I love a person who simplifies something made unreasonably complicated on the wikis

@yijin5424

4 жыл бұрын

right?

@wing_your_dreamz

4 жыл бұрын

💓💓Van't Hoff factor and Abnormal molar masses best Explanation.💓💓ALCHEMY 💓 ➡️kzread.info/dash/bejne/oolhxcmodbTZqtY.html

@albinocat

Жыл бұрын

The wikis are bound and determined to write everything in the most professional linguistics possible, resulting in what appears to be unintelligible gibberish.

@jjhassy

Жыл бұрын

@@albinocat Just like academic papers. It's like "ooo look how many big words I can use until it's completely incoherent"

@albinocat

Жыл бұрын

@@jjhassy ikr lmfao

Better than a 70 minute lecture from my professor. Thank you

Intelligent people are those who can make things easy to understand. Thank you lot sir ☺️ thank you

After all 11 years later, You are still helping students like us

that's it? i thought it was like 99x times harder than it really is

@CheapSkateGamer96

8 жыл бұрын

+TK This is a really oversimplified explanation... Sometimes the ions don't all break apart and you have a decimal that is close to the numbers he wrote. In reality you use the equations for freezing point depression, boiling point elevation, and osmotic pressure and solve for i.

@jqyhlmnp

5 жыл бұрын

TK most of science can be as complex af for theoretical shit, but everyday useful science is relatively simple, including _i_

@wing_your_dreamz

4 жыл бұрын

💓💓Van't Hoff factor and Abnormal molar masses best Explanation.💓💓ALCHEMY 💓 ➡️kzread.info/dash/bejne/oolhxcmodbTZqtY.html

@jev_

2 жыл бұрын

@@CheapSkateGamer96 i= 1-(n-1)x, n is the number of ions and x = alpha = degree of dissociation

@kenokyu7227

Жыл бұрын

​@@jev_ correction: i = 1+(n-1)alpha

well said! i couldnt find anything as clear cut as this explanation, for such a simple answer.

Know that you're still helping students 10 years later

seriously...that's it? omg this is a lifesaver

Omg thank you!! I’ve been trying so hard to understand this and you just made it super easy!!!

We need more people like you in the education system.

Thank you very much!! ❤ Student from Syria🙋‍♂️

Thank you for making it so easy and quick to understand!

I LOVE YOU. THANKS FOR MAKING LIFE SIMPLE. MY CHEM PROFESSOR LECTURES FOREVER ON THIS TOPIC WHEN IT TAKES ONLY 1MINUTE TO UNDERSTAND IT. BLESS UR SOUL.

Thank you so much! In 1:38, you've successfully taught me what my chemistry teacher has been trying to do for the past week! I thought this was complicated, but when you described this in simple terms, this became the easiest thing in the world! thank you so much!

@aftabkhann2314

3 жыл бұрын

Hey is this account still active

@boltzmann3989

2 жыл бұрын

@@aftabkhann2314 lol

@aftabkhann2314

2 жыл бұрын

@@boltzmann3989 yeah man,it always makes we wonder whether old accounts are still active

@lukeadams8228

Жыл бұрын

@@aftabkhann2314 Are you still active

thanks bro, your simplification skills are incredible

Bro randomly made a short video before 10 years ago and yet have helped 362K students lol.

Thank you so much sir.....lots of love to your channel and you too💖 from 🇮🇳

oh my god, now i finally understand, thank you very much!

@aftabkhann2314

3 жыл бұрын

Hey is this account still active

This is what we call "science " because everything is simple!!😁 thanks

love this simple fast to the point explanation thanks sir

Thank you very much love from India 🇮🇳🇮🇳🇮🇳

Thank you so much!

how do u calculate the van't hoff factor for Acids ( both weak and strong ) and bases ( also weak and strong ) cuz i'm struggling to find any information about this, also i understand that anything that's not ionic it's van't hoff value is 1, but I find stuff on the internet saying H3PO4 has a van't off factor of 4, even though it's not ionic another question: what is the van't hoff factor for Cu(OH)2 which is a weak base

Thank you so much!!🎉❤

You're amazing, thank you!

