I genuinely think that you know more than my professor does. Since you can teach this in simple words, without making it too complicated and still can apply these to much more complex situations. Thank you so much man, great lectures.

@QuestionSolutions

2 жыл бұрын

Thank you very much for your kind words! I wish you the best with your studies. :)

@lords9966

2 жыл бұрын

Bro your professor also teach good but at the class you always do bla bla bla

Watching these is making my statics final seem a lot more doable, really wish I would have found your channel at the start of this semester! Thank you for your videos!

@QuestionSolutions

2 жыл бұрын

I am really glad to hear that. I hope they are helpful to you and wish you the best on your finals! Keep up the good work.

Thank you for teaching us more effectively than my books or some of my professors. I also love the website!!! i don't understand why this channel is so underrated.

@QuestionSolutions

2 жыл бұрын

You're very welcome. I am really glad to hear these videos are helpful to you :) Best wishes with your studies!

I can actually see myself passing this course. Thanks a lot for the videos!

@QuestionSolutions

Жыл бұрын

You can most definitely pass this course. Try to do the questions I show in the videos beforehand, and then if you get, watch the rest. Do your best, do as many questions as you can and have a positive mindset. You got this!

Your videos are the best! Keep making more sir! It helps me grasp the concepts very well!

@QuestionSolutions

2 жыл бұрын

Glad to hear! Keep up the good work and best wishes with your studies :)

This just made my life 100 times easier. Thank you.💗

@QuestionSolutions

Жыл бұрын

You're very welcome! Keep up the awesome work with your courses ❤

University of Pretoria student watching your videos , keep up the great work it helps a lot.

@QuestionSolutions

2 жыл бұрын

Really glad to hear these videos help out a lot :) I wish you the best with your studies!

everytime i didnt understand what i learn from my class, i will find your channel and it very helpful. Keep making helpful video for everyone. Thank you. You are the best!!

@QuestionSolutions

4 ай бұрын

I’m so glad to hear that the content on this channel has been helpful for you! You're very welcome and thank you for taking the time to write such a nice comment :) ❤️

Ryerson student watching your videos, you are amazing !!!! more structural engineering topics

@QuestionSolutions

2 жыл бұрын

Thank you very much! Best wishes with your studies.

Its been 2 years since you uploaded this and its still helping students!! Thank you so much for this video, keep up the great work!

@QuestionSolutions

6 ай бұрын

Thank you very much. I hope all of the videos are helpful to you and your friends. Best wishes with your studies :)

most beautiful and concise ways to explain. Good luck in life brother!!

@QuestionSolutions

2 жыл бұрын

Thank you very much, I really appreciate it. I wish you the same!

Please do not stop. What a legend.

@QuestionSolutions

3 жыл бұрын

I will do my best!

thank you so much for these!!!! i got a 16% on my first statics exam 💀with the help of your vids i got a 96% on my next, thank you for creating such a great resource for this course

@QuestionSolutions

8 ай бұрын

Wow, that's amazing! I am really happy for you and well done! Keep up the awesome work and best wishes with your studies.

thank you so much for this video. It made me ace my final exam! you are a life saver!

@QuestionSolutions

8 ай бұрын

I am really happy you aced your final exam! Good job, and keep up the awesome work. Best wishes with your future studies.

Thank you for this clear explanation!

@QuestionSolutions

Жыл бұрын

You're very welcome!

I wish we had more content like this, brief yet detailed and understandable.

@QuestionSolutions

2 ай бұрын

I hope the video was helpful to you :)

@unknownguy8232

2 ай бұрын

@@QuestionSolutions it was helpful thank you. :)

The contents in the channel are really great. Anyone can understand easily .

@QuestionSolutions

3 жыл бұрын

Thank you!

thank you for this video! you explain better than my teacher

@QuestionSolutions

2 ай бұрын

You're very welcome :)

Thanks for your videos❤ m having a quiz and ur tutorials helped me.

@QuestionSolutions

9 ай бұрын

I'm so glad! Keep up the great work and I hope your quiz went well.

West hills community college student watching your vids, keep it up.

@QuestionSolutions

2 жыл бұрын

Awesome! Same to you, keep up the awesome work :)

Love u man. You are the best!

@QuestionSolutions

3 жыл бұрын

Thanks 😁

Awesome video❤ best explanation out there😮😮

@QuestionSolutions

Жыл бұрын

Glad it was helpful and thank you very much! ❤

@adi5962

Жыл бұрын

@@QuestionSolutions I will get a good grade in this course just because of you😌

Thanks the video man,I really really appreciate ❤️❤️❤️❤️

@QuestionSolutions

Жыл бұрын

You're very welcome! ❤

I am watching this to prepare for my FE exam , thank you!

@QuestionSolutions

11 ай бұрын

You're very welcome! I wish you the best with your exam.

