Factoring a Cubic Polynomial (Synthetic Division 01)

We use synthetic division to factor a cubic polynomial. For more practice using synthetic division please watch this video:
Synthetic Division 2:
• Factoring a Cubic Poly...

Пікірлер: 29

  • @tmd02
    @tmd028 жыл бұрын

    I did a foundation year for Electronic Engineering specifically designed to set you up for the degree. Then I find there's a shit ton of GCSE/A Level maths that wasn't taught to me is needed, great.

  • @MewTCG1

    @MewTCG1

    3 жыл бұрын

    Shit pal, what are you up to now?

  • @muhammadabdullahriazbhatti
    @muhammadabdullahriazbhatti Жыл бұрын

    What if you're not give a root to begin with? Plus could you please tell how do you create these video lesson? Thanks a bunch!

  • @Gipsy4u
    @Gipsy4u8 жыл бұрын

    Thanks, Good video to the point, short and meaningful

  • @ArunNarasimhan_arun1997107
    @ArunNarasimhan_arun19971078 жыл бұрын

    good video. I learned something important from it

  • @Ahmed-jl7uh
    @Ahmed-jl7uh8 жыл бұрын

    You saved me. Thank you

  • @bravo5977
    @bravo5977 Жыл бұрын

    Baba Dankie Baba🙌🏾🔥❤️

  • @chiragm9695
    @chiragm96956 жыл бұрын

    Nice explanation 🔥🔥

  • @iaminsane8945
    @iaminsane89456 жыл бұрын

    It's helpful ..thanx for this video

  • @pankajkumarsharma7144
    @pankajkumarsharma71447 жыл бұрын

    perfect method for solving

  • @vanshv9001
    @vanshv90018 жыл бұрын

    Nice explanation

  • @oscarcrowe6965
    @oscarcrowe69654 жыл бұрын

    Thank you so much

  • @Mohamedhassan-ep5ek
    @Mohamedhassan-ep5ek4 жыл бұрын

    Thank you sir but will I alway roots from x?

  • @jvandorvort2865
    @jvandorvort28652 жыл бұрын

    NICE XPLANATION BRO

  • @ngohomukhovha5035
    @ngohomukhovha50352 жыл бұрын

    I have a question that I want you to tackle it for me.

  • @infernacop3296
    @infernacop32965 жыл бұрын

    Thnx

  • @XlightNtrEnx
    @XlightNtrEnx7 жыл бұрын

    how do you know to use 1, what if we had to use another number to factor?

  • @vedanthvbaliga4415

    @vedanthvbaliga4415

    6 жыл бұрын

    just find the roots by trial and error method and then use this method

  • @adrianforbes7863

    @adrianforbes7863

    6 жыл бұрын

    And the way you do that is by setting x to a number, call it a, in the original polynomial and if the result is 0 then a is a root, and (x-a) is a factor. e.g. for the polynomial x^3 +2x^2 - 3x, if you substitute 1 into x, you get y = 0, so 1 is a root and (x-1) is a factor. I was wondering though, Is there another method that works every time, other than trial and error?

  • @GreaterDeity

    @GreaterDeity

    3 жыл бұрын

    @@adrianforbes7863 I hope so because that sounds incredibly inefficient.

  • @arnabsaha8497
    @arnabsaha84977 жыл бұрын

    nice

  • @ianjaydelosangeles3173
    @ianjaydelosangeles31738 жыл бұрын

    roots are based on factors of the constant 15? T_T

  • @zallankhan3471
    @zallankhan34715 жыл бұрын

    if we plug back x=5 or x=-3, it doesnt satisfy the original equation. HOW?

  • @rootmath

    @rootmath

    5 жыл бұрын

    I'm not sure what you mean. If you plug those numbers into the factored polynomial or the original polynomial you get 0.

  • @zallankhan3471

    @zallankhan3471

    5 жыл бұрын

    rootmath my bad! I got it all wrong. Thanks anyway!

  • @NiNJAxOFxWAR
    @NiNJAxOFxWAR9 жыл бұрын

    thx for video

  • @freelance.p3126
    @freelance.p31264 жыл бұрын

    I don't get why u would do long division? This is so much simpler and faster.

  • @GreaterDeity
    @GreaterDeity3 жыл бұрын

    What if you are not given 1 is a root... my homework does not give that.

  • @alexandria.n

    @alexandria.n

    3 жыл бұрын

    you have to plug in values until your equations equals 0. Try 1; -1; 2; -2; 3; -3 until you get 0 and whatever value gave you 0 is your first factor.