Finally a guy with right motive!

Thank you so much my chem teacher didn't teach this unit

Thank you. I was left with a doubt... But thats ok! GREAT EXPLANATION...

Thx man sooo simple explanation love it 😍❤️❣️

This is a great video for learning how to count. It doesn't actually help at all for finding the measured Van't Hoff constant.

@MrDGenova

8 жыл бұрын

+SarcasticSalamander Nope, it doesn't. Perhaps I should change it to finding the "theoretical Van't Hoff factor".

u made this sooooo easy thank you

Thanks for the video!!!

Thanks man. Life saver 🙆🏻

Tysm. 11th grader ( me ) wanted to find the elevated boiling point with an ion bond soluble. Def scratched my head when my book just multiplied by two, saying to just count the ions. Im sorry for being a much talker, but my book did another example for NaF. The writer didn't multiply by two. Is thjs a mistake?

Thank you so much

very helpful, thank you

Why can't everyone else just explain it that easily, I was so worried it was this big complicated thing because no explanation made sense.

thanks man!!!!

Thank you💝💖

Thank you my professor made it sound so much harder

now it's making a sense to me .. finally get it :) thanks a lot

@aftabkhann2314

3 жыл бұрын

Hey is this account still active

LEGEND

That made it sound very easy

If the salt is hydrated do you include the water when counting? So for AgNO3.2H2O would it be 2 or 4? Thank you for the video!

@MrDGenova

4 жыл бұрын

No, that water would just mix in with the rest of the water.

@zoei2644

4 жыл бұрын

MrDGenova Oh okay thank you so much!

You are a genious

What if the solvent used isn't water? e.g. what is Van't Hoff factor for NaCl dissolved in benzene?

@MrDGenova

7 жыл бұрын

The solvent doesn't affect the theoretical Van't Hoff factor. If NaCl fully dissociates, its value will be 2. However, theoretical and actual are two different things. Benzene is nonpolar, so NaCl may not be as soluble in it, so maybe it won't dissolve quite as well or dissociate as fully. I'm not sure. I'd need to see it in the context of the question asked.

Thanks.

THANK YOU BRO

Thanks sir 😭😭😭🙏🙏🙏, it was so simple to understand 😃😃🤩🤩🔥🔥🔥

What about MgSO4?

Thank you!

@wing_your_dreamz

4 жыл бұрын

💓💓Van't Hoff factor and Abnormal molar masses best Explanation.💓💓ALCHEMY 💓 ➡️kzread.info/dash/bejne/oolhxcmodbTZqtY.html

Sir thanks so much love from india thanks sir ❤️❤️❤️

What will be vant Hoff factor for K2SO4??

@antonyshigin4977

2 жыл бұрын

K₂SO₄ ⇌ 2K⁺ + SO₄-² Hence vant Hoff factor i = 2 + 1 = 3

epic man, thank you so much!

@wing_your_dreamz

4 жыл бұрын

💓💓Van't Hoff factor and Abnormal molar masses best Explanation.💓💓ALCHEMY 💓 ➡️kzread.info/dash/bejne/oolhxcmodbTZqtY.html

Thanks so fricking much

Thank you so much, oh my god my head was going to explode

Thank you so much for your video!!! The book I have does not explain much.

@aftabkhann2314

3 жыл бұрын

Hey is this account still active

what a legend

Thank you sirr👍🏻

Thanks Mr Genovo

Damn that’s easy, thanks

❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤ loads of love

Thank u sir

It's that easy... :O I made it mroe difficult than it was. Thanks so much!

@wing_your_dreamz

4 жыл бұрын

💓💓Van't Hoff factor and Abnormal molar masses best Explanation.💓💓ALCHEMY 💓 ➡️kzread.info/dash/bejne/oolhxcmodbTZqtY.html

thanks

Thanks

u r awesome

Sir i didn't get it can u explain why AlPO4 vant hoff factor will be 2???