Thanks so much this really helped!!!

@QuestionSolutions

2 ай бұрын

I am really glad to hear that! Keep up the great work and best wishes with your studies.

You're so smart with all these Mechanical Engineering topics. Did you study at Waterloo, UofT or MIT?

@QuestionSolutions

3 жыл бұрын

Many thanks! I hope these videos are helpful to you, and yes, UofT 👍

@rehanrashid9296

3 жыл бұрын

@@QuestionSolutions haha I have engineering friends in all 3 of the major Toronto universities: UofT, York, and Ryerson that watch your videos. Keep it up! What I personally love is that you are able to animate the problems and actually show the "dynamics" of the problem to help us visualize these problems, rather than just seeing a textbook problem that we have to infer movement, etc.

@QuestionSolutions

3 жыл бұрын

@@rehanrashid9296 That's awesome. Really glad to hear they are watching these videos. Thanks so much for taking the time to comment, I appreciate them. I will keep doing my best to help!

thank you for helping me understand well!! university tenaga nasional here!!

@QuestionSolutions

2 жыл бұрын

You're very welcome!

Very much helpful..🖤

@QuestionSolutions

Жыл бұрын

Happy to hear that! Best wishes with your studies!

i really wished u were my lecturer man, i would actually enjoy it

@QuestionSolutions

2 жыл бұрын

Thank you! Hopefully, these videos will be just as helpful with your studies.

These videos are worth more than my rented textbook and professor combined

@QuestionSolutions

2 жыл бұрын

😅 That was a funny comment!

Great explnation

@QuestionSolutions

3 ай бұрын

Thank you very much!

Thanks a lot!

@QuestionSolutions

2 жыл бұрын

You're very welcome!

You're my hero sir

@QuestionSolutions

Жыл бұрын

Thanks :)

Thank you for summarizing my statics textbook. Godbless you. You're the best. However, do you have a lect about coeff of friction?

@QuestionSolutions

Жыл бұрын

You're very welcome, and unfortunately, I don't have a video about coefficient of friction. Hopefully, one day :)

can anyone explain what made the x component a sin and the y component cos? that was the one part I didn't understand, thank you for this video

@QuestionSolutions

2 жыл бұрын

So you're missing the fundamentals on breaking forces into components using sine and cosine, please take a few minutes to watch this video :kzread.info/dash/bejne/gKaAl8ZmYqbHkrQ.html If you can watch the whole thing, great, but if not, please watch from the start to the end of the first example, I go through it step by step on how to use sine and cosine.

@ 9:50, you used a right angle triangle but is the spring making a right angle with the board? edit: I see now that from the point extension begins to the pin forms the right angle.

@QuestionSolutions

2 жыл бұрын

Yes, at the initial position, when the board is resting, it will lie perfectly horizontal.

Lovely video. There is one thing I didn't understand though. At 6.30, the equation for calculating moments- I understand the 2nd part and the third part. I am struggling to understand why in the first part, the distance from B is not taken into consideration.

@QuestionSolutions

2 жыл бұрын

For which force was the distance from B not considered? Please let me know which, I can't figure out what you mean and I would really like to clarify for you. :)

For a force couple moment, do we still ignore the force at one of the two points when we are calculating force moment? Just like what you did in the example?

@QuestionSolutions

2 жыл бұрын

Please provide a timestamp so I know where you are referring to. Thanks!

On the first example on the summation of the forces in the y-axis you made a mistake when adding -24 and -40. It's 64 and not 54..... By the way I love your content.

@QuestionSolutions

Жыл бұрын

I am not sure what you mean. We didn't add -24 and -40. We solved 3 equations. The answers shown are correct. To see the steps, please see: www.cymath.com/answer?q=x-10%2Bb(4%2F5)%3D0%2C%20y-24-40%2Bb(3%2F5)%3D0%2C%2024(2)%2B40(6)-b(3%2F5)(6)%3D0 If I am still incorrect, please provide a timestamp to the location on the video so I can look and if incorrect, write a pinned comment. :) Thanks!

💯 explanation

@QuestionSolutions

2 жыл бұрын

Thanks!

You select wonderful problems! Question if you have time. The problem at 7:00. If there is an additional moment at the intersection of pipe A and B, what would cause it and why does it not have to be included in the computation of the X Y forces?

