This was really helpful, thanks man

Thank you so much for this bro 🙏🏻🙏🏻🙏🏻 Respect

Kudos for the great explanation

Giving my thanks to you sir! 💙 Well explained! 🤗 💯💙

Great video, this helped me a lot. Thank you

THE BEST VIDEO EVER!!! THANK YOU!!

Bro, ngl- you're a life saver! Thanks so much for this video, man. So cool-

@saremraves8716

3 жыл бұрын

Were you solving bartleby

Very very good explanation. Thanks

thanks for the video by the way, really appreciate it

Thank you, really helped me out

Awesome explained ❤

Thank you so much sir...I was facing the problem while doing the problems on moment..now I got it..😘

Nicely explained thank u

This is great! Can you do a video explaining what happens when a bike hits a bump on the road? So essentially, like this.. but goes up the curb and then down the curb too. Does hitting that bump or bumps cause the car to slow down? Does the earth and car exchange momentum and the momentum and speed of the car reduced? Or does the car slow down as it goes up the curb (convert kinetic energy to potential energy) but then return goes back to its original speed once it for rolls back down the curb as that potential energy is returned to kinetic energy?

Thank you for including details!

thank you sir

hi , i have one doubt about the second part when horizontal force is applied at the top of the wheel . here reaction by the knife edge of curb on wheel must pass through top point of wheel for satisfying coplanar 3 force equilibrium .i always learned that normal reaction always passes through centre of the sphere . if we assume this wheel climbing on another fixed small wheel then there will be normal reaction and how can its line of action of reaction will be ?

How about if you apply the force to a moving cart ( the force applied to the center of mass) it will tip the cart or it will roll over the obstacle?

Respect : )

Sir what is the maximum height of step so that the force F required to roll the cylinder of radius R weighing W over the step without no slippage at all if coefficient of static friction is u??

Hey dude, for situation two, what do i do when the only given information is mg? which is 50kg btw

How can the speed corresponding to the so calculated F be calculated?

Can you explain scenario when wheel rotates around a shaft with diameter of X as in a real world and force is applied to a shaft parallel with ground level? Does the force needed is just start force to initiate motion and what happens than? Is the force decrementing as we progress with the wheel forward? what would be the force function curve. Does shaft diameter has an effect on the force needed? Thanks

Solve for the required value of force P to move the 10 inches (radius) ball through the 5 inches square block.

To get the force F you equated the clockwise and CCM, I think that means that the wheel is in equilibrium meaning the net turning force on it is zero. So how will the wheel go up the kerb if net turning force on it zero? Shouldn't the CWM be greater so that the body turns in the CW direction up the kerb?

@RobertoBenedettiunipg

2 жыл бұрын

Yep that way he finds the equilibrium point solving for F. If the applied F is just slightly greater then the tire will climb up

How does this change when the wheel is not perpendicular to the curb?

Friction at corner point is not mentioned here, why? I think Friction force is the cause of rolling motion

Sir what if we need to find the minimum velocity with which the object should be moving so that it is able to just climb the curb (given that the object is in pure rolling) ? I tried conserving the angular momentum about the pt of contact and the total mechanical energy before and after climbing...is that the way to go about it? Any help would be appreciated.

@PhysicsNinja

4 жыл бұрын

Good question. I will get back to you on this one.

@sakshamkoul7834

4 жыл бұрын

@@PhysicsNinja Thank you so much sir for acknowledging the comment. I kinda got the answer on a stack exchange question though. physics.stackexchange.com/questions/338644/sphere-rolling-up-a-step What I gathered from the above was that we need to conserve the angular momentum about the pt of contact...and the kinetic energy just after collision (which would be purely rotational, assuming the object never leaves contact with the curb) would provide the necessary increase in the gravitational potential energy i.e. mgh This would lead to 2 equations which can then be solved with not much difficulty Is that the right approach? Thanks in advance sir

why doesnt the normal force at the bottem of the wheel (due to gravity) produce torque?

