Finite Element Analysis on TRUSS Elements | FEM problem on trusses| Truss Problems in FEM

Very Important problem. New method to solve truss problems.
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One Dimensional Bar Elements :
1. • Thermal Load Problems ... ( Forces are applied towards left i.e opposite )
2. • Basic Steps in the Fin... ( Basic Steps in FEA)
3. • Composite bar formulat... ( Two bars parallel with spring attachment)
4. • 1D Finite Element Anal... ( Two bars parallel with spring attachment)
5. • Structural Analysis of... ( Gap between the bar and wall problem)
6. • Structural Analysis of... ( Gap between the bar and wall problem)
7. • FEM Thermal Analysis |... ( Step bar both ends fixed )
8. • FEM Bar Elements Probl... ( Tapered bar)
9. • Finite Element Analysi... ( Uniform bar with gap between bar and wall)
10. • Finite Element Methods... ( Very Important problem on bar)
11. • FEM Bar Problems |Fini... ( One End is fixed )
12. • FEM bar problem | FEA ... ( One end is fixed load applied at the another end)
Truss Elements Problems
1. • Connectivity table for... ( Three elements, connectivity table)
2. • Boundary conditions in... ( Boundary conditions )
3. • Trusses Method for Beg... ( two elements, one roller support & one hinged support )
4. • Analysis of Trusses Us... ( Two elements both end are fixed )
5. • Analysis of TRUSSES Wi... ( Three elements)
6. • Finite Element Analysi... ( Three elements, two hinged and one roller support)
7. • FEM truss problems | F... ( Two elements, One roller support )
8. • FEM Truss Problems| Fi... ( one hinged support and one roller support)
9. • FEM TRUSS PROBLEM | Ca... ( Four elements , two loads at different nodes)
Constant Strain Triangle ( CST Elements ):
1. • Isoparametric triangul...
2. • Problem 3_CST problem ...
3. • Problem 2 _ CST Elemen...
4. • Stiffness matrix for t... ( Stiffness matrix calculation )
5. • Problem 1_ CST Element...
6. • Constant Strain Triang...
7. • Two Dimensional CST El...
8. • Strain Displacement Re... ( Strain- displacement derivation )
9. • Constant Strain Triang...
Beam Element Problems:
1. • Reaction forces on a b... ( More details about Reaction forces calculation)
2. • Nodal forces and Bendi... ( SF and BM formula for different loading conditions)
3. • Find the Deflection an... ( Beam with Spring support)
4. • Analysis of Beams in F... ( UDL load entire the span of beam)
5. • Beam Problem in Finite... ( Concentrated loads )
6. • Structural Analysis fo... ( Cantilever beam )
7. • FEM beam problems | Fi... ( Cantilever beam with roller support at end, point load)
8. • Beam problem in Finite... ( Continuous cantilever beam with two supporters)
Your Suggestion
Please feel free to Contact
Email: maheshmg533@gmail.com

Пікірлер: 208

  • @satyasrikar4677
    @satyasrikar46773 жыл бұрын

    Mr Gadwantikar, your explanations have really helped me a lot. In fact, a mountainous amount of guidance I would say. You have explained way more clearer than my lecturers and finding a channel that would have all the videos of finite element method readily is a big rarity. Keep going ahead with more good stuff. Thank you very much.

  • @MaheshGadwantikar

    @MaheshGadwantikar

    3 жыл бұрын

    Thank You So Much 🙏 Srikar

  • @a38preethishn56
    @a38preethishn56Ай бұрын

    your explanations has really super in the way of teaching is god keep rocking sir

  • @MaheshGadwantikar

    @MaheshGadwantikar

    Ай бұрын

    Thank you sister 🙏

  • @a38preethishn56
    @a38preethishn56Ай бұрын

    your teaching is Nice sir Thank you very much

  • @MaheshGadwantikar

    @MaheshGadwantikar

    Ай бұрын

    My pleasure 😊

  • @user-qc6oc2no5d
    @user-qc6oc2no5d2 жыл бұрын

    you save my fem grade thank you so much sir!