@QuestionSolutions

Жыл бұрын

So with a collar, due to the constraints, it will create an opposing force in the x and y directions, along with an opposing moment. This moment isn't the same as a moment caused by a force a certain distance away from a point. You can think of it as an applied moment, in other words, a separate moment. When we do computation in the x or y forces, we do not care about moments. We only care about moments when we write a moment equation. Let me know if that clears it up 👍

@r2k314

Жыл бұрын

@@QuestionSolutions Thank You.

hi sorry i have a question for the last example at 9:59 . For Hooke's Law, to determine the stretch of the spring, is it not 1m (the stretched) minus the unstretched (3sintetha). Please explain why you only wrote 3sintetha

@QuestionSolutions

Жыл бұрын

For hook's law, we just have F=ks, where "s" is the stretch of the spring. So imagine you have a 2 m long spring in front of you. It's not stretched, it's just 2 m. Then "s" here would be 0. Now if the spring was stretched to 3 m, then "s" would be 1m, which is just 3-2m. So here, our spring has a length of 1m. When it was stretched, it becomes 1+3sinθ, in other words, the stretch is just "3sinθ" What we found is only the stretch, not the total length. Let me know if you need further clarifications :)

May you please tell me how d owe know around which point to we calculate the moment when they dont mention in the question, such exercise 5:32 and thank you for the amazing effort.

@QuestionSolutions

8 ай бұрын

So you want to take the moment about a point that has the most unknowns. You can take it about any point you want, but if you take it about a point that has 2 unknowns, you can eliminate those 2 forces since their lines of action go through it. See: kzread.info/dash/bejne/g4KC0LKTZpu5hKw.html

Hello Professor, thanks for the video. I do have a question concerning 7:22 why doesn't Point B also have a moment like Point A has? Or is the 20 Nm given is that the moment for B?

@QuestionSolutions

2 ай бұрын

So point A has a moment because it's a collar there. Collars create a moment about it self (see 7:09). At point B, it just a smooth surface, which cannot create a moment (see 7:15). The 20 Nm is independent to both, it is simply an additional moment given/ applied to the object.

Hello there, could you please explain to me how you found FA at 6:55 ? I would really appreciate that.

@QuestionSolutions

2 жыл бұрын

There really isn't much to explain. You have 3 equations with 3 unknowns, so you can use any method you're comfortable with to solve them. I usually use substitution, but you can use elimination or even a matrix. If you don't like any of those, you can graph the three equations to get your answer :) If you forgot about substitution, I highly recommend reviewing it because you will need it for pretty much all throughout this course, dynamics, and many more. www.khanacademy.org/math/cc-eighth-grade-math/cc-8th-systems-topic/cc-8th-systems-with-substitution/v/the-substitution-method This is for 2 equations, but it's the same process for 3 equations. You can also use wolfram alpha to check your answers.

thank you so much for the videos! I am a little confused on how you solved for theta and got 2 values in the last example problem, could you clarify? thanks again!

@QuestionSolutions

Жыл бұрын

So the easiest way is to graph the equation and see where the x-intercepts are. Please see: www.desmos.com/calculator/zaqa0burem

@alexvaldes4597

Жыл бұрын

@@QuestionSolutions Now I see. Thank you again for the videos and responses you are the best!

Hi, I got A_x and T_BC the same, but A_y = 20kN instead of 16kN for the first example.

@QuestionSolutions

2 ай бұрын

I am not sure what to tell you. 😅 You've made a numerical error but I don't know where. If you got TBC the same, then plugging in 80 into the FY equation directly solves for AY. See: www.cymath.com/answer?q=x-24-40%2B(80*3%2F5)%3D0 I just put AY as "x".

For the last question, how did you get the 82.535 deg angle, beause i can only get the 14.539 deg when using the solve for x method?

@QuestionSolutions

6 ай бұрын

See: www.desmos.com/calculator/ph4oxvuno0 Both values satisfy the equation between 0 and 90 degrees.

at 11:04, can u please explain how u get the angle 82.535 and why they are two different angles? thankyou

@QuestionSolutions

Жыл бұрын

So the easiest way to get the angles is to actually graph the equation. When you graph it, you will find 2 x-intercepts. Those are the 2 values you're looking for. You can solve this without graphing but you'd need to use trigonometric identities and it would take way longer than actually graphing it. There are 2 angles because at those 2 different angles, the system would be in equilibrium. In other words, at the angles 14.5 or 82.5 degrees, nothing would be moving, it's at rest. 👍

Hi can you explain to my why the tension of the rope are Tbc(4/5), Tbc(3/5)

@QuestionSolutions

Жыл бұрын

So we need to break the force in the rope down into it's components. We are given a slope triangle and each side corresponds to the component side we need. Please see: kzread.info/dash/bejne/gKaAl8ZmYqbHkrQ.html I cover an example with a slope triangle and show how to use them. It's the 2nd example.

Hi, I seem to have forgotten my past lessons. Could you tell me what I should restudy in order to solve the x and y components at 5:05? Thank you

@johnpatrickaguilar9442

2 жыл бұрын

I got it!

@QuestionSolutions

2 жыл бұрын

@@johnpatrickaguilar9442 Awesome :) There is a video on breaking forces into components if you need to watch, let me know, I can find it for you. It's on the statics playlist. 👍

@johnpatrickaguilar9442

2 жыл бұрын

@@QuestionSolutions Thanks for the reply, but I think I got it now. Thank you!

