In seven minutes you just taught me what my calculus teacher couldn’t in two weeks. Thank you!

@themathandphysicstutor

Жыл бұрын

Glad to help

@starks8400

Жыл бұрын

I just bombed a test over this exact subject and now I see it was so easy 😂

@zz-rb4bc

2 ай бұрын

Less, the intro took a minute

Could not have been clearer! You just cured me of my looming AP calc stress entirely, what an absolute life saver.

@themathandphysicstutor

Жыл бұрын

Thank you so much for the kind words! Glad I could help! Please share with your friends

Oh my gosh! It's like you are a mind reader with topics! I just am starting AP Calc AB!!!

@themathandphysicstutor

3 жыл бұрын

Awesome!! Videos will be posted throughout the year- AP Calc AB is the course I teach 🤗 Please help spread the word to others who might find this channel helpful!!

... A good day to you, When I finished watching evaluating the indeterminate limit #5, I was thinking of an alternative way to solve the same limit as follows: lim(x-->4)((sqrt(x + 5) - 3)/(x - 4)) (Rewrite the denominator (x - 4) as: (x - 4) = (x + 5) - 9 and treat this new expression as a difference of two squares: (x - 4) = (x + 5) - 9 = (sqrt(x + 5) - 3)(sqrt(x + 5) + 3) to finally cancel the common factor (sqrt(x + 5) - 3) of numerator and denominator to obtain the solvable limit form: lim(x-->4)(1/(sqrt(x + 5) + 3)) = 1/(3 + 3) = 1/6 ... to my surprise it works out; hope you appreciate this alternative approach too ... Thank you for your great math efforts, Jan-W

Is the solution for lim x approaches to -2 |x+2|/(x+2) equal to does not exist or i can do something more?

if you arrive at #/0, this does not necesarily mean that the limit is DNE. I am seing many cases in which they do in fact exist, while being #/0.

@pafrAmamA

5 ай бұрын

Sorry, so ive figure out, if x --> 0, its in these cases where #/0 is not DNE

just started ap calc and this helped a lot

@themathandphysicstutor

3 жыл бұрын

Im so happy to hear that. My school year starts next week and then you can expect regular content throughout the whole year. If you have trouble with anything let me know. And help me spread the word about about the channel! We are kind of new and want to help as many kids as possible! We feel so bad for what you guys are going through! Have a great day!

My calculus revision was completed by this ... ❤️ Thanks from india ...

@themathandphysicstutor

Жыл бұрын

Thank you

Good work, could I say when a function itself is not able to produce output at a specific input and it haults the operation at a specific x value. To overcome this situation we take help from the limit and limit helps us to take out of this situation. After calculating the limit value we GIVE THIS VALUE TO THAT FUNCTION WHICH WAS Not PRODUCING ANY OUTPUT AT SPECIFIC INPUT??? iF THIS IS THE CASE THEN can say that function and limit both are different BUT it is the limit which helps the function which was trapped on a specific value and now because of limit function is able to walk smoothly again?? In a result could I say that whenever a function trapped in an undefined situation, we have to bring in LIMIT at this point?? please help me out! thanks.

How do I solve if its like this lim { 2, x { x^2-2x+1, x>= -1 x-> -1 both of the limit is different, so does this mean the limit does not exist? (I got 2, and for the bottom I got 4)

Such an underrated channel you just nailed it ma'am😊

@themathandphysicstutor

5 ай бұрын

Thank you so much 😀

This is truly a life saver! I was in total despair in my calculus course thinking it is just IMPOSSIBLE, but now I see it's not that bad thanks to you. Thank you zilions!!

@themathandphysicstutor

4 ай бұрын

You're very welcome!

This is really, really good. I want to get a fast as you are with the algebra. Can you recommend any videos. I love your approach and clarity. I am specifically interested in fractions and factoring. Many thanks!

@themathandphysicstutor

4 ай бұрын

Thank you so much. It comes with practice

super helpful, thank you!

@themathandphysicstutor

3 жыл бұрын

Thank you

Example number 2 isn't it supposed to be 1, because -2² is -4 which will make the numerators -4+4+4=4 and the denominator =4 which will be 4/4=1?