  • @a38preethishn56
    @a38preethishn56Ай бұрын

    truss proble is simple to understand in the teaching sir

  • @MaheshGadwantikar

    @MaheshGadwantikar

    Ай бұрын

    🙏

  • @wocko25
    @wocko254 жыл бұрын

    Thank you so much for this!

  • @praveenjain5280
    @praveenjain52804 жыл бұрын

    Thank you so much sir The exact video which I was lookin for

  • @MaheshGadwantikar

    @MaheshGadwantikar

    4 жыл бұрын

    Ty

  • @amiduallie6225
    @amiduallie62252 жыл бұрын

    You're genius at your work bro. You make things much easier. Thanks a lot for your help.

  • @mertovski8793
    @mertovski87932 жыл бұрын

    maaannn this is gooood. i'll take an exam tomorrow. best regards from turkeyyyy

  • @akshitdhiman7494
    @akshitdhiman74944 жыл бұрын

    Exact video i was looking for...thanku so much sir😍

  • @MaheshGadwantikar

    @MaheshGadwantikar

    4 жыл бұрын

    Thank You

  • @aqmalariif2722
    @aqmalariif2722 Жыл бұрын

    Keep it up, your explaination really make me understand this subject easily

  • @MaheshGadwantikar

    @MaheshGadwantikar

    Жыл бұрын

    Thank you for your support ariif bro

  • @naveenkumarnani5725
    @naveenkumarnani57254 жыл бұрын

    Sir I'm so happy because of you I learn fem easily... I subscribed your channel along with my 20+ friends

  • @MaheshGadwantikar

    @MaheshGadwantikar

    4 жыл бұрын

    Thank you so much nani

  • @naveenkumarnani5725

    @naveenkumarnani5725

    4 жыл бұрын

    @@MaheshGadwantikar it's my pleasure sir..

  • @MaheshGadwantikar

    @MaheshGadwantikar

    4 жыл бұрын

    Thanks for your kind words and it's inspiring me lot

  • @chandrahasdeepak438
    @chandrahasdeepak4383 жыл бұрын

    Sir verygood explaination and with Goodhand Writing ❤️! Thank you sir

  • @MaheshGadwantikar

    @MaheshGadwantikar

    3 жыл бұрын

    Thank You

  • @hyderabadifoodblogger4912
    @hyderabadifoodblogger49125 жыл бұрын

    Awesome video it help me alot thank u so much and explanation is very nice

  • @MaheshGadwantikar

    @MaheshGadwantikar

    5 жыл бұрын

    Thank you so much...!!

  • @anwarseid6656
    @anwarseid66564 жыл бұрын

    Thank you so much for this knowledgeable video

  • @MaheshGadwantikar

    @MaheshGadwantikar

    4 жыл бұрын

    Thanks

  • @dessalegntassaw2796
    @dessalegntassaw27964 жыл бұрын

    Thank you !

  • @basim17609
    @basim176094 жыл бұрын

    Sir , we have skewed support so v3 is not zero, so we need to use stiffness matrix K* =T K T transpose

  • @difnadir2361

    @difnadir2361

    3 жыл бұрын

    Yes V3 is not 0,but V'3 =0

  • @ammydeep6354
    @ammydeep6354 Жыл бұрын

    Thanks sir I got seventy% marks with the help of your vedio

  • @MaheshGadwantikar

    @MaheshGadwantikar

    Жыл бұрын

    My pleasure 🙏

  • @syedinayatshah7700
    @syedinayatshah7700 Жыл бұрын

    Thankyou sir 🙏.Tomorrow is my paper and I learned from you alot

  • @MaheshGadwantikar

    @MaheshGadwantikar

    Жыл бұрын

    Thank you bhai

  • @MaheshGadwantikar

    @MaheshGadwantikar

    Жыл бұрын

    & all the best

  • @kiranbhaskar5527
    @kiranbhaskar55272 жыл бұрын

    Tq sir very neat explanation

  • @chefnabil5351
    @chefnabil53514 жыл бұрын

    you are Best tanks

  • @jidapa2969
    @jidapa29693 жыл бұрын

    Thank you so much Mr.Mahesh

  • @MaheshGadwantikar

    @MaheshGadwantikar

    3 жыл бұрын

    ❤️🙏

  • @amiduallie6225
    @amiduallie62252 жыл бұрын

    You're really great sir

  • @MaheshGadwantikar

    @MaheshGadwantikar

    2 жыл бұрын

    Thank You So Much

  • @gurkiratsingh-fn1fo
    @gurkiratsingh-fn1fo3 жыл бұрын

    sir in the element 3 support is inclined so i think we need to transform the displacement components from local to global axis.coz the stiffness matrix written in ur solution is for global axis