At 9:30, how did you figure out the angle was the same? I mean, during a test, you can't really flip the coordinate system and verify it, so is there any other way to know that?

@QuestionSolutions

3 ай бұрын

So I didn't "flip" the coordinate system to verify it, it was just to show students who watch this video. It should be intuitive to you that the angle is the same, but if it's not, that's okay, you just need to draw parallel lines and use alternate interior angles and co-interior angles to get a verification.

For the 1st problem, why is there no reaction at C? Shouldn't there be a horizontal and vertical reaction that prevent translation?

@QuestionSolutions

2 жыл бұрын

There is, but we don't care about point C since we're focusing on the beam only.

Hi, I think clockwise is a negative moment right ? why at 6:30 you said pick clockwise to become positive ?

@QuestionSolutions

Ай бұрын

Please see: kzread.infoP029mqnp4XY

Great video. Can you please explain a little better why at 7:56, when we take the sum of moments around point A, we include M_A (if its created by the forces at A) and the 20 Nm one at the curve of the body? Which forces are these moments generated from?

@QuestionSolutions

2 жыл бұрын

This is based on what type of support system it is. In this case, if you look at your textbook/ resource on what types of forces are created based on the support type, you will see that this crease a force perpendicular to the collar and a moment about it. The 20 Nm moment is already included in our problem, it's a given, so you can think of it as someone else applying a specific moment at that location. Let me know if you need more clarifications.

could you please explain how at 6:45 you concluded that the distributed force (12kN) is going to be counterclockwise and, hence negative? Is it not as if we are applying a force on the rod from the top? I feel that it would move clockwise in that sense. I am a little unsure about the signs of moments, I am having a hard time visualizing the movements, can you please explain them?

@QuestionSolutions

3 жыл бұрын

Sure, so remember we are calculating the moment about point B. That means the whole rod pivots around point B. Imagine the bar moving about point B. If we apply the 12 kN force at the location that's shown, so it's coming downwards from the top, it's impossible for it to turn clockwise, we are literally pushing something down about point B. It will 100% turn counter-clockwise. If you don't believe me, take a ruler, hold the right edge between your thumbs and push down from the top anywhere on the left side. You will see that it will try to turn counterclockwise. It's negative because we picked clockwise to be positive. So anything that goes counterclockwise becomes negative and anything clockwise becomes positive. If you picked counterclockwise to be positive, then all the clockwise moments will be negative and counter-clockwise moments will be positive. That part is up to you, but make sure to follow through. Also, I am not being mean or anything, but you are missing a lot of fundamentals when it comes to moments. Please take a few minutes to watch this video: kzread.info/dash/bejne/g4KC0LKTZpu5hKw.html I promise it'll help you out in the long run, even if its a tiny bit :)

@wt7146

3 жыл бұрын

@@QuestionSolutions Thank you so much! that for sure cleared a lot of my misconception. Will definitely give the video another watch! You're doing an awesome job! Thank you! (:

@QuestionSolutions

3 жыл бұрын

@@wt7146 Awesome! :)

how do you find the angles in q4? 10:50. i know youre supposed to graph them, but how?

@QuestionSolutions

2 жыл бұрын

www.desmos.com/calculator/7vtdo9ziaz You're looking for the x-intercepts between 0 and 90 degrees.

Wonderfully made video. Could someone kindly explain the step-by-step procedure for me to arrive at the right answer? I seem to have a different values for all 3 of them once I try solving it (5:35)

@QuestionSolutions

Жыл бұрын

Please see: www.cymath.com/answer?q=x-10%2Bt(4%2F5)%3D0%2C%20y-24-40%2Bt(3%2F5)%3D0%2C%2048%2B40(6)-t(3%2F5)(6)%3D0

@babyzed7940

Жыл бұрын

@@QuestionSolutions thank you so much 🙏🏽, you probably get this a lot but you are really a big help to all of the students who stumbles upon you videos 💯. Hope you continue doing more videos, as well as engaging to the comments.

@QuestionSolutions

Жыл бұрын

@@babyzed7940 Always really nice to read a kind comment, thank you very much! Best wishes with your studies :)

Do you have a tutorial video for geometry in getting the x and y components?

@QuestionSolutions

8 ай бұрын

Yes, I do, see: kzread.info/dash/bejne/gKaAl8ZmYqbHkrQ.html

In 5:33, why are the values in moment + when it is clockwise. In Torque isn't + is for counterclockwise and - for clockwise?

@QuestionSolutions

4 ай бұрын

It makes no difference to the direction you pick to be positive. You will get the same answer. See: kzread.infoP029mqnp4XY?feature=share

Could you explain how the force is balanced here at 10:13? I can't find a force to balance the horizontal force F_Ax. Thank you very much!!

