

You're welcome.

Woooooow 👍👍👍👍👍

@DaChemOG

3 жыл бұрын

Thank you!

بالتوفيق استاذي

@DaChemOG

3 жыл бұрын

Thank you!

بالتوفيق ياصديقي

@DaChemOG

3 жыл бұрын

Thank you!

موفق باذن الله 🌹

@DaChemOG

3 жыл бұрын

Thank you!

Good teacher

@DaChemOG

3 жыл бұрын

Thank you! 😃

Wow thanks ❣️

@DaChemOG

3 жыл бұрын

No problem 😊

thank you so much 😊🥰

@DaChemOG

3 жыл бұрын

You’re welcome 😊

بالتوفيق

@DaChemOG

3 жыл бұрын

Thank you!

omg thank you!!

@DaChemOG

2 жыл бұрын

No problem!!

💖

@DaChemOG

3 жыл бұрын

Thank you!

Nace 😍

@DaChemOG

3 жыл бұрын

Thaaaanks!

Top top

@DaChemOG

3 жыл бұрын

Thank you thank you

🤗🤗🤗✌✌

@DaChemOG

3 жыл бұрын

:)

Similar to E and E°

Why do T = 0 degree Celcius when delta G = delta G not

@DaChemOG

3 жыл бұрын

Hello Hoshpreet. T is actually equal to 25 Celsius at standard conditions when ΔG = ΔG° (not zero Celsius). You may be thinking of STP instead, which applies to Ideal Gases.

Justice to gibbs free energy😂

🐣🐣🐣🐣

@DaChemOG

3 жыл бұрын

:)

😃😃😃

@DaChemOG

3 жыл бұрын

:D

😄😄

@DaChemOG

3 жыл бұрын

:D :D