Very well organized and explained! 😊

@themathandphysicstutor

6 ай бұрын

Thank you! 😊

the method in number 2 is the difference of two squares, right? I'm looking forward to your response. Thank you!

@themathandphysicstutor

5 ай бұрын

The denominator uses difference of two squares. The numerator uses sum of cubes. :)

Thank you so much!

@themathandphysicstutor

10 ай бұрын

You're welcome!

Thank you for this tutorial

@themathandphysicstutor

6 ай бұрын

You're welcome 😊

good lecture thank you.

@themathandphysicstutor

2 жыл бұрын

You’re welcome

Thank You!!!♥👍

@themathandphysicstutor

Жыл бұрын

You are so welcome

dam you really explained everything so clearly !

@themathandphysicstutor

Жыл бұрын

Thank you

You're saving my grade!

@themathandphysicstutor

Жыл бұрын

That’s what I’m here for. Please share with anyone else who needs savings

thank you ☺

@themathandphysicstutor

7 ай бұрын

You're welcome 😊

You just saved my grade 🥳 This is really great 💓

@themathandphysicstutor

4 ай бұрын

Glad I could help!

THANK U

@themathandphysicstutor

5 ай бұрын

You're welcome!

Wow brilliant work there

@themathandphysicstutor

Жыл бұрын

Thank you

Thank you this helped me

@themathandphysicstutor

9 ай бұрын

No problem

What a great use of 7 min!

@themathandphysicstutor

Жыл бұрын

I agree

where did x-4 come from for the top on number 5? i thought we had x-5+9 up there

@themathandphysicstutor

Жыл бұрын

-5+9=4 :) we just combined

@mkvsanh

Жыл бұрын

@@themathandphysicstutor thank you! 🤦‍♂️

0:27 isn't 4th exactly like 1st? In both situations you get a direct answer. It's just a whole number.

@themathandphysicstutor

10 ай бұрын

Many students get confused with an undefined answer vs. a 0 answer, hence the distinction.

awesome!

@themathandphysicstutor

Жыл бұрын

Thank you! Cheers!

❤

Marvelous love from Pakistan ❤

@themathandphysicstutor

6 ай бұрын

Thank you

Whoa whoa whoa 4:25 this limit is NOT DNE! Do not write that people! Just because the function does not exist where x is approaching, does not mean there isn’t a limit. It means there is either a vertical asymptote, jump, or a removal discontinuity (hole) in your graph. If you get a number/0 after plugging in, that means that your answer can be DNE, infinity, or negative infinity.

@thecatch6299

Жыл бұрын

@@themathandphysicstutor I’m right arent i?

@themathandphysicstutor

Жыл бұрын

Hi TheCatch- unfortunately you are incorrect. We aren’t looking at one sided limits here, if we were we could describe the limit as positive or negative infinity. The definition of a limit specifically states that the answer must be a number and infinity is not a number. If there was a removable discontinuity we would have gotten 0/0 when originally plugging in. There is most definitely not a jump discontinuity since this is not a piecewise function and is comprised of a quotient of polynomials (which is the type of functions focused on in this video). Since we got a number over a 0, that alludes to a vertical asymptote, which means the graph is approaching + or - infinity which again, cannot be stated as answer to this problem. We say the limit does not exist, and would have to do further investigation using one sided limits to accurately describe the behavior of the function. Hope this helps your confusion. 😊

@thecatch6299

Жыл бұрын

@@themathandphysicstutor looks like I thought that the limit was as x approached 0, not 2. That was my problem. If it was approaching 0 it would be 1/2.

You should really set up a Patreon account for donations.

@themathandphysicstutor

Жыл бұрын

Thank you. You can always leave a “super thanks”. We really are just here to help! Thanks again for the consideration

why did she forget the negatives

@themathandphysicstutor

10 ай бұрын

Where?

I just want to ask questions so can you please send me your email

@themathandphysicstutor

Жыл бұрын

My tutoring schedule is currently booked. I’ll let you know if I have cancelations. Usually I book up mid school year. Thank you