@QuestionSolutions

Жыл бұрын

The horizontal components comes from the weight and the spring placed at an angle. So the pin counteracts those forces in both x and y directions. So the simple answer would be the x-components of the spring force and weight is countered by the x-component of the pin at A.

@astriiix__

Жыл бұрын

@@QuestionSolutions Thanks a lot!🥰

i do loves the teaching but untill now i didnt know how did you find the value at ax,ay and moment

@QuestionSolutions

4 күн бұрын

Please give me a timestamp so I can help you out better. Thanks!

At 2:20, the horizontal net force does not like being zero, unless there is one more force on the opposite direction. I really get confused on this.

@QuestionSolutions

2 жыл бұрын

I am not entirely sure what you mean. But if there are no other horizontal forces effecting an object, F_x wouldn't exist, since nothing is being countered. What do you mean by "does not like being zero?" In statics, all net forces must equal zero, if it doesn't the object is moving around. Maybe I am not understanding your question, sorry!

hey! im stuck at 7:44 where you get the answers for F-A and F-B. i dont understand how you got 39,683 and 82,54 N. Could you or anyone else explain?

@QuestionSolutions

Жыл бұрын

Hey! So all you're doing is solving for 2 unknowns with 2 equations. It might be easier to represent F_A as "x", and F_B as "y." You can use substitution, elimination, or whatever method you're comfortable with to solve them. Please see: www.cymath.com/answer?q=x(4%2F5)-y(5%2F13)%3D0%2C%20x(3%2F5)%2By(12%2F13)-100%3D0

do you mind showing me how to solve for theta at the last question? i really dont know how to the value of theha

@QuestionSolutions

Жыл бұрын

I think it's much easier to graph these problems to get a solution. That's probably what I did, I don't remember now, but usually, I try to graph them since it's faster. Otherwise, you'll have to use trigonometric identities to solve them 😅

Why is the 12 kN force in 6:51 negative? Doesn't it create a clockwise motion?

@QuestionSolutions

3 ай бұрын

No, it creates a counter-clockwise moment. Imagine the object is free to move about point B. If I push down exactly where force B is, which way will it spin? It will spin counter-clockwise about point B.

Hi! I was just wondering why at 6:01 fa in the x direction is not zero because it’s being held by a roller support meaning there would be no reaction, thanks!

@QuestionSolutions

8 ай бұрын

That would only be true if it's along the horizontal plane. Notice that our force is applied at an angle. That means that force must be broken into components and you'd get an X and Y component. 👍

@elementwave5509

8 ай бұрын

@@QuestionSolutionsthanks!

How is moment A there at 7:56. Isn't the distance =0 from the axis of rotation to the Normal force of the rod?

@QuestionSolutions

Жыл бұрын

So this moment isn't created by a force that is a certain distance away. This is a counter moment created in the joint because of the collar. You can think of it as a separate force applied.

Hello sir. Question at 7:12 . Why on the black pic the moment is ccw, but at Fa, moment is cw?

@QuestionSolutions

8 ай бұрын

So it's just an assumption. All we know is that there is a moment applied at the collar. The direction, we have no idea until we solve the problem. So you have to make an assumption about the direction, and if you get a negative value, then it's opposite to your assumption.

You're great:3 and your videos also. I can understand every step and procedure of each of the problems based on my course. The problem's from Hibbler books are easy to figure out. But my university following Analytical Mechanics by Ferries and Chambers for Mechanics Course. And the problems of that book are horrible. Too much difficult to understand. Could you please check out that book and give me some tips to solving those :))

@QuestionSolutions

2 жыл бұрын

Unfortunately, I don't know that book. But the premise of these topics are all the same. The goal isn't really to solve just problems from a single book, but rather, it is to figure out how to apply the equations learned in each section, which is why I show these examples. I also disagree that problems from Hibbler are easy to figure out, there are some very challenging ones that are very well formed by the authors of that book. I do apologize but I can't help because I don't have that book to even look at 😅

@undefined.infinity3106

2 жыл бұрын

@@QuestionSolutions It's okay 😀. I do not mean the problems are easy. The figures are quite understandable and find out the required information is easy to compare the Ferris's book. The procedure is the same but I think some problems and figures are not enough informative to approach the solving method.

@QuestionSolutions

2 жыл бұрын

@@undefined.infinity3106 Sorry I couldn't be more of help. What year was your book published? I am having a really hard time locating it.

@undefined.infinity3106

2 жыл бұрын

@@QuestionSolutions 3rd Edition. 2016-17 hey, it's completely okay. There was a group project-based that book. I was trying to solve those problems on my own. By following the solving the procedures. Sometimes I can not end up with the same answer with the book. For that, I try to solve that again and again. And that gets frustrating to solve some problems. I think im not properly able to understand the basics and solving methods. So im trying to watch these contents to find out any solution for those. 😀

@QuestionSolutions

2 жыл бұрын

@@undefined.infinity3106 I see, are they the same exact topics that's covered in these videos? As in, the same equations and so forth?