Hey guys, I have a similar question, but the question is to find the minimum coefficient of friction at the contact point between the curb and the wheel, so the wheel doesnt slip down. Can somebody help me out?

What if no mass was given in the problem?

What is the force at point h ?

Dear Physics Ninja, May I have permission to use your picture for my presentation on wheelchairs to a group of physical therapists? I would of course credit Physics Ninja in the presentation. Thank you.

@PhysicsNinja

Жыл бұрын

Yes no problem

For the torque on the wheel why don't we need to consider moment of inertia of the wheel?

@PhysicsNinja

3 жыл бұрын

If you then wanted to find how fast it goes up ( the angular acceleration) then you would need to know the moment if intertidal of the wheel. Sum of the torques = I*alpha

@aniruddhachakrabortyindia

3 жыл бұрын

@@PhysicsNinja Thank you sir. It was really helpful

Hey I have just peeked through this video without listening to any of the audio, so sorry if the following question was already answered in the video. For part 2, is it possible to roll the wheel up the curb even if h>=R?

@PhysicsNinja

2 жыл бұрын

not possible for a horizontal force. The force would need to have a vertical component.

@GabrielConstantinides

2 жыл бұрын

@@PhysicsNinja thank you very much for this, I appreciate it alot. I hope it was not a silly question, I just noticed that the formula for part 2 seemed to allow for h>=R whereas part 1 didn't

I thought that when 3 forces act on a common point there was no torque?

I have a large 4' by 8' workbench that I want to move in and out of my garage. A wheel in each corner (total of 4 wheels), total weight of bench and contents of built in drawers is probably 600#, concrete lip to 'jump' into the garage is 1 inch high. What size wheel/casters is required for one person to relatively easily push the bench to 'jump' that lip?

@rowanationer

3 жыл бұрын

Dude youve been given the tools to work that out

@rowanationer

3 жыл бұрын

Determine what your max force is (100N?) then make the radius your variable.

In the condition when force is applied on top of the body why the force F and force due to weight are assumed concurrent? Pls reply for this question

@PhysicsNinja

5 жыл бұрын

Not sure i understand your question. Why wouldn't they be concurrent?

@varshavarsha5790

5 жыл бұрын

@@PhysicsNinja sir if at the point when the wheel is on the crub the reaction R will be having two components right?? One radial component and one tangential component so when the surfaces are smooth which component can balance this tangential component??

@varshavarsha5790

5 жыл бұрын

@@PhysicsNinja i am asking like is there any proof stating that the forces are concurrent at the point

@PhysicsNinja

5 жыл бұрын

@@varshavarsha5790 You can calculate the components of reaction forces as a function of the applied force and the weight of the wheel. I've never done this but it should have both components. You'll probably find that one of the components (or both) will vanish is some limiting cases. I think in the limit where F=0 the reaction force should also be equal to 0 and when the wheels starts to lift (N=0) the reaction force should only have a horizontal component. Hope this helps.

@varshavarsha5790

5 жыл бұрын

@@PhysicsNinja yeah sir I could get you but what force could balance the component which the R has with applied force?? Or please correct me if I am going wrong in my understanding

What if no mass was given in the problem

I am trying to work out the size of a water wheel to turn a bbq spit roast set up. I'm trying to make a home smoker with bbq wood smoke . The average force needs to turn I would say about 400lbs I need to no the size of the wheel and the size of the containers to turn catch the water and turn the gear rods. Please anyone help 🙏

Grt from india

Should be friction force on the top step

@PhysicsNinja

3 жыл бұрын

Sure but that’s where the pivot is so no torque

Why is the contact force equal to 0? is it because there is no friction coefficient given or because the normal force is 0 (which I don't understand why)?

@PhysicsNinja

6 жыл бұрын

Ana Lucia Benavente Luna the contact force is 0 only if the height of the step is 0 - no step. The normal force is 0 because the wheel will just begin to lift.

