Why do physics classes that cost hundred of dollars and demand a commitment of 5 hours a week, less helpful than this 18min youtube video? thank god for you

@PhysicsNinja

Жыл бұрын

Thanks for the support. You’ve got this

This is awesome. Thanks for being thorough, yet concise. Keep it up!

This is far far the best explanation I got till now. Thanks man

thanks man u just saved my uni life

@tiernanomahoney3925

2 жыл бұрын

University...., I'm learning this in 9th grade.

@akbaer60

Жыл бұрын

@@tiernanomahoney3925 least overstudied south korean

Beautifully made, I love how you mention all possible cases of this question. It makes perfect sense.

@PhysicsNinja

Жыл бұрын

Thank you so much!

Wow, this is a lot easier than my professor made it out to be. Thank you so much!

Who watched this in the last week of 2020 then you are a legend, thanks dr

You did a very good job explaining Gauss' Law through a real example...Thanks man , you're a Ninja...:)

Excellent video! Made me understand Gauss's Law perfectly.

Watched you video and went back to what my professor did and it made a lot of sense to me. Thank you very much and I must say my professor teaches well too.

It all makes sense now. You are amazing good sir!

This is a super useful video and extremely well explained. Thank you so much, you clarified everything for me!

@PhysicsNinja

Жыл бұрын

Thank you so much. These types of comments motivate me to make more videos.

Brilliant explanation. I have never actually been into the world of physics, mostly programming and mathematics. Your video triggered me into learning electromagnetic fields.

@PhysicsNinja

Жыл бұрын

Thanks you. Good luck with your studies.

Superb and amazing 👌🙌😍 explanation. Infinitely many thanks to you from my bottom of the heart.

You just saved a human being from just loosing his mind thank u for existing.

Gosh! This video is perfect. I have my finals in 2 days and you saved me! This topic makes a lot more sense now. Thank you very much sir!

@PhysicsNinja

Жыл бұрын

You got this!

Hi there, you're just awesome. This was simple and clear. Thank you

Thanks for the clear and concise lesson. I haven't seen this since taking physics, and revisiting the concept for one of upper div EE courses has been rough with my professor

@PhysicsNinja

2 жыл бұрын

thanks for the comment. I'm happy the video was helpful for you. Good luck with your course.

Awesome video I was upset when saw gauss law that make confuse but finally I find this video that clearly explain to me.🙏🙏🙏 Bro

Wow... It's now that I understand this completely... Thank you.... 😊

You're a life saver. Thank you!!!!!!!!!

dude this video helped me out immensely. Thanks!

Gotta say, this is the explanation that made sense to me. Keep this up!

Thank you so much!! I was so confused and now I solve for my upcoming mid exam.

Thanks for the helpful video sir!

thank you so much, this video really helps me to understand this topic

Thank you so much! This really helped

You are the best bro. Thank you so much!!!!!!!!

Great work

hi how can i calculate the surface charge density on the inner surface of the outer spherical conductor and on the outer surface of the outer spherical conductor?

thank you keep updating please

thanks for the video. helped me a lot to understand

You're amazing. Thanks for the video!! It's very helpful.

@PhysicsNinja

Жыл бұрын

Glad it was helpful!

thank you for your amazing channel♥♥

thanks man well explained

Sir , can i please know about the potential inside the shell? As electric field is zero inside shell , the potential will be constant but would it be same as due to inner sphere or the conducting shell.?

great video

This is what I been looking for

The world's best teacher

Thank you Sir!!!! I understand now！

Thank you!

you just seem like you'd be a cool professor to have

Can't thank you enough 🙏😭

Thank you so much sir

I agree with the comments - this is great!!!!👍 👍👍👍🙏🙏🙏🙏💜💜💜

How would we find potential at the center of both spheres?

thanks you ......... thanks you..... nice explanation.

Tks nice explanation

absolute legend

Excellent

You really saved me!

so if im asked to get the EF inside the sphere what would the answer be=(? 0?

Online learning moment. So much simpler than my professor made it out to be.

When we say a sphere, are we automatically talking about a hollow object or not? I know a spade is a spade but when it comes to shpere, is it solid or hollow becomes important. Also, if the central charged object is off centre ie not at the centre of the metal shell, how it will change the calculation? Thank you ninja

you are the man

قمه الجمال والله و قمه الفهم ف 18 دقيقه بس loved that 💛💛💛💛💛

beautiful

If inner -Q and outside 3Q how is the solution change

Hocam eyvallah ellerin dert görmesin.

so helpful

you are the best

Helpful..Thanks..