@6:15 Im confused as to how you assumed that Fa Triangle from the provided 30 deg. I Don't understand how you constructed the other triangle and know that it is the same angle as the one provided if it's coming from another spot, I Just don't see it.

@QuestionSolutions

Жыл бұрын

So for these types of things, if it doesn't come intuitively to you, which is perfectly fine, I encourage you to draw it out on a large piece of paper. Using a protractor can also help to understand geometric concepts as well. It's all to do with perpendicular and parallel lines (creating alternate interior angles, corresponding angles, etc.) but it can be hard to see sometimes. The best way is always to draw it out on a big piece of paper with a nice straight edge and visually seeing it. This will not only help you see things faster but give you an intuition as to how you can figure out other angles without too much trouble.

Goated

@QuestionSolutions

2 жыл бұрын

😅

Sir at the last example Finding Angle between 0°-90° Angle14.539 90-14.539 Should it be=75.461° ? Why 82. 535? How?

@QuestionSolutions

2 жыл бұрын

Please see: www.desmos.com/calculator/rvdow9qi6p You are looking for x-intercepts between 0 and 90 degrees.

thanksssss

@QuestionSolutions

2 жыл бұрын

You're welcome!

I have problems in visualising the angles, do you know where or how can i improve? This makes it hard for me to solve questions

@QuestionSolutions

2 жыл бұрын

Could you give me an example? Like on these problems, where did you have a hard time visualizing angles? Then I can give you some tips.

3:30,we never got taught this at school i think, how do you know that you need to divide 5 by 13 Times 26 to get Fx?

@QuestionSolutions

Жыл бұрын

Please see: kzread.info/dash/bejne/gKaAl8ZmYqbHkrQ.html Especially the 2nd example, where I explain how to use a slope triangle to figure out the forces.

hi there , excellent videos. quick question how did you go about finding the FA components at 6:15 ?? could you have moved the y component to the right instead of the x component up ? that is so confusing

@QuestionSolutions

4 ай бұрын

So components can be translated along their axis and yield the same result. What I mean is, you can actually move the y-component to the right, and the x-component to the bottom. It makes no difference to your answer since either method creates a right angle triangle with a 30 degree angle.

@eduardocarrillo930

4 ай бұрын

@@QuestionSolutions youre absolutely right man , thanks for the reply

@QuestionSolutions

4 ай бұрын

You're very welcome!@@eduardocarrillo930

@Thecarfreak100

3 ай бұрын

@@QuestionSolutions Hi! I Can't thank you enough for these videos you uploaded, much appreciated. I also do have a question like this. When you brake the FA into components like the process in video, doesn't the angle to the bar make 60 degres?(between ("Fr and Fx") And in that case the Y-axis become a Sin and the X- axis a cos? I feel confused about this, in what way am I thinking wrong and do you have any tips? Thanks in advance! 🤗

@QuestionSolutions

3 ай бұрын

You're very welcome! The way it's shown, the light green components and the dark green force, the angle is 30 degrees. If you move the components, you can draw them with a 60 degree angle. The angle doesn't matter, the components doesn't matter, none of that matters for sine and cos. In fact, whether it matters or not shouldn't be an issue to you. Forget that all and just look from the perspective of the angle. If it's in front of the angle, use sine, if it's adjacent to the angle, use cosine. Nothing else matters, don't look for patterns, or associations, or anything like that. Please see (it's less than 60 seconds): kzread.infovynnKlJD_Jo @@Thecarfreak100

6:42 sir plz tell me why you can't take 3sin30+4 as a distance

@QuestionSolutions

6 ай бұрын

We use both, one gives the vertical component and the other gives the horizontal component. So 3cos30 gives us the horizontal length of the left side, while the 3sin30 gives the vertical length.

Hello, for the first question, how do determine the x and y direction of the Tension in the rope (Point C)??

@QuestionSolutions

2 жыл бұрын

So in a rope, the force always goes towards the support. So in this case, from B to C. Once you draw the vector, you can break it into components along the x and y components.

@topefestus2193

2 жыл бұрын

@@QuestionSolutions ok thanks for replying. One more question please. Do I assume the direction of the arrows for point C?

