when the teachers got the looks, so you just come in the class to look at them 💀

just amazing, thanks bro !!☺️

Excellent explanations! you made the emine hydrolysis reaction mechanism seem so easy!

@jOeCHEM

3 жыл бұрын

I'm so glad! Thanks for watching :) for guided practice, make sure to check out the link in the description (goes to my website), where I have a guided worksheet + answers, for free.

JOECHEM LETS GOOOOOOOO THANKS SO MUCH FOR THIS

Excellent explanation! You have a gift at making organic chemistry relatable. Thank you for the video, you have a new subscriber.

@jOeCHEM

4 жыл бұрын

Mai Rav Mai, thank you for putting a big ole’ smile on my face. If you need anything more Ochem related (videos or worksheets), please check out my site joechem.io. And a million thanks you for the sub 😁

@mairav6191

4 жыл бұрын

@@jOeCHEM Thank you so much, and anytime!

This is amazing. You make these things look so easy. Subbed :) -- Thank you!

@jOeCHEM

3 жыл бұрын

Aditya! Thank you for the kind words 😁Make sure to check out my actual website joechem.io where all my videos as well as worksheets + solutions are available for free. And if you'd subscribe to my channel (if you haven't already), I'd massively appreciate it!

@adityaiyengar152

3 жыл бұрын

@@jOeCHEM Definitely have subscribed, man! Keep it up

How do you know which side the double bond will go to (left or right) of where the original ketone was? Or will you get a mixture of products? Will one be a major?

@jOeCHEM

5 жыл бұрын

Assuming there is NOT a symmetrical structure, attempt to form the double bond on the molecule where you can lock the structure in a conformation that is sterically favorable. In this example, the double bond is formed between carbons 2, 3 because a E double bond can be formed and the methyl group can be locked into place, creating a minimized steric situation.

@jOeCHEM

5 жыл бұрын

Go to the worksheet link on this video (on my website): joechem.io/videos/37 Here is the worksheet: s3.us-east-2.amazonaws.com/prod-joechem/worksheets/Reactions%20of%20Carbonyls Here is the solution to the worksheet: s3.us-east-2.amazonaws.com/prod-joechem/worksheets/ANSWERS%20-%20Reactions%20of%20Carbonyls

Bro is getting me through ochem

for the double bond placement for enamine, why is it on the left? The carbon on the right is more substituted so more stable, so shouldnt we put the double bond there?

@jOeCHEM

Жыл бұрын

Hi Directioner Here! If you're talking about the ring problem at 11:57, the double bond is on the *less* substituted side in this case because if you were to "lock" in the right hand side (with the tertiary carbon with the methyl group), you'll likely incur more steric strain since you're working in the context of a ring as opposed to a 4:38 where we had a straight chain situation where you can lock the double bond into an E conformation, minimizing steric strain.

at 2 min 48 sec, is the hydronium a h30+? Can we protonate the OH with an H30+ or do we need to use that specific hydronium? -Gabbie

@jOeCHEM

3 жыл бұрын

Hi Gabbie! In an acidic environment, you can either use a specific acid if you’re provided with one (e.g. H2SO4) or you can generically use H3O+. At 2:48, I used H3O+ generically, but I drew it such that I could expose a proton to pick off. Does that answer your question?

@129354gabbie

3 жыл бұрын

@@jOeCHEM yes it does thank you!