@PhysicsNinja

Жыл бұрын

Most welcome!

Any reason you didn't do an example in the case of an insulating shell? Is it just not common?

Thanks.

14:40 Would you, sir, clarify how the charge outside be positive when the charge is negative on the shell?

Is the electric field on the outer shell when (r=c) is zero ???? and when (r= a) is zero too??

How would E change in the case of r being between b and c if the shell is an insulator?

@PhysicsNinja

3 жыл бұрын

If the charge is spread uniformly in the outer shell then you can still calculate using Gauss' Law. The field will be different!

thanksss!!!

Why the outer sphere dont affect in the white field (a

@PhysicsNinja

3 жыл бұрын

It’s only what’s on the inside that matters. If you would calculate the total fuel from outside shell you would find 0. It’s takes a bit of calculus to show but that’s also what you get from Gauss’ Law

sir, if a=b then how will we find the electric field anywhere inside the spherical shell??

@PhysicsNinja

4 жыл бұрын

If a=b it looks like it would simply be a conducting sphere with radius c. E=0 inside conductors. The charge would be at the surface c.

Tq for the video

Thanks a lot but how do you find the potential across two points in such a setup?

@PhysicsNinja

2 жыл бұрын

Delta V= -integral( E.dl)

I love you so much

Tanks man

thanks

todos te amamos

you are awsome :3

Do licensed electrical contractors know this or should?. I know some physics 1/2/3, Digital Systems 1 and so on. I have a BS in Computer Science but I am interested in getting the plumbing and electrical licenses (Homeowner issues....). Any advise?

@PhysicsNinja

3 жыл бұрын

Absolutely not!

nice

It was awesome But I have a doubt, what about at point b? I mean how to find E right at b point?

@bunty4763

6 ай бұрын

See case 2 heading there clearly written that a

for region two, it is still inside the outer sphere which is conducting, so how is it possible that region two does not have zero electric field?

@PhysicsNinja

Жыл бұрын

Because the is charge on the inner sphere

S I am saddam husain from india . SirMy small talk with you is that you should solve more problems like this in the book of DavyJ Griffth by putting limit in electric field and solved more such problems sir please......and please reply sir

If it is metal sphere. The r

@PhysicsNinja

2 жыл бұрын

Yes

ty

I wonder why the electric field at r=a ( conducting sphere ) equals to zero🤔

🐐

Best video ! kzread.info/dash/bejne/oq5-w9ChXbLSZMo.html Can we say (-1 Q ) charge distributed evenly in both inner and outer shell or just (-3Q)charge in inner shell and (+ 2Q) charge in outer shell.

At 2:00 are you saying that the only way E=0 everywhere inside is if q_enclosed=0. I'm pretty sure that isn't true. As you know, the integral (which evaluates to q_enclosed) can be zero but the integrand E could be non-zero in places. The implication the other way is true: if E=0 inside everywhere is zero, then q_enclosed is zero. My question is: Can you explain why in an electrostatic situation on a conducting sphere, that the electric field inside is zero necessarily. I know that in an electrostatic situation, the electric field has to be zero where the charges are (otherwise the charges would move), but why does the electric field have to be zero where the charges are not. The usual explanation in texts is by contradiction: i.e. if we had an electrostatic arrangement and we were to place another charge inside the sphere it would move if the electric field was non-zero inside, supposedly contradicting the original electrostatic situation. But by placing another charge inside the sphere aren't we changing the original electrostatic arrangement that we assumed. So we're not contradicting the original electrostatic arrangement. So it's not really a contradiction. Can you tell me where I'm going wrong with this. Thanks.

good video but I hated the many ads poped and distracted me.

But for a conductor the electric field inside is zero and therefore in the case 2 the charge is zero

@vectorial6467

27 күн бұрын

Or the inside is dielectric?

jesus. now I can show off the girls in my uni!

@PhysicsNinja

4 ай бұрын

Chix will dig it.

Hi sir this is Vikram from India, please do some problems on coupled oscillators in SHM with simple mathematics or advanced Mathematical methods.

so bad wroong

@PhysicsNinja

Жыл бұрын

Lol

hi how can i calculate the surface charge density on the inner surface of the outer spherical conductor and on the outer surface of the outer spherical conductor?

@PhysicsNinja

4 жыл бұрын

Total charge on that surface / (4*pi*R^2) The term in denominator is the total surface area of the sphere.

@amlhassan7090

4 жыл бұрын

@@PhysicsNinja ok thanks

@amlhassan7090

4 жыл бұрын

@@PhysicsNinja is there is any chance / way that i can send you a question to help me with ?