  • @rhishikeshjadhav1772

    @rhishikeshjadhav1772

    3 жыл бұрын

    I'm also concerned about the same problem...... In the book by Daryl L. Logan, the solution is given (most probably correct one)

  • @prof.dr.sadiqs.muhsunal_ji6353

    @prof.dr.sadiqs.muhsunal_ji6353

    3 ай бұрын

    Dir sir. The form of stiffness matrix already deals with global coordinates x @ y . So u3 and v3 must be considered in x and y and not as indicate by the mister . Therefore u3 and v3 have a displacements tword x and y . I.e, v3 not zero. Thanks

  • @prof.dr.sadiqs.muhsunal_ji6353
    @prof.dr.sadiqs.muhsunal_ji63533 ай бұрын

    Dir sir. The form of stiffness matrix already deals with global coordinates x @ y . So u3 and v3 must be considered in x and y and not as indicate by the mister . Therefore u3 and v3 have a displacements tword x and y . I.e, v3 not zero. Thanks

  • @pratik8197
    @pratik81975 жыл бұрын

    Thank you

  • @akaykaushik7255
    @akaykaushik72553 жыл бұрын

    Bery very nice explanation sir

  • @MaheshGadwantikar

    @MaheshGadwantikar

    3 жыл бұрын

    Thank You

  • @a38preethishn56
    @a38preethishn56Ай бұрын

    super teaching

  • @MaheshGadwantikar

    @MaheshGadwantikar

    Ай бұрын

    Thank you

  • @manuelantonio2990
    @manuelantonio29903 жыл бұрын

    Great video, it helped me a million! Keep up the good work brother.

  • @MaheshGadwantikar

    @MaheshGadwantikar

    3 жыл бұрын

    Thank You Brother 🎉

  • @satishvarmavaidadi9792
    @satishvarmavaidadi97924 жыл бұрын

    Good explaining good

  • @MaheshGadwantikar

    @MaheshGadwantikar

    4 жыл бұрын

    Thanks you so much Varma

  • @ikchimedza6819
    @ikchimedza68193 жыл бұрын

    Very good video!!

  • @MaheshGadwantikar

    @MaheshGadwantikar

    3 жыл бұрын

    Thank You 👍

  • @alistairtaruc4918
    @alistairtaruc49183 жыл бұрын

    amazing sir thank u

  • @MaheshGadwantikar

    @MaheshGadwantikar

    3 жыл бұрын

    Most welcome

  • @semihtuncer12
    @semihtuncer123 жыл бұрын

    Thank you so much .

  • @MaheshGadwantikar

    @MaheshGadwantikar

    3 жыл бұрын

    ❤️❤️

  • @stevendna8956
    @stevendna89565 жыл бұрын

    Thanks sir. Very well explained. 🙏🙏🔥👌

  • @MaheshGadwantikar

    @MaheshGadwantikar

    5 жыл бұрын

    Thanks a lot

  • @rajkumargadasana2768
    @rajkumargadasana27684 жыл бұрын

    For finding k3 matrix 4th row 2nd column was -0.5 and also in global stiffness matrix also 1St row 6th column was -0.5 ....please check sir...thankyou sir