@nathanmaizels7690

8 жыл бұрын

+Nishant Chavan It dissociates into two ions: Al and PO4. PO4 doesn't dissociate further, so it is only two moles of ions for every mole of AlPO4 dissolved. Look at 1:00, and see that Al2(SO4)3 has i=5. The (SO4)3 doesnt dissociate into 15 ions, since SO4 doesn't dissociate; it only contributes three moles of ions for each mole dissolved. This is the same for PO4.

So what is the answer for NaOCl?

@MrDGenova

2 жыл бұрын

It splits into Na+ and OCl-, so 2.

My chemistry professor can’t teach this is so easy.

Thanks!

@wing_your_dreamz

4 жыл бұрын

💓💓Van't Hoff factor and Abnormal molar masses best Explanation.💓💓ALCHEMY 💓 ➡️kzread.info/dash/bejne/oolhxcmodbTZqtY.html

Helpful

so van't hoff factor of Ca(NO3)2 is 4 right ?

@MrDGenova

8 жыл бұрын

+srx2106 3. 1 for Ca2+, and 2 for the 2 NO3- s.

@srx2106

8 жыл бұрын

+MrDGenova thank you :)

Sir thanks alot

jona hill?

thnx..

thnks m8

thank you sir. I have a test today 😰

Why is HF different than HCl?

@MrDGenova

10 жыл бұрын

The theoretical Van't Hoff factor is the same for both HCl and HF (2), because each dissociates into two ions in solution. However, the actual Van't Hoff may vary, because in reality not every molecule breaks apart into its ions. HCl is a strong acid, so nearly every molecule of HCl will break apart, and the actual Van't Hoff factor will be very close to 2. HF, on the other hand, is a weak acid, so the vast majority of HF molecules will not dissociate, and the Van't Hoff factor would actually be closer to 1. This video only covers theoretical Van't Hoff factors, which assume 100% dissociation for every molecule.

@EricZuckerman1

8 жыл бұрын

+Mehdi Ali Recall that both of these acids are covalent. So, we consider covalent compounds that are soluble to simply dissolve (and not dissociate) and have i = 1 (theoretically). However HCl is a strong acid and will dissociate into ions appreciably and have i = 2 (theoretically). So, these covalent compounds have different van't Hoff factors because HCl is one of those exceptions that you need to know.

8 years ago😵

so sir vant hoff factor for aluminium phosphate will be 5 as it us AlPO4

@MrDGenova

8 жыл бұрын

+Nishant Chavan No, it will be 2. AlPO4 splits into Al^3+ and PO4^3-, for a total of 2 ions.

@robertdestefano2554

6 жыл бұрын

no factor is 2 Al and PO4 the polyatomic ion

na3po4 i =4 why?

@austinlupo7099

7 жыл бұрын

PO4 has a charge of 3- so it becomes 3Na^+ + PO4^3-. A total of 4 ions

So what's Vant hoff factor for KNO3 ??? Somebody help plzz

@MrDGenova

2 жыл бұрын

2. One for K+, one for NO3-

@bhuvankiransagarg.b9678

2 жыл бұрын

@@MrDGenova thanks you so much 😊

#ion pairing

H2So4 Will be 6?? im my calculations is 6

@MrDGenova

7 жыл бұрын

I just saw this comment, so not sure if it's useful to you now. H2SO4 will be 3. It breaks apart into two H+ ions, and one SO42- ion, for a total of 3 particles.

@fernandaaraujo15

7 жыл бұрын

MrDGenova Thank you

why does he kinda sound like ryan higa

I looked for at least half an hour online for how and when to use this in colligative boiling and freezing point formulas, but couldn’t find anything. I didn’t pay attention in my Honors Chem class for like 2 weeks and I have a test tomorrow, first class. Pray for me please😂

@MrDGenova

4 жыл бұрын

I have other videos that do more with it: kzread.info/dash/bejne/omZ1rLl6qbnefKw.html

Am i right????

i=1+alpha(Z-1)

2019

P-chem is killing me

Bruh

this was not explained very well

Terrible video, unbearably bad audio. No actual info, just counting... What were you thinking?

Thanks