@analuciabenaventeluna3841

6 жыл бұрын

Thank you :)

reaction force at ppint h

how about plugging in numbers for an actual example, say 30kg-mass ??? thanks

@jeromecancino5261

3 жыл бұрын

Just substitute values

@kareemsalessi

3 жыл бұрын

@@jeromecancino5261 NO KIDDING !!!

@jeromecancino5261

3 жыл бұрын

Multiply that by 9.81 so you will find weight.

@kareemsalessi

3 жыл бұрын

@@jeromecancino5261 Either I don't know what you'r talking about, or you don't know what I am talking about!!!! I meant to ask him to calculate the amount of Kilogram-Force needed to pull a 30kg wheel up the step!!!

I hate when somebody explains this kinds of topic like we've never seen physics before..

@PhysicsNinja

5 жыл бұрын

Kaan Apan you’re welcome!

@kaanapan1183

5 жыл бұрын

Physics Ninja I didnt want to offend you but it is way too long i looked for this kind of problems but you explained whole topic man. Maybe shorten this videos and make another one for entire topic

@kumoriani

4 жыл бұрын

Wow

@ekt2656

4 жыл бұрын

@@PhysicsNinja Well I appreciate the extra explanation even if I am familiar with the topic already. Also if he/she is so good at physics why'd he/she need a video?

@VincentNacon

2 жыл бұрын

@@kaanapan1183 If you didn't know any better... you're basically telling us you're too stupid to understand the video. lol Asking him to make it simpler is like asking him to change the law of physic. This is pretty simple as you're gonna get. Bet you weren't expecting to see this old comment, huh? Fool.

Physics-None-Ninja:: What you are doing above is "FORMULATING", which you may well have copied from elsewhere, while trying to show that you are re-inventing the wheel. Only if you compute your numbers, using actual values, would you be "CALCULATING". In other words, that's probably a better way of concluding your video, by reaching a tangible result, in numbers, rather than beginning & ending with formulas!!!! .

@PhysicsNinja

3 жыл бұрын

Thanks for watching. My channel is about helping students set up problems and apply basic physics to solve problems. Many of the problems i present are 100's of years old, including this one. I try to put my own spin on it and present it in a way that is easy to understand. I often get to a final equation and don't plug and chug number into the problem. Instead i try to take limiting cases to make sure the results makes sense. Putting numbers into a final equation to get another number is less educational, even a child can do that.

@kareemsalessi

3 жыл бұрын

@@PhysicsNinja I suggest you try it once for each video, else, people may thing you do NOT know what you are talking about, but that you are just copying texts of others!!! Only when you utilize numbers, you'd be able to see how close your approach is to reality. For instance, a much acclaimed online-physics-professor (Von Bizen) comes up with rocket-launch-acceleration of, something like 2m/s/s, which is impossible for a rocket to lift off earth!!! Worse yet, a TWR==1.2, because he believes, as you probably do, that a TWR>1 would lift any rocket off the earth!!!!

@kareemsalessi

3 жыл бұрын

@@PhysicsNinja More clarification::: Assume you are pulling up a 30kg wheel up the stair; you plug in your numbers and come up with a required force of over 30kg-force to pull up the wheel. Only then you'd know that your formulation is wrong somewhere, and the you could try to fix the mistake; else, students may continue finding that forces above the actual wheel-weight, which makes no sense at all, because the whole physics behind using wheels is to reduce the amount of force needed to carry the load, on a flat surface, or up slopes, or up the stair!!!

@gabrielfernando1872

2 жыл бұрын

wow, I sometimes forget how psychotic ppl on the internet can be

@gabrielfernando1872

2 жыл бұрын

dude is being just straight-up lazy and ignorant...

Hey dude, for situation two, what do i do when the only given information is mg? which is 50kg btw

@saremraves8716

3 жыл бұрын

Bartleby