  • @MaheshGadwantikar

    @MaheshGadwantikar

    4 жыл бұрын

    Okay

  • @rajkumargadasana2768

    @rajkumargadasana2768

    4 жыл бұрын

    @@MaheshGadwantikar tq sir for replying me

  • @CKSEditz
    @CKSEditz2 жыл бұрын

    Nice explained thankyou so much ❤️

  • @MaheshGadwantikar

    @MaheshGadwantikar

    2 жыл бұрын

    Thank you so much ❤️

  • @CKSEditz

    @CKSEditz

    2 жыл бұрын

    @@MaheshGadwantikar bahut muskil lg rha tha KZread me video ni mil rha tha fir apka video dekh k sb ashan lg rha h sir ❤️🙏

  • @MaheshGadwantikar

    @MaheshGadwantikar

    2 жыл бұрын

    Acha laga, Mera mehnat safal huwa

  • @leoakari2335
    @leoakari2335 Жыл бұрын

    hay quá thầy ơi

  • @syedshadabquadri7641
    @syedshadabquadri76414 жыл бұрын

    Good work

  • @MaheshGadwantikar

    @MaheshGadwantikar

    4 жыл бұрын

    Thanks sir

  • @bakhtawarmallah1177
    @bakhtawarmallah11773 жыл бұрын

    good job sir..

  • @MaheshGadwantikar

    @MaheshGadwantikar

    3 жыл бұрын

    Thank You 🙏

  • @ignatiusikemefuna2440
    @ignatiusikemefuna24407 күн бұрын

    Thank you. Can you help me to analyze a continuous isotropic plate using finite element method in Matlab

  • @MaheshGadwantikar

    @MaheshGadwantikar

    7 күн бұрын

    No I am not good in matlab

  • @ThexGhostxGamer
    @ThexGhostxGamer3 жыл бұрын

    Thanks

  • @gillianashleylazaro8650
    @gillianashleylazaro86504 жыл бұрын

    sir can i get the link of the second video? continuation of this one. i cant find it, thank you somuch

  • @manibitra0099
    @manibitra00994 жыл бұрын

    Good explain

  • @MaheshGadwantikar

    @MaheshGadwantikar

    4 жыл бұрын

    Thanks

  • @MJs-85
    @MJs-854 жыл бұрын

    16:27 it is U1U1 i think not u1v1 ... i hope you would agree .. the first element in global matrix which was 0.5 according to u

  • @awazhamza7437
    @awazhamza74372 жыл бұрын

    hello .sorry sir how can i find next video to solve reaction forces? the video stated that you will find reactions of forces in the next video following this video

  • @a38preethishn56
    @a38preethishn56Ай бұрын

    NICE sir

  • @MaheshGadwantikar

    @MaheshGadwantikar

    Ай бұрын

    Thank you 🙏

  • @indianhits148
    @indianhits1482 жыл бұрын

    thank u soo much sirr... it helped a lott for my examss

  • @MaheshGadwantikar

    @MaheshGadwantikar

    2 жыл бұрын

    My pleasure

  • @powerisinsoul7061
    @powerisinsoul70614 жыл бұрын

    Sir how to find reaction...Please Help me ASAP as i have the paper

  • @Saikiran-qb2yo
    @Saikiran-qb2yo2 жыл бұрын

    how to do elimination, u have used some elimination methods so could u plz brief it

  • @yogeshwarnishad2164
    @yogeshwarnishad21645 жыл бұрын

    Nice sir ji

  • @MaheshGadwantikar

    @MaheshGadwantikar

    5 жыл бұрын

    Thank you so much Nishad

  • @dipakchaudhary4470
    @dipakchaudhary44703 жыл бұрын

    [T][k][T]^T Is not applied when inclined roller support is not provided

  • @niharikamudavath8678
    @niharikamudavath86784 жыл бұрын

    Sir while calculating global stiffness matrix if 0.5 in one matrix and 1 in other matrix then we should add it get k ?

  • @MaheshGadwantikar

    @MaheshGadwantikar

    4 жыл бұрын

    Yes, you should add it if both are lies in the same displacements.. For more details watch a video on global Stiffness matrix method.

  • @mvasavi777
    @mvasavi777 Жыл бұрын

    Sir in element 3 it is inclined then is any need to convert local to global cordinates..

  • @krishnakumarbidari4862
    @krishnakumarbidari48625 жыл бұрын

    for skew support truss [f]=[T][K][T]^t {u} isnt it?? i found this procedure and different answer than yours for same question with same data what shall i follow?