@QuestionSolutions

2 жыл бұрын

@@topefestus2193 Yes, that's correct, in the end, it is just an assumption. I think I cover forces along ropes and stuff on this video: kzread.info/dash/bejne/im2blqlqlaWuc6Q.html

@topefestus2193

2 жыл бұрын

@@QuestionSolutions This has been really helpful. Many thanks

can u please explain the flipping of triangles in Q3? Thanks! :)

@QuestionSolutions

2 жыл бұрын

Hmm, I am not entirely sure I can explain it, but I will give it a shot. The triangle is a ratio triangle, so when the a line is perpendicular to that same force, you're just flipping it 90 degrees. At 7:31, look at the brown line at the top diagram, with the 12,13,5 triangle (right side). Now in your mind, turn that line so that it matches the green force arrow on the bottom image (right side). See how it just flips 90 degrees? I think this comes with intuition or maybe doing a lot of questions, but if you struggle with seeing this, I think an easy way to understand it would be convert the triangle into an angle. So you just use sin or cosine, use the proper sides and replace the triangle with the angle. After that, you can draw the perpendicular line and calculate the angle again. It really just boils down to knowing that a ratio triangle is just another way of giving an angle. If that doesn't work, I encourage you draw this on a blank piece of paper (draw it big), and then use a protractor to see the angle change with the perpendicular lines. That way, it will click in your mind. :)

@EngineersAcademy2020

2 жыл бұрын

You can find your answer in this video: kzread.info/dash/bejne/i4RmqqSucrrNpqQ.html

What software you're using. I think it would help my students

@QuestionSolutions

4 ай бұрын

I use illustrator to draw the diagrams and after effects to animate.

Can you tell me how to solve for teta at 11:00 since there is both sin and cos in one equation? Thank you

@QuestionSolutions

2 жыл бұрын

Probably easiest to just graph it and find the values. Otherwise, you will have to use trigonometric identities.

@gabbylayun1756

2 жыл бұрын

@@QuestionSolutions how do you graph it? i still don't get it T_T

@QuestionSolutions

2 жыл бұрын

@@gabbylayun1756 www.desmos.com/calculator/rvdow9qi6p We are looking at the values between 0 and 90 degrees. You will see 2 such values. :) To graph it on paper, you just plug values of theta in and get a rough idea of where the graph intersects the x-axis.

wait! on 6:12 you broke it into x and y components. i get that however my mind is not able to understand why is y component cos and x component sin?? isnt it the other way round? i tried to understand it but i cannot :(

@QuestionSolutions

Ай бұрын

Watch this video, it's less than 60 seconds, and you will definitely understand :) kzread.infovynnKlJD_Jo?feature=share If you still don't, let me know.

There is an error at 8:17 the 100N force going downwards, shouldent it be negative ? -100(0.3)

@QuestionSolutions

Жыл бұрын

We took clockwise to be positive, so the 100N force creates a clockwise moment, which means positive. Keep in mind that this is not an equation for the summation of forces but a moment equation. So we need to keep in mind the direction of the moment created by the force.

@jesseliew7152

Жыл бұрын

@@QuestionSolutions ohhh yaa, thanks for answering me

At 5:03, do we get to choose if cw, or ccw is positive? Thanks.

@QuestionSolutions

2 жыл бұрын

Yes, the assumed direction is totally up to you. If you get a positive answer, then your assumption is right, if you get a negative answer, then it's opposite to your assumption.

@bunjeonkookie569

2 жыл бұрын

Ohhhh ok. so regardless of the the direction (cw or ccw) they’ll both have the same answer?

@bunjeonkookie569

2 жыл бұрын

Thank you for your help, I understand now ☺️ and thanks for the videos, they help a ton!

The example at 8:51, how were you able to solve the problem and get 14.359 degrees and 82.535 degrees?

@QuestionSolutions

Жыл бұрын

You can graph them to see where it intersects. Please see: www.desmos.com/calculator/0h0abna2ty You're looking for the x-intercepts.

I am still confused.In the last problem,how was the angle found in one equation with two unknowns?

@QuestionSolutions

Ай бұрын

You can graph the equation, there is only one unknown, which is theta. There aren't 2 variables.

at 6:48 why didn’t you add the other 4m like you did at force FAcos30

@QuestionSolutions

Жыл бұрын

I assume you're talking with respect to to the FSsin30. So remember, we only care about the perpendicular distance for moments. For the sin component (which is horizontal here), the perpendicular distance, in other words, the height from the force to point B, is 3sin30, we need to break that 3 m angle slope and use the vertical distance. So we don't need the 4 m horizontal length since that's parallel to the force component.

Hello sir im having a hard time if its negative or positive what can you suggest for me to watch

@QuestionSolutions

2 жыл бұрын

Can you give me a timestamp as to where you would get confused with negatives and positives? I can help if I know exactly where you're confused. In general, positives and negatives are based upon your assumptions. For example, if I pick right to be positive, and a force is facing left, then it's going to be negative. If the force faces the way you picked to be positive, then it's positive. The same with moments. If I pick clockwise to be positive, then any moment that is clockwise will be positive and any moment that is counter-clockwise will be negative.

How to get the Tension BC in x and y axis

@QuestionSolutions

8 ай бұрын

Please use timestamps so I know where you're referring to. Thanks!

how did you find Fa and Fb at 7:48?