  • @MaheshGadwantikar

    @MaheshGadwantikar

    5 жыл бұрын

    Which is easy method? Easy to understand u can follow that procedure..

  • @krishnakumarbidari4862

    @krishnakumarbidari4862

    5 жыл бұрын

    I got different answer

  • @MaheshGadwantikar

    @MaheshGadwantikar

    5 жыл бұрын

    Then you follow my procedure, its actual answer obtained..for more problem plz do Support us

  • @jibranjameel3182
    @jibranjameel31822 жыл бұрын

    great

  • @vadicherlapraveen
    @vadicherlapraveen3 жыл бұрын

    the angle was you taken 45 but sin & cos 45 value is 0.707..... so i think it must be a angle of 30 degree 0.5 value is satisfied ... nice information from you sir

  • @manikantareddy7425

    @manikantareddy7425

    2 жыл бұрын

    In matrix we have square values i.e, (1/root2)^2 =2 so that all values are 0.5 hope it's clear Comment if any further clarification needed

  • @user-ve6jz7sw4f
    @user-ve6jz7sw4f11 ай бұрын

    A great video but your way of handling support 3 is wrong.

  • @mohammedabdullah7134
    @mohammedabdullah71344 жыл бұрын

    This is wrong answer sir check book " A first course in the finite element method" Daryl L. LOGAN

  • @just2minutesevery

    @just2minutesevery

    3 жыл бұрын

    absoluelty you are right

  • @zainabjawad122

    @zainabjawad122

    3 жыл бұрын

    Right

  • @haha-uu9ws

    @haha-uu9ws

    6 ай бұрын

    Definitely

  • @sujalsapkota6875
    @sujalsapkota68753 жыл бұрын

    But support at node 3 is inclined so this method is not correct.

  • @madhukarelagandula8780
    @madhukarelagandula87805 жыл бұрын

    Sir in the element-3, l = cos45° that means, l =1/√2 ( which is the value of 'l' in the matrix ) but why you are substituting this value in the place of 'L' (which is the length of the 3rd element right 🤔) Reply me sir, i have an exam tomorrow

  • @madhukarelagandula8780

    @madhukarelagandula8780

    5 жыл бұрын

    'L' value is different and 'l' is different. But you substituting the 'l' value in the place of 'L' value !

  • @MaheshGadwantikar

    @MaheshGadwantikar

    5 жыл бұрын

    In this Problem , I don't think any 'I' there in the equation. Only we have the length of the element = L, Note : There is no difference in 'I' and L, both are same value.

  • @MaheshGadwantikar

    @MaheshGadwantikar

    5 жыл бұрын

    Dear Madhukar , We have only length in the equation ( l or L).

  • @MaheshGadwantikar

    @MaheshGadwantikar

    5 жыл бұрын

    I Understood your doubts, For Element 2, the length is 1m.

  • @madhukarelagandula8780

    @madhukarelagandula8780

    5 жыл бұрын

    If there is no difference between 'l' and 'L' , why don't you replace the 'L' value (as zero) with the value of 'l' in the element-1 ? ( Check the difference sir, L=1 and l=0 in the element 1)

  • @satyasangoju4142
    @satyasangoju41424 жыл бұрын

    in other truss video you told 1Gpa=10^3 n/mm2.....but in this u said it as 10^3......plz correct it......what is the correct answer

  • @MaheshGadwantikar

    @MaheshGadwantikar

    4 жыл бұрын

    Where 1MPa=N/mm2 ok, and 1GPa =10^3 MPa= 10^3N/mm2

  • @sriguruskandha9920
    @sriguruskandha9920 Жыл бұрын

    Stiffness matrix for 3d pin jointed truss ?

  • @kadavathvenkatesh820
    @kadavathvenkatesh8202 жыл бұрын

    Remember please when you teach a subject mention a subject name and which year you teach clearly mention in before starting video

  • @3DPRINTechnology
    @3DPRINTechnology5 жыл бұрын

    How you calculated the area? Area means cross-section area of another area?

  • @MaheshGadwantikar

    @MaheshGadwantikar

    5 жыл бұрын

    The area of cross section of each Element.. Generally a bar Elements will be considered in truss problem..

  • @3DPRINTechnology

    @3DPRINTechnology

    5 жыл бұрын

    If you are online, please answer it. also, the distance calculation needs to be elaborated in detail. Thank you

  • @MaheshGadwantikar

    @MaheshGadwantikar

    5 жыл бұрын

    From the geometry of the fig, we have find out the length.

  • @3DPRINTechnology

    @3DPRINTechnology

    5 жыл бұрын

    @@MaheshGadwantikar how to calculate the area if dia of bar is not given? You explained triangular truss structure nicely in this video, do you have or can you please prepare one video explaining square truss in which the lower horizontal beam is fixed and upper horizontal beam has UDL? If you already have any relevant video, please share the link.

  • @MaheshGadwantikar

    @MaheshGadwantikar

    5 жыл бұрын

    If Dia is not given, then would have given Area value directly.

  • @teganthomas2235
    @teganthomas22354 жыл бұрын

    How is F3X=0?

  • @rajatgajbhiye7244
    @rajatgajbhiye72445 жыл бұрын

    Sir if any numerical numbering of node is not given then how to give the numbering of node.

  • @MaheshGadwantikar

    @MaheshGadwantikar

    5 жыл бұрын

    Yes ,It's available.. Please check in my playlist

  • @rohanpatil7860
    @rohanpatil78604 жыл бұрын

    sir, how did you take (L = 1/ √ 2) & M =(1/ √ 2) for element(3) because, cos45 = ( √ 2/2) and sin45 = ( √ 2/2).

  • @raphaelomungi8682

    @raphaelomungi8682

    4 жыл бұрын

    if you understand surds, (1/√2) =(√2/2)

  • @pitabashabaral3401
    @pitabashabaral34013 жыл бұрын

    Sir this is wrong because one support is inclined..so we need to use another transformation matrix for that support..

  • @mvasavi777
    @mvasavi777 Жыл бұрын

    Sir also expalin 4 element problem

  • @HappyKumar-uy3qj
    @HappyKumar-uy3qj3 жыл бұрын

    Sir how to find bandwidth of truss

  • @DC-gb4nh
    @DC-gb4nh4 жыл бұрын

    There is no external force acting on F3x so you took it 0?

  • @MaheshGadwantikar

    @MaheshGadwantikar

    4 жыл бұрын

    No force, so it will be 0

  • @brucekabali3175
    @brucekabali31752 ай бұрын

    you did not consider the fact that node 3 has an inclined support.

  • @2424ahmed
    @2424ahmed4 ай бұрын

    ❤❤❤

  • @MaheshGadwantikar

    @MaheshGadwantikar

    4 ай бұрын

    ❤️❤️❤️

  • @zainabjawad122
    @zainabjawad1223 жыл бұрын

    Sir in this question, the support is inclined so, this solve is wrong

  • @a38preethishn56
    @a38preethishn56Ай бұрын

    New method to solving the problem HOW?

  • @maheshsonawane4754
    @maheshsonawane47545 жыл бұрын

    👍

  • @evangelosgeorgiou1662
    @evangelosgeorgiou16623 жыл бұрын

    Sir i did not understand, why do you put l and lm inside of the stiffness matrix at 4:07, where did l and lm come from?

  • @MaheshGadwantikar

    @MaheshGadwantikar

    3 жыл бұрын

    L is nothing but cos tita and m is sine tita

  • @evangelosgeorgiou1662

    @evangelosgeorgiou1662

    3 жыл бұрын

    @@MaheshGadwantikar Thank you very much, but whats the difference between L=1m for element 1, and l that we put inside the stiffness matrix?