@QuestionSolutions

11 ай бұрын

Please see: kzread.info86uENomd53U I made a short video for you. Thanks!

7:29 Prof the MA is not cause by FA right?

@QuestionSolutions

2 жыл бұрын

That's correct, force FA's line of action would go through point A, so it can't create a moment about point A. The moment is created by the other forces applied to the object.

Where can i find sample problems like this?

@QuestionSolutions

3 ай бұрын

Most statics textbooks have plenty of questions. If you need a reference, please check the description, I always list the books used.

can you explain how you arrived at Fa and Fb in problem 3? I cannot seem to solve it. I set Fa(4/5)=Fb(5/13) and substituted but am not getting the same answer as you. any tips?

@QuestionSolutions

2 жыл бұрын

Probably a numerical error, it's really hard to say without seeing your steps. You can always graph it or you can use wolfram alpha to double check your answers. 👍

@loekkettering2743

2 жыл бұрын

I have the same problem!

@QuestionSolutions

2 жыл бұрын

@@loekkettering2743 I am pretty sure there is a typo on my part, sorry!

@loekkettering2743

2 жыл бұрын

@@QuestionSolutions I have managed to get the answers, your calculations are correct. Thank you for the very informative video, helped me a lot!

@QuestionSolutions

2 жыл бұрын

@@loekkettering2743 Awesome! :)

At 5:38 how do I solve the moment equation to get FA

@QuestionSolutions

Жыл бұрын

It probably looks a bit confusing with all the sin and cos terms, but you can convert them to decimal form to make it easier. For example, sin30 = 0.5 and 3sin30 = 1.5 and cos30 = 0.866 and 3cos30 = 2.598. If you use these instead of cos and sin, you'll see that it's easy to do. Let me know if you need further help. You can double check your work using cymath.com

@williamalston3434

Жыл бұрын

Ok so I was doing my math wrong

At 5:24 , can i know how you calculate it . Where the Tbc go

@QuestionSolutions

3 жыл бұрын

You can use the moment equation to directly solve for Tbc. Think of Tbc as x, then you can easily solve for it :)

@nurulashykin9023

3 жыл бұрын

@@QuestionSolutions thankyou

@QuestionSolutions

3 жыл бұрын

@@nurulashykin9023 You're very welcome!

why does the ratio triangles flip?

@QuestionSolutions

Жыл бұрын

It's to do with trigonometry and hard to explain through a comment, but if ratio triangles are hard to visualize, try converting them to angles. If you would like to really understand them, I encourage you to draw it out on a big piece of paper, and then using a protractor, play around with it. See how drawing another line perpendicular to it creates a new ratio triangle, but you will notice that the numerical values are the same, just opposite to them.

At 6:40, How did you get 3sin30?

@QuestionSolutions

Жыл бұрын

So that's the perpendicular distance from point A to the line of action of B. In other words, it's the vertical distance from A to B. That can be found by using sine, since the vertical distance is opposite to the 30 degree angle, giving us 3sin30. The 3 is the 3 meter diagonal length, in this case, the hypotenuse of the triangle.

Professor how in the roller support rotation can occur ,could you explain me?

@QuestionSolutions

7 ай бұрын

Please give me a timestamp so I know where you're referring to. Thanks!

@yigitcanbaysal824

7 ай бұрын

@@QuestionSolutions At 2:21 for example

@QuestionSolutions

7 ай бұрын

So one way to think about it is to imagine you placing a piece of wood or a ruler on top of a cylinder, like a can. If you push up from one end of the ruler, it would rotate about the can. In other words, the can cannot stop the ruler from rotating at all. All it can do is stop the ruler from touching your desk by creating an equal force upwards in the vertical direction. In the diagram I show at 2:20, try to imagine what would happen if you lifted up the beam from the left side end. It would rotate about the roller, right? This is why on a roller, rotation can occur. @@yigitcanbaysal824

@yigitcanbaysal824

7 ай бұрын

Oh I see, thank you professor I really appreciate it

@QuestionSolutions

7 ай бұрын

@@yigitcanbaysal824 You're very welcome. Let me know if you have any other questions

5:26 best method on solving fbc ? thanks

@QuestionSolutions

2 ай бұрын

You can directly solve for T_BC from the moment equation. After that, isolate for a single variable in eq1, then plug that value into eq2 and solve. So substitution method. If you need a refresh, I have some shorts on the channel that go through how to use the substitution method.

@unrelease9933

2 ай бұрын

@@QuestionSolutions really appreciate the fast reply this is why you're the best !

@QuestionSolutions

2 ай бұрын

@@unrelease9933 Thanks! I hope it helped you out.

@ronnaraneta1812

2 ай бұрын

​@@QuestionSolutions Hello, how did you get the 80Kn value of TBC? Thanks