  • @MaheshGadwantikar

    @MaheshGadwantikar

    3 жыл бұрын

    Yes

  • @nmaheshkumar6746
    @nmaheshkumar67465 жыл бұрын

    Sir upload full fea notes as per osmania university for be students I request you sir

  • @MaheshGadwantikar

    @MaheshGadwantikar

    5 жыл бұрын

    OK Mahesh Kumar

  • @lovepreetsingh4566
    @lovepreetsingh45663 жыл бұрын

    This wrong, coordinate of support 3 are rotated by 45 degree we have to consider that also

  • @deepakkumaar2637
    @deepakkumaar26372 жыл бұрын

    Hey, Mahesh Can you tell me in which book have this example?

  • @MaheshGadwantikar

    @MaheshGadwantikar

    2 жыл бұрын

    MD.Jalaluddin

  • @deepakkumaar2637

    @deepakkumaar2637

    2 жыл бұрын

    Sir, Do you have softcopy of this book? If yes please share with me. OR Any online source of it.

  • @arkham-8015
    @arkham-80152 жыл бұрын

    How’s is 1/root 2 equal to root 2

  • @seenumehta9952
    @seenumehta99522 жыл бұрын

    Sir how 1 by √2 is √2 in element 3

  • @fqkhan245
    @fqkhan2454 жыл бұрын

    Here you took v3 as zero its not correct .check again you have to use the global coordinates so in end u2,u3,v3 are to be found out and we would have 3x3 matrix in end 🤔🤔

  • @MaheshGadwantikar

    @MaheshGadwantikar

    4 жыл бұрын

    🤔

  • @fqkhan245

    @fqkhan245

    4 жыл бұрын

    @@MaheshGadwantikar after checking reply me with correct answer 🙏 waiting for your response

  • @ersinyildiz

    @ersinyildiz

    4 жыл бұрын

    I agree. Did he give the correct answer?

  • @marojahansamosir4342
    @marojahansamosir43423 жыл бұрын

    why not transform the matrix?

  • @ersinyildiz
    @ersinyildiz4 жыл бұрын

    How come does V3 equal to 0 at 22:52 ? That roller at node3 makes an angle of 45 degree with global coordinate system. You just edit global K matrix with respect to local coordinate system at node 3. I believe this is a mistake, if not please explain this.

  • @voiceOver5000

    @voiceOver5000

    4 жыл бұрын

    I also think that there is a mistake, because of the orientation of the force, the beam must elongate to the right-hand side. please correct us.

  • @MaheshGadwantikar

    @MaheshGadwantikar

    4 жыл бұрын

    By tomorrow i will post the pdf of the given problem in the description. Please wait

  • @ersinyildiz

    @ersinyildiz

    4 жыл бұрын

    Before any boundary condition implementation, transformation should be made at the roller support with an angle. By doing this, corresponding component of the K matrix are transformed to local coordinate system with respect to corresponding element. After that boundary conditions will implemented. Solving the system will result transformed results for that node. Retransformation should be done to obtain results in global coordinate system. Tomorrow I will share a book which describes this procedure.

  • @ersinyildiz

    @ersinyildiz

    4 жыл бұрын

    Check Example 3.11 on page 106 of the book of Daryl L. Logan named "A First Course in the Finite Element Method" 4th edition.

  • @ichisan3775

    @ichisan3775

    2 жыл бұрын

    @@ersinyildiz it is a good recomment. I have a question that the symbol l in T transformation is length of element or just 1. Thank you.

  • @nileshkarwar5143
    @nileshkarwar51434 жыл бұрын

    Calculation for second member is wrong , we need to consider inclined support angle also

  • @MaheshGadwantikar

    @MaheshGadwantikar

    4 жыл бұрын

    It's considered in the Problem.. Check Once

  • @nileshkarwar5143

    @nileshkarwar5143

    4 жыл бұрын

    It consider for member 3 what about member 2

  • @angieladagook7490
    @angieladagook74903 жыл бұрын

    Hi, i've been solving a problem using this method but i'm not quite sure if it's right. Anyway, about the area how did it arrive to different areas, is it because of the angle or is it just given? hope you can answer thanks

  • @MaheshGadwantikar

    @MaheshGadwantikar

    3 жыл бұрын

    Please Wait 1 day, I will upload another video on same problem by considering the Inclined support

  • @angieladagook7490

    @angieladagook7490

    3 жыл бұрын

    @@MaheshGadwantikar by any chance do u have email i could send a problem and help thanks

  • @MaheshGadwantikar

    @MaheshGadwantikar

    3 жыл бұрын

    m a h e s h m g 5 3 3 at g m a i l . c o m

  • @angieladagook7490

    @angieladagook7490

    3 жыл бұрын

    already sent an email

  • @shahvaizkhan4131
    @shahvaizkhan41313 жыл бұрын

    Is there any matlab code for solving this sort of problems?

  • @MaheshGadwantikar

    @MaheshGadwantikar

    3 жыл бұрын

    No idea about Matlab coding

  • @enga-qs6co
    @enga-qs6co Жыл бұрын

    11:45 one by root 2 is nothing but root 2?????

  • @devendrabisen6631
    @devendrabisen66314 жыл бұрын

    Thrita 2 ki value 0 kaise aayi

  • @rajendrabutalekar7805
    @rajendrabutalekar7805 Жыл бұрын

    E=210×10^3

  • @MaheshGadwantikar

    @MaheshGadwantikar

    Жыл бұрын

    Yes

  • @RAYUDU_ROCKY_45_999
    @RAYUDU_ROCKY_45_99911 ай бұрын

    -1² = -1 x -1 = +1

  • @naseradeenashwear708
    @naseradeenashwear7083 жыл бұрын

    Are You sure about the application of B. C. at node 3

  • @MaheshGadwantikar

    @MaheshGadwantikar

    3 жыл бұрын

    Yes.

  • @naseradeenashwear708

    @naseradeenashwear708

    3 жыл бұрын

    @@MaheshGadwantikar But you put v3=0 and v3 in global is not zero because the support is inclined

  • @naseradeenashwear708

    @naseradeenashwear708

    3 жыл бұрын

    @@MaheshGadwantikar Hi I am still waiting for your answer Sir.

  • @naseradeenashwear708

    @naseradeenashwear708

    3 жыл бұрын

    Are you sure about the application of the boundary conditions. I saw you put v3 =0 but in global axis it is not zero as the support at node 3 is inclined. In other words node 3 is deformed in both global directions the horizontal and vertical.

  • @aaryad9043

    @aaryad9043

    3 жыл бұрын

    i also think he took wrong direction for U3 and V3 they should be in direction as x and y so V3 can't be zero

  • @HimanshuPothareFilms
    @HimanshuPothareFilms4 жыл бұрын

    the value of cos 45 is worng...The value of cos(45) is √2/2

  • @ashishmistry6102

    @ashishmistry6102

    4 жыл бұрын

    1/√2 & √2/2 both are the same🙏

  • @monkeyface802
    @monkeyface8023 жыл бұрын

    Why as engineers do we over complicate things. The idea of engineering is to make things easier not more difficult!! This is ridiculous!

  • @didarulhasansaharaj4396
    @didarulhasansaharaj4396 Жыл бұрын

    The node 3 has skewed support. The displacements in node 3 have to be transformed to global axis. Your solution is wrong.

  • @basharm.m2372
    @basharm.m23723 жыл бұрын

    Can i contact u bro i need your help

  • @MaheshGadwantikar

    @MaheshGadwantikar

    3 жыл бұрын

    Sure You can

  • @basharm.m2372

    @basharm.m2372

    3 жыл бұрын

    @@MaheshGadwantikar do u have Number whats up

  • @MaheshGadwantikar

    @MaheshGadwantikar

    3 жыл бұрын

    Visit Channel Description

  • @alemayehugirma7315
    @alemayehugirma73153 жыл бұрын

    Hi my best how are you ? that is best example, best to do more and can you give your email address.? I sent to more assignment to help me

  • @MaheshGadwantikar

    @MaheshGadwantikar

    3 жыл бұрын

    m a h e s h m g 5 3 3 @ g m a i l . c o m

  • @ShresthChandan
    @ShresthChandan3 жыл бұрын

    Sorry but the shown solution is wrong third roller is rotated

  • @fuzzpi4607
    @fuzzpi46072 жыл бұрын

    